# New constants and real representation of new spaces(part one) ```Title : New constants and real representation of new spaces
Elia T .Alabbas
Title : New constants and real representation of new spaces( Part one)
Author : Elia T . Alabbas
Tishreen University
Subject-class : Algebraic Geometry
[email protected]
ABSTRACT
This is a continuation of what the researcher started from previous
research, This research aims to reach an infinite number of Pythagoras
triads, By proportioning the lengths of the right-angled triangle, This will
help to represent really many spaces, The researcher was able to discover
New constants in the right-angled triangle: They are (0.28), (0.96), (1),
These New constants capable of generating an infinite number of
( 7,24,25).
Also the researcher was able to discover New constants in the rightangled triangle: They are (1), (2.4), (2.6), These New constants capable of
generating an infinite number of Pythagorean triads,(1,2.4,2.6) It is the
source of the Pythagorean triad ( 5,12,13).
Title : New constants and real representation of new spaces
Elia T .Alabbas
Depending on the Pythagorean theorem&quot; a right angled triangle:the square of the
hypotenuse is equal to the sum of the squares of the other two sides&quot; and
previous research. the researcher works to find New constants in the rightangled triangle.
A2 + B2 = C2
C
A
B
Figure 1
The research paper symbols:
A: The first side length.
B: The second side length
C: Hypotenuse length
IN previous research (Alabbas,2017,6)The researcher was able to
A = (0.6) C
discover constants in the right-angled triangle: They are (0.6), (0.8).
A = (0.6)C
B= (0.8) C
C
B= (0.8) C
Figure 2
Title : New constants and real representation of new spaces
Elia T .Alabbas
A new start:
First:
By proportioning the lengths of the right-angled triangle:
New Observation:
(7,24,25)
A=7
B = 24
C = 25
A / C = 7 / 25 = 0.28
A = (0.28)C
B / C = 24 /25 = 0.96
B = (0,96)C
C / C = 25 /25 =1
From the above, the researcher reaches the new constants:
(0.28) ,(0.96), (1)
[A, B ,C]
[0.28, 0.96, 1]
A2 + B2 = C2
(0.28)2 + (0.96)2 = (1)2
0.0784 + 0.9216= 1
example:
A=?
B=?
C=2
The solution:
A = (0.28)C
A = 0.56
B = (0.96)C
Title : New constants and real representation of new spaces
Elia T .Alabbas
B = 1.92
solution Validation by using the Pythagorean theorem:
A2 + B2 = C2
(0.56)2 + (1.92)2 = (2)2
0.3136 + 3.6864= 4
Pythagorean trilogy
(0.56,1.92,2)
The researcher was able to discover constants in the right-angled
triangle: They are(0.28), (0.96), (1).
[0.28, 0.96, 1]
C
A = (0.28) C
A = (0.28)C
B = (0,96)C
B= (0.96) C
A: The first side length.
Figure 3
B: The second side length
C: Hypotenuse length
[0.28, 0.96, 1] These New constants capable of generating an
[0.28, 0.96,1], [0.56,1.92, 2] , [0.84, 2.88, 3] ,[1.12, 3.84, 4] , [1.4, 4.8, 5]
[1.68, 5.76, 6]………………..(1)
IN previous research (Alabbas,2017,) [ 0.6, 0.8, 1] These constants
capable of generating an infinite number of Pythagorean triads
[ 0.6, 0.8, 1] , [1.2, 1.6, 2] , [1.8, 2,4, 3] , [2.4, 3.2, 4] , [3, 4, 5]
[3.6, 4.8,6]…………………(2)
{
From (1) &amp; (2) The Researcher notes [ 0.6, 0.8, 1] ,[0.28, 0.96,1]
}
Title : New constants and real representation of new spaces
Elia T .Alabbas
Hypotenuse length is represented In two different places in space in a
very simple way, Thus enabling the researcher to represent six spaces
in a real way.
Second:
By proportioning the lengths of the right-angled triangle:
New Observation:
(5,12,13)
A=5
B = 12
C = 13
A/A=5/5=1
B / A = 12 / 5 = 2.4
B = (2.4)A
C / A = 13 / 5 = 2.6
C = (2.6)A
From the above, the researcher reaches the new constants:
(1) ,(2.4), (2.6)
[A, B ,C]
[1, 2.4, 2.6]
A2 + B2 = C2
(1)2 + (2.4)2 = (2.6)2
1 + 5.76=6.76
First example:
A=2
B=?
C=?
The solution:
A= 2
B = (2.4)(2)
Title : New constants and real representation of new spaces
Elia T .Alabbas
B = 4.8
C = (2.6)(2)
C = 5.2
solution Validation by using the Pythagorean theorem:
A2 + B2 = C2
(2)2 + (4.8)2 = (5.2)2
4 + 23.04=27.04
Pythagorean trilogy
(2,4.8,5.2)
Second example:
A=3
B=?
C=?
The solution:
A= 2
B = (2.4)(3)
B = 7.2
C = (2.6)(3)
C = 7.8
solution Validation by using the Pythagorean theorem:
A2 + B2 = C2
(3)2 + (7.2)2 = (7.8)2
9 + 51.84=60.84
Pythagorean trilogy
(3,7.2,7.8)
Third example:
A=4
B=?
C=?
The solution:
A= 4
B = (2.4)(4)
B = 9.6
C = (2.6)(4)
C = 10.4
Title : New constants and real representation of new spaces
Elia T .Alabbas
solution Validation by using the Pythagorean theorem:
A2 + B2 = C2
(4)2 + (9.6)2 = (10.4)2
16 + 92.16=108.16
Pythagorean trilogy
(4,9.6,10.4)
Fifth example:
A=5
B=?
C=?
The solution:
A= 5
B = (2.4)(5)
B = 12
C = (2.6)(5)
C = 13
solution Validation by using the Pythagorean theorem:
A2 + B2 = C2
(5)2 + (12)2 = (13)2
25+144=169
Pythagorean trilogy
(5,12,13)
The researcher was able to discover constants in the right-angled
triangle: They are(1), (2.4), (2.6).
[1, 2.4, 2.6]
C = (2.6)A
A
B = (2.4)A
C = (2.6)A
A: The first side length.
B: The second side length
C: Hypotenuse length
B= (2.4) A
Figure 4
Title : New constants and real representation of new spaces
Elia T .Alabbas
[1, 2.4, 2.6] These New constants capable of generating an