Electric Circuits Physics 102 Lecture 2 14 February 2002 HAPPY VALENTINE’S DAY 14 Feb 2002 Physics 102 Lecture 2 1 LAURA HELLER - WEDNESDAY LAB 14 Feb 2002 Physics 102 Lecture 2 2 Capacitors Two parallel conducting plates with equal but opposite charges form a capacitor. Neglecting “fringing” near the edges: The field inside is uniform with E = σ / ε 0 (σ is the charge per unit area on the plate q/a) The field outside vanishes. d A The charge on each plate of a capacitor is proportional to the potential difference between the plates, q = CV . Capacitance has units farad=coulomb/volt. For this geometry C = ε 0 A / d , so ε 0 has units of farads/meter. 2 Capacitors store energy 14 Feb 2002 = CV / 2 2 = Q / 2C Physics 102 Lecture 2 3 Capacitors and Dielectrics A dielectric material in a capacitor will reduce the field strength by a factor κ = E0 / E (dielectric constant). The voltage is also reduced because V = Ed . Since q = CV = const. , C must increase when the dielectric is inserted. For parallel plates: C = κε 0 A / d 14 Feb 2002 Physics 102 Lecture 2 4 Energy in Capacitor with Dielectric 2 Without a dielectric: With a dielectric: 2 C0V0 Q0 = = 2 2C0 2 0 0 2 0 CV Q = = 2κ 2κC0 If we charge up a capacitor with a dielectric nearby, what will happen? A) Nothing, dielectrics are electrically neutral. B)The dielectric is repelled. C)The dielectric is sucked in. 14 Feb 2002 Physics 102 Lecture 2 5 A dielectric is inserted between the plates of a capacitor. The system is then charged and the dielectric is removed. The electrostatic energy stored in the capacitor is A. greater than B. the same as C. smaller than it would have been if the dielectric were left in place. 14 Feb 2002 Physics 102 Lecture 2 6 A parallel-plate capacitor is attached to a battery that maintains a constant potential difference V between the plates. While the battery is still connected, a glass slab is inserted so as to just fill the space between the plates. The stored energy A. increases. B. decreases. C. remains the same. 14 Feb 2002 Physics 102 Lecture 2 7 Electromotive Force and Currents I I I Chemical reactions can transfer charge from one place to another Charge separation creates an electrical potential difference, or emf (electromotive force) Sustained emf creates a current in a conducting wire: I = ∆q / ∆t [unit of current ampere=coulomb/second] 14 Feb 2002 Biochemical Dry cell battery Auto battery Van de Graaff Lightning 1-100 mV 1.5 V 12 V 4.5 MV 108-109 V Potential DIFFERENCES Physics 102 Lecture 2 8 Voltage Vs. Current The voltage is the energy per charge. In a fluid analogy, voltage is like a pressure difference. Batteries produce voltage differences. Pumps, for example, produce pressure differences. Water reservoir Pressure difference from height of reservoir corresponds to voltage. Current is the number of charges through a cross section per second. Current corresponds to the flow of water in the fluid analogy. Av → I ∆P → ∆V 14 Feb 2002 Physics 102 Lecture 2 9 Ohm’s Law In many materials, the current that flows is proportional to the voltage across (potential difference) the material: I ∝ V The proportionality constant is the resistance R, a property of the particular piece of material Ohm’s Law: V = IR I ∆V Note that Ohm’s “Law” is only an approximation that holds true over a particular range of currents and voltages, and it is not at all correct for some materials; it is not a fundamental law. 14 Feb 2002 Physics 102 Lecture 2 10 Series and Parallel Circuits When multiple resistors are connected in a circuit, we use two simple rules: I I Resistors in series R = R1 + R2 I i Resistors in parallel 1 1 1 = + R R1 R2 I More complex circuits are broken into simple pieces 14 Feb 2002 Physics 102 Lecture 2 11 Resistive Properties of Materials I Resistivity is an intrinsic property of a material N N N I L is length of object A is cross sectional area of objectFF ρ is the resistivity (units ohms·meters) L R=ρ A Resistivity (and resistance) often depend on temperature (increasing with T in metals) ρ = ρ0 [1 + α (T − T0 )] R = R0 [1 + α (T − T0 )] 14 Feb 2002 Physics 102 Lecture 2 Cool 12 •Recall that power is energy per unit time. •As charges move (or currents flow), the electric field does work on the particles (changes their energies). ∆E ∆qV P= = = IV ∆t ∆t 2 = I ( IR) = I R •Recall that a watt is the SI power unit, so kilowatt-hour is a unit of energy. 14 Feb 2002 Physics 102 Lecture 2 2 V V = V= R R 13 A. I B. They’re the same C. II •The resistance of circuit I is smaller than of circuit II •Hence more current flows through battery in I •P=IV, hence power is greater in circuit I 14 Feb 2002 Physics 102 Lecture 2 14 AC Circuits I I I Outlets supply 120V 60 Hz “AC” (alternating current) which is generated by a local power plant. There are three wires a)a ground [green], b)a neutral [white], and c) a HOT wire [black]. Why do we get power from an alternating current? 14 Feb 2002 Physics 102 Lecture 2 15 RC Circuits I Circuits with both capacitors and resistors have time variable currents q = q0 (1 − e − t / RC ) V = V0 (1 − e − t / RC ) I = I0 e − t / RC 14 Feb 2002 Physics 102 Lecture 2 16 RC Puzzler This is called a “relaxation oscillator.” Why does the light blink? 14 Feb 2002 Physics 102 Lecture 2 17