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Fractal – Group 2 Buenaobra Munda Del Rio Malate Explicit Formula: An = 3n – 2 Recursive Formula: A1 = 1 An = (An-1) + 3 Box Making Report Math Performance Task Solution: Dimensions: 15 x 20 Maximum volume of the box: V = (20 – 2x)(15 – 2x)(x) [(20 – 2(3)] [(15 – 2(3)] (3) (15 -6) (3) (20 - 6) (14) (9) (3) length = 14 in width = 9 in height = 3 in V = 378 in^3 Illustration: 15 – 2x = 15-2(3) = 15 – 6 = 9 in 3 in Submitted by: Alcantara, Munda, Sarabia, Tancontian The first step for the box making is identifying the length, width and height of the box using the dimensions of the cardboard. The formula above shows how we got our desired measurements for our box. We identified the “x” which is 3 inches and will also be the height of the box. After solving, we got the measurements, 14 inches for the length, 9 inches for the width and 3 inches for the height. We got the maximum volume of the box by multiplying the length, width, and height of the box. Over-all, the maximum volume of the box is 378 in^3. 3 in 3 in 20 – 2(x) = 20 – 2(3) = 20 – 6 = 14 in