5. Fundamental amplifier forms & Elementary R configurations Reading: Sedra & Smith Sec. 5.6 (S&S 5th Ed: Sec. 4.7) ECE 102, Fall 2011, F. Najmabadi Fundamental MOS Amplifier Forms We are considering only signal circuit here! Voltage Amplifier Model Input Resistance: Voltage gain: Open-loop gain: Output resistance: Ri = vi/ii Av = vo/vi with load Avo = vo/vi with no load Ro (resistance seen between output terminals with vi= 0 ) vi Ri = vsig Ri + Rsig vo RL = Av = Avo ⋅ vin RL + Ro vo Ri RL = ⋅ Avo ⋅ vsig Ri + Rsig RL + Ro Possible MOS amplifier configurations Common-Source Common-Gate Common-Source with Rs Same as Common Gate (vi does not change) Common-Drain Not Useful PMOS configurations are the same as NMOS Common-Source Common-Gate Common-Drain Since PMOS has the same signal model, configurations and results are exactly the same Textbook includes RD in the fundamental configurations Small Signal Circuit for a Common Source Amplifier Textbook: Textbook is inconsistent. It includes RD for common source and common gate but does not include RS in common drain. Lecture: Note RD is parallel to RL. To avoid confusion, I am using only one resistor, R’L. Common Source Configuration (Gain) Signal Circuit: vo = − g m v gs (ro || RL′ ) Av = vo = − g m (ro || RL′ ) vin Avo = − g m ro Small Signal Circuit with MOS SSM Relevant circuit for Gain calculation By KCL Common Source Configuration (Ri) Small Signal Circuit with MOS SSM Relevant circuit for Ri calculation ii = 0 Ri = vi =∞ ii Common Source Configuration (Ro) Small Signal Circuit with MOS SSM Relevant circuit for Ro calculation (set vi = 0) Current source becomes open circuit Ro = ro Common Source with Source Resistor Small Signal Circuit: Small Signal Circuit with MOS SSM Input Resistance ii = 0 ⇒ Ri = vi =∞ ii Common Source with Source Resistor (Gain*) Relevant circuit for Gain calculation Node voltage method: v gs = vi − vS Node vS vS vS − vo + − g m (vi − vS ) = 0 RS ro Node vo vo vo − vS + + g m (vi − vS ) = 0 RL′ ro * Text book ignore ro vo g m ro RL′ =− vi ro + (1 + g m ro ) R S + RL′ g m RL′ Av ≈ − 1 + g m R S + RL′ / ro Av = Avo = − g m ro Common Source with Source Resistor (Ro*) set vi = 0 Attach vx and compute ix Ro = vx /ix Node voltage method: v gs = −vS Node vS vS vS − v x + − g m ( −vS ) = 0 RS ro vS vx = RS ro + (1 + g m ro ) RS ix = vS vx = RS ro + (1 + g m ro ) RS * Text book ignore ro i 1 1 ≡ x = Ro v x ro + (1 + g m ro ) RS Ro = ro + (1 + g m ro ) RS Common Gate Configuration Small Signal Circuit: Small Signal Circuit with MOS SSM Common Gate Configuration (Gain*) Node voltage method: v gs = −vi Node vo vo vo − vi + + g m (−vi ) = 0 ′ RL ro vo 1 + g m ro vi = ro || RL′ ro vo 1 + g m ro = (ro || RL′ ) vi ro Av ≈ g m (ro || RL′ ) Av = Avo ≈ g m ro Common Gate Configuration (Ri and Ro*) Input Resistance KVL: vi = (ii +g m v gs )ro + ii RL′ vi (1 + g m ro ) = ii (ro + RL′ ) vi ro + RL′ Ri = = ii 1 + g m ro 1 R′ + L Ri ≈ g m g m ro Output Resistance (set vi = 0) Current source becomes open circuit Ro = ro * Text book ignore ro Common Drain Configuration (Source Follower) Gain Node voltage method: v gs = vi − vo Node vo vo vo + − g m (vi − vo ) = 0 RL′ ro g m vi = vo + g m vo ′ ro || RL g m (ro || RL′ ) Av = 1 + g m (ro || RL′ ) Avo = g m ro ≈1 1 + g m ro Common Drain Configuration (Source Follower) Input Resistance ii = 0 Ri = vi =∞ ii Output Resistance (set vi = 0) ix = vx v v − g m v gs = x + x ro ro 1 / g m Ro = 1 1 || ro ≈ gm gm MOS Amplifier Fundamental Configurations (PMOS circuits are identical) Common Source Common Gate Av = − g m (ro || RL′ ) Av = g m (ro || RL′ ) Common Source with RS Common Drain/Source Follower g m RL′ Av = − 1 + g m R S + RL′ / ro Av = g m (ro || RL′ ) 1 + g m (ro || RL′ ) Elementary R Configurations Transistor can be configured to act as a resistor for small signals! Ex: Output resistance of a CS Amplifier ro Set vi = 0, current source becomes open circuit Ro = ro Notation: ro is the small-signal resistance between the point and ground If we connect any two terminals of a MOS, we get a two-terminal device. o For Small Signals, this two terminal device can be replaced with its Thevenin equivalent circuit. o As there is NO independent sources present, the Thevenin equivalent circuit is reduced to a resistor. Transistor can be configured to act as a resistor for small signals! But, MOS should be in saturation for small signal model to work! o Connection between MOS terminals are, therefore, made through ground for small signals. o In fact, one or both MOS terminals have to be connected to bias power supplies to ensure that MOS is in saturation Real Circuit Small Signal Circuit A) B) No Small Signal circuit MOS is NOT in saturation Elementary Configurations for MOS resistance (PMOS circuits are identical) ro (1 +g m R ) + R ∞ ≈ ro (1 +g m R ) ro +R 1 R ≈ + 1 + g m ro g m g m ro Output resistance of CS Amp with Rs ro Input resistance of CG Amp 1 1 || ro ≈ gm gm Input resistance of CS Amp Diode-connected Transistor Always in saturation! Above configurations are for Small Signal. Typically one or both grounds are connected to bias voltage sources to ensure that MOS is in saturation! Gain, input, and output resistances of MOS amplifiers can be found using the fundamental amplifiers and elementary R configurations