Course roadmap ME451: Control Systems Modeling Analysis Laplace transform Lecture 14 Time response of 1st-order systems Transfer function Models for systems • electrical • mechanical • electromechanical Block diagrams Linearization Dr. Jongeun Choi Department of Mechanical Engineering Michigan State University Time response • Transient • Steady state Frequency response • Bode plot Stability • RouthRouth-Hurwitz • Nyquist Design Design specs Root locus Frequency domain PID & LeadLead-lag Design examples (Matlab simulations &) laboratories 1 Performance measures (review) Transient response 2 First-order system A standard form of the first-order system: (Today’ (Today’s lecture) Peak value Peak time Percent overshoot Delay time Rise time Next, we will connect these measures with ss-domain. DC motor example Settling time Steady state response Steady state error (Done) 3 4 DC motor example (cont’d) Step response for 1st-order system If La<<Ra, we can obtain a 1st-order system Input a unit step function to a first-order system. Then, what is the output? u(t) u(t) y(t) y(t) 1 0 0 TF from motor input voltage to motor speed is 1st1st-oder motor position is 2nd2nd-order (Partial fraction expansion) 5 How to eliminate steady-state error Make a feedback system with a controller having an integrator (copy of Laplace transform of a unit step function): Meaning of K and T K : Gain Final (steady(steady-state) value K=1,T=1 1 0.8 Controller T : Time constant 1 Time when response 0 rises 63% of final value Indication of speed of response (convergence) Response is faster as T becomes smaller. One has to select controller parameters to stabilize the feedback system. Suppose K=T=1, and obtain such parameters! 7 Amplitude u(t) u(t) 6 0.6 0.4 0.2 0 0 1 2 3 Time 4 5 6 8 DC gain for a general system Settling time of 1st-order systems DC gain : Final value of a unit step response For firstfirst-order systems, DC gain is K. Relation between time and exponential decay For a general stable system G, G, DC gain is G(0). Final value theorem Examples 5% settling time is about 3T! 2% settling time is about 4T! 9 Step response for some K & T K=1,T=1 Amplitude Amplitude 5 Time K=2,T=1 5 Time K=2,T=2 10 5 Time 10 Obtain step response 2 Amplitude Amplitude Unknown 1 0 0 10 2 1 0 0 Suppose that we have a “black-box” system 2 1 0 0 System identification K=1,T=2 2 10 5 Time 10 1 0 0 Can you obtain a transfer function? How? 11 12 Ramp response for 1st-order system Ramp response for 1st-order system K =1 ,T =1 Input a unit ramp function to a 1st-order system. Then, what is the output? y(t) y(t) 0 0 K=1,T=1 4 Amplitude Amplitude u(t)=t u(t)=t 5 y(t) y(t) u(t)=t u(t)=t 3 slope 2 1 0 0 1 2 T im e Time 3 4 5 Steady state response We may want to modify the system s.t. (Partial fraction expansion) 13 How to eliminate steady-state error Make a feedback system with a controller having a double integrator (copy of Laplace transform of ramp function): u(t)=t u(t)=t 14 Summary and exercises Time response for 1st-order systems Step and ramp responses Time constant and DC gain System identification Controller Next, time response for 2nd-order systems Exercises 0 Review examples in this lecture. One has to select controller parameters to stabilize the feedback system. Suppose K=T=1, and obtain such parameters! 15 16