Basic Amplifier Stages II • CS - Example • Common Gate Amplifier

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Basic Amplifier Stages II
• CS - Example
• Common Gate Amplifier
• Cascode Amplifier
• Transistor Frequency Response
Reading instructions: 185-187, 194-196, 205, 207-210, 214,
217-229,490-495
Modern Electronics: F7 Basic Amplifiers II
1
Basic Amplifier Stages II
Gate biasing
R
100kW
V(t)
VDD
R1
3MW
C1
0.01mF
R2
1MW
Parameters:
k’=0.0015 A/V2
W/L=100
VT=0.5V
VDD=5V
VDD
RD
47W
l=0.1
C2
1mF
RL
50W
vOUT
1) Calculate
bias points
2) What fraction
of the current
is ”used”?
3) Calculate
medium
frequency
voltage gain
Modern Electronics: F7 Basic Amplifiers II
2
Common Gate Amplifier
VDD
An common gate stage has
• Low input resistance (transconductance)
• High Output resistance (saturation)
• Application: ”Current Buffer” io=ii
RD
vIN
vOUT
𝐺𝑀 = π‘”π‘š
𝑅𝑖 =
Source
vsg
1/gm
Drain
1
π‘”π‘š
𝑅0 = 𝑅𝐷
gmvsg
RD
vo
Gate
Modern Electronics: F7 Basic Amplifiers II
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Common Gate Amplifier
VDD
An common gate stage has
• Low input resistance (transconductance)
• High Output resistance (saturation)
• Application: ”Current Buffer” io=ii
• Addition of ro makes the amplifier
”bilateral”
RD
RS
vIN
RL
vOUT
𝐺𝑀 = π‘”π‘š
RS
vi
Source
1/gm
ro
π‘Ÿ0 + 𝑅𝐷 𝑅𝐿
𝑅𝑖 =
1 + π‘”π‘š π‘Ÿπ‘œ
Drain
gmvin
RD
RL vo
𝑅0 = 𝑅𝐷
Gate
Modern Electronics: F7 Basic Amplifiers II
π‘Ÿ0 + 𝑅𝑆 1 + π‘”π‘š π‘Ÿ0
𝑅0 ≈ 𝑅𝐷
π‘”π‘š π‘Ÿ0 𝑅𝑠
4
Common Drain Amplifier – Source Follower
𝐺𝑀 ≈ π‘”π‘š
VDD
𝑅𝑖 = ∞
𝑅0 =
vIN
RL
vOUT
𝐴𝑉 = π‘”π‘š
1
1
1
π‘”π‘š + π‘Ÿ + 𝑅
0
𝐿
1
1
1
π‘”π‘š + π‘Ÿ + 𝑅
0
𝐿
<1
• Vout≈Vin-(VT+Vov)
vgs
• Level Shifter
vi
gmvgs
ro
RL
vo
• Voltage Buffer
•
Output stage – low output
resistance
Modern Electronics: F7 Basic Amplifiers II
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2 minute exercise I
VDD
gm2, r02
Ix
vx
A diode connected FET can
operate as a small signal resistor
1) Draw the small signal model
of the circuit.
2) Calculate the equivalent
resistance. R=Vx/Ix
Modern Electronics: F7 Basic Amplifiers II
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2 minute exercise II
VDD
gm2
• How do you use this to build a
CS-amplifier using only
transistors?
• What is the corresponding
voltage gain?
Modern Electronics: F7 Basic Amplifiers II
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Cascode
VDD
gm2vgs2
=-gm2vds1
RD
M2
vo
RD
M1
vOUT
vIN
vi
gm1vi
ro1
𝐺𝑀 ≈ π‘”π‘š1
• Two stage amplifier
𝑅𝑖 = ∞
• Increases output resistance
• Good high frequency
properties
ro2
𝑅0 = π‘Ÿ01 + π‘Ÿ02 + π‘”π‘š2 π‘Ÿ01 π‘Ÿ02 ≈ π‘”π‘š2 π‘Ÿ01 π‘Ÿ02
Modern Electronics: F7 Basic Amplifiers II
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Differential Amplifier
VDD
VDD
RD
π΄π‘‘π‘š
π‘£π‘œπ‘‘
=
≈ −π‘”π‘š 𝑅𝐷
𝑣𝑖𝑑
RD
vod
-Vid/2
Vid/2
• Two input signals –
opposite phase
• Output signal –
differential
ITAIL
• Rejects commonmode signals (eg.
supply noise)
• Amplifies differential
signals
Modern Electronics: F7 Basic Amplifiers II
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2 minute problem – differential / single ended
VDD
RD
VDD
RD
RD
Vout
vod
Vid/2
-Vid/2
Vd
If VDD varies with DV – (l=0, transistors in saturation)
• How much does vod change?
• How much does Vout change?
Modern Electronics: F7 Basic Amplifiers II
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High Frequency Transistors
• Rd and Rs are usually small
• Cgd<<Cgs
RG
+
vin
-
Cgd
+
v1
gmv1
- Cgs
+
r0
vout
-
• The Cgd feedback
capacitance complicates the
analysis
• We will use the Miller
approximation
Modern Electronics: F7 Basic Amplifiers II
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Maximum current gain frequency: fT
Cgd
RG
+
vin
-
iin
+
v1
gmv1
- Cgs
π‘”π‘š − π‘—πœ”πΆπ‘”π‘‘
π‘–π‘œπ‘’π‘‘
= β„Ž21 =
≈
𝑖𝑖𝑛
π‘—πœ”(𝐢𝑔𝑠 + 𝐢𝑔𝑑 )
π‘”π‘š
≈
π‘–πœ” 𝐢𝑔𝑠 + 𝐢𝑔𝑑
Unit current gain |h21|=1
when w=2p*fT
𝑓𝑇 ≈
π‘”π‘š
2πœ‹ 𝐢𝑔𝑠 + 𝐢𝑔𝑑
r0
Maximum current gain (iout/iin) when
output is shorted to ground
160
140
Current Gain (dB)
iin
120
100
80
60
fT
40
20
0
10
5
10
10
Frequency (Hz)
Modern Electronics: F7 Basic Amplifiers II
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Current Best High Frequency Transistors
• fT ~ 500-800 GHz
• MSG/U: These are power gain curves. fmax ~ 1 THz
•
More about this in FFF115 High Speed Devices
Modern Electronics: F7 Basic Amplifiers II
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Miller Approximation
RG
+
vin
-
Cgd
+
v1
gmv1
- Cgs
RG
r0
+
+
vout
vin
-
-
+
gmv1
v1
- Cgs CM
+
vout
r0
-
• A feedback capacitance can be approximated
as a larger capacitance at the input.
• This is useful for simplifying calculations of the
imput impedance / approximate transfer
function
• Not accurate for output impedance!
Modern Electronics: F7 Basic Amplifiers II
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Frequency Dependent Voltage Gain
Cgd
RG
+
vin
-
+
+
v1
gmv1
- Cgs
RL
-
𝐾 = −π‘”π‘š 𝑅𝐿
25
1
20
π‘—πœ”
1−𝑝
1
−1
𝑝1 =
𝑅𝐺 (𝐢𝑔𝑠 + 𝐢𝑔𝑑 (1 + π‘”π‘š 𝑅𝐿 ))
• High gm
• Small Cgs, Cgd!
• Depends on RL
Voltage Gain (dB)
𝐴𝑣 πœ” ≈ 𝐾
vout
15
w-3dB=|p1|
10
5
0
5
10
10
10
Frequency (Hz)
Modern Electronics: F7 Basic Amplifiers II
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670 GHz Common Source Amplifier
CS Amplifiers
Input
Output
5x Common Source
Stages
Modern Electronics: F7 Basic Amplifiers II
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