6-1 Integer Exponents Property Product of Power of a Powers Power Power of a Product Words To multiple powers that have the same base, add the exponents To find a power of a power, multiply the exponents To find a power of a product, find the power of each factor and multiply the exponents Algebra am•an=am+n (am)n=amn (ab)m=ambm Example 56•59=56+9 (34)2=34•2=38 (232•17)5= 10175 15 23 =5 Holt McDougal Algebra 1 6-1 Integer Exponents Property Quotient of Power of a Powers Quotient Words Algebra Example Holt McDougal Algebra 1 To divide powers having the same base, subtract the exponents m a mn a n a 7 4 72 4 2 4 To find a power of a quotient, find the power of the numerator and the denominator and divide m a a m b 7 b 7 3 3 7 2 2 m 6-1 Integer Exponents Holt McDougal Algebra 1 6-1 Integer Exponents Notice the phrase “nonzero number” in the previous table. This is because 00 and 0 raised to a negative power are both undefined. For example, if you use the pattern given above the table with a base of 0 instead of 5, you would get 0º = . Also 0–6 would be = . Since division by 0 is undefined, neither value exists. Holt McDougal Algebra 1 6-1 Integer Exponents Example 2: Zero and Negative Exponents Simplify. A. 4–3 B. 70 7º = 1 C. (–5)–4 D. –5–4 Holt McDougal Algebra 1 6-1 Integer Exponents Caution In (–3)–4, the base is negative because the negative sign is inside the parentheses. In –3–4 the base (3) is positive. Holt McDougal Algebra 1 6-1 Integer Exponents Simplify. a. 10–4 Check It Out! Example 2 b. (–2)–4 c. (–2)–5 d. –2–5 Holt McDougal Algebra 1 6-1 Integer Exponents Example 3A: Evaluating Expressions with Zero and Negative Exponents Evaluate the expressions for the given value of the variables. x–2 for x = 4 p–3 for p = 4 –2a0b-4 for a = 5 and b = –3 for a = –2 and b = 6 Holt McDougal Algebra 1 2 6-1 Integer Exponents What if you have an expression with a negative exponent in a denominator, such as ? ***An expression that contains negative So if a base with a negative exponent is in a or zero exponents isitnot considered to be simplified. denominator, is equivalent to the same base with Expressions should be rewritten with only the opposite (positive) exponent in the numerator. positive exponents.*** Holt McDougal Algebra 1 6-1 Integer Exponents Simplify the expression. 5. (42)7 = 414 6. [(–2)4]5 7. (n3)6 = n18 8. [(m + 1)5]4 = (m + 1)20 Holt McDougal Algebra 1 = (–2)20 Example 2 Exponents 6-1 Integer Simplify the expression. x 3 x3 a. = 3 y y b. –7 x 2 = –7 x Holt McDougal Algebra 1 2 (– 7)2 49 = = x2 x2 6-1 Integer Exponents Find the values of x and y with the given information. y b 3 b x b y 2 b b 13 b 3x b Holt McDougal Algebra 1 6-1 Integer Exponents Solve for x and/or y 1. 4 2 x 4 8 2 x 2. 64 82 Holt McDougal Algebra 1 3 y 1 y 6-1 Integer Exponents Simplify each expression. 1. 2. 4 1 10 3. 4. –3 Holt McDougal Algebra 1 6-1 Integer Exponents Another way to write nth roots is by using fractional exponents. For example, for b >1, suppose b1 = b2k 1 = 2k Square both sides. Power of a Power Property If bm = bn, then m = n. Divide both sides by 2. So for all b > 1, Holt McDougal Algebra 1 6-1 Integer Exponents Check It Out! Example 1 Simplify each expression. a. Use the definition of 1 b .n =3 b. Use the definition of = 11 + 4 = 15 Holt McDougal Algebra 1 1 b .n 6-1 Integer Exponents Additional Example 2: Simplifying Expressions with Fractional Exponents Simplify each expression. A. B. = 243 C. = 25 D. =8 E. = 81 Holt McDougal Algebra 1 =1 6-1 Integer Exponents Additional Example 4B: Properties of Exponents to Simplify Expressions Simplify. All variables represent nonnegative numbers. Holt McDougal Algebra 1 6-1 Integer Exponents Holt McDougal Algebra 1 6-1 Integer Exponents A monomial is a number, a variable, or a product of numbers and variables with whole-number exponents. Holt McDougal Algebra 1 6-1 Integer Exponents Monomials NOT a monomial 5+z 2/n 4a x-1 Holt McDougal Algebra 1 Reason A sum is not a monomial A monomial cannot have a variable denominator A monomial cannot have a variable exponent The variable must have a whole number exponent. 6-1 Integer Exponents Monomial 10 3x Degree 0 1 1+2=3 -1.8m5 5 The degree of a monomial is the sum of the exponents of the variables. A constant has degree 0. Holt McDougal Algebra 1 6-1 Integer Exponents Example 1: Finding the Degree of a Monomial Find the degree of each monomial. A. 4p4q3 The degree is 7. B. 7ed The degree is 2. C. 3 The degree is 0. Holt McDougal Algebra 1 6-1 Integer Exponents Check It Out! Example 1 Find the degree of each monomial. a. 1.5k2m The degree is 3. b. 4x The degree is 1. c. 2c3 The degree is 3. Holt McDougal Algebra 1 6-1 Integer Exponents A polynomial is a monomial or a sum or difference of monomials. Each monomial in a polynomial is called a term. The degree of a polynomial is the degree of the term with the greatest degree. Holt McDougal Algebra 1 6-1 Integer Exponents Polynomials Degree of polynomial 2 x x 5 x 12 3 Leading Coefficient Holt McDougal Algebra 1 2 Constant term 6-1 Integer Exponents Special Polynomials • Binomial – Polynomial with two terms • Trinomial – Polynomial with three terms Holt McDougal Algebra 1 6-1 Integer Exponents Example 2: Finding the Degree of a Polynomial Find the degree of each polynomial. A. 11x7 + 3x3 The degree of the polynomial is the greatest degree, 7. B. The degree of the polynomial is the greatest degree, 4. Holt McDougal Algebra 1 6-1 Integer Exponents Check It Out! Example 2 Find the degree of each polynomial. a. 5x – 6 The degree of the polynomial is the greatest degree, 1. b. x3y2 + x2y3 – x4 + 2 The degree of the polynomial is the greatest degree, 5. Holt McDougal Algebra 1 6-1 Integer Exponents Holt McDougal Algebra 1 6-1 Integer Exponents Some polynomials have special names based on their degree and the number of terms they have. Degree Name Terms Name 0 Constant 1 Monomial 1 Linear 2 Binomial 2 Quadratic Trinomial 3 4 Cubic Quartic 3 4 or more 5 Quintic 6 or more Holt McDougal Algebra 1 6th,7th,degree and so on Polynomial 6-1 Integer Exponents Example 4: Classifying Polynomials Classify each polynomial according to its degree and number of terms. A. 5n3 + 4n cubic binomial. B. 4y6 – 5y3 + 2y – 9 6th-degree polynomial. C. –2x linear monomial. Holt McDougal Algebra 1 6-1 Integer Exponents Check It Out! Example 4 Classify each polynomial according to its degree and number of terms. a. x3 + x2 – x + 2 cubic polynomial. b. 6 constant monomial. c. –3y8 + 18y5 + 14y 8th-degree trinomial. Holt McDougal Algebra 1 Example 2 Exponents 6-1 Integer Tell whether is a polynomial. If it is a polynomial, find its degree and classify it by the number of its terms. Otherwise, tell why it is not a polynomial. Expression Is it a polynomial? Classify by degree and number of terms a. 9 Yes constant monomial b. c. d. e. 2x2 + x – 5 Yes Quadratic trinomial 6n4 – 8n No; variable exponent n– 2 – 3 No; negative exponent 7bc3 + 4b4c Yes Holt McDougal Algebra 1 Quintic binomial 6-1 Integer Exponents Example 5: Application Continued A tourist accidentally drops her lip balm off the Golden Gate Bridge. The bridge is 220 feet from the water of the bay. The height of the lip balm is given by the polynomial –16t2 + 220, where t is time in seconds. How far above the water will the lip balm be after 3 seconds? After 3 seconds the lip balm will be 76 feet from the water. Holt McDougal Algebra 1 6-1 Integer Exponents Check It Out! Example 5 What if…? Another firework with a 5-second fuse is launched from the same platform at a speed of 400 feet per second. Its height is given by –16t2 +400t + 6. How high will this firework be when it explodes? 1606 feet Holt McDougal Algebra 1 6-1 Integer Exponents Solve for x and/or y 1. 4 2 x 4 8 2 x 2. 64 82 Holt McDougal Algebra 1 3 y 1 y 6-1 Integer Exponents Simplify the expression. Write your answer using only positive exponents. a. b. 8x3 = 15 y (2xy–5)3 (2x)–2y5 –4x2y2 8 = – 12 x y 4x 2 y 7 6 2 Holt McDougal Algebra 1 y3 16x4 6-1 Integer Exponents Lesson Quiz: Part II 5. In an experiment, the approximate population P of a bacteria colony is given by , where t is the number of days since start of the experiment. Find the population of the colony on the 8th day. 480 Simplify. All variables represent nonnegative numbers. 6. 7. Holt McDougal Algebra 1 6-1 Integer Exponents Lesson Quiz: Part I Find the degree of each polynomial. 1. 7a3b2 – 2a4 + 4b – 15 2. 25x2 – 3x4 5 4 Write each polynomial in standard form. Then give the leading coefficient. 3. 24g3 + 10 + 7g5 – g2 4. 14 – x4 + 3x2 Holt McDougal Algebra 1 7g5 + 24g3 – g2 + 10; 7 –x4 + 3x2 + 14; –1 6-1 Integer Exponents Lesson Quiz: Part II Classify each polynomial according to its degree and number of terms. 5. 18x2 – 12x + 5 6. 2x4 – 1 quadratic trinomial quartic binomial 7. The polynomial 3.675v + 0.096v2 is used to estimate the stopping distance in feet for a car whose speed is v miles per hour on flat dry pavement. What is the stopping distance for a car traveling at 70 miles per hour? 727.65 ft Holt McDougal Algebra 1