Electromagnetic Field Theory
ENT222
Topic 7:
Magnetostatic Field
Coulomb’s
Law
dz/dα=-ρ(1+cot2 α)
cosec2 α-cot2 α=1
z=a/tan θ=a cot θ
dz/dθ=-1-cot2 θ
cosec2 A-cot2 A=1
constant along the path in circle
Only ax because component z has
been cancelled due to the existence
of a pair of z-component in opposite
direction.
2Hob=kyb
Z-component has been
cancelled.
HΦ is all the same along Amperian path. It implied that HΦ is constant in
integration
*isolated means 2 different charge (or pole) can be
splitted.
Conservative
It implies that B is
constant.
Therefore,
not
conservative
=
0