9/16/2019 Nanyang Technological University - Production - [PRINT] 19S1 Mathematics 1, MSE BARIQ HIBATULLAH NURLIS, 9/14/19 at 5:34:27 PM SGT Question1: Score 0.66/1 2 ⎛ Let u = ⎜ ⎝ 2 −4 ⎞ ⎟ ⎛ and v 3 ⎞ = ⎜ −1 ⎟ ⎠ ⎝ 2 . Find ⎠ (a) the magnitude of u, express your answer up to 2 decimal places. Answer : Your response 4.89 Correct response 4.90 Grade: 1/1.0 . (b) the dot product of u and v . Answer : Your response -4 Correct response -4 Grade: 1/1.0 . (c) the angle between u and v , give your answer in radians, up to 2 decimal places. Answer : Your response 102.6 Correct response 1.79 Grade: 0/1.0 . Total grade: 1.0×1/3 + 1.0×1/3 + 0.0×1/3 = 33% + 33% + 0% Question2: Score 1/1 Let a, b and c be unit vectors such that a ⋅ b ,b⋅c = 1/5 and a ⋅ c . Evaluate (write in the exact form) = 1/8 = ||2a|| = 1/2 Your response 2 Correct response Your response 5 Correct response Your response 3/8 Correct response Your response 1/8 - 1/5 Correct response Grade: 1/1.0 2a ⋅ 5b = Grade: 1/1.0 a ⋅ (b − c) = Grade: 1/1.0 (a + b + c) ⋅ (a − b) = Grade: 1/1.0 Total grade: 1.0×1/4 + 1.0×1/4 + 1.0×1/4 + 1.0×1/4 = 25% + 25% + 25% + 25% Question3: Score 1/1 If ||u|| = 2 , ||v|| = 3 and u ⋅ v = 3 , find ||u + 2v|| , express your answer up to 2 decimal places. Answer : Your response 7.22 Correct response Grade: 1/1.0 . https://ntulearn.ntu.edu.sg/webapps/blackboard/content/contentWrapper.jsp?content_id=_1732809_1&displayName=Vectors+Assignment&course_id=… 1/3 9/16/2019 Nanyang Technological University - Production - Total grade: 1.0×1/1 = 100% Question4: Score 1/1 Let u and v be vectors where ||u + v|| = 4 and ||u − v|| = 7 . Find u ⋅ v . Answer : Your response Correct response -33/4 Grade: 1/1.0 Total grade: 1.0×1/1 = 100% Question5: Score 0/1 Consider two vectors a and b , find x, y and z . = −4i − j and b = 4i + j + k . If c = xi + yj + kz, x > 0 is the unit vector that is perpendicular to both a Answer : x = Your response No answer Correct response 1/17*17^(1/2) Your response No answer Correct response -4/17*17^(1/2) Your response No answer Correct response 0 Grade: 0/1.0 y = Grade: 0/1.0 z = Grade: 0/1.0 Total grade: 0.0×1/3 + 0.0×1/3 + 0.0×1/3 = 0% + 0% + 0% Question6: Score 0/1 This question was not seen and has no response Question7: Score 0/1 This question was not seen and has no response Question8: Score 0/1 This question was not seen and has no response Question9: Score 0/1 This question was not seen and has no response Question10: Score 0/1 This question was not seen and has no response Question11: Score 0/1 This question was not seen and has no response https://ntulearn.ntu.edu.sg/webapps/blackboard/content/contentWrapper.jsp?content_id=_1732809_1&displayName=Vectors+Assignment&course_id=… 2/3 9/16/2019 Nanyang Technological University - Production - Question12: Score 0/1 This question was not seen and has no response Question13: Score 0/1 This question was not seen and has no response Question14: Score 0/1 This question was not seen and has no response Question15: Score 0/1 This question was not seen and has no response https://ntulearn.ntu.edu.sg/webapps/blackboard/content/contentWrapper.jsp?content_id=_1732809_1&displayName=Vectors+Assignment&course_id=… 3/3