ADVANCED ELECTRICAL CIRCUIT BETI 1333 SECOND ORDER SOURCE-FREE SERIES RLC CIRCUIT Halyani binti Mohd Yassim halyani@utem.edu.my LESSON OUTCOME At the end of this chapter, students are able: to describe second order source-free series RLC circuit 2 SUBTOPICS Introduction of Second Order Circuit Source-free Series RLC Circuit 3 INTRODUCTION π2 π£ ππ‘ 2 ππ π2 π ππ‘ 2 1. Using second order differential equation 2. contains two storage elements Second Order Circuit 4 INTRODUCTION Sourcefree • Series • Parallel Step response • Series • Parallel Second Order Circuit 5 SOURCE-FREE SERIES RLC CIRCUIT 1. No external sources of excitation What? 2. Contains several resistors, a capacitor and an inductor 3. Output response: Transient/natural response 6 SOURCE-FREE SERIES RLC CIRCUIT Source-free Series RLC Circuit Assumption: π(0) = πΌ0 Initial current through inductor and π£ 0 = 1 0 π(π‘) πΆ −∞ ππ‘ = π0 Initial voltage across capacitor By Applying Kirchhoff‘s Voltage Law: ππ + ππΏ + ππΆ = 0 ππ 1 0 π π + πΏ + π(π‘) ππ‘ = 0 ππ‘ πΆ −∞ Figure 1 Second order differential equation: π 2 π π ππ 1 + + π=0 2 ππ‘ πΏ ππ‘ πΏπΆ 7 SOURCE-FREE SERIES RLC CIRCUIT Types of natural response of source-free series RLC circuit: 1. Overdamped response (πΌ > π0 ) π π‘ = π΄1 π π 1 π‘ + π΄2 π π 2 π‘ π 1 π + π + =0 πΏ πΏπΆ 2 π 1,2 π =− ± 2πΏ π 2πΏ 2 − 1 πΏπΆ Roots of the characteristic equation π πΌ= , 2πΏ Damping factor π0 = 1 πΏπΆ Undamped natural frequency 2. Critically damped response (πΌ = π0 ) π π‘ = (π΄2 + π΄1 π‘)π −πΌπ‘ 3. Underdamped response (πΌ < π0 ) π π‘ = π −πΌπ‘ (π΅1 πππ ππ π‘ + π΅2 π ππ ππ π‘) Note: π΄1 and π΄2 can be determined from the initial ππ(0) conditions namely π 0 and ππ‘ . ππ(0) 1 = − (π πΌ0 + π0 ) ππ‘ πΏ 8 EXAMPLE 1 The switch in Figure 2 moves from position A to B at t = 0. Find i(t) for t > 0. Figure 2 9 SOLUTION 1 Step 1: Find initial voltage across capacitor, V0 and initial current through inductor, I0 when t < 0. Tips 1: When t < 0, capacitor acts like an open circuit and inductor acts like a short circuit. Tips 2: There is no current flow through inductor due to open circuit. Figure 3 π 0 = 0π΄ π£ 0 = ππ = 5π΄ ∗ 5Ω = 25π 10 SOLUTION 1 Step 2: Determine type of natural response of this circuit when t > 0. Figure 4 πΌ= π 2 = = 10, 2πΏ 2 ∗ 0.1 π0 = 1 πΏπΆ = 1 0.1 ∗ 0.2 = 7.071 πΌ > π0 → overdamped response Current response for overdamped case: π π‘ = π΄1 π π 1 π‘ + π΄2 π π 2 π‘ 11 SOLUTION 1 Step 3: Find roots of characteristic equation for this circuit. Figure 5 π 1,2 π 1,2 π 1,2 π =− ± 2πΏ π 2πΏ 2 − 1 πΏπΆ 2 2 =− ± 2 ∗ 0.1 2 ∗ 0.1 = −0.36, −19.64 2 1 − 0.1 ∗ 0.2 12 SOLUTION 1 Step 4: Determine π΄1 and π΄2 from initial conditions π 0 and ππ(0) , ππ‘ when t > 0. π 0 = π΄1 π −0.36(0) + π΄2 π −19.64(0) = 0π΄ π΄1 + π΄2 = 0 → π΄1 = −π΄2 ππ(0) 1 1 π΄ = − π πΌ0 + π0 = − 2 0 + 25 = −250 ππ‘ πΏ 0.1 π ππ = −0.36 ∗ π΄1 π −0.36π‘ − 19.64 ∗ π΄2 π −19.64π‘ ππ‘ ππ(0) = −0.36 ∗ π΄1 π −0.36 0 − 19.64 ∗ π΄2 π −19.64 0 = −250 ππ‘ 0.36 ∗ π΄2 − 19.64 ∗ π΄2 = −250 → π΄2 = 13 → π΄1 = −13 Current response: π π‘ = −13π −0.36π‘ + 13π −19.64 π΄ 13 EXAMPLE 2 Calculate i(t) for t > 0 in the circuit of Figure 6. Figure 6 14 SOLUTION 2 Step 1: Find initial voltage across capacitor, V0 and initial current through inductor, I0 when t < 0. Tips 1: When t < 0, capacitor acts like an open circuit and inductor acts like a short circuit. Tips 2: Current flows through inductor, which is less resistance than capacitor. Figure 7 π0 = 20π π 20π πΌ0 = = = 20π΄ π 1Ω 15 SOLUTION 2 Step 2: Determine type of natural response of this circuit when t > 0. Figure 8 πΌ= π 1 = = 2, 2πΏ 2 ∗ 0.25 π0 = 1 πΏπΆ = 1 0.25 ∗ 1 =2 πΌ = π0 → critically damped response Current response for critically damped case: π π‘ = (π΄2 + π΄1 π‘)π −πΌπ‘ 16 SOLUTION 2 Step 3: Determine π΄1 and π΄2 from initial conditions π 0 and ππ(0) , ππ‘ when t > 0. π 0 = (π΄2 + π΄1 (0))π −2 0 = 20π΄, → π΄2 = 2 ππ(0) 1 1 π΄ = − π πΌ0 + π0 = − 1 20 + 20 = −160 ππ‘ πΏ 0.25 π ππ = −2(π΄2 + π΄1 π‘)π −2π‘ + π΄1 π −2π‘ ππ‘ ππ(0) = −2(2 + π΄1 (0))π −2(0) + π΄1 π −2(0) = −160 ππ‘ −4 + π΄1 = −160 → π΄1 = −156 Current response: π π‘ = (2 − 156π‘)π −2π‘ π΄ 17 SELF REVIEW QUESTIONS 1. A source-free RL circuit is an example of second order circuit. TRUE FALSE 2. Name two storage elements in a second order source-free RLC circuit. Answer: _____________ 3. Given R = 10Ω and C = 0.5F. Determine the value of L so that the natural response of source-free series RLC circuit is critically damped response. a) 1.25H b) 12.5H c) 125H d) 0.125H 4. Following is TRUE about a second order circuit except a) consists of a resistor and two capacitors in a circuit b) is described using second order differential equation c) consists of one storage elements d) has three types of natural response 5. Given L = 2H and C = 4F. Interpret the value of R when πΌ > π0 . a) R > 2 b) R < 0.5 c) R > 0.2 d) R < 5 18 ANSWERS 1. 2. 3. 4. 5. FALSE Inductor and capacitor b c a 19