Percent Yield Worksheet
a. Benzene  45.6 : 18 = 2,5 mol C6H6
1 mol C6H6  1 mol C6H5Cl
2,5 mol  x
Theoretical yield  45 g C6H5Cl
b. % = (45 : 63,7) x 100% = 70 %
x = 2,5 mol = 45 g C6H5Cl
a. Sulfur dioxide  40,5 g : 64 = 0,63 mol SO2
Carbon disulfite  25 g : 76 = 0,32 mol CS2
Theoretical yield 
1 mol CS2  2 mol SO2
x = 0,64 mol = 40,96 g SO2
0,32 mol  x
% = (40,5 : 40,96) x 100% = 98,87 %
b. Carbon dioxide  32,4 g
Oxygen  2,5 mol
Theoretical yield 
3 mol O2  1 mol CO2
2,5 mol  x
% = (32,4 : 36,52) x 100% = 88,7%
x = 0,83 mol = 36,52 g CO2