ST 516 Experimental Statistics for Engineers II The One-Quarter Fraction Need two generating relations. E.g. a 26−2 design, with generating relations I = ABCE and I = BCDF . Product of these is ADEF . Complete defining relation is I = ABCE = BCDF = ADEF . 1 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II This is a resolution-IV design. Why? There is no resolution-V 26−2 design. Why not? To set up runs, either: create the full 26 design with ABCE and BCDF confounded with blocks, and choose the block with both positive; or set up a basic design in 4 factors, then add the other 2. For example, basic design is 24 in A, B, C , D, and defining relations show that E = ABC and F = BCD. 2 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Basic Design 3 / 15 Run A 1 2 3 4 5 6 7 8 9 10 11 12 .. . + + + + + + .. . 16 B C D E = ABC - - - - + + - + + - - + + - + + + + + + - - + - - + + + - + + + - + .. .. .. .. . . . . + Two-level + Fractional + +Factorial Designs + F = BCD + + + + + + .. . + The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Projections This 26−2 IV design projects into: a single complete replicate of a 24 design in A, B, C , and D, and any other of the 12 subsets of 4 factors that is not a word in the defining relation; a replicated one-half fraction of a 24 design in A, B, C , and E , and in the other two subsets of 4 factors that are a word in the defining relation; two replicates of a 23 design in any three factors; four replicates of a 22 design in any two factors. 4 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Example with this design Response is shrinkage in injection molding, and factors are: A, mold temperature; B, screw speed; C , holding time; D, cycle time; E , gate size; F , hold pressure. 5 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Data file injection.txt: A + + + + + + + + B + + + + + + + + C + + + + + + + + D + + + + + + + + 6 / 15 E + + + + + + + + F + + + + + + + + Shrinkage 6 10 32 60 4 15 26 60 8 12 34 60 16 5 37 52 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II R commands injection <- read.table("data/injection.txt", header = TRUE) for (j in 1:(ncol(injection) - 1)) injection[ , j] <- coded(injection[ , j]) summary(lm(Shrinkage ~ A * B * C * D * E * F, injection)) Output Call: lm(formula = Shrinkage ~ A * B * C * D * E * F, data = injection) Residuals: ALL 16 residuals are 0: no residual degrees of freedom! Coefficients: (48 not defined because of singularities) Estimate Std. Error t value Pr(>|t|) (Intercept) 27.3125 NA NA NA A 6.9375 NA NA NA B 17.8125 NA NA NA C -0.4375 NA NA NA D 0.6875 NA NA NA 7 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Output, continued E F A:B A:C B:C A:D B:D C:D D:E A:B:D A:C:D 0.1875 0.1875 5.9375 -0.8125 -0.9375 -2.6875 -0.0625 -0.0625 0.3125 0.0625 -2.4375 NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA Residual standard error: NaN on 0 degrees of freedom Multiple R-Squared: 1, Adjusted R-squared: F-statistic: NaN on 15 and 0 DF, p-value: NA NaN Note that all 2-factor interactions are aliased with one or two other 2-factor interactions, and all but two 3-factor interactions are aliased with main effects or other 3-factor interactions. 8 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Main effect alias chains A = BCE = DEF = ABCDF B = ACE = CDF = ABDEF C = ABE = BDF = ACDEF D = BCF = AEF = ABCDE E = ABC = ADF = BCDEF F = BCD = ADE = ABCEF 9 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Other alias chains AB AC AD AE AF BD BF ABD ACD 10 / 15 = CE = ACDF = BDEF = BE = ABDF = CDEF = EF = BCDE = ABCF = BC = DF = ABCDEF = DE = ABCD = BCEF = CF = ACDE = ABEF = CD = ACEF = ABDE = CDE = ACF = BEF = BDE = ABF = CEF Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II 70 ● 40 30 Effects 50 60 B ● A ● 0 10 20 A:B ● ● 0.0 ● ● ● ● ● ● 0.5 ● ● ● ● 1.0 1.5 Half Normal plot 11 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II The half-normal plot suggests that A and B are the important effects. Interaction plot with(injection, interaction.plot(A, B, Shrinkage)) Residual plots suggest that C is a dispersion effect. Analyze absolute residuals r <- residuals(aov(Shrinkage ~ A * B, injection)) summary(aov(abs(r) ~ A * B * C * D * E * F, injection)) 12 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Output A B C D E F A:B A:C B:C A:D B:D C:D D:E A:B:D A:C:D 13 / 15 Df Sum Sq Mean Sq 1 1.00 1.00 1 0.25 0.25 1 56.25 56.25 1 3.06 3.06 1 1.00 1.00 1 1.00 1.00 1 0.25 0.25 1 2.25 2.25 1 1.00 1.00 1 1.56 1.56 1 0.06 0.06 1 2.25 2.25 1 9.00 9.00 1 0.56 0.56 1 0.25 0.25 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II Montgomery suggests calculating, for each effect, F ∗ = log sum of squares of residuals at high level sum of squares of residuals at low level In R, not easy to calculate F ∗ , but we can look at the half-normal plot for abs(r ) or r 2 : qqnorm(aov(abs(r) ~ A * B * C * D * E * F, injection), label = TRUE) qqnorm(aov(r^2 ~ A * B * C * D * E * F, injection), label = TRUE) The effects shown in the second of these, for r^2, are essentially sum of squares of residuals at high level − sum of squares of residuals at low level 14 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction ST 516 Experimental Statistics for Engineers II In p the spirit of R’s “Scale-Location” residual plot, we could use |residual|: qqnorm(aov(sqrt(abs(r)) ~ A * B * C * D * E * F, injection)) p All three half-normal plots (r 2 , |r |, and |r |) give the same indication as F ∗ : C appears to be a dispersion factor. 15 / 15 Two-level Fractional Factorial Designs The One-Quarter Fraction