Uploaded by Sailesh Arvapalli

ASSIGNMENT 2 BY ROLL NO 10

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E.MANOJ ROLLNO:10

1.

Write a C program to perform all the operations of single linked list

Output

2. a) Explain AVL trees with example.

In computer science, an AVL tree is a self-balancing binary search tree. It was the first such data structure to be invented.

[2]

In an AVL tree, the heights of the two child subtrees of any node differ by at most one; if at any time they differ by more than one, rebalancing is done to restore this property. Lookup, insertion, and deletion all take O(log n) time in both the average and worst cases, where n is the number of nodes in the tree prior to the operation. Insertions and deletions may require the tree to be rebalanced by one or more tree rotations.

Here we see that the first tree is balanced and the next two trees are not balanced

In the second tree, the left sub tree of C has height 2 and the right sub tree has height 0, so the difference is 2. In the third tree, the right sub tree of A has height 2 and the left is missing, so it is 0, and the difference is 2 again. AVL tree permits difference (balance factor) to be only 1.

Balance Factor = height(left-sub tree) − height(right-sub tree)

If the difference in the height of left and right sub-trees is more than 1, the tree is balanced using some rotation techniques.

In a binary tree the balance factor of a node N is defined to be the height difference

BalanceFactor(N) := –Height(LeftSubtree(N)) +

Height(RightSubtree(N)) of its two child subtrees. A binary tree is defined to be an AVL tree if the invariant

BalanceFactor(N)

{

1,0,+1} holds for every node N in the tree.

A node N with BalanceFactor(N) < 0 is called

"left-heavy", one with BalanceFactor(N) > 0 is called "right-heavy", and one with BalanceFactor(N) = 0 is sometimes simply called "balanced". b) Explain all the types of rotations with example.

AVL Rotations

To balance itself, an AVL tree may perform the following four kinds of rotations

• Left rotation

• Right rotation

• Left-Right rotation

• Right-Left rotation

The first two rotations are single rotations and the next two rotations are double rotations. To have an unbalanced tree, we at least need a tree of height 2. With this simple tree, let's understand them one by one.

Left Rotation

If a tree becomes unbalanced, when a node is inserted into the right subtree of the right subtree, then we perform a single left rotation

In our example, node A has become unbalanced as a node is inserted in the right subtree of A's right subtree. We perform the left rotation by making A the left-subtree of B.

Right Rotation

AVL tree may become unbalanced, if a node is inserted in the left subtree of the left subtree.

The tree then needs a right rotation.

As depicted, the unbalanced node becomes the right child of its left child by performing a right rotation.

Left-Right Rotation

Double rotations are slightly complex version of already explained versions of rotations. To understand them better, we should take note of each action performed while rotation. Let's first check how to perform Left-Right rotation. A left-right rotation is a combination of left rotation followed by right rotation.

Right-Left Rotation

The second type of double rotation is Right-Left

Rotation. It is a combination of right rotation followed by left rotation.

3. a) Explain stacks and all its operations.

A stack is an Abstract Data Type (ADT), commonly used in most programming languages. It is named stack as it behaves like a real-world stack, for example – a deck of cards or a pile of plates, etc.

A real-world stack allows operations at one end only. For example, we can place or remove a card or plate from the top of the stack only. Likewise,

Stack ADT allows all data operations at one end only. At any given time, we can only access the top element of a stack.

This feature makes it LIFO data structure. LIFO stands for Last-in-first-out. Here, the element which is placed (inserted or added) last, is accessed first. In stack terminology, insertion operation is

called PUSH operation and removal operation is called POP operation.

Stack Representation

The following diagram depicts a stack and its operations –

A stack can be implemented by means of Array,

Structure, Pointer, and Linked List. Stack can either be a fixed size one or it may have a sense of dynamic resizing. Here, we are going to implement stack using arrays, which makes it a fixed size stack implementation.

Basic Operations

Stack operations may involve initializing the stack, using it and then de-initializing it. Apart from these basic stuffs, a stack is used for the following two primary operations −

• push() − Pushing (storing) an element on the stack.

• pop() − Removing (accessing) an element from the stack.

When data is PUSHed onto stack.

To use a stack efficiently, we need to check the status of stack as well. For the same purpose, the following functionality is added to stacks −

• peek() − get the top data element of the stack, without removing it.

• isFull() − check if stack is full.

• isEmpty() − check if stack is empty.

At all times, we maintain a pointer to the last

PUSHed data on the stack. As this pointer always represents the top of the stack, hence named top.

The top pointer provides top value of the stack without actually removing it.

First we should learn about procedures to support stack functions

Push Operation

The process of putting a new data element onto stack is known as a Push Operation. Push operation involves a series of steps −

• Step 1 − Checks if the stack is full.

• Step 2 − If the stack is full, produces an error and exit.

• Step 3 − If the stack is not full, increments top to point next empty space.

• Step 4 − Adds data element to the stack location, where top is pointing.

• Step 5 − Returns success.

If the linked list is used to implement the stack, then in step 3, we need to allocate space dynamically.

Algorithm for PUSH Operation

A simple algorithm for Push operation can be derived as follows − begin procedure push: stack, data

if stack is full

return null

endif

top ← top + 1

stack[top] ← data end procedure

Pop Operation

Accessing the content while removing it from the stack, is known as a Pop Operation. In an array implementation of pop() operation, the data element is not actually removed, instead top is decremented to a lower position in the stack to point to the next value. But in linked-list implementation, pop() actually removes data element and deallocates memory space.

A Pop operation may involve the following steps −

• Step 1 − Checks if the stack is empty.

• Step 2 − If the stack is empty, produces an error and exit.

• Step 3 − If the stack is not empty, accesses the data element at which top is pointing.

• Step 4 − Decreases the value of top by 1.

• Step 5 − Returns success.

Algorithm for Pop Operation

A simple algorithm for Pop operation can be derived as follows − begin procedure pop: stack

if stack is empty

return null

endif

data ← stack[top]

top ← top - 1

return data end procedure b) Write a C program for queues using linked list

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