Unit Conversion Worksheet Name: _________________________________ Date: __________________ When converting from one a unit to another it is useful to use conversion factors. Conversion factors are fractions that equal 1 because the numerator (top) equals the denominator (bottom), but they use different units. In algebra you learned that multiplying any quantity by 1 does not change the quantity’s value, so we can use conversion factors to change the units of a measurement without changing the value of a measurement. For instance, since 1 km = 1000 m, 1 min = 60 s, and 1 hr = 60 min, we can create the conversion factors below: 1 ππ 1000π π , 1ππ ππ 1πππ π 1β ππ , ππ 60π 1πππ 3600π π 1β , 1ππ ππ 1000π π 1 ππ and …….. you can make your factor or conversion. By using all 3 of these conversion factors you can convert 15 km/hr into m/s. Be careful to use the conversion factor that cancels the units you are trying to convert out of. If you can cancel (reduce to 1) those units you did it correctly. 15 π (1000π) 1β π₯ π₯ = 4.2π/π β (1 ππ) 3600π Carry out the following conversions. If you have trouble, start by writing out the conversion factors you’ll need. 1) 1.5 year (non-leap year) into seconds. 2) 23 km into cm. 23ππ ( ) ( ) π₯ ( ) ( ) = _________ππ 1 3) 35 kg. into g, 35π 4) 15.6 kg into mg . ( ) ( ) 15.6ππ 5) 8.5 m/s into km/hr 8.5 = _________ππ ( ) ( ) π( ) π ( ) = _______________π π₯ ( ) ( ) π₯ ( ) ( ) = ___________ ππ⁄β 6. Use figure describe the trip without stopping. Takes 10 hour and 30 minutes to travel from Little Elm Texas to Pensacola Fl, and it corresponding distance is 1088.56 km. a) How many meter there are from Little Elm Texas to Pensacola Fl, b) How many centimeter there are from Little Elm Texas to Pensacola Fl, c) How many millimeters there are from Little Elm Texas to Pensacola Fl, d) What is the total time in minutes? e) What is the total time in seconds? f) What is the ration, distance/time in meters/second? 2 Part II: Pre-AP Physics Only (For General Physics, if you want to Earn 10 daily grade points. Solve problems 7 to 13 showing your work step by step. Incomplete work is not accepted. 7) 35 kg. into g, 35π ( ) ( ) = _________ππ 8) 53 kg2 into g2, 53ππ2 ( ) ( ) 9) 53 kg3 into g3, 53ππ3 ( ) ( ) = _____________π2 = _____________π3 10) How many square meters are there in 10,000 m × 10,000 m 11) How many square kilometers are there in 10,000 m × 10,000 m 12) How many square centimeter are there in 10,000 m × 10,000 m 3 13. The mass of the Earth is 5.98π₯1024 ππ, and its radius is 6400 km. 3 a) Calculate the volume of the Earth [Ideas: Use the equation of volume of sphere π = (4)ππ 3] b) Calculate the average density of the earth in πΎπ/π3? πππ π π [Ideas: Use the equation density =π£πππ’πππ or π = π ] c) Calculate the average density of the earth in π/ππ3 ? 4