The formulas used to convert between temperatures are as follows:
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°C = (°F - 32) * 5 / 9
°F = (°C * 1.8) + 32
K = °C + 273.15
°C = K - 273.15
gym to swim laps. If swimming burns 7.95×105cal per
hour, h?
To practice converting between different units of energy.
Duncan is a college student studying for a chemistry exam this evening. He also plans to go
swimming at the school gym and have a dinner of ramen noodles. While the water for the
ramen is heating, it absorbs energy as it gets hot. Later, while swimming, Duncan uses the
potential energy in the food he has consumed.
The following conversion factors may be useful in this problem:
1 cal1 kJ==4.184 J1000 J
1) Duncan takes a break from studying and goes to the gym to swim laps. If swimming
burns 7.95×105cal per hour, how many kilojoules does swimming burn in that same amount
of time?
In other words, convert 7.95×105cal to kilojoules.
Express your answer numerically in kilojoules.
1 cal = 0.004184 kj
6.95 x 10^5 = 69500 x 0.004184 = .................kj
Pure Substance
An iron Nail
propane
salt substitute
Mixture
A soft Drink
A cheese sandwich