! SOWETO/DIEPKLOOF ! P.O.BOX 39067 ! BOOYSENS 2016 ! Tel. 011 938-1666/7 Fax 011 938-3603 email: sec@global.co.za website: www.sec.org.za Content Page Summary of Relevant Content 1–3 Worked Examples: Structured Questions 4–5 Worksheet 1: Multiple Choice Questions 6–8 Worksheet 2: Multiple Choice Questions 9 – 10 Worksheet 3: Multiple Choice Questions 11 – 13 Model Answers: Structured Questions 14 – 18 Answers: Worksheet 1, 2 and 3 19 © Science Education Centre 2002 Science Education Centre ! SOWETO/DIEPKLOOF ◈ P.O.BOX 39067 ◈ BOOYSENS 2016 !!! " 011 9381666/7 # 011 9383603 email: sec@global.co.za ENERGY, WORK, POWER ENERGY If something has ‘energy’ it can make things happen. To speak in more scientific terms: Energy is the capacity of a system to perform work. The 'Law of Conservation of Energy' states that energy can neither be destroyed nor created, but can be transformed from one form to another. There are several types or forms of energy. ENERGY FORMS The energy forms most commonly used are: • chemical energy • potential energy (EP) • kinetic energy (EK) • heat energy • magnetic energy • electrical energy • nuclear energy • sound energy • electromagnetic wave energy. Energy is always measured in joules (J) no matter what form it is in. Note: Sometimes EK and EP are considered together under the heading mechanical energy; sound and electromagnetic waves are considered under the heading wave energy. Chemical Nuclear Potential - EP (EP = m·g·h) Electrical (E = I · V · t) ENERGY FORMS unit: Joule (J) Magnetism Kinetic - EK (EK = ½ m · v2) Energy waves (EMS) Sound Heat Fig. 1: Energy forms: all energy resources result from the sun ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 1 Chemical energy Chemicals such as food, oil, coal and gas would be included in this list. They can all be burnt to provide heat. The chemicals inside a battery will react together to provide electricity. Chemicals are stores of energy that can be released at a convenient time. Potential energy (EP) Potential means hidden or stored. A battery, a spring or a stretched elastic band are examples of stored energy. Anything that is high up will have the ‘potential’ to be pulled down by gravity, e.g., water behind a dam. This is sometimes called ‘gravitational energy’. Kinetic energy (EK) This is the energy of movement. The k.e. of a moving object increases with mass (kg) and/or velocity (m/s). The equation used to calculate the k.e. of a moving object is: Kinetic energy = ½ · Mass · Velocity2 = ½ m · v2 Electromagnetic waves (EMS) Any wave form, such as light, X-rays, ultraviolet or gamma waves, belongs to a set known as the electromagnetic spectrum (EMS). They are sometimes called waves, rays or even radiations. These titles are sometimes even mixed together, e.g., ‘microwave radiation’. They all transfer energy from place to place. Infrared radiation is a good example and is responsible for the warming effect of a sunny day. Try to avoid phrases such as ‘heat wave’ when you really mean infrared radiation. Heat energy Ice melts when it is heated, an iron bar will expand when heated, etc. Sound energy This is an energy form because sound is the movement of air molecules. Magnetic energy Magnetism is an energy form and can make things happen (attraction/repulsion). Electrical energy The most easily converted energy form. A bulb will give out light (and heat) when provided with electrical energy. The amount of electrical energy passing through a device depends on: the current flow (in amperes), the potential difference (in volts) and the time (in seconds) for which the circuit is switched on. Increase any of these and the total energy will increase. The equation used to find electrical energy is: Energy = Current x Potential Difference x Time = I x V x t Nuclear energy As atomic nuclei break up they have a heating effect on their surroundings. In nuclear power plants nuclear energy is converted into heat, which is used to provide steam to drive a turbine in order to generate electricity. ENERGY TRANSFERS Energy changes Energy arrows (see figure 2 below) can be used to show the changes that take place when energy is used. It is quite usual for energy to be wasted (in the form of heat) when one form of energy is changed into another. Light (causes bulb to glow) Battery (Echem) Electrical Energy Heat (causes bulb to get hot: energy wasted) Fig. 2: The major energy changes that take place in a torch light ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 2 WORK In Physics, work requires a force to move. For instance: pushing a car to 'bump start' it involves work. Work always involves an applied force moving a certain distance and is measured by the product of the force and the distance it moves along its line of action. If the force is perpendicular to the direction of motion, no work is done. Work = F x s = force x distance (in the direction of the force) " " " NB Work done equals energy gained. It is a scalar. It is measured in joules (J). Total Work Done Kinetic Energy Potential Energy Energy Dissipated = = = = Applied Force x Distance* Resultant Force x Distance* Weight x Distance* Frictional Force x Distance* * Distance must always be in the direction of the force POWER Energy and power are not the same: do not confuse the terms 'energy' and 'power'. The word energy has no connection with time but power does. To be powerful means to be able to use a large amount of energy all the time. Power is the rate at which energy is used or transformed power = energy ÷ time " " or: power = work ÷ time It is a scalar. It is measured in watts (W). FORMULAE • F x s = work (provided F and S are in the same direction) • Work = Power x Time • Work done = energy gained. • Kinetic energy: EK = 1/2 m · v2 or: EK = acceleration · mass · distance* = a · m · s (derived from: v2 = u2 + ½ · a · t2 with u = 0 m/s) • Potential energy: EP = m · g · h ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 3 WORKED EXAMPLES STRUCTURED QUESTIONS Q1 A 2kg mass is accelerated horizontally from rest at 1 m/s2 for 20 m. Find: i) the force required, ii) the work done, iii) the power required. Q2 A mass of 10 kg is raised from rest to a height of 20 m using a cable with a tension of 140 N. Find a) total work done b) gain in EP c) gain in EK d) power required Q3 A pump delivers 10000 kg of water into a dam 50 m vertically above a river in 10 minutes. If the voltage of the motor is 380 V find the current required to pump the water (assume there are no frictional forces). Q4 A bullet with a mass of 20 g is fired horizontally at 500 m/s into a stationary wooden block with a mass of 4 kg. The block with the bullet embedded in it then slides for 1,55 m across a rough horizontal surface before it comes to a stop. a) Show by calculation that the velocity of the bullet and the block immediately after impact, is 2,5 m/s in the direction of motion. b) Calculate the loss of kinetic energy of the system when the bullet strikes the block. What happened to the energy? c) Calculate the average magnitude of the frictional force between the block and the surface when the block slides over it. Q5 A force of 100 N acts on a 10 kg block at an angle of 600 from the horizontal, as shown in the sketch. 100 N The frictional force experienced by the block is 20 N. 20 N 10 kg 600 Determine the acceleration with which the block moves. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 4 Q6 An object with mass 25 kg moves at a constant speed of 4 m/s along a horizontal surface towards point A. It then moves up an incline towards point B which is 0,9 m higher than point A (see sketch below). Provided all surfaces are frictionless, will the object reach point B? Show all calculations to support your answer. B 0,9 m 25kg Q7 A John, with a mass of 47kg, rides a skateboard with a mass of 3kg on a rough horizontal road. At the bottom of an incline, his velocity is 4m/s. He rides up the incline and reaches the top with a velocity of 1 m/s. the difference in height between the top and the bottom of the incline is 0,6 m. a) Calculate the work done against friction while John rode up the incline. b) When John reaches the top of the incline with a velocity of 1 m/s, his cat with a mass of 5 kg, drops from a tree into his arms. Calculate the velocity of John and the cat as they move together on the skateboard. 1 m/s 4 m/s 0,6m Q8 A skier of mass 70 kg starts from rest to move down a hill of slope 300 with a constant acceleration of 3,2 m/s2 from a point P on the top to the foot Q of the hill. The distance PQ is 100 m. a) Calculate the velocity of the skier on reaching Q. b) Calculate the loss of mechanical energy of the skier between the points P and Q. c) State the law of conservation of energy. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 5 Science Education Centre ! SOWETO/DIEPKLOOF ◈ P.O.BOX 39067 ◈ BOOYSENS 2016 !!! " 011 9381666/7 # 011 9383603 email: sec@global.co.za Topic: Work, Energy, Power Worksheet 1: Multiple Choice Questions Time: 30 Minutes Instructions: Make a cross over the letter A, B, C, D or E to show the correct answer. 1) The diagram below shows an object of mass 10 kg being pulled for a distance of 3 m by a force of 30 N. 10 kg 30 N 3m The work done is A B C D E 9J 30 J 90 J 300 J 900 J 2) A box of weight 50 N is pulled 2 m along a horizontal floor by a force of 10 N and then the box is lifted vertically through a height of 1 m (see sketch below). 1m 10 N 2m 50 N What is the total work done on the box? A B C D E 35 J 55 J 70 J 110 J 180 J 3) A girl weighing 400 N runs up a flight of stairs of vertical height 5 m in 4 seconds. Her increase in gravitational potential energy is A 1600 N B 1600 J C 1600 W D 2000 J E 2000 W ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 6 4) During the latter part of the motion of a rocket its mass is halved because the fuel is used up, while its velocity increases by a factor of 10. By what factor does the kinetic energy of the rocket increase during this stage? A B C D 5 10 50 100 5) A ball is projected vertically upwards and then returns to the ground. Ignore all friction. Which one of the following statements about the kinetic energy and potential energy of the ball is true? A B C D The kinetic energy is always equal to the potential energy The kinetic energy is always less than the potential energy The kinetic energy is always more than the potential energy. The sum of the kinetic energy and potential energy is always constant. 6) Two skiers S and T have identical masses. They begin from rest from the top of a hill at point A and move to the ski resort. Skier S takes route 1 and skier T takes route 2, as shown in the sketch. Which one of the following statements concerning the speed with which S and T reach the ski resort is correct? Ignore all friction forces. A B C D E S and T both have a speed of zero. The speed of S is smaller than the speed of T. S and T both have the same speed. The speed of S is greater than the speed of T. The information given is insufficient to answer the question. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 7 Questions 7 to 10: Here are some possible ways in which energy can change: A B C D E chemical to heat kinetic to sound kinetic to heat potential to heat potential to kinetic Which is the most important change in each of the following examples? 7) The release of an arrow from a bow. 8) The impact of the arrow in a target. 9) A cyclist riding along a level road at constant velocity. 10) A stone in mid-air, as it falls. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 8 Science Education Centre ! SOWETO/DIEPKLOOF ◈ P.O.BOX 39067 ◈ BOOYSENS 2016 !!! " 011 9381666/7 # 011 9383603 email: sec@global.co.za Topic: Work, Energy, Power Worksheet 2: Multiple Choice Questions Time: 30 Minutes Instructions: Make a cross over the letter A, B, C, or D to show the correct answer. 1. An object moving in a straight line at constant velocity has kinetic energy E and momentum p. If the speed of the object is doubled, the new value of kinetic energy and momentum will be … Kinetic Energy 2E 2E 4E 4E A B C D Momentum 2p 4p P 2p 2. A boy lifts a packet upwards by applying a constant force to it of magnitude greater than the weight of the packet. The work done by this force equals the gain in … A B C D potential energy of the package. potential energy plus kinetic energy of the package. kinetic energy of the package. kinetic energy minus the gain in potential energy. 3. An object is dropped from the top of a high building and falls freely to the ground. Which one of the graphs below best represents its potential energy (Ep) as a function of the distance (s) fallen by the object? Ep Ep A B distance Ep distance Ep C distance ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power D distance 9 4. A large and a small sphere are released at the same time from the same height above the ground. Which one of the following quantities associated with the spheres will be the same for both after 1 second, if frictional effects are ignored? A speed B momentum C potential energy D kinetic energy 5. Which one of the following expressions has the same units as power? A force x distance B work x time C force x acceleration D force x velocity 6. A person lifts a heavy load to a vertical height of 2,0 m in 3 seconds. If he/she had done this more slowly in 6 seconds, the work on the load would have been: A twice as great B four times as great C the same D half as great. 7. At what height above the ground must a mass of 10 kg be to have a potential energy equal in value to the kinetic energy possessed by a mass of 10 kg moving with a velocity of 20 m/s? A 10 m B 20 m C 50 m D 100 m 8. A girl runs up one flight of steps. Which one of the following factors does not affect the work done by the girl against gravity? A mass of the girl B height of the steps C speed of the girl D acceleration due to gravity 9. A girl weighing 400 N runs up the a flight of stairs (height 5 m) in a time of 4 seconds. Her rate of working against gravity is A 320 W B 400 W C 500 W D 2000 W 10. A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy … A at the moment of impact. B 2 seconds after the stone is released. C after the stone has fallen 40 m. D when the stone is moving at 20 m/s. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 10 Science Education Centre ! SOWETO/DIEPKLOOF ◈ P.O.BOX 39067 ◈ BOOYSENS 2016 !!! " 011 9381666/7 # 011 9383603 email: sec@global.co.za Topic: Work, Energy, Power Worksheet 3: Multiple Choice Questions Time: 30 Minutes Instructions: Make a cross over the letter A, B, C, or D to show the correct answer. T 1. An object of weight W is lifted vertically through a distance h by a cable hanging from a helicopter. The helicopter accelerates upwards and the tension in the cable is T. The work done on the object (in J) and the type of energy that this work is converted into, is … A B C D Work done on the object Th (T – W) h Th (T – W) h W Work done converted into potential energy only potential energy only potential and kinetic energy potential and kinetic energy 2. Thembi does exercises in the gym. The amount of work she does is measured in various time frames. In which of the following cases will her power output be greatest? When she does A B C D 10 J work in 10 s 60 J work in 20 s 80 J work in 30 s 100 J work in 40 s 3. A car moving at a speed of v has kinetic energy Ek. If the speed of the car increases to 2v, the kinetic energy will then be … A B C D 2 Ek 4 Ek 8 Ek 16 Ek 4. Two toy cars X and Y of mass m and 2m respectively are at rest at point A. They are allowed to run down a smooth frictionless track. As the cars pass point B, how will their velocities compare A B C D vx = vy vx = 2 vy 2 vx = vy 4 vx = vy ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power Y X A B 11 5. In the diagram to the right a simple pendulum with mass m swings to and fro. At position B the value of the potential energy and kinetic energy are as follows: EP maximum maximum minimum minimum A B C D EK maximum minimum minimum maximum A B C 6. When a racing car brakes heavily, coming to a halt, into what form of energy is its kinetic energy transformed? A B C D potential energy kinetic energy internal energy elastic energy 7. Which one of the following is a measure of power? A B C D N/s kg · m/s J/C J/s 8. Observe the pendulum in the drawing to the right. At the highest point A of its swing the ball has 500 J potential energy in respect to its lowest point. At the lowest point B of its swing the ball has 500 J kinetic energy. The total mechanical energy of this system is … A B C D 0J 250 J 500 J 1000 J A 9. Two children A and B of equal masses are at a swimming bath. Child A drops vertically from a diving board 5 m high. Child B slides from the same height down a slide into the water. A 5m ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 12 B 5m B The children start moving at the same instant. Which one of the following statements is true? (Ignore air resistance and friction on the slide.) The children hit the water … A B C D at the same time with the same speed at the same time with different speeds at different times with the same speed at different times with different speeds 10. An object is dropped from the top of a high building and falls freely to the ground. Which one of the graphs below best represents both its potential energy and kinetic energy as functions of the time fallen by the object? energy energy A EP energy EP time energy C EP ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power B D EP time 13 time time Model Answers Structured Questions: Q1: i) Since there is only one force acting on the mass, this force is the resultant force (FRes). 2 kg 2 kg a = 1m/s2 FRes FRes ii) Force x distance = work 2N x 20m = 40 J = work done iii) Power = work/time = 40J/time =m·a = 2kg · 1m/s2 =2N Since we don't know the time, we have to apply the equations of motion: given: u = 0 m/s s = u t + 1/2 · a · t2 v = ____ 20 = 0 + 1/2 · 1 · t2 a = 1 m/s2 t2 = 40 t = ??? ∴ t = √40 = 6,3 seconds s = 20 m therefore: Power = 40J/6,3s = 6,3 W Answer to Q2 140 N 140 N Start with a force diagram: 10kg Weight = mg = 100 N 40 N↑ 10 kg = a = 4 m/s2↑ (keep this for later) a) Work done = applied force x distance = 140N x 20m = 2800 J ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 14 FRes = 40 N↑ = m · a b) EP = m · g · h = 10kg · 10m/s2 · 20m = 2000 J c) EK = a · m · s = 4m/s2 · 10kg · 20m = 800 J or: EK = FRes · s = 40N · 20m = 800 J d) Power = work done / time taken 1. Find time using equations of motion: TABLE: s u = 0 m/s v = a = 4 m/s2 s = 20 m t = ??? = u t + 1/2 a t2 20m = 0 + 1/2 · 4 · t2 40/4 = 10 = t2 t = 3,16 seconds Power = work done / time taken = 2800/3,16 = 886 W Answer to Q3 This is a case of pump lifting a certain mass of water (10000 kg) up a certain vertical distance (50 m) in a certain time (600 s). Using Power = Voltage · Current we can find I. Work = Force · distance = 100000 N · 50m = 5 ·106 J Power = work/time = 5 ·106 / 600 = 5/6 ·104 = 8333 W 8333 W = 380 V · I ∴ I = 8333/380 = 21.9 A block of wood comes to rest 1,55 m from initial position Answer to Q4 + ve 500m/s Start with a diagram: given: mass of bullet mB = 20 g = 0,02 kg velocity of bullet vB = 500 m/s mass of wood mW = 4kg velocity of wood before impact vW = 0 m/s a) This is a momentum problem. Take bullet direction as positive. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 15 Momentum before = Momentum after mB · vB + mW · vW = (mB + mW) v 0,02 · (+ 500) + 4 · 0 = (0,02 + 4) v 10 + 0 = 4,02 · v ∴ v = 10/4,02 = 2,5 m/s (rounded up to 2,5) b) bullet + block bullet only EK before impact: ∴ c) = 1/2 m · v2 EK after impact: = 1/2 · 0,02 · (5·102)2 = 1/2 (mB + mW) v2 = 1/2 (00,2 + 4,0) · 2,52 = 0,01 · 25 · 104 = 2,01 · 6,25 = 2500 J = 12, 6 J EK lost (in the form of heat and sound) = EK (before) - EK (after) = 2500 J - 12,6 J = 2487,4 J table: u = 2,5 m/s v = 0 m/s a = ? t = ? s = 1,55 m frictional force frictional force ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power equation of motion: = u2 + 2 · a · s v2 0 = 2,52 + 2 · a · 1,55 -6,25 = 3,1 · a ∴a = -2 m/s2 =m·a = 4,02 · 2 = 8,04 N in the opposite direction to movement 16 Answer to Q5 The block can only move horizontally, therefore all forces must be in the horizontal direction, which the 100 N is not. So, first one has to find the component of the 100 N in the horizontal direction. 100 N cos 600 = adj/hyp = F/100N hence: F = 100N · cos 600 = 100N · 0,5 = 50 N 600 F Now we have: 10 kg 50 N 20 N FRes = 50N - 20N = 30N = a · m = a · 10 kg ∴ a = 3 m/s2 (in the opposite direction to the friction) Answer to Q6 To reach B the object must have an energy greater or at least equal to Potential energy at point B: EP = m g h = 25 · 10 · 0,9 = 225 J EP > EK But kinetic energy at point A: EK = 1/2 m v2 = 1/2 · 25 · 42 = 8 · 25 = 200 J As a result the object will not reach point B since it does not have sufficient energy at point A to do so. Answer to Q7 a) At the bottom John has only kinetic energy: EK = 1/2 m v2 = 1/2 · (47 + 3) · 42 = 25 · 16 = 400 J At the top he has potential energy (he has risen 0,6 m higher) and kinetic energy (he is still moving at 1 m/s). therefore: EP = m g h = (47 + 3) · 10 · 0,6 = 50 · 6 = 300 J EK = 1/2 m v2 = 1/2 · (47 + 3) · 12 = 25 J ∴ He still has (300 + 25) J = 325 J of energy at the top. ∴ Energy lost to friction = 400 J - 325 J = 75 J ∴ Work done against friction = 75 J ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 17 b) John's direction of movement taken as positive) Momentum before = momentum after mjohn · vjohn + mcat · vcat = (mjohn + mcat ) · v 50 · 1 + 5 · 0 = (50 + 5) · v v = 50/55 = 0,9 m/s in the direction John is moving. Answer to Q8 a) let's use equation of motion: u = 0 (starting from rest) v=? a = 3,2 m/s2 t=? s = 100 m velocity at Q: v2 = u2 + 2 · a · s = 0 + 2 · 3,2 · 100 = 640 ∴ v = 25,3 m/s v = 25,3 m/s b) Loss of energy = EP (top) - EK (bottom) = m · g · h - 1/2 m · v2 vertical distance between P and Q: P = 70 · 10 · 50* - 1/2 · 70 · 640 = 35000 J - 22400 J 100m = 12600 J 300 Q sin 300 = opp/hyp = opp/100 ∴ opp (height) = 0,5 · 100 = 50 m c) In an isolated system the energy is always conserved. It may be converted from one form to another, but it is never lost. ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 18 ANSWERS TO MULTIPLE CHOICE QUESTIONS Worksheet 1: Worksheet 2: Worksheet 3: 1 C 1 D 1 C 2 C 2 B 2 B 3 D 3 A 3 B 4 C 4 A 4 A 5 D 5 D 5 D 6 C 6 C 6 C 7 E 7 B 7 D 8 C 8 C 8 C 9 A 9 C 9 C 10 E 10 C 10 A ___________________________ © Science Education Centre 2002 Physics/FET/Revision: Work, Energy, Power 19