Question 1 1 1 3 − (27𝑥 −2 𝑦 2 𝑧 3 ) 99. 3√𝑥 4 𝑦𝑧 Question 2 Solve the following equations 1 1 −2𝑥−3 1 3𝑥−1 2×( ) =( ) 4 8 1 𝑥+3 3( ) − 3 = 189 16 32𝑥 − 6 × 3𝑥 + 9 = 0 4𝑥 − 2𝑥+2 = 32 2 × ( 3√𝑥𝑦)
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