Uploaded by Sarwar Mzory

6-shear-Stress-in-Beams

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Shear Stress in Beam
• Transverse loading applied
to a beam results in normal
and shearing stresses in
transverse sections.
• When shearing stresses are
exerted on the vertical
faces of an element, equal
stresses must be exerted
on the horizontal faces.
28 March 2017
1
• Longitudinal shearing stresses
must exist in any member
subjected to transverse loading.
for non-uniform bending, M acts on
C𝐢 and M + dM acts on D𝐷, consider
dA at the distance y1 from N.A.
the total horizontal force on C𝐢 is
𝑀. 𝑦
𝑑𝐴
𝐼
𝐹1= 𝜎𝐢 𝑑𝐴 =
Similarly
𝐹2 = 𝜎𝐷 𝑑𝐴 =
𝝉
𝑀 + 𝑑𝑀 . 𝑦
𝑑𝐴
𝐼
and the horizontal force on 𝐢 𝐷is
𝐹3 = 𝝉 b dx
28 March 2017
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equation of equilibrium
𝐹3 = 𝐹2 − 𝐹1
𝝉 b dx =
𝑀 + 𝑑𝑀 . 𝑦
𝑑𝐴 −
𝐼
𝑑𝑀
𝝉 b dx =
𝐼
𝑑𝑀 1
𝝉 =
𝑑π‘₯ 𝐼. 𝑏
𝑀. 𝑦
𝑑𝐴
𝐼
𝑦 𝑑𝐴
𝑦 𝑑𝐴
𝝉 =
𝑉
𝐼. 𝑏
𝑦 𝑑𝐴
denote Q = ∫y dA is the first moment of the cross section area above the level y
(area CD𝐢 𝐷) at which the shear stress 𝝉 acts, then
𝝉 =
𝑉. 𝑄
𝐼. 𝑏
28 March 2017
shear stress formula
3
Notes
For two equal rectangular beams of height
h subjected to a concentrated load P, if no
friction between the beams, each beam
will be in compression above its N.A., the
lower longitudinal line of the upper beam
will slide w.r.t. the upper line of the lower
beam.
For a solid beam of height 2h, shear stress
must exist along N.A. to prevent sliding,
thus single beam of depth 2h will much
stiffer and stronger than two separate
beams each of depth h.
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Shear Stress in Beam of Rectangular Cross Section
𝑉. 𝑄
𝝉 =
𝐼. 𝑏
for V, I, b are constants, 𝝉 ~ Q
β„Ž
𝑸=𝑏
−𝑦
2
𝑏 β„Ž2
𝑸=
− 𝑦2
2 4
β„Ž
−𝑦
2
𝑦+
2
Then
𝑉. 𝑄
𝑉 β„Ž2
𝝉=
=
− 𝑦2
𝐼. 𝑏
2 𝐼 4
𝜏=0 at y=± h/2, πœπ‘šπ‘Žπ‘₯ occurs at y= 0 (N.A)
Parabolic variation
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π‰π’Žπ’‚π’™
𝑉. 𝑄
𝑉 β„Ž2
=
=
− 𝑦2
𝐼. 𝑏
2 𝐼 4
π‰π’Žπ’‚π’™
𝑉. 𝑄
𝑉 β„Ž2
=
=
− 02
𝐼. 𝑏
2 𝐼 4
π‰π’Žπ’‚π’™
𝑉. β„Ž2
=
8 𝐼
π‰π’Žπ’‚π’™
𝑉. β„Ž2
=
𝑏. β„Ž3
8
12
π‰π’Žπ’‚π’™ (at y=0)
𝑏. β„Ž3
𝑰=
12
π‰π’Žπ’‚π’™
𝑉
= 1.5
𝐴
12 𝑉
=
8 𝑏. β„Ž
𝝉𝒂𝒗𝒆 =
π‰π’Žπ’‚π’™ =
𝑉
𝐴
3𝑉
2 𝑏. β„Ž
= average shear stress
π‰π’Žπ’‚π’™ (at y=0) = 1.5 𝝉𝒂𝒗𝒆
28 March 2017
6
A 14-ft long simply supported timber beam carries a 6-kip concentrated load at mid
span, as shown in Figure. The cross-sectional dimensions of the timber are shown in
Figure.
(a) At section a–a, determine the magnitude of the shear stress in the beam at point H.
(b) At section a–a, determine the magnitude of the shear stress in the beam at point K.
(c) Determine the maximum horizontal shear stress that occurs in the beam at any
location within the 14-ft span length.
(d) Determine the maximum tension bending stress that occurs in the beam at any
location within the 14-ft span length.
28 March 2017
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28 March 2017
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28 March 2017
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If the T-beam is subjected to a vertical shear of V= 12 Kip, determine the maximum
shear stress in the beam. Also, compute the shear-stress jump at the flange web
junction AB. Sketch the variation of the shear-stress intenstiye over the entire cross
section.
26 March 2018
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