Chapter 2 Circular (trigonometric) functions 69 remember remember 1 1 1 1. cosec x = ----------sec x = -----------cot x = -----------sin x cos x tan x 2. Symmetry properties of trigonometric functions and their inverses (a) First quadrant: π π sin --- − θ = cos θ ⇔ cosec --- − θ = sec θ 2 2 π π cos --- − θ = sin θ ⇔ sec --- − θ = cosec θ 2 2 (b) Second quadrant: sin(π − θ) = sin θ ⇔ cosec(π − θ) = cosec θ cos(π − θ) = −cos θ ⇔ sec(π − θ) = −sec θ tan(π − θ) = −tan θ ⇔ cot(π − θ) = −cot θ π π sin --- + θ = cos θ ⇔ cosec --- + θ = sec θ 2 2 π π cos --- + θ = −sin θ ⇔ sec --- + θ = −cosec θ 2 2 (c) Third quadrant: sin(π + θ) = −sin θ ⇔ cosec(π + θ) = −cosec θ cos(π + θ) = −cos θ ⇔ sec(π + θ) = −sec θ tan(π + θ) = tan θ ⇔ cot(π + θ) = cot θ 3π 3π sin ------ − θ = −cos θ ⇔ cosec ------ − θ = −sec θ 2 2 3π π cos ------ − θ = −sin θ ⇔ sec --- − θ = −cosec θ 2 2 (d) Fourth quadrant: sin(−θ) = −sin θ ⇔ cosec(−θ) = −cosec θ cos(−θ) = cos θ ⇔ sec(−θ) = sec θ tan(−θ) = −tan θ ⇔ cot(−θ) = −cot θ 3π 3π sin ------ + θ = −cos θ ⇔ cosec ------ + θ = −sec θ 2 2 3π 3π cos ------ + θ = sin θ ⇔ sec ------ + θ = cosec θ 2 2 ( ( ) ) ( ( ) ) ( ( ) ) ( ( ) ) 2A WORKED ORKED Example xample 1 ( ) ( ) ( ( ) ) ( ( ) ) ( ( ) ) Reciprocal trigonometric functions 1 Copy and complete the following table using the right-angled triangles at the top of page 70. Give exact values for: i sin x ii cos x iii tan x iv cosec x v sec x vi cot x. sin x a b c d e f cos x tan x cosec x sec x cot x 83 Chapter 2 Circular (trigonometric) functions Compound and double angle formulas Compound angle formulas Consider the right-angled triangles shown in the figure at right. Let AD = 1, ∠BAC = x and ∠DAC = y. Then AC = cos y CD = sin y 1 ∠DCE = x (since ∠BCA = 90° − x and ∠ECB = 180°) ⇒ DE = sin x sin y ⇒ CE = cos x sin y y ⇒ BC = sin x cos y x ⇒ AB = cos x cos y A D E C F B BE = sin(x + y) (as BE = FD) = BC + CE E D = sin x cos y + sin y cos x ∴ sin(x + y) = sin x cos y + cos x sin y C and AF = cos(x + y) = AB − BF 1 = AB − DE (since DE = BF) sin (x + y) = cos x cos y − sin x sin y ∴ cos(x + y) = cos x cos y − sin x sin y. y Using a similar approach, or by replacing y x with −y, the following identities can also be A F B derived: cos (x + y) 1. sin(x − y) = sin x cos(−y) + cos x sin(−y) = sin x cos y − cos x sin y (since cos(−y) = cos y and sin(−y) = −sin y) 2. cos(x − y) = cos x cos(−y) − sin x sin(−y) = cos x cos y + sin x sin y. Furthermore: sin ( x + y ) tan(x + y) = ------------------------cos ( x + y ) Now sin x cos y + cos x sin y = ----------------------------------------------------------cos x cos y – sin x sin y Dividing the numerator and denominator by cos x cos y, this simplifies to: tan x + tan y tan(x + y) = ---------------------------------1 – tan x tan y Similarly: tan x – tan y tan(x − y) = ----------------------------------1 + tan x tan y Note: These identities can also be derived using a unit circle approach. In summary, the compound angle formulas are: sin(A + B) = sin A cos B + cos A sin B cos(A + B) = cos A cos B − sin A sin B tan A + tan B tan(A + B) = --------------------------------------1 – tan A tan B sin(A − B) = sin A cos B − cos A sin B cos(A − B) = cos A cos B + sin A sin B tan A – tan B tan(A − B) = ---------------------------------------1 + tan A tan B 90 Maths Quest 12 Specialist Mathematics π π 10 If cos x = −0.4, x ∈ ---, π and cosec y = 1.25, y ∈ 0, --- , find the value of each of 2 2 the following, correct to 2 decimal places. a sin x b tan(x + y) c cos y d cos(x − y) 11 Simplify each of the following expressions using the double angle formulae. x 2 tan --a sin2x − cos2x b sin x cos x 2 c -----------------------x 2 1 – tan --2 cos 2x sin 2 x – sin 4 x e ------------------------------d ------------------------------f (sin x − cos x)2 sin 2x sin 4 x – cos 4 x π 12 If cos x = −0.6 and x ∈ ---, π , find the values of: 2 16 a cos 2x b sin 2x WORKED ORKED Example xample π 13 If tan x = 2 and x ∈ 0, --- , find the exact values of: 2 a tan 2x b sin 2x 14 If sin A = a sin 2A 1 ------5 c tan 2x. c cos 2x. π and x ∈ 0, --- , find the exact values of: 2 b cos 2A c sin 3A A d sin2 --- . 2 π 15 If cos B = 0.7 and x ∈ 0, --- , then find each of the following, correct to 2 decimal 2 places: B B B B a cos --b sin --c tan --d cot --- . 2 2 2 2 Work ET SHE 2.1 16 Use the double angle formulas to find the exact values of: π π a sin --b cos --c 8 8 More identities Prove the following identities. 1 cot x sec x = cosec x 2 (1 + cot2x)(1 – cos2x) = 1 1 3 (1 + sin x)(1 – sin x) = -----------sec2 x 4 cosec2x + sec2x = cosec2x sec2x π tan --- . 8 Chapter 2 Circular (trigonometric) functions WORKED ORKED Example xample 19 97 4 Simplify each of the following. a sin(sin−1 0.5) b cos(sin−1 0.5) c tan sin−1 ------2- π e sin−1 ⎛ cos--- ⎞ ⎝ 6⎠ π f cos−1 tan ⎛– --- ⎞ ⎝ 4⎠ 5π g tan−1 ⎛ 2 cos------ ⎞ ⎝ 6⎠ 2π h sin−1 ⎛ cos------ ⎞ ⎝ 3⎠ 5π i cos−1 ⎛ sin ------ ⎞ ⎝ 4 ⎠ 7π j sin−1 ⎛ tan ------ ⎞ ⎝ 4 ⎠ k tan−1[cos (−π)] 11 π l cos−1 ⎛ cos --------- ⎞ ⎝ 6 ⎠ ( 2 ) d cos(tan−1 3 ) 5 multiple ultiple choice π Consider the function y = sin−1(x + 1) + --- . 3 a The implied domain of this function is: A [−2, 0] B [−1, 1] C (−1, 1) D [0, 2] E (0, 2) b The range of this function is: A π π – ---, --2 2 B 5π π – ------, --6 6 5π π C ⎛– ------, --- ⎞ ⎝ 6 6⎠ D π 5π – ---, -----6 6 E R 6 multiple ultiple choice Consider the function with the rule f (x) = cos−1 (sin 2x). a The implied domain of f (x) is: A [−π, π ] B π π – ---, --4 4 π π – ---, --2 2 C D R E [0, π ] D [0, π] E [−1, 1] b The range of f (x) is: A [−2, 2] WORKED ORKED Example xample 20 B R [ C − 1--- , 2 1 --2 ] 7 State the i implied domain and ii range of each of the following. a y = sin−1(1 − x) b y = cos−1(x + 1) c y = tan−1(2x) d y = sin−1(x2) e y = cos−1(2x + 3) f y = tan−1(4 − x) g y = cos−1(x2 − 1) h y = sin−1(cos x) i y = tan(2 sin−1x) k y = cos(2 sin−1x) l y = cos−1( 3 tan x) j y = tan−1(sin x) 8 Sketch the graph of the following functions and state the i implied domain and ii range of each. 21 π b y = 2 sin−1x + --a y = tan−1(x + 1) 2 WORKED ORKED Math y = cos−1(x − 1) π e f (x) = 3 tan−1x + --4 g f (x) = 1 --3 π sin−12x + --3 d y = sin−1(2 − x) f f (x) = 2 cos−1 x + ( 1 --2 ) π h f (x) = cos−1(x + 2) − --2 Graphs of inverse trig. functions ET SHE Work c cad Example xample 2.2