Uploaded by Stephanie Leblanc

# HW 4 Solution(1)

```Or in 20
n Y
Problemt
3
lv
2.4
m
Point 1 Both shearand bending
compressive
y
Vn
i
Mn
v
On
ox
E
Linear
y
a
em
f
sx
x
at
f
20
or
ya
I
X
Y
5ketch internalreactions
y
a
z
Ans
TEXT
is
the same
t
Ixy
b
Anse
I
or 20
Point 3
No shear
&micro;IfT
y
01 0
but has bending tensile
3
&micro;
Tf
Point
nY
ar
for the section justright of A
d
Point 2 shear but no bending
z
I
i
2
as
n
M
z
X
I
G
or 20
I
fI
Are
Gx
3
052t F Lx 051
of Fa Ex
pg
a
Fac x 052 FL x
o
FL x
Fac x OJ t F Lx
o
FL x a
t
f
Q
Fa Lx o
t
f
O E x Ca
Q o
Fa Lx
o
0
0 Ex La
y
x
o
t
o
tf
Cz
6
t F
2
then for
o
Cz O
FL
6
o2
0 Ex
Leg
La
f
J
A
or
Fa_
Etf fFALI
YAB
Cz O
zfFaLzx
x
Cz
for
Cz
y
y
CL
ELI Cz
Since y
For
Csx
Since 0 101 0 then
t
z
a3
2tF2xg
ELI f
FLx
F
2
FLxg a
x
yC
a
CI
y ELI Ea
Thus
FL
FLxz
D
1
ay
f
gFI
x
to B
2
FFI
3
FLx
3
F 7550N
Problem 2
b
l
y
375
4
I
O
I
I
D
II
EI
Need deflection before the
use
V
0
YBC
F
a
e
y
y
375N
so
y
Im
0.5M
2
a2
Zex
EI
Use YAB
2
62 l
5.3
y
EI
IT
fy
5.3712
can use
1
Fg
0.25M
Fa
6 EID
Im
0.5in
Need deflection at
I
III
Needdeflection aftertheforce
so use
0.25M
b
e
x
O
YAB
F 7375N
D
1375
I
0.5M
X't 62 e
r6x_6EIe
force so
Sso
t
Im
17.45834y
v
O
0.5 m
I
yma
the force
either yarsory.sc
22E
D
for simplicity
Tggd
a circular
for
cross section
2,0052
23
22
20052
E
IDI
69
C69
l E.FIoaI
4g
22.200516
0002
f 207
109111
I'd
O 0323mor32.3
mn
a
x 05h 375Lx
of 650
II 650 x OJ 375 x
IJM 650 Lx
2
0.55 3752 0.755 t 650 Ex 15
o2550 5SOSx O S
375 Ex 0.7570 650 x i
375 Ex 0.255 5SOSx 0.57
o
05 371 Lx
2
6502
EI O
O2551 SSO x
iz
Lx
0.257
OS
z
375 Ex o 7SJ t 650 X
372
Lx 0.755 6502
2
D
172
CL
0 05
Boundaryconditions
For O S E
D
ELI
0.75 m
x
6520
0
2 072
3725
0.255
2
5250
0.572 CL
2
or
te f
plug
D
0
ELI
e
3721 x
0.255
SEL
x oS
CL
O Sm
t
Cs
Cs
69.5313
Ex L O ZSm
6520
2
0
6 9.53 3
D o
fOCOJ
XZ
69.5313
ELI
For
X
6
2
t
CLI ELI
6521
2
69.5313
4
207 109
Flogged
2 tt 0