Level 10 Chemistry
Lesson 1- 17th March, 2020
Ms Tiziana 2019/2020
Water of hydration follow the link - https://www.youtube.com/watch?v=OuF4hjTFdsg
Devise an experiment to calculate the percentage of water present in copper (II) sulfate.
1. Describe the method used. When writing a method please write it in numbered
steps.
i. The Crucible is weighed, and the mass is written down.
ii. After Hydrated Copper(II) Sulfate is added to the crucible till the top and
then weighed.
iii. The two different masses were calculated and subtracted to find the
Hydrated Copper(II) Sulfate mass.
iv. Then the crucible with Copper(II) Sulfate is heated for 10 minutes.
v. When all the water is going the Unhydrated anhydrous Copper(II) Sulfate
then left to cool.
vi. Later it is weighed and the mass was written
1. Record the data collected.
The weight of the crucible / g
12.73g ✅
Weight of crucible + copper (II) sulfate / g
24.11g ✅
Weight of crucible + heated copper (II) sulfate / g
20.01g ✅
2. Calculate the mass of water present in the copper (II) sulfate heated.
24.11 -12.73=11.38g
11.38-7.28=4.1g of water ✅
20.01-12.73=7.28g
3. Calculate the number of moles of water present in the copper (II) sulfate heated.
1 mole = 18g
? = 4.1g
4.1/18=0.28 moles of water present ✅
4. Calculate the percentage of water present in the copper (II) sulfate heated.
4.1/11.38X100%=36% ✅
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Level 10 Chemistry
Lesson 1- 17th March, 2020
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Ms Tiziana 2019/2020