T R I T A - MAT - 1981 - 9 , Mathematics A P P L I C A T I O N S OF V A R I A T I O N A L I N E Q U A L I T I E S TO A MOVING BOUNDARY PROBLEM FOR HELE SHAW FLOWS by Bjbrn Gustafsson T A B L E OF CONTENTS I. INTRODUCTION a. General introduction b. A s u r v e y o f t h e c. II. Some f u r t h e r contents bibliographical FORMULATIONS OF T H E MOVING BOUNDARY a . N o t a t i o n s and b. A c l a s s i c a l c. CONDITION preliminaries formulation (A) A semi-weak f o r m u l a t i o n (B) d . T h e weak f o r m u l a t i o n (C) e . Two l i n e a r c o m p l e m e n t a r i t y III. notes f. Two v a r i a t i o n a l g. T h e moment i n e q u a l i t y problems inequalities (D1) and ( E 1 ) and (E2) (F) R E L A T I O N S BETWEEN T H E MOVING BOUNDARY C O N D I T I O N S , AND E X I S T E N C E AND U N I C I T Y RESULTS a. ( A ) =» ( B ) ( T h m 1) b. ( B ) => ( C ) (Thm 2) c. ( C ) => ( D ) ( T h m 3 , Thm 4 ) d. ( D ) .» ( E ) (Thm 5) e. E x i s t e n c e , u n i q u e n e s s and r e g u l a r i t y solutions to (E) of (Thm 6) f. ( D ) •» ( C ) (Lemma 7 , Lemma 8 , Thm 9 ) g. (C) * (F) ( T h m 10) I V . SUMMARIZING R E S U L T S AND A P P L I C A T I O N S a . Main t h e o r e m s b. A d d i t i o n a l c. V. (D2) properties Applications REFERENCES (Lemma 1 1 , Thm 1 2 , Thm 13) (Lemma 1 4 , Thm 15) t o q u a d r a t u r e domains ( T h m 16) -1- I. INTRODUCTION a. General introduction The aim o f the present paper is to prove a global existence and u n i q u e n e s s t h e o r e m f o r a k i n d o f weak s o l u t i o n t o a m o v i n g b o u n d a r y l e m (MBP) a r i s i n g in two-dimensional i n t r o d u c e d by S. R i c h a r d s o n i n T h e o r e m 13 ( p . 6 9 ) . [17] H e l e Shaw f l o w s . prob- T h i s p r o b l e m was . Our main r e s u l t s a r e summarized We a l s o g i v e some a p p l i c a t i o n s to quadrature in domains (p.78f). O u r MBP o c c u r s a s a s p e c i f i c e x a m p l e i n a c l a s s o f MBP:s w h i c h c a n be d e s c r i b e d a s follows: L e t t h e r e t o e a c h r e g i o n D i n some s u i t a b l e c l a s s o f r e g i o n s ]R n be a s s o c i a t e d ( b y some r u l e t o be s p e c i f i e d ) f i n e d , h a r m o n i c and p o s i t i v e in a neighbourhood in 3 D , t a k i n g t h e b o u n d a r y v a l u e z e r o on 3D. main D = D Q t>0 (it to the problem i t such t h a t i s assumed 3D t that D of the de- boundary T h e n , g i v e n an i n i t i a l t o f i n d a f a m i l y o f d o m a i n s t -> D^ moves w i t h t h e v e l o c i t y here a f u n c t i o n g^ g r a d g^ in -(grad do- for 9o )| p t has a c o n t i n u o u s g extension 3D ). t More g e n e r a l l y t h e r o l e o f t h e b o u n d a r y b y some d i s t i n g u i s h e d s u b s e t S o f i t , 3Dj>S t remains 3D a b o v e c a n be so t h a t o n l y S t played moves while fixed. T h i s d e f i n e s t h e c l a s s o f MBP:s w h i c h we h a v e i n m i n d . In order s p e c i f y a s i n g l e p r o b l e m i n i t one has t o s p e c i f y t h r e e t h i n g s : the to class o f r e g i o n s D u n d e r c o n s i d e r a t i o n , t h e r u l e w h i c h a s s o c i a t e s g^ w i t h D a n d the subset S<=3D f o r e a c h D. L e t us a t o n c e n o t i c e t h a t a f a m i l y t -* D kind necessarily vector field We s h a l l i s an i n c r e a s i n g f a m i l y - g r a d g^ t s o l v i n g a MBP o f t h e ( D ^ cz D^. f o r T < t ) since p o i n t s p e r p e n d i c u l a r l y o u t f r o m D^ a t 3 D g i v e t h r e e e x a m p l e s i n t h e c l a s s o f MBP:s j u s t t h e t h i r d o f w h i c h i s t h e one w h i c h s h a l l be t r e a t e d i n t h i s above the t (or S^). described, paper. -2- Ex. 1: D is Let or ]R and l e t , i n t h e c l a s s o f bounded domains c o n t a i n i n g K, g^ be t h a t function 9 K be a f i x e d c o m p a c t s e t i n ]R i n D-^K w h i c h t a k e s t h e b o u n d a r y _ M on K ° " 10 on 3D and l e t whenever harmonic values , S = 3D . T h e MBP s o a r i s i n g o c c u r s cathode, D^K in electrochemistry, i s an e l e c t r o l y t e which gradually dissolves i s an a n o d e , t h e s u r f a c e n under e l e c t r o l y s i s to the r u l e described above. g r a d g^ i s t h e e l e c t r i c and R ^ D Here current in which case K is a so t h a t D grows -g^ is the e l e c t r i c according potential (up to a p o s i t i v e f a c t o r ) . of and See [ 7 ] for details. 2 Ex. 2: L e t L be a s u b s p a c e o f R 3 (or R ) of codimension one, l e t be o n e o f t h e h a l f - s p a c e s in which i t L as b e i n g h o r i z o n t a l H as b e i n g t h e l o w e r h a l f - s p a c e ) and t h e c l a s s o f subdomains D of separates H such t h a t R (or 3D = L U S R ) (think J for H and of consider some sufficient- l y smooth c u r v e ( o r s u r f a c e r e s p e c t i v e l y ) S i n H. L e t h be a f i x e d positive f u n c t i o n on L s u f f i c i e n t l y s m a l l a t i n f i n i t y ( t y p i c a l l y h ( x ) = _h 2 x = ae , a,b>0 if L = R) in D which takes the boundary 9 D rh on L Mo on S T h i s model ing water zone of the l a t t e r and d e f i n e t o be t h a t h a r m o n i c values . is suggested in [16] to d e s c r i b e the growth o f a ( t h e r e g i o n D) p e n e t r a t i n g a r o c k is i m p i n g e d on b y a h e a v y w a t e r j e t . to the hydrostatic portional to the flow propagat- ( H ) when t h e s u r f a c e T h i s example is i n s t a n c e o f p o r o u s medium f l o w g o v e r n e d by D a r c y ' s tional function law. p r e s s u r e o f t h e w a t e r and g^ i s - g r a d g^ proporis pro- velocity. 2 Ex. 3: Let D range over a l l o r i g i n , and l e t , r e s p e c t t o 0 £ D, for i.e. such bounded domains i n D, g Q R containing be t h e G r e e n ' s f u n c t i o n an the for D with (L) -3- g^(z) = - l o g |z| + h a r m o n i c in g (z) =0 on 3D . D H e r e we h a v e i d e n t i f i e d S = 3D i n t h i s This and used z = x + i y t h i s means t h e f o l l o w i n g : 2 (corresponding and m o d e r a t e r a t e . Then the r e g i o n o f f l u i d the mathematical model The f u n c t i o n g Q in ]R fluid is the grow according to described. is here proportional to the hydrostatic pressure in the d i r e c t i o n of perpen- ]R - p l a n e ) , a n d a c c o r d i n g t o t h e s o - c a l l e d H e l e Shaw - g r a d g^ i s p r o p o r t i o n a l to the average of i t (that At vis- injected at a constant D will ( t h e p r e s s u r e t u r n s o u t t o be c o n s t a n t 2 to the occupied have high Newtonian and i n c o m p r e s s i b l e . to the o r i g i n be distance i s t o be p a r t l y t o t h e r e g i o n D) w h i c h m i g h t w e l l point corresponding dition occurs L e t two l a r g e s u r f a c e s The space between the s u r f a c e s b u t w h i c h i s s u p p o s e d t o be equation It t o e a c h o t h e r a n d t o t h e ]R - p l a n e a n d a t a s m a l l from each o t h e r . dicular variable. origin. parallel the f l u i d as H e l e Shaw f l o w s w i t h f r e e b o u n d a r i e s a n d w i t h a More p r e c i s e l y , cosity J i s t h e MBP t o w h i c h t h e p r e s e n t p a p e r i s d e v o t e d . source at the by a f l u i d with example. in two-dimensional lying ]R D , to the f l u i d v e l o c i t y , o r more correctly across the gap. T h i s g i v e s the moving boundary 3D m o v e s w i t h t h e v e l o c i t y - g r a d g^ , up t o a c o n s t a n t confac- tor). The assumption that the f l u i d harmonic f u n c t i o n a logarithmic (div ( -grad singularity is i n c o m p r e s s i b l e i m p l i e s t h a t g^ i s a gQ) = 0) and t h e i n j e c t i o n o f f l u i d at the o r i g i n f o r g^ . Further, g^ t a k e s a c o n s t a n t v a l u e on 3D ( a c o n s t a n t w h i c h c a n be c h o s e n t o be z e r o ) the pressure outside the f l u i d the pressure drop across l y constant along high). is constant be a p p r o x i m a t e - p r e s u p p o s e s t h a t t h e c u r v a t u r e o f 3D i s n o t T h i s m o t i v a t e s t h a t g^ e q u a l s t h e G r e e n ' s f u n c t i o n f o r respect to the origin. because ( t h e a i r p r e s s u r e ) and because 3D due t o t h e s u r f a c e t e n s i o n w i l l 3D ( t h i s gives D with too -4- F o r more d e t a i l s and t e c h n i c a l background to t h i s example, see [17] . A s i d e f r o m t h i s H e l e Shaw i n t e r p r e t a t i o n Ex. 3 (possibly with several to describe "migration of oil in particular Another logarithmic Chapter XV, the choice f o r singularities) in hydrostatic g^ in has b e e n u s e d environment". See [15], §7. i n t e r p r e t a t i o n o f the moving boundary conditions in the ex- amples above i s t h a t t h e y d e s c r i b e a one-phase S t e f a n problem w i t h zero specific tem- heat ( i . e . D is a melting solid held at i t s melting p e r a t u r e , t a k e n t o be z e r o , D i s t h e g r o w i n g l i q u i d p h a s e w i t h g^ a n d t h e l i q u i d a n d p . 26 f f i s supposed to have z e r o s p e c i f i c in the present paper (Ex. 3 a b o v e ) was i n t r o d u c e d e q u a t i o n f o r t h e Riemann mapping f r o m t h e u n i t d i s c o n t o t h e domain (C [3] In t h a t paper the moving boundary c o n d i t i o n f o r m u l a t e d as a d i f f e r e n t i a l plane See e . g . paper. T h e MBP t o be t r e a t e d i n t h i s S. R i c h a r d s o n i n [ 1 7 ] . heat). temperature and assuming t h a t D t (identifying ]R is function with the is simply connected). This complex differential e q u a t i o n i s o f a q u i t e uncommon t y p e a n d no e x i s t e n c e o r u n i q u e n e s s for solutions uniqueness however, to i t proof for is given in [17]. solutions motion ( t h e complex e x i s t e n c e and t o t h e same d i f f e r e n t i a l t o have been g i v e n i n [ 2 1 ] . Richardson also discovers (A l o c a l in by a. equation proof partial seems, ) [17] a sequence o f simple c o n s t a n t s moments, see p. 9 ) and uses them t o o b t a i n a f u n c t i o n a l for his d i f f e r e n t i a l of equation e q u a t i o n f o r t h e Riemann mapping function. I n t h e p r e s e n t p a p e r we r e - f o r m u l a t e l e a d s us i n t o t h e t h e o r y o f v a r i a t i o n a l t h e o r y we a r e a b l e t o g i v e a g l o b a l a k i n d o f w e a k s o l u t i o n t o t h e MBP. R i c h a r d s o n ' s MBP i n a w a y w h i c h inequalities. By u s i n g this e x i s t e n c e and u n i q u e n e s s p r o o f for -5- The t h e o r y of v a r i a t i o n a l ful inequalities i n h a n d l i n g MBP:s o f v a r i o u s t y p e s . w o r k s b y G. D u v a u t a n d inequality CM. Elliott. formulation for classical h a s a l r e a d y p r o v e d t o be u s e - M o s t r e l e v a n t f o r us a r e In [5] Duvaut g i v e s a type outlines (our Ex. variational inequality formulations 1 is t r e a t e d in [6] §4). Elliott solutions. 3) f r o m a p u r e l y mathematical intended to p a r t l y fill t h i s gap. paper by E l l i o t t - J a n o v s k y w i l l ly overlap since E l l i o t t tions and n u m e r i c a l 3). exist s i m p l e t r e a t m e n t o f t h e H e l e Shaw MBP point of view The p r e s e n t paper P r o b a b l y o u r p a p e r and t h e is announced seems t o w o r k a l o n g s o m e w h a t d i f f e r e n t questions our a l s o announces a paper complement each o t h e r r a t h e r than we a n d s i n c e t h e w o r k o f E l l i o t t [6] a n d o t h e r s t h e r e seems s o f a r t o no c o m p l e t e , d e t a i l e d a n d r e l a t i v e l y (Ex. In f o r problems of t o g e t h e r w i t h V . J a n o v s k y on o u r H e l e Shaw p r o b l e m ( E x . Despite the works of E l l i o t t variational t w o - p h a s e S t e f a n p r o b l e m s * / and i n d i c a t e s e x i s t e n c e and u n i q u e n e s s p r o o f s f o r t h e i r Elliott the complete- lines seems t o be m o r e d i r e c t e d t o w a r d s w h i l e the p r e s e n t work i s c o m p l e t e l y than applicatheo- retical . Acknowledgements: I am v e r y much i n d e b t e d t o P r o f e s s o r H a r o l d S . S h a p i r o h a v i n g p r o p o s e d t h e p r o b l e m a n d f o r t h e many l o n g a n d v a l u a b l e s i o n s on i t w i t h o u t w h i c h I w o u l d p e r h a p s n o t h a v e b e e n a b l e t o t h e p r o j e c t t o an e n d . excellent I a l s o wish to thank Gunhild Melin f o r and r a p i d t y p i n g o f t h i s for discuscarry her manuscript. /Here " c l a s s i c a l " stands f o r the r e q u i r e m e n t t h a t both phases s h a l l have s t r i c t l y p o s i t i v e s p e c i f i c heat. When o u r p r o b l e m i s i n t e r p r e t e d as a S t e f a n p r o b l e m t h e s p e c i f i c h e a t i s z e r o ( c f . p . 4 a n d 26 f f ) . / R e c e n t l y t h e r e h a s a p p e a r e d t h e w o r k [19] o f M. S a k a i w h i c h c o n t a i n s a d e t a i l e d t h e o r e t i c a l s t u d y o f t h e H e l e Shaw p r o b l e m . S e e p . 13 f f . -6- b. A s u r v e y o f t h e This tion contents paper c o n s i s t s is Section In Section of four sections of which the present introduc- I. I I we f o r m u l a t e a n u m b e r o f p r o p e r t i e s , ( A ) t o ( F ) , o f o n e 2 parameter f a m i l i e s t -> o f domains i n express our moving boundary The f i r s t classical of these, sense, i.e. This formulation boundary of i t . 9D w h i c h i n v a r i o u s ways a r e ( A ) , expresses that t + D that to condition. 9D^ s o l v e s o u r MBP i n a t moves w i t h t h e v e l o c i t y is not v e r y f l e x i b l e t o be r a t h e r s m o o t h a n d t ]R because i t - g r a d g^ requires the also involves a . t parametrization Thus, t h i s formulation cannot cover occasions at which changes connectivity. (B) i s a weakened and somewhat more f l e x i b l e way o f f o r m u l a t i n g moving boundary c o n d i t i o n . I t does not r e q u i r e p a r a m e t r i z a t i o n o f 9D^, a l t h o u g h i t (directly involves a contour We t h e n a r r i v e a t o u r c o n c e p t o f weak s o l u t i o n , freed ourselves ther, from all regularity ( C ) makes no e x p l i c i t requirements is. integral (C). I n ( C ) we h a v e <> \ 1 = Here A g D I t can r a t h e r e a s i l y + 2 6 f u n c t i o n o f D^, g ^ i s t h e Green's f u n c - with respect to the o r i g i n , extended to a l l D , t is nothing else than See p . 2 6 f f . by and 6Q i s t h e D i r a c measure a t t h e T h e s e f u n c t i o n s a r e c o n s i d e r e d as d i s t r i b u t i o n s Also distribution ^ 0 t o be z e r o o u t s i d e language. be equation is the c h a r a c t e r i s t i c tion for it t Fur- function. s e e n t h a t t h e m o v i n g b o u n d a r y c o n d i t i o n can be e x p r e s s e d i n l a n g u a g e by t h e a along f o r the boundary. r e f e r e n c e t o the Green's L e t us i n d i c a t e m o r e c l o s e l y w h a t ( C ) at least) the the condition on ]R^. (B) formulated w i t h i n ( 1 ) c a n be g i v e n a d i r e c t p h y s i c a l defining origin. Actually, (1) distribution interpretation. -7- * By i n t e g r a t i n g (1) with respect to t and putting t one < > 3 D X T obtains " \ Thus, = (1) A u (5) u^ = 0 t > 0 + 2 7 T of (2), # 0 6 ( 3 ) m u s t be i n c r e a s i n g (for t > 0 ) outside Now ( C ) tribution u on ]R ( 3 ) combined w i t h ( 4 ) and ( 5 ) , i . e . which s a t i s f i e s (2) of seen t h a t these c o n d i t i o n s of must a l s o > 0 and a s o l u t ~ satisfy we s a y that i s a weak s o l u t i o n i f f o r e a c h t > 0 t h e r e e x i s t s a d i s 7 the coupling solutions t n T is e s s e n t i a l l y t u Since g and D t -> D . ( f o r t > 0 ) ~ replace t i s e q u i v a l e n t t o ( 2 ) and ( 3 ) t o g e t h e r . t i o n t -* (4) t u u t (3)-(5). The c o n d i t i o n s to the Green's ( 4 ) and (5) f u n c t i o n , and i t w i l l be are s t r o n g enough t o guarantee uniqueness for (given DQ) . (3) - (5) Observe the remarkable f e a t u r e of the transformation leading from to ( 3 ) - (5) of having on t ; l i b e r a t e d the problem f r o m any e s s e n t i a l t h e c o n c e p t o f weak s o l u t i o n meaning f o r each f i x e d particular value of value of t i s a c o n c e p t w h i c h has an dependence independent t , a n d a weak s o l u t i o n c a n a l w a y s be f o u n d f o r w i t h o u t b o t h e r i n g about t h e s o l u t i o n f o r any t . / T h e s u b s c r i p t t i n u^. i s u s e d t o i n d i c a t e t h a t u^. i s a f u n c t i o n o n ] R w h i c h d e p e n d s on t ( i . e . t i s a p a r a m e t e r ) . We n e v e r u s e s u b s c r i p t s to denote p a r t i a l d e r i v a t i v e s in t h i s paper. 2 (1) any other -8- In Sections I I a n d I I I we w a n t t o w o r k 2 on a b o u n d e d d o m a i n Q c= IR condition (C) ( a sufficiently is not formulated e x a c t l y t o make some m i n o r m o d i f i c a t i o n s is of that the D :s it. c o n s i d e r a t i o n and t h i s It t-set is also required that Next to c o n d i t i o n Xj) problems ( C ) come c o n d i t i o n s ( L C P : s ) , one f o r each ( 5 ) by r e p l a c i n g X from < 1 . D t U T • (Au^ + A ^ ) t X - 1 2 7 r f 6 "UQ D + 0 (7) ° = (D2) t */ ([0,T], t under 0 < T < °°). t. express complemen- In these problems the explicit (D1) is o b t a i n e d from (3) by t h e i n e q u a l i t y (3)- resulting such that = 0 is the solution - t v in s m a l l ) , we h a v e of so-called l i n e a r t. (3) > 0 Here ^ *t forced ( D 1 ) i s t h e p r o b l e m o f f i n d i n g u ^ , d e f i n e d on Q, w i t h Thus b o u n d a r y v a l u e z e r o on SFI u t 0 (D1) and (D2) w h i c h has d i s a p p e a r e d . the occurrence of D > for all r for all t o c c u r r e n c e o f t h e domains r compact in t h e m o v i n g b o u n d a r y c o n d i t i o n as a s e r i e s tarity > h a s t o be a b o u n d e d s e t u €Hg(fi) Therefore, T h u s , the Dirac measure in are r e l a t i v e l y t large disc). (HUtt)) a s a b o v e b u t we h a v e b e e n r e p l a c e d by an a p p r o x i m a t i o n t o i t to require (6) in a Sobolev space = u t i s t h e same as + ^ essentially in Q, on dQ 7 . of (D1) but e x p r e s s e d i n terms o f t h e function instead: t 1 6Q i n that ( 7 ) has t o be s m o o t h e d o u t . u eH ! (fi), t ( ) Then I ^ e H g ^ ) and i t is required -9- Av < 0 t (8) (v -* ) t .Av t = t Each o f the LCP:s tional inequalities, Find ( f o r each t ) (9) / V(u-u ) • Vu t and ( E 2 ) t (D1) and (D2) i s e q u i v a l e n t t o a s e r i e s o f ( E 1 ) and ( E 2 ) r e s p e c t i v e l y . u GHg(ft) > 0 for all t v e HQ(Q) u £ Hj(ft) with is < 0 and t Au + A ^ t < 0 , t > 0 for is F i n d v G H g ( f 2 ) such t h a t v (10) such t h a t Au^ + A ^ t (E1) w i t h v > ip t > ^ and / v ( v - v ) • Vv t t o o u r MBP i s t h e t t e n c e o f an i n f i n i t e n u m b e r o f s i m p l e c o n s t a n t s o f m o t i o n f o r the complex c n< t> D / z all t One v e r y n i c e p r o p e r t y o f s o l u t i o n s t -> D (11) varia- it, exisnamely moments n (z = x + iy) dx dy f o r n = 1 , 2 , 3 , . . . . T h e z e r o t h o r d e r moment C g ( D ) t increases l i n e a r l y with t. = |D^| = a r e a o f D^ F o r t h e c a s e t h a t t h e D^ a r e simply con- nected the set ( 1 1 ) o f c o n s t a n t s o f m o t i o n may a l s o be e x p e c t e d t o be complete, g i v e n Dp s i m p l y c o n n e c t e d , a map i.e. suitable regularity requirement) property that the c (D^) n Our f i n a l remain formulation (F) some s h o u l d be c o m p l e t e l y d e t e r m i n e d b y the constant. ( F ) o f the moving boundary c o n d i t i o n i s a s t r e n g t h e n e d f o r m o f t h i s moment p r o p e r t y . satisfies t -* D^. ( s a t i s f y i n g i f f o r each t > 0 N a m e l y , we s a y t h a t t -»• D^ -10- j CP (12) > 27RT - C P ( 0 ) for every + / CP s u b h a r m o n i c f u n c t i o n TP i n D - T o s e e w h y ( 1 2 ) s t r e n g t h e n s ( 1 1 ) T observe that a natural (13) / CP = 27Tt - C P ( 0 ) D D T h e moment i n e q u a l i t y Section ing CP i n D T (CP = z yields 1 1 (11) ) . ( 1 2 ) t u r n s o u t t o be s u f f i c i e n t l y strong to to ( C ) . III consists precise relationships ships that 0 harmonic f u n c t i o n be e q u i v a l e n t ( 1 1 ) is + / CP t for every generalization of essentially o f a number o f theorems g i v i n g between the c o n d i t i o n s (and the f l o w o f Section III ( A ) to ( F ) . These the relation- i n g e n e r a l ) a r e as s h o w n i n t h e follow- diagramme. Thm (A) => Thm 1 2 (B) Thm (0 Thm Thm 3 ==> Thm 9 10 (E1) Thm Lemma 8 4- Thm 4 5 (E2)l (D2) (F) 5 (D1) hm + 7 Minimal properties and monotonicity properties (Thm 7 with cor ) Have u n i q u e solutions with regularity properties (Thm 6) s V H e r e an arrow in the sense of , say (C) Thm 3 = ^ > ( D 1 ) , means t h a t a s o l u t i o n t + D . ( C ) i n a s i m p l e w a y (made p r e c i s e vides a solution t + u t of ( D 1 ) . in Theorem 3 ) p r o - -11- As t h e diagramme shows t h e c o n d i t i o n s while tion (A) III implies ( B ) and ( B ) implies (C) to (F) (C) to ( F ) . are a l l equivalent The main goal o f i s t o show t h e e x i s t e n c e and u n i q u e n e s s o f s o l u t i o n s t o (weak s o l u t i o n s ) . This result i s s t a t e d as C o r o l l a r y ( A ) => ( B ) => ( C ) , s h o w i n g t h a t a c l a s s i c a l together with the fact solution t h a t a weak s o l u t i o n 9.1. (C) The steps i s a l s o a weak solution, is unique, serve to motivate c o n c e p t o f weak s o l u t i o n a n d a l s o p r o v e s u n i q u e n e s s f o r c l a s s i c a l The hardest step or (C)(Theorem 9). ( u ^ and v^ r e s p e c t i v e l y ) while i n v o l v e s showing that a c e r t a i n f u n c t i o n function of a set This ties of (Theorem III (C) concerns sets (namely -Av^.) (D ) is a Its proof requires regularity (D1) and (D2) possessed by them ( L e m m a Section (D1) and (D2) c o n c e r n D^). properties proper- corollaries). c o n c l u d e s by showing t h e e q u i v a l e n c e between ( C ) and ft <= ] R 2 ( a d i s c ) ) . T h i s h a s f o r c e d us t o s m o o t h o u t t h e of the Green's function space). (F) 10). I n S e c t i o n I I I we w o r k w i t h i n a S o b o l e v s p a c e ( H Q ( ^ ) on a f i x e d domain step characteristic ( T h e o r e m 6 ) and a l s o m o n o t o n i c i t y 7 with (D1) func- this t ( n a m e l y t h e s e t w h i c h i s t o be t h e c o m p l e m e n t o f i s t h e c o n t e n t o f Lemma 8 . of the solutions Since the solutions. in t h e diagramme i s t o c a r r y o v e r a s o l u t i o n o f (D2) t o a s o l u t i o n o f tions only Sec- Section (in order that it shall belong to that IV begins by showing t h a t the s o l u t i o n s depend i n any e s s e n t i a l w a y on t h e c h o i c e o f Q bounded singularity Sobolev o f ( C ) do n o t ( a s l o n g as i t l y l a r g e ) and a r e n o t a f f e c t e d by t h e s m o o t h i n g o f t h e G r e e n ' s is sufficient- function (Lemma 1 1 ) . P We a r e t h e n a b l e t o s u m m a r i z e much o f t h e w o r k i n S e c t i o n m u l a t i n g a k i n d o f Main T h e o r e m - T h e o r e m 13. initial states that this t -* defined for all solution satisfies i I I I be for- I t s t a t e s t h a t g i v e n an d o m a i n Dg ( a n o p e n b o u n d e d s e t c o n t a i n i n g t h e o r i g i n ) u n i q u e weak s o l u t i o n 1 there is a t £ [0,«>) o f o u r MBP. I t t h e moment i n e q u a l i t y a n d t h a t i t also has -12- those monotonicity properties which i t D t t increases with served for all and t h a t i s supposed t o h a v e , namely inclusions between i n i t i a l that domains a r e pre- t > 0 . T h e n a t u r e o f o u r MBP i s s u c h t h a t o n e e x p e c t s and n i c e r w i t h i n c r e a s i n g t. For example, f o r a l l nicer 9D^. i s expected t>0, to consist of a n a l y t i c curves t -» oo should approach that of a c i r c u l a r t h e shape o f (even i f t o become 3DQ d o e s n o t ) a n d a s y m p t o t i c a l l y disc. as We a r e n o t a b l e t o p r o v e a n y c o m p l e t e r e s u l t o f t h a t s o r t b u t we a t l e a s t make some s t e p s sists in that d i r e c t i o n . of analytic T h u s i n T h e o r e m 15 we p r o v e t h a t curves f o r t > 0 under the assumptions that n i t e l y c o n n e c t e d and t h a t i t c o n t a i n s Dg c o m p a c t l y l a r g e o r t h e a s s u m p t i o n t h a t 3Dg i s a n a l y t i c This domains The f i r s t i s p r e s e r v e d by s o l u t i o n s asserts c. result states is to so-called sufficientthe theorem). quadrature o f o u r MBP ( T h e o r e m 1 6 ) , a n d t h e s e c o n d bibliographical fi- t h a t t h e p r o p e r t y o f b e i n g a QD t h e e x i s t e n c e o f QD:s o f c e r t a i n k i n d s Some f u r t h e r t (Remark 1 a f t e r paper c o n c l u d e s w i t h two a p p l i c a t i o n s (QD:s). is ( i . e . t h a t DQ <= D^.). T h e l a s t a s s u m p t i o n c a n be r e p l a c e d b y t h e a s s u m p t i o n t h a t ly 9D^. c o n - (Corollary result 16.1). notes T r e a t m e n t s o f MBP:s o f k i n d s s i m i l a r t o o u r s by t h e methods o f tional inequalities article space [11] and a r e f o u n d i n [ 5 ] and [6], See a l s o §3 o f t h e C h a p t e r V I I I o f t h e r e c e n t book [ 1 2 ] variasurvey (MBP:s i n one dimension). In the context of Stefan problems t h e r e "weak s o l u t i o n " , d i s c u s s e d e . g . lution i n [ 8 ] and i s an e s t a b l i s h e d n o t i o n [3]. T h i s c o n c e p t o f weak i s n o t t h e same a s t h a t u s e d i n t h e p r e s e n t In [3] Crowley proves u n i c i t y [ 8 ] and [ 3 ] ) t o MBP:s o f o u r t y p e paper. f o r weak s o l u t i o n s (in particular of ( i n the sense that of Ex. of 1, p . 2 ) . so- -13- I n t h e p r e s e n t paper two k i n d s o f LCP:s kinds of v a r i a t i o n a l side. Our c o n c e p t o f the problems (E2) inequalities ( ( E 1 ) and ( E 2 ) ) a r e t r e a t e d s i d e weak s o l u t i o n (D1) and ( E 1 ) . ( ( D 1 ) and ( D 2 ) ) and two (C) i s most n a t u r a l l y (E1). For example the v a r i a t i o n a l inequalities of solutions of variational and [ 2 ] ) c o n c e r n t h o s e o f t h e t y p e (among o t h e r t h i n g s ) subject of [19] [6] on e x i s t e n c e , (e.g. unicity [12], [13] (E2). (preprint) [ 1 9 ] o f M. S a k a i o u r H e l e Shaw MBP i s t r e a t e d . The main k i n d s , a n d t h e r e s u l t s on t h e MBP a r e of this. and a r r i v e d at in [ 5 ] , i s t h e c o n s t r u c t i o n and i n v e s t i g a t i o n o f q u a d r a t u r e mains of r a t h e r general as a p p l i c a t i o n s (D2) and inequalities R e c e n t l y t h e r e has a p p e a r e d t h e paper in which with t y p e than (D1) and [11] a r e o f the k i n d ( E 2 ) , and most l i t e r a t u r e and r e g u l a r i t y connected The main r e a s o n f o r a l s o i n v o l v i n g i s t h a t t h e s e p r o b l e m s a r e o f more c o n v e n t i o n a l by do- obtained These r e s u l t s are s i m i l a r to (or s l i g h t l y strong- e r t h a n ) t h o s e o f t h e p r e s e n t p a p e r , w h i l e t h e methods used a r e q u i t e dif- ferent. L e t us i n d i c a t e r a t h e r b r i e f l y w h a t S a k a i has d o n e on t h e H e l e Shaw problem. 1) S a k a i f o r m u l a t e s a c o n c e p t o f s o l u t i o n o f t h e H e l e Shaw f l o w s . * / concept is s i m i l a r to (but weaker than) our concept of c l a s s i c a l in the sense that the core of it to our (p. 22). however, t>0 equation (iii) a global and i t of (A) one ( i . e . (essentially) Sakai's concept of solution i s a l w a y s t o be d e f i n e d f o r and t o change c o n n e c t i v i t y . Sakai's concept of solution is very complicated. that a solution it. a solution solution in this sense always e x i s t s (Uniqueness of s o l u t i o n s but he is is, all i s f o r m u l a t e d i n a way t h a t a l l o w s t h e domain t o d e v e l o p t a i n kinds of s i n g u l a r i t i e s of this i s an e q u a t i o n e q u i v a l e n t This cer- As a c o n s e q u e n c e Sakai not i s , however, proved; c f . 4 able expects to prove below.) * / W h e n e v e r t h e t e r m " s o l u t i o n " ( o f H e l e Shaw f l o w s ) a p p e a r s on t h e f o l l o w ing pages, i t i s u n d e r s t o o d t o mean s o l u t i o n i n t h i s s t r i c t s e n s e o f Sakai. The e x a c t d e f i n i t i o n o f t h i s concept o f s o l u t i o n i s , however, t o o c o m p l i c a t e d t o be r e p r o d u c e d h e r e . -14- 2) S a k a i f o r m u l a t e s a c o n c e p t o f weak s o l u t i o n w h i c h i s as (with our notations): G i v e n an a r b i t r a r y bounded domain D , n u f o r each t > 0 (i) follows i s a domain c o n t a i n i n g {Do.} i s a weak s o l u t i o n t>0 Dg s u c h t h a t if z / cpda + t ' t p ( O ) < / cpda 0 D " t D for all function cp w h i c h a r e s u b h a r m o n i c a n d i n t e g r a b l e on D^, (ii) has f i n i t e area, (iii) is minimal w i t h the p r o p e r t i e s (i) and (ii). T h i s c o n c e p t o f w e a k s o l u t i o n i s s i m i l a r t o o u r moment i n e q u a l i t y In f a c t , the essential test class difference t h a n we h a v e . is that A further f i n i t e a r e a o f the domains ( ( i i ) ) Sakai proves cessarily (iii) domain s a t i s f y i n g such t h a t It follows in [19]) that a Theorem 3.7) (i) if and ( i i ) satisfying (i) that there (i.e. However, to ( i i i ) (i) and ( i i ) t then t i o n a l s o i n our sense (i.e. s u i t a b l e R and r ) . i s u n i q u e up t o n u l l - s e t s satisfies (F) weak s o l u t i o n s a r e i d e n t i c a l t in interval the solu- [0,T] in our T h e r e f o r e the two concepts modulo n u l l - s e t s . k i n d o f answer t o a q u e s t i o n posed by Sakai (i) a n d s o i s a weak ( C ) on e a c h f i n i t e 9.1). minimal) D <=G). On t h e o t h e r h a n d , a weak s o l u t i o n (Corollary Sakai satisfying f r o m w h a t has b e e n s a i d a b o v e t h a t a weak s o l u t i o n o u r moment i n e q u a l i t y ne- point. i s a minimum ( n o t o n l y t h e r e i s a domain D larger requires t h e r e i s no d i f f e r e n c e a t t h a t G also satisfies sense o f Sakai s a t i s f i e s and f o r is t h a t Sakai o n l y i t c a n be l o o k e d u p o n a s a k i n d o f n o r m a l i s a t i o n . (essentially and ( i i ) difference Sakai has a somewhat w h i l e we r e q u i r e b o u n d e d n e s s . i s bounded, so i n e f f e c t As r e g a r d s proves ( T h e o r e m 6.4 in ( i ) (F). Incidentally inequality techniques. of this gives a (p.113 in [19]) concerning r e l a t i o n b e t w e e n h i s c o n c e p t o f weak s o l u t i o n a n d t h a t one o b t a i n e d b y variational sense the -15- 3) S a k a i s h o w s e x i s t e n c e a n d u n i q u e n e s s f o r weak s o l u t i o n s . T h e i s p r o v e d by s i m p l y c o n s t r u c t i n g This construction is rather t h e domains "by h a n d " ( m o r e o r (i) and ( i i ) due t o t h e r e q u i r e m e n t t u r e domains for under (iii). of 4) 2) a b o v e . (Actually domains Uniqueness the having is then trivial Sakai proves e x i s t e n c e o f ( s u b h a r m o n i c , harmonic and a n a l y t i c ) w a y , a n d t h e w e a k s o l u t i o n s o f H e l e Shaw f l o w s a r e j u s t Sakai proves t h a t a s o l u t i o n i s a l s o a weak s o l u t i o n Since Sakai's concept of solution of classical (Proposition is stronger i s b e t t e r than our Theorems solutions. Existence of solutions S a k a i has a p a r t i a l known a p r i o r i is a solution Sakai result to f u l f i l if (certain (Corollary solution actually 13.4). is a solution i s bounded by a n a l y t i c then, for t > 0 , every 3D^ i s a n a l y t i c except at certain " c o r n e r s " and ends o f s l i t s ) . of these exceptional although curves. non- t>0 d e g e n e r a t e component o f points uniqueness c e r t a i n of the requirements f o r a solution {D.} z points exceptional The union o v e r a l l i s a s e t w h i c h i s a t most c o u n t a b l y t>0 infinite 13.3.) Finally, Sakai proves t h a t f o r large t a s o l u t i o n o f H e l e Shaw f l o w s i s a s i m p l y c o n n e c t e d domain bounded by a s i m p l e a n a l y t i c c u r v e and it asymptotically a s t + °° c o n v e r g e s t o a d i s c mann m a p p i n g f u n c t i o n f r o m the unit disc 13.5). that in the sense t h a t the Rie- ( s c a l e d in the proper way) con- v e r g e s u n i f o r m l y on t h e c l o s u r e o f t h a t d i s c t o t h e i d e n t i t y map sition priori) 1 and 2 . i s , however, never proved shows t h a t a s o l u t i o n e s s e n t i a l l y More p r e c i s e l y , (a i n t h a t d i r e c t i o n a s s e r t i n g t h a t a weak (Proposition 13.1 concept T h e weak s o l u t i o n b e i n g u n i q u e , t h e above r e s u l t a l s o shows 6) in applications is weaker than our s o l u t i o n a n d h i s c o n c e p t o f weak s o l u t i o n than that of o u r s , t h i s r e s u l t 5) va- this.) in [19]). for quadra- r a t h e r g e n e r a l c l a s s e s o f p o s i t i v e measures and f o r rious classes of test functions this less). l e n g t h y and i s done i n such a way t h a t d o m a i n o b t a i n e d c a n b e p r o v e d t o be t h e m i n i m u m o f a l l the p r o p e r t i e s existence (Propo- -16- F O R M U L A T I O N S OF T H E MOVING BOUNDARY a. Notations F 2 = I : R D identify s u c h as z and = t h e open d i s c = D(0;r) = D(0;1) in = {x £ F : a < x < b} [a,b] = {x€ : will 2 F F at the with center be t h e u s a g e con of ]R . a and r a d i u s r. a<x<b} the o r i g i n . (Actually ft will a l w a y s be a d i s c in F centered origin.) 3D = t h e b o u n d a r y o f D in F , means : D in D C ft ( i f D C F D i n ft , fi D - D U 3D = t h e c l o s u r e o f if 2 3 D = 3Df"lft = t h e b o u n d a r y o f fi in (C w h e n e v e r g e n e r a l l y denote our "universe", a f i x e d boundary region containing D E C w i t h the complex plane £ for variables (a,b) ft F Often the o n l y consequence o f t h i s w i l l letters D preliminaries we w i l l venient. D(a;r) and CONDITION ft F 2 ( D <= F 2 D <= Q if 2 ) i s open and b o u n d e d , DEFT) 2 da = dx dy = element o f area measure in F (will integrals) |D| = a r e a o f (also D Izl if D <= F = yx +y 2 Xp = t h e c h a r a c t e r i s t i c if D C F 2 ( <D X n (z) 2 if 2 z = x + iy £ £ ) function of D 1 for z £ D 0 for z € D • o f t e n be o m i t t e d in -17- 6 = 6Q = t h e D i r a c m e a s u r e w i t h r e s p e c t t o t h e o r i g i n p o i n t mass a t VU . G R A D U g^(z^) - R (the n unit R ) n | ) i s t h e G r e e n ' s f u n c t i o n f o r t h e domain D (=-log|z-^| =0 on 3D g (z) = g (z,0) C (ft) : the D 0 e in order C (ft) A |z-c| ft < + o f whose d e r i v a t e s R which are l o c a l l y (0 < A < 1 ) , i . e . J J J U ) - " ( G ) | z,;eK z *£ u : all of (m = 0 , 1 , 2 , . . . , o o ) . e x i s t and a r e c o n t i n u o u s with exponent SUp z) s p a c e o f f u n c t i o n s ft -»• R : t h e space o f f u n c t i o n s a D, 0 e D) (linear) < m in as a f u n c t i o n o f (if D m + harmonic which Holder continuous satisfy co a f o r e a c h c o m p a c t K <= ft . C ' (ft) m a : those functions C (ft) i n C (ft) whose d e r i v a t e s of order m */ such t h a t !R„ K 1I ,r 2 the class of simply connected regions ' (i.e. 3D is a Jordan curve of admits a twice continuously : t h e c l a s s o f open s e t s D C R : t h e c l a s s o f open bounded s e t s Thus to (m-0,1,..., 0 < A < 1 ) . a S : m belong 51 = U ?L R,r>0 with 2 D c= R , r ""/region = d o m a i n = o p e n s u b s e t o f R 2 with 0 £ D and class differentiate . K D c R o B r parametrization). C C D C C F . with 0 £ D. K (R,r > 0). -18- = C " ( f i ) : t h e (1 i n e a r ) differentiate V (ft) f u n c t i o n s ft -»• ]R functions on ft ( i n f i n i t e l y w i t h compact : the space o f r e a l - v a l u e d d i s t r i b u t i o n s H '' (ft) m space o f t e s t support). on ft . : t h e Banach space o f r e a l - v a l u e d d i s t r i b u t i o n s :) whose d i s t r i b u t i o n d e r i v a t i v e s (m > 0 , 1 < p < » ) , _ m H 'P(ft) m ' . 11 9 n,k>0 n+k<m P of order 3 n + k n + k \P(ft) of the n D n K w k i t n u ni, n e l Hj(ft) : t h e c l o s u r e o f c"(fl) = Hj' (ft) 2 P ^ ) (m > 0, H ' (ft) . 1 < p in 1 2 1 We w i l l Hg(ft) the p r i m a r i l y work will inner o°). < K . 2 form u H (ft) = H ' (ft) m L^(ft) u 11 3 x V n,k*0 3 x 3 y n+k<m m belong to of normed by : the space o f d i s t r i b u t i o n s 1 < m on ft , a l l -1 in t h e Sobolev space Hg(ft) and a l w a y s be c o n s i d e r e d as a r e a l Hilbert H (ft). space, equipped with product <-> = / - - - = / ^ l M f This bilinear Prop.23.4). n o r m ||u ||^ ^ • f o r m i s an i n n e r p r o d u c t The norm i t defined induces, above. because ||u || = / ( u , u ) , ft i s bounded ([20], is equivalent to the -19- For (1) ue£>'(ft), tpe$)(ft) <u,cp> = <(p,u) = u(cp) The f o l l o w i n g (i) o we set (value of u facts are well-known v e L (ft) i f and o n l y i f on cp). (and easy t o verify): t h e map £ > ( f t ) £ c p - » (cp,v> i s c o n t i n u o u s in t h e L (ft) t o p o l o g y , and i n t h a t c a s e t h e ( u n i q u e ) c o n t i n u o u s e x t e n s i o n 2 i t t o L (ft) i s g i v e n by (2) (u,v) = / u • v ft (u,v£L (ft)) (when v € H i f and o n l y i f £ > ( f t ) 9 c p - > <<p,v) is continuous The (unique) continuous e x t e n s i o n of (ft)) d e f i n e s a b i l i n e a r (also denoted ( . , . ) the dual . 2 1 (ii) v£H (ft) 1 HfUft) t o p o l o g y . -1 ([20], Prop. 23.1) in t h i s map t o 1 1 p a i r i n g between Hg(ft) ) , b y means o f w h i c h H Vft) s p a c e o f H^(ft) and H (u,v) -1 namely Thus - A H^(ft) identifies meaning. (4) (u,v) u£Hg(ft) and Despite that vGH u and s p a c e ) and ( f t ) t h e p r o d u c t u*v it will of the dual of H" (ft). 1 for v has i n g e n e r a l (in similarity with integral ( t h e p a i r i n g d e f i n e d under /u«v = < u , v ) If (ft) -1 v e n i e n t t o use the symbolic for two r e p r e s e n t a t i o n s ( i n being a H i l b e r t 1 If onto H (u,v€Hj(fl)) ( [ 2 0 ] , Thm 2 3 . 1 ) . Q with that = - (u,Av) H (ft), n . T h e L a p l a c i a n o p e r a t o r A i s an i s o m o r p h i s m o f H g ( f t ) (3) the 1 H (ft) (ft) c a n be i d e n t i f i e d 1 with the property of ueHj(ft), /u*v (ii) veH" (ft) 1 as (2)) s o m e t i m e s be c o n - an a l t e r n a t i v e above). in (4) to agree with Ju«v ft . . t h e n one wants t h e s y m b o l i c This notation Thus, i n ( 4 ) h a p p e n t o be s u c h t h a t t h e i n t e g r a l i n the sense o f measure t h e o r y , no is actually /u«v ^ the case, at least exists integral in the -20- f o i l owing two situations: (i) vel_ (ft) (ii) u (then u - v G L 2 is a continuous (in H" (ft)) u e HJ(«) C L (ft)) (ft) s i n c e 1 function 2 ( i n H g ( f t ) ) and These two cases w i l l cover our needs. Using the above kind of n o t a t i o n formula /VU'Vv = - /u-Av (u,v£Hj(fi)) the elements of u > 0 if in D c ft H (ft), H will u tinuous function On t h e o t h e r h a n d t h e and such s e n t e n c e s w i l l i s known t o have a r e p r e s e n t a t i o n (necessarily u n i q u e ) and s h a l l ing in terms of t h a t continuous as ( 6 ) and ( 7 ) when D ueHj(ft), ft) function. is non-open w i l l i n f o r m a t i o n about (in be considered be i n t e r p r e t e d sentence u v£H~ (ft) 1 i f and o n l y if be u s e d o n l y i f and o n l y if then have i t s usual Similarly, inequalities meansuch be u s e d o n l y when we h a v e a d d i - the f o l l o w i n g are (tp,v) > 0 the in the form of a con- and t h e i r meaning w i l l (u,tp) > 0 if d e p e n d on t h e context. true, f o r a l l tp£H ( f t ) w i t h tp > 0 and v > 0 in D distribution u > 0 (ft),... Q i s o p e n , a l w a y s has i t s meaning and s h a l l has no meaning i n g e n e r a l If -1 D , in tional form T h u s s t a t e m e n t s such as the sense o f d i s t r i b u t i o n s . u > 0 (3) takes the . 1 as d i s t r i b u t i o n s . i s a Radon m e a s u r e . 1 Primarily v ; 1 for all tp£H (ft) n with tp > 0 . -21- Some a b b r e v i a t i o n s sometimes MBP moving boundary LCP linear complementarity QD quadrature used: problem problem domain Formulas a r e numbered s u b s e q u e n t l y w i t h i n each s e c t i o n When a f o r m u l a i s r e f e r r e d t o f r o m a n o t h e r s e c t i o n i t s number i s by t h e number o f t h e s e c t i o n t o w h i c h i t b e l o n g s 12 o f s e c t i o n III). b. A c l a s s i c a l f o r m u l a t i o n o f t h e moving boundary We s h a l l O G D and such t h a t 1 et (g^(z) D imply a map ( a , b ) 3 connected in D, to D g^ = 0 3D). condition D t regions, Dc]R 2 2 g* X C . with respect to on For the The assumpVg^ have c o n t a i n i n g 0 £ ]R . T h e n we s a y (A) or is a classical there exists (twice continuously that £S s o l u t i o n o f our moving boundary 2 problem i f For D = DU3D. be an o p e n i n t e r v a l t -» be case. ( a s i d e f r o m t h e e x i s t e n c e o f g^) t h a t gp and ( a , b ) c= F satisfies condition 3D i s a J o r d a n c u r v e o f c l a s s = -log|z| +harmonic continuous extensions Let = formula i s a l s o a weak s o l u t i o n . simply connected regions denote the Green's f u n c t i o n f o r t i o n s on (III.12) -Vg^ in order to i s o b v i o u s how t o e x t e n d i t t o t h e m u l t i p l y such t h a t origin preceded we f o r m u l a t e t h i s c o n d i t i o n o n l y f o r s i m p l y c o n n e c t e d Let S denote the class of a l l DeS solution IV). condition 3D o f D m o v e s w i t h t h e v e l o c i t y able to prove l a t e r that a c l a s s i c a l but i t (e.g. g i v e an e x a m p l e o f a p r e c i s e f o r m u l a t i o n o f t h e that the boundary simplicity ( I to a map z; : ]R / Z differentiate) such * ( a , b ) -»• ]R that 2 of class C -22- (i) c ( s , t ) £ 3D (ii) c(*,t) for all t : 1R/Z 2 -* 3D. s,t is a ( o f c l a s s C ) f o r each (10) (iii) 9c( aV Comment: 3D^. (i) p (g(s,t)) and ( i i ) te(a,b) , f o r a l l s . t . say t h a t f o r each f i x e d t , ?(*,t) parametrizes T h e p a r a m e t e r v a r i a b l e s ( i n w h i c h z; has p e r i o d 1) n u m b e r s t h e ticles - Vg n u g =-Vg t} diffeomorphism D on 3 D , and ( i i i ) t (c(s,t)). t _ to D . Here V g s a y s t h a t e a c h s u c h p o i n t moves w i t h t h e velocity is the continuous extension of the gradient n u parof t t c. A semi-weak f o r m u l a t i o n o f the moving boundary condition N e x t we g i v e a f o r m u l a t i o n o f t h e m o v i n g b o u n d a r y c o n d i t i o n s e r v e s as a l i n k between the c l a s s i c a l formulation. containing (B) L e t S be as on p . 21 the o r i g i n . t h e map ( a , b ) 3 t D satisfies be an o p e n interval that £ S t (B) o r i s a semiweak s o l u t i o n o f our moving boundary oo 2 ~~~~~~~~~~~~~~ f o r each tp £ C ( F ) , / t p d x d y is a continuously d i f f e r e n D tiable function of t d 3 D t with d t (a,b) c F weak condition problem i f , D f o r m u l a t i o n and t h e f i n a l and l e t T h e n we s a y which \ t Comment: denotes the d e r i v a t e in the d i r e c t i o n of the outward — — 3n o f 3D. , ds d e n o t e s t h e a r c - l e n g t h m e a s u r e on 3D. . normal -23- To see t h a t does, just (B) expresses integrate smal1). This t h e same m o v i n g b o u n d a r y c o n d i t i o n as (11) w i t h r e s p e c t to time from t to (A) ; t + fit ( 5 t > 0 gives D 9 / cp • - g j j t ds • fit + 0 ( 6 1 T ) 3 g / cp - / cp = - t 5t D D + t 9 D expressing that t the width of the s t r i p " from 9D t to 9 D , is t + g t D D ^ ^ . ^ D^, t h a t • fit + <27(6t ) . (A) wants i t to This is precisely condition i s t h e f o r m u l a t i o n we a r e g o i n g t o w o r k w i t h a n d f o r w h i c h we shall p r o v e e x i s t e n c e and u n i c i t y of solutions. We g i v e t h e first and d i s c u s s Let r , R , T > 0 , let ft i t afterwards. ^ denote the class of a l l ,r T h e n we s a y t h a t D K t h e map [ 0 , T ] satisfies (C) or 3 t -» D °t " °0 X = satisfies u^ > 0 and + t o p e n s e t s D C ]R eft 2 7 T t for all ' W t£[0,T] X ] D r 2 with Q = B formulation and D let R D C C D C C D . r K D R > r i s a weak s o l u t i o n boundary problem i f X what be. d . T h e weak f o r m u l a t i o n o f t h e moving b o u n d a r y This distance 2 T - the moving boundary c o n d i t i o n is the (with parameters r , R , T ) of our moving the function u = Uj.£Hg(ft) defined by -24- Discussion: — — XQ First, observe that equation _^ " 2iTt • - XQ Hj(ft) + H" (ft) | Xj) e H (ft) (13) r e a l l y d e f i n e s and A i s an u. t since isomorphism . 1 T h e l e f t member o f ( 1 5 ) c a n e i t h e r be i n t e r p r e t e d as t h e d u a l i t y 1 -1 1 -1 p a i r i n g b e t w e e n H Q and H ( u ^ G H g , 1 - X ^ £ H ) o r a s an o r d i n a r y ? t Lebesgue i n t e g r a l ( 1 - X » cf. p . 1 9 f ) . Since 1 - X ( that t t " t h e i n t e g r a n d i n (15) i s n o n - n e g a t i v e ) (14) and (15) t o g e t h e r e x p r e s s t h a t N e L N u u^ > 0 in ft and t h a t > 0 s o u u^. = 0 ( a . e ) outside D t . L e t us m o t i v a t e t h e c o n c e p t o f weak s o l u t i o n b y s k e t c h i n g how arises from condition of bution language 39D 3 "at XQ that equation t? *( l e n g t h measure o f 3 D ) a r c t / tpds on F 2 Ag D = - 2TT 6g — ^ - . • ( a r c l e n g t h measure o f 3D ) t i t to zero outside D^, a n d w h e r e , g^ is extended to t when p a s s i n g f r o m t h e o u t s i d e o f normal d e r i v a t i v e f r o m t h e i n s i d e o f D. into itself). all hence a l s o e q u a l s t h e jump o f t h e o u t w a r d normal d e r i v a t i v e 9 n 3D that is understood that the Green's f u n c t i o n by p u t t i n g 2 distribution t where i t ]R . i n t h e r i g h t member i s t h e Combine t h i s w i t h t h e f a c t (18) distri- t = — 5 ^ — 3D ( 1 1 ) i n ( B ) c a n be e x p r e s s e d i n as Here the second f a c t o r (17) interpretation it. Observe f i r s t (16) ( 8 ) a n d a l s o be g i v i n g a p h y s i c a l it o f g^ across (besides being j u s t T h e n we g e t the -25- (19) 9 ^ Xx n D = AA g \ = t n + + Now ( 1 3 ) (20) is with u t = Jg 0 t 2 T T6 6 0 2 7 1 is essentially (19) integrated with respect to time. That i s ( 1 3 ) . (14) and (15) a r e c l e a r l y a l s o s a t i s f i e d for dx D T integration of (19) gives (21) *D • D X t = 0 A t u + which e s s e n t i a l l y (20) s i n c e g * 0 2 7 T t 6 > 0 , and Q g^ with x ) . between (21) and (13) i s smoothed o u t t o - [ j j - j X p t h e f a c t t h a t 6g € H (22) (C) t u. - / g 0 where D for x £ [ 0 , t ] t (D T increases T The d i f f e r e n c e u^ i n = 0 outside -\ r in (13). This replacement r (Q) i s t h a t t h e D i r a c measure §Q (equivalently i s n o t i n t e n d e d t o be e x a c t l y 1 g ^€H (ft) D Q (20) but is necessitated ) . Thus, the by function rather dx n T (23) \ ( Z ) (Here g ^ z , ? ) fjGD.) dition fact, I ~~ W 9 D T ( Z ' C ) ^ i s t h e G r e e n ' s f u n c t i o n w i t h r e s p e c t t o an a r b i t r a r y T h i s m o d i f i c a t i o n o f gp d o e s n o t a f f e c t since one has it i s e a s i l y s e e n t h a t g^ = point the moving boundary i n a n e i g h b o u r h o o d o f 3D. conIn -26- (24) g (z) = g (z) D + D g (z) log|z[ + l o g [ zJ D --yyj - -jjj-y J / log|z-c|da l o g |z-c | d a f o r z £ ID. ? 9 (z) z€D 0 zefls D D ND. N e x t l e t us g i v e a d i r e c t p h y s i c a l m e a n i n g t o ( 1 3 ) , o r r a t h e r t o i n t h e c o n t e x t o f h e a t c o n d u c t i o n p r o b l e m s and S t e f a n p r o b l e m s . (25) sider the ordinary heat c(T)|T + q = V (k(T)VT) > 0 and q = q ( x , y , t ) Thus, con- equation , d e s c r i b i n g t h e h e a t f l o w i n some m a t t e r . ture, c = c(T) (19) the s p e c i f i c Here T = T ( x , y , t ) heat, k = k(T) > 0 is the the thermal temperaconductivity is a source term (the heat production per u n i t volume). d e n s i t y o f t h e m a t t e r i s a s s u m e d t o be c o n s t a n t a n d i s t a k e n a s u n i t y . i s a l s o assumed t h a t If c(T) an o r d i n a r y If c(T) (26) c(T) c and k do n o t d e p e n d e x p l i c i t l y and k ( T ) a r e s m o o t h , s t r i c t l y heat conduction is of the = L • S(T-Tg) on positive functions (25) describes problem. form + a smooth, s t r i c t l y Then Tg i s t h e m e l t i n g t e m p e r a t u r e , L > 0 and equation T>Tg T(x,y,t) positive function the latent heat, the d e f i n e t h e s o l i d and l i q u i d phases r e s p e c t i v e l y and t h e = Tg d e f i n e s t h e moving boundary s e p a r a t i n g t h e s e Now I c l a i m t h a t o u r e q u a t i o n c(T) = 6(T) . solid. inequalities phases. (27) It x,y,t. ( 2 5 ) c a n be s e e n t o d e s c r i b e a t w o - p h a s e S t e f a n p r o b l e m o f a m e l t i n g T<Tg The (19) is of the type (25) with two -27- Thus our moving boundary problem w i l l type (of be a S t e f a n p r o b l e m o f " g e n e r a l i z e d type" because c l a s s i c a l l y h e a t t o be e v e r y w h e r e strictly positive). generalized one r e q u i r e s t h e Our problem w i l l also in be a o n e - p h a s e p r o b l e m s i n c e o u r b o u n d a r y c o n d i t i o n s a r e s u c h T = constant specific practice that (= 0) i n one phase ( t h e s o l i d p h a s e ; t h e d e s c r i p t i o n o f s o l i d p h a s e as t h a t d e f i n e d b y T < T g c a n n o t be t a k e n l i t e r a l l y in the this case). T o p r o v e t h e c l a i m we i n t r o d u c e t h e e n t h a l p y the temperature function T = / c ( T ' ) dT (28) H(T) (29) T (J>(T) = / k ( T ' ) d T ' (30) (25) defined H and by and 1 respectively. (The lower l i m i t s of these <J> (heat function) the integrals are immaterial.) In terms of becomes |£ = A * + q . Now t h e (31) c(T) = 6(T) (32) k(T) = 1 choices yield (33) <j>(T) = T (34) H(T) = the Heaviside f u n c t i o n of 0 1 for T T < 0 T > 0 Thus by o b s e r v i n g that x i s e s s e n t i a l l y t h e H e a v i s i d e f u n c t i o n o f gp t t ( t h e r e a r i s e s a t i n y p r o b l e m o f how t o d e f i n e t h e H e a v i s i d e f u n c t i o n a t t h e D -28- jump p o i n t , but t h i s problem is g (19) and , Xn n i n in any case u n i m p o r t a n t <(>, H i n ( 3 Q ) c a n be c h a n g e d b y a d d i t i v e w i t h o u t a n y t h i n g h a p p e n i n g ) we s e e t h a t (35) (j, (36) H = (37) q = 2TT6 = = g T X (19) with t q proves the claim. is c l e a r from the formulation of t D Dj e f i (C) that ( g i v e n Dg) a weak c a n be u n i q u e a t m o s t up t o s e t s o f t w o - d i m e n s i o n a l t measure z e r o ; set constants and It tion (30) goes o v e r i n t o functions D n u This since the for (13) - (15) such t h a t D almost everywhere. is not affected Xn> t = Xn if Lebesgue i s r e p l a c e d by in the sense of d i s t r i b u t i o n s , i.e. will on. I f we h a d w a n t e d t o we c o u l d h a v e r e m e d i e d t h i s s i t u a t i o n b y representatives another t T h u s p h r a s e s s u c h a s " u n i q u e up t o n u l l - s e t s " a p p e a r i n some t h e o r e m l a t e r solu- i n each e q u i v a l e n c e c l a s s o f D:s (calling choosing eR D a n d D' D K,r equivalent if x n = Xn' a . e . ) . f o r such r e p r e s e n t a t i v e s : T h e r e i s a t l e a s t one n a t u r a l i n each e q u i v a l e n c e c l a s s t h e r e choice is a unique maximal e l e m e n t , t h e u n i o n o f a l l i t s members, o r , what amounts t o same, let DeJL be r e p r e s e n t e d b y the K,r (38) D 1 = ]R ^ 2 supp(1 - x ) D , w h e r e s u p p means s u p p o r t the r e p r e s e n t a t i v e boorhood U D' o f in the sense o f d i s t r i b u t i o n s . D consists of those points with the property |U n D| = I U I choices of representative D , namely words, which have a n e i g h - . One r e a s o n w h y we h a v e c h o s e n n o t t o f o r m u l a t e canonical z In o t h e r d o m a i n s i s t h a t we l a t e r (C) shall in terms of work w i t h these other -29- (39) D. = D U { z e ft : u . ( z ) > 0 } n and i t i s not q u i t e c l e a r w h e t h e r t h e s e two c h o i c e s always are the A nice feature of parameter in i t : one f o r each t e [0,T] . ( c f . p . 45 f ) , t In f a c t , if D. ( i n R x D K it , r (42) g r a d u. + = 0 t since t and and (13) u^ satisfy (C) then i m p l i e s t h a t Au £ L solve the f o l l o w i n g i s assumed t h a t 3 D ) and a c o n t i n u o u s l y in u u D t free = 3(ft^D ). t differentiate function that (40) (41) if differentiate boundary problem (at least u . o n D. s u c h t t . and i t f o l l o w s t h a t Find a region problems, E a c h o f t h e s e p r o b l e m s c a n be v i e w e d as a f r e e 3D m u s t be c o n t i n u o u s l y t i s t h a t t h e t i m e v a r i a b l e a p p e a r s o n l y as a ( C ) j u s t c o n s i s t s o f a number o f u n c o u p l e d boundary problem f o r u (C) same. D and = 0 on 3D. S a k a i , i n [ 1 9 ] , works w i t h a n o t h e r r e p r e s e n t a t i v e , namely t h a t d e f i n e d b y ( i ) - ( i i i ) on p . 14 ( w h i c h he s h o w s t o be u n i q u e ) . domain -30- e . Two l i n e a r complementarity problems These two problems c o n s t i t u t e formulation step b e t w e e n t h e weak o f t h e moving boundary p r o b l e m and v a r i a t i o n a l The e x p r e s s i o n ([6]) an i n t e r m e d i a t e "linear complementarity and has been a d o p t e d D (i.e. D G HQ(Q) function p r o b l e m " has been u s e d by Elliott here. put Q - Let r , R , T > 0 , inequalities. Dg e f i p defined and l e t r DQCp be a g i v e n d o m a i n ) . For each t e [ 0 , T ] introduce with the by (43) (Since the r i g h t function member a b o v e b e l o n g s in Hg(ft). Au (45) u + A^ t ( 4 3 ) defines a unique condition (C) becomes t > 0 t /u (46) (fi) ) Expressed with the aid of (44) ,-1 to H t • ( A u + Aijjj.) = 0 . t Now, t h e f i r s t but w i t h of our l i n e a r complementarity ( 4 4 ) weakened t o the i n e q u a l i t y Au problems t + A^ o n e i s t h e same t h i n g e x p r e s s e d i n t h e f u n c t i o n say v t t is j u s t (44)-( 4 6 ) , < 0 , and t h e = u t + second T h u s we that t h e map [ 0 , T ] 3 t - » u e H J ( G ) s a t i s f i e s (D1) t (47) u > 0 (48) Au t (49) /u t t + Ai|; < 0 t •(Au + A^ ) t a n d we s a y t that = 0 , (D1) if for all te[0,T] -31- t h e map [ 0 , T ] 3 t v (D2) £ Hg(ft) t satisfies (D2) if for all t£[0,T] (50) (51) Av^ < 0 (52) J ( v - * ) t -Av t = 0 t Comments: A d i f f e r e n c e is that the regions the i n i t i a l tained T d o m a i n DQ w h i c h i s now g i v e n b e f o r e h a n d a n d i s (43)) given functions iJ^CH a n d we w i l l for iJJ £Hj(ft) t u £Hg(ft) t . satisfy the problems t That (53) I. = {z£ft (C) (54) Av + = 0 Consider : v. ( z ) ft grad v We will involving i s , we w i l l for implicitly con- arby t o r e f e r t o ( D 1 ) and ( D 2 ) also refer to all the use f o r m u l a t i o n s (given tg) for of the form given . ( D 1 ) and ( D 2 ) correspondences such as Similar "let remarks hold = ( D 1 ) a n d ( D 2 ) c a n be c o n s i d e r e d as f r e e ( D 2 ) f o r example. for (D2) \ g r a d \p. Introducing boundary the coincidence set iMz)} implies I and (55) (56) without problem in (C) and ( E 1 ) and ( E 2 ) . one can see t h a t determined (not necessarily (D1) f o r t = tg" For f i x e d t £ [ 0 , T ] conditions. (ft) not of the form ( 4 3 ) . -» U ^ J V J . (B), (D1) and ( D 2 ) a r e m e a n i n g f u l sometimes take the l i b e r t y isolated values of [0,T] 3t (A), . is c l e a r that the conditions bitrary versions have d i s a p p e a r e d f r o m the f o r m u l a t i o n , e x c e p t in the function ^ It for D as c o m p a r e d w i t h t h e e a r l i e r on 91 that outside 1^., v^. s a t i s f i e s the over- -32- T h u s we h a v e a f r e e b o u n d a r y c o n d i t i o n f o r 91^. . T h i s f r e e boundary lem i s known as "the o b s t a c l e p r o b l e m " ( t h e f u n c t i o n obstacle). f. See [ 1 1 ] o r Two v a r i a t i o n a l We s h a l l valent, respectively, Au. + the . inequalities i n e q u a l i t i e s w h i c h a r e t o be e q u i - to the l i n e a r complementarity n a n d \p be as on p . 3 0 f t h e map [ 0 , T ] 9 t (57) f o r example f o r m u l a t e two v a r i a t i o n a l L e t r , R , T , ft , D (E1) [12] describes prob- u e Hg(ft) t satisfies . problems T h e n we s a y (E1) if, (D1) and that for all te[0,T], < 0 and (58) • / V(u - u ) • Vu. > 0 t ft Z i u e HQ(Q) We s a y (E2) Z for all ~ with Au + A ^ < 0 . t that t h e map [ 0 , T ] 3 t -> v , € H ' ( f t ) s a t i s f i e s (59) and •i (60) / V ( v - v . ) • Vv. ft 1 v£ O f t ) z z with > 0 for " v > ii. . all (E2) if, for all (D2). t e [0,T], -33- g . T h e moment Let ft (thus 31= say inequality denote the class of a l l with U ft R,r r,R>0 inequality, / cp - (61) D R,r D <= K as on p . 23 ) , a n d l e t T>0. with OeD T h e n we that t h e map [ 0 , T ] 3t (F) IR bounded open s e t s t if, -* D^G % satisfies ( F ) , or s a t i s f i e s f o r e a c h t £ [0 , T ] , / c p > 2-rrt • i p ( 0 ) D 0 for every function Remarks: 2 2 cp £ H (]R ) By d e f i n i t i o n which is subharmonic (see e.g. [20], Sect. i s r e q u i r e d t o be u p p e r s e m i c o n t i n u o u s perty with r e s p e c t t o small involving (F) ( T h e o r e m 10, ( F ) n n n 2irt (n = 0) for n >1 pro- 2 i n ( F ) , H (]R ) , i s p e r h a p s n o t t h e most ( C ) ) works f a i r l y a n d ± Im z n we s e e t h a t ( F ) i m p l i e s t h e moment ID. I = I D I + function and t o have t h e s u b - m e a n v a l u e is a choice f o r which the proof of our only By c h o o s i n g cp = ± Re z Dg U DJ. . discs. The choice of the t e s t class one, but i t in 30) a subharmonic 2 natural t h e moment and (n>0) theorem well. in a neighbourhood property: of -34- R E L A T I O N S BETWEEN T H E MOVING BOUNDARY C O N D I T I O N S , AND E X I S T E N C E AND U N I C I T Y We s h a l l RESULTS now s e t up t h e r e l a t i o n s ditions (A) - (F) in Section unicity of solutions of I I and t h e r e b y a l s o p r o v e e x i s t e n c e (C) - (F) a l s o p r o v e some m o n o t o n i c i t y Thm 2 Thm 1 => (B) =^> (for ( A ) and ( B ) o n l y u n i c i t y ) . and c o m p a r i s o n The diagramme below i l l u s t r a t e s (A) between the moving boundary Thm 3 Thm 5 (D1) Thm T h m 10 (D2) and We w i l theorems. the contents of this (C) con- sections. (E1) 4 Thm 5 <^> Minimal properties and monotonicity properties (Thm 7 with cor ) (E2) r Have u n i q u e solutions with regularity properties (Thm 6 ) s Thus the c o n d i t i o n s infer (A) or (C) follows solutions. (C) - (F) are a l l (B) from them. equivalent, b u t we a r e n o t a b l e The e x i s t e n c e and u n i c i t y o f s o l u t i o n s from the elementary f a c t that ( E 1 ) and ( E 2 ) have unique to to -35- a. (A) (B) T h e o r e m 1: S u p p o s e t h e map ( a , b ) 3 t - » also satisfies Proof: D e S t satisfies (A). Then it (B). A l l we h a v e t o p r o v e i s t h a t t h e formula 8g J cp d x d y (1) = - / cp 3D, oo holds f o r a l l cp e C ( F function of t. (2) Let ds an 7 ) a n d t h a t t h e r i g h t member o f i t x , y be t h e c o o r d i n a t e v a r i a b l e s is a continuous 2 i n TR a n d l e t S = 5(s,t) n = n(s,t) denote the components o f e ( s , t ) £ | R 9g 95(s,t) _ D u at ax t (p.21-22). Then ( A ) ( i i i ) becomes (C(s,t)) (3) 9n(s,t) _ u at a t (C(s,t)) y T h u s t h e r i g h t member o f 99 3g D - / * ^ ~ 3D, 't (1) d s = is ag D - / vf-iir a n d we o n l y h a v e t o p r o v e t h e (4) w / ^ x d y 7 TR . 9y d y t To prove = ^ ( f formula dy-|n x) d ( 4 ) we c o n s i d e r t h e e x p r e s s i o n c p d x d y as a C°° 2 - f o r m on 7 S i n c e a 2 - f o r m on 1R i s a u t o m a t i c a l l y c l o s e d ( i . e . d ( c p d x d y ) = 0 ) -36- and hence e x a c t (IR = a dx + b d y CO being simply connected), there (a = a ( x , y ) , b = b ( x , y ) ) such t h a t T = ]R/Z (the range of the v a r i a b l e s ) . Stokes' formula at the f i r s t / cp dx d y = 4r D, j [dx + b - 3 + s t e p , we g e t b ( C ( 2 3s3t 3s3t 3t 3S ds + / ¥ n 3s3t 2 , t ) ) % ^ s ^3x * 3 t f 3y 3 t 3s 9x t 13? ( ds 3n 3n 9 ^ "3? ' "3t L ? ) ¥ D r S = 9U ^ 3s 3x 3t 3s. 3s /95 J ; M 3y 3 t 3s J 3y * 3 t 3 s 3y 3t ¥ I ^ * "9T * v J.. ^ 9t 3t 8s' a ( t h e map <; = ( £ , n ) is a continuous differentiate ) This proves Theorem and c ( « , t ) function of 1. ds s * t t. assumptions is a diffeomorphism from the above computations with respect to ; t is of class C It also follows 3y ' 3 t 3 s . J 3n . > " W x 3x * 3t ds 9t d { The above computation is v a l i d under the g i v e n r e g u l a r i t y (1) using 2 ? 3s3t / T Then, t 2 9 / T i.e. / a dx + b d y 3D i ( d s , t ) ) % ^ dt s u c h t h a t da) = c p d x d y , = ip . Now, l e t 4r on ]R i s a C°° 1 - f o r m ¥ ->- 3 D ) . t h a t t h e r i g h t member and t h a t hence / cpdxdy ^ t of is continuously -37- (B) •» (C) b. T - > E S s a t i s f i e s (B) a n d c h o o s e r , R , T > 0 s o t h a t D c:c= D a n d D <=<=B , a n d l e t ft = B . T h e n EFT Theorem 2: Suppose ( a , b ) 3 [0,T] c (a,b), for all TE[0,T] N T Q p T R a n d [ 0 , T ] 3 t -» D. E R „ satisfies , r D K T, N R (C) T R . i Further, t = / g 0 u dt n T (a v e c t o r - v a l u e d defined 9D ( z ) = u^EHGCFT) o c c u r r i n g i n (C) i s the function i n t e g r a l ) , where g i s t h e "smoothed o u t G r e e n ' s n function" by H ^ T ] / 9 D ( Z » C ) D A ? = r g (z) D + loglzl - -^p—y- / l o g I z - c I da^ for z £ B g (z) z D E D p ^ B Z E ft v Proof: — — — We f i r s t D c=<= D c=cz B r t Now ^ fort£[0,T]. R to prove that have t o prove t h a t D <= < 0 9 n on D. E J L ^ t K , r Since B <=<= D r for X < t 3D so t h a t f o r m u l a t for Q and r D TE[0,T], i.e. Djccz B it R that suffices . ( 1 1 . 1 1 ) shows that / cp d x d y > 0 D t f o r a l l cpGC'TQR ) s u c h t h a t function of / cp d x d y < D t, X t Thus / cpdxdy is a non-decreasing D i.e. / cp d x d y D. cp>0. for X < t , t -38- 2 oo for all cp£C (]R ) with c larity requirements D r E F I T R for ip>0. It i s e a s y t o see ( i n v i e w o f t h e on 3 D ) t h a t t h i s implies t h a t D c = D t t£[0,T] is T for t regu- x<t. Thus proved. i N e x t we h a v e g EHG(ft) is continuously d i f f e r e n t i a b l e n due t o t h e r e g u l a r i t y and so D ^ c c ft , Now l e t A t u t on t = / g 0 n ( D t T Thus, E S ) . implies 1 g £ H n dx (ft), g ^£H^(ft). N be d e f i n e d b y ( 1 1 . 1 3 ) , i.e. ( T E T O . T ] ) . to complete the proof o f Theorem 2, t h e r e are t h r e e First n i n a l l ft , i s bounded n 3D ft^D^ 2 to prove. t = 0 u GHj(fi) Then in o r d e r u assumption f o r g^ g is continuous , and a t 3D. Vg t + -\- ^'l^j\ \ = . In f a c t i n ft ^ 3 D things that , T and t h e n t h a t (11.14) and ( 1 1 . 1 5 ) ( 1 0 ) means b y d e f i n i t i o n hold. that t <u ,P) T = / <g ,P> n 0 -1 for all 1 (ft) = H G ( f t ) . P £ H 1 that the function (see the l a s t tainly written (u ,Acp) = ^<g t i.e. using [0,T] It will 3 x -+ ( g f o l l o w f r o m t h e c o m p u t a t i o n s t o come , P ) E ]R n p i e c e o f t h e Remark on p. 1 -1 D (9) S i n c e A : H G ( f t ) -> H ,Acp) d x for all is continuous 40 f ) , T exists. t dx x (ft) f o r each P E H ^(ft) so t h e i n t e g r a l i s an i s o m o r p h i s m , tp£H (ft) Q in (11) ( 1 1 ) c a n be cer- -39- 1 ( D " x D " X t 2 0 T r (for prove D d s - = ^ - ^ t 3 -X D ( 2 d T tp£C~(ft). ( f o r veH^n)) a 1 1 Green's . (second) formula gives d s " i ; t = , \ V A / k p , \ = t t D 0 M = ( 1 1 . 1 1 ) we g e t t J < P = /( D 0 h~ Do. 7 T t 3 9 /cp-g ~3l 3D P n 1 = s A t p ) % Combining t h i s w i t h t = ( 1 3 )for \ a u ; ' ^ t u t p > tp£C"(n)) 8 <X ' x We f i r s t 1 Z '"nrTT D t D T ? r ds)dT * *TFT ]D ' r r x c p > i + 0 C % T ' A c p ) d x A Thus ( 1 3 ) is proved f o r tp£C~(ft) . To extend i t to a l l tp£H (ft) 0 j(q~ ,Atp}dx o f ( 1 3 ) d e p e n d 0 T c o n t i n u o u s l y w i t h r e s p e c t t o t h e H g - n o r m on tp ; f o r C ( ^ ) i s dense in we n e e d o n l y t o p r o v e t h a t t h e r i g h t member 1 c 1 H QJ (( Q ) a n d tT hH eI l e f t member o f respect to ( 1 3 )obviously 1 is H -continuous with Q tp We h a v e t /<g D t t , A t p ) d x | •= | / ( g , , t p ) d T | < J D O x N|| O • / | | G 0 II D x dx x O | (g x Q t , t p ) [ d x < / || G O X Q || H • IM|- 1 Q H 1 Q dx -40- and t h u s i t i s enough to prove that t / II 9 N 0 x u II dx < » . */ T o p r o v e t h i s we e s t i m a t e ||g n t u II3D " 3 D t 1 , ^ 2 > x V ( "9D D § ft t 93 } L x / g"n 3D • \-% { ' } t A ( '. 9 D " 3 D x ] t x D ds T = - / t g 3D '—7r=^- n D 9g D t ds < max ' 3D 3 n g • (- n D t G Du || n u 0 bounded f o r — D ^ ds) 3 n X X t < g n / 3D X • max 3D x - g n " / 9g 3 n t " u = 33 D ^ °t Since g IIg x<t Q D X 2TT || . for T H (ft) X 9g = n ft t - 2 - g for n te[0,T] this shows that T < 2Tr«max g " 3D T n Q te[0,T] < for all 0 0 te[0,T] . In p a r t i c u l a r ||g || i s t n U and so (15) is true. t / g dx d i d 0 x e x i s t , t h e n i t w o u l d be t r i v i a l l y t r u e t h a t t h e r i g h t member o f ( 1 3 ) d e t p e n d s c o n t i n u o u s l y on c p . A s u f f i c i e n t c o n d i t i o n f o r / g dx t o e x i s t Remark: I f we k n e w a p r i o r i that the vector-valued integral n n i s t h a t t h e map [ 0 , T ] 3 t - > g n 'We a r e t h e n u s i n g t h e f a c t , D cD, for x <t . x t 1 eHg(ft) be c o n t i n u o u s already proven 0 (see ( p . 37-38 ) T [ 1 8 ] , p . 73 f ) . that -41- It seems v e r y reasonable that this i s the case but I h a v e no p r o o f f o r I t m a y , h o w e v e r , be s e e n f r o m t h e c o m p u t a t i o n on p . t + cjp is continuous from the l e f t , i.e. that t Moreover, it follows f r o m p . 39 that 40 a t least CJQ -> g^ a s x t it. that i ^ t . t + i is weakly continuous, t i s c o n t i n u o u s f o r each p e h H ( f t ) . In f a c t , from u i.e. that t -* ( g ,p) n t u \ { M ~1 = D we s e e t h a t t <g n u ( p = Atp, t p e c T ( f i ) ) , continuous " S x i D ' l p > ,p) i s c o n t i n u o u s f o r a dense set o f p:s t s i n c e t h e f i r s t t e r m i n t h e r i g h t member o f by a s s u m p t i o n then f o l l o w s N O ( (p. automatically 22 ) , and t h e c o n t i n u i t y f r o m t h e b o u n d e d n e s s o f ||g (End of Remark.) It remains from (10) for all || D (16) (t£[0,T]). to prove (11.14) and ( 1 1 . 1 5 ) . g^ >0 (11.14) follows immediately . T / u . ( 1 - x t (11.15) first ) = <u ,1-x D t But { p = 1- x observe t > = / (9 t 0 D t by c h o o s i n g in D (11) that .1-X D D T >DT t . now % > " 1 T since V t D T C = I (ft) Z (now p r o v e n ) , s i n c e To prove p€ H is -1 § D • ( 1 " D X FTT ( p . 37-38 ) + ) = / n t % - 0 f ° r T e C 0 » t ] ft^-D^.T and g D = 0 outside . Thus • -42- / (g O ,i-x D >dr = D x t and ( 1 1 . 1 5 ) is proven. This finishes - c the p r o o f o f Theorem 2. ( C ) => ( D ) Let r,R,T,ft,D Theorem 3: t t t = t + ^t be t h e f u n c t i o n s d e f i n e d b y Proof: (D2) u G HJ(A) T satisfies ( C ) and (11.13), (11.43) let and ( D 1 ) a n d [ 0 , T ] 3 t -* v e H j ( f t ) t T h i s was p r o v e d a l r e a d y on p . 30 - 1 < 0 , a n d ( D 1 ) «* ( D 2 ) i s n u satisfies r . sisted of replacing the equality X R • Then [ 0 , T ] 3 t satisfies be a s on p. 3 0 . t t u Q S u p p o s e t h e map [ 0 , T ] 3 t -* D e f L u ,^ ,v eHj(fl) v o ( t h e s t e p ( C ) => ( D 1 ) j u s t con- i n ( 1 1 . 1 3 ) b y an i n e q u a l i t y b a s e d on obvious). t A l t h o u g h o b v i o u s we f o r m u l a t e t h e e q u i v a l e n c e b e t w e e n ( D 1 ) a n d as a s e p a r a t e (D2) theorem. •i Theorem 4: L e t cessarily u^v^^eH^f!) d e f i n e d by ( 1 1 . 4 3 ) ) . (D1) i f and o n l y if be r e l a t e d b y v Then t = u t + if> t [0,T] 3 t-» u e Hj(n) [ 0 , T ] 3 t -* v . e H ^ ( f i ) t satisfies (D2). (^ t not satisfies ne- -43- d - (D) * (E) Let r,R,T,ft,Dg and be as on p. 3 0 . T h e o r e m 5: (i) t h e map [ 0 , T ] 3 t - » u € H J ( « ) s a t i s f i e s t satisfies (ii) if it ( E 2 ) i f and o n l y if it (D1) . t h e map [ 0 , T ] 3 t - > v satisfies ( E 1 ) i f and o n l y t e HJ(ft) s a t i s f i e s (D2) . Proof: ( i ) «- : S u p p o s e t -> u / u -(Au + t to\> ) t t satisfies < 0 = J u -(Au t ( D 1 ) . T h e n , b y (11.47) a n d (11.49) , +A^ ) t t • 1 for all ueH (ft) with Q Au + < 0. Thus < 0. Since (by subtracting / u «A^ ) t t / u »A(u - u ) < 0, t t or / Vu «V(u - u ) > 0 , t t for all ueHj(ft) s h o w s t h a t t -* u ( i ) => : S u p p o s e with t Au + A i p t for all ueHg(ft) (11.58)). t -* u^ s a t i s f i e s t with t (E1). this Then +A^ ) t Au + A i ^ < 0 . Here the c h o i c e u = is > 0 , while the choice Hence (11.57) i s (11.48) satisfies (E1). / u «(Au + A^ ) < / u «(Au t t ((17) is just a reformulation of s h o w s t h a t t h e r i g h t member o f ( 1 7 ) u = 2 ( u ^ + 4^) - i j ^ s h o w s t h a t i t i s < 0. -44- / U «(Au t + A^ ) t = 0 . t Writing p = Au + A ^ and u s i n g t (18), (17) becomes / u -p < 0 t for all p e H (ft) T h i s shows u t with p < 0 . _ 1 that > 0 . Now ( 2 0 ) , (11.57) and ( 1 8 ) c o n s t i t u t e t h e c o n d i t i o n s h a v e p r o v e n t h a t t -» u ( i i ) <= : S u p p o s e / ( v - i|» )«Av t t -> v < 0 = t satisfies (D1) satisfies t /(v -^ )-Av t t i n ( D 1 ) a n d s o we . (D2). T h e n , by ( 1 1 . 5 1 ) and (11.52) t 1 for all v£Hg(ft) / V(v - v ) - W t for all that > 0 t veHg(ft) with S u p p o s e t -* v / (v-^ )«Av t for all < t v > ip . t vGH^(ft) with (E2) / (v -* ).Av t t t = 0 t t < 0 , or satisfies t t (11.50) t h i s shows (E2). Then t v > ^ shows t h a t is . . ((21) s h o w s t h a t t h e r i g h t member o f f /(v-v )«Av Since (11.59) t /(v -^ )»Av v = 2 ( v . - X/J.) + ip Thus T , t -» v^ s a t i s f i e s ( i i ) => : v > 4> . with it is (11.60)). (21) is > 0 , is < 0. Thus T h e c h o i c e v = 4> while the choice T -45- T h u s , w i t h tp = v - ip (23) / tp»Av Av i p £ H (ft) with cp > 0 . T h i s shows that < 0 . + Since (11.59), ( 2 4 ) and (22) c o n s t i t u t e t h e c o n d i t i o n s we h a v e p r o v e n t h a t This finishes e. becomes < 0 t for all (24) (21) t t -» v t satisfies (D2) (D2) . t h e p r o o f o f Theorem 5. E x i s t e n c e , u n i q u e n e s s and r e g u l a r i t y o f s o l u t i o n s t o Let r,R,T,ft,Dg t h e o r e m we s h a l l in and ^ recall t be as on p . 3 0 . some g e n e r a l (E) Before formulating the regularity next results. i Let 2<p<°° are (25) cp£Hg(ft) . Then the f o l l o w i n g implications true: A cp e L ( f t ) => cp e H p Here that cp£C ' ( f t ) a its first with exponent sup and l e t z,ceK 2 > (ft) P means t h a t cp i s c o n t i n u o u s l y d i f f e r e n t i a t e order partial derivatives a (0<a<1), i.e. z - ? a f o r each compact are l o c a l l y Holder in y-derivative and continuous < + oo K c ft , a n d s i m i l a r l y f o r t h e ft Sep 3y -46- The f i r s t operator A implication in (25) is a consequence of the f a c t t h a t is uniformly e l l i p t i c . ( [ 1 2 ] , Theorem 4 . 1 0 , p. 34). T h e s e c o n d i m p l i c a t i o n f o l l o w s f r o m a w e l l - k n o w n lemma b y ( [ 1 2 ] , Lemma A 9 , Aip £ L ( f t ) f o r a l l and i/j e C ' ( f t ) f o r a l l p t (11.43) of ^ we s e e t h a t p < ~ a n d s o , b y ( 2 5 ) , ye Thus 1 Sobolev p.56). Now f r o m t h e d e f i n i t i o n t a A^ eL°°(ft) u n i q u e n e s s and r e g u l a r i t y T h e o r e m e 1.1 in [ 2 ] . concerns the f u n c t i o n v^ H »P(ft) for all 2 theorem f o r solutions of v a r i a t i o n a l More p r e c i s e l y , the part existence, inequalities, of Theorem 6 which i s a d i r e c t c o n s e q u e n c e o f T h e o r e m e 1.1 D e s p i t e o f t h i s we w i l l u^. in include a proof o f Theorem 6 h e r e . We p r o v e is very easy to i s n i c e t o be s e l f - c o n t a i n e d t o s u c h a l o w p r i c e ; prove a n d we p r o v e o f s o l u t i o n s b e c a u s e we h a v e a p r o o f o f t h a t p a r t w h i c h i s l e r and more e l e m e n t a r y t h a n t h e s t a n d a r d p r o o f s and w h i c h perhaps i s T h e o r e m 6: (i) The v a r i a t i o n a l u , t v eHj(fi) t inequalities (te ( E 1 ) and ( E 2 ) have u n i q u e u t (iii)u , t a n d v^. a r e r e l a t e d b y v £H ' (fl) 2 t for all (This p solutions [0,T]). ( T h i s depends o n l y on t h e f a c t t h a t ^ (ii) for all [2] f o l l o w by t h e n a p p l y i n g T h e o r e m s 4 and 5. e x i s t e n c e and u n i q u e n e s s o f s o l u t i o n s because t h i s regularity p < °° a < 1 . while those parts concerning and i t . t Theorem 6 below is e s s e n t i a l l y a special case of a standard e.g. the £Hg(ft).) v^. = u^ + i j ^ . p < <» . I n p a r t i c u l a r a < 1 . p a r t d e p e n d s on i>. e H ' ( f t ) , a l l 2 p p < °° . ) u , t v £C ' (ft) t 1 a simpnew. -47- Proof: (i) follows from standard Hilbert f o r example. Fix te[0,T] K = {u £ Hj(n) : Au + A i p t and < 0} space t h e o r y . Consider (E1) let . i Then K is a closed convex set and t h a t c a n be it in Hg(ft). That i t formulated tp€Hg(ft) (u,cp) > - ( ^ , c p ) for all cp£Hg(ft) t (28) shows t h a t K i with cp > 0 , with cp > 0 . is the i n t e r s e c t i o n of a set of c l o s e d h a l f s p a c e s and so i s c l o s e d ( w e a k l y and The c o n d i t i o n € K i n ( E 1 ) now b e c o m e s t > 0 for all u£K (K b e i n g c l o s e d and c o n v e x ) •i u £Hg(ft), t Find namely t h a t u. e K such t h a t u ( w e a k l y and strongly) strongly). (for fixed t£[0,T]) z Thus (i) (ii) follows , this condition i n f ||u|| . ueK is proved ( w i t h a s i m i l a r argument f o r Alternative u t (ii) it is s u f f i c i e n t a n d v^ b e l o n g s t o 1: F o r t h e f a c t t h a t t o p r o v e t h a t one o f H ' (ft) 2 . p We g i v e t w o v £H ' (ft) t 2 < p < ° ° ) we may r e f e r t o t h e e x i s t i n g equalities (E2)). by c o m b i n i n g T h e o r e m 5 and T h e o r e m 4 . In view of functions i s s a t i s f i e d by a u n i q u e w h i c h s o l v e s t h e minimum norm p r o b l e m t ||u.|| = z (iii): or and (u-u ,Uj.) and obvious t for all t is i s c l o s e d f o l l o w s f r o m t h e f a c t t h a t t h e c o n d i t i o n Au + AiJ> < 0 <Au + Aif^.cp) < 0 u is convex 2 p alternatives. (whenever ^ literature the e H ' (ft), 2 on v a r i a t i o n a l o f the kind ( E 2 ) , f o r example [ 2 ] , Theoreme 1.1. p in- -48- Alternative 2: We c a n p r o v e t h a t u^£H ' (ft) p by a r a t h e r s i m p l e and e l e m e n t a r y a r g u m e n t w h i c h a l s o m i g h t be o f i n d e p e n d e n t i n t e r e s t . g o e s as follows: We w a n t t o s h o w t h a t i f then the s o l u t i o n Au + Ai/; < 0 lfieHj(fi) n H ' ( f i ) 2 uGHg(ft) f o r some 2 < p < ° o p , of , - /v(u'-u)«Vu > 0 for all U'GHJM A u ' + Aip < 0 with also belongs to H ' ( f t ) . 2 ((31) p is (E1) end, consider the following a u x i l i a r y t h e c o n d i t i o n s on u a r e more i Find r It ueHg(ft) min(0,Aip) variational inequality, To in this which restrictive: satisfies < Au + A^ < 0 , - /v(u'-u)«Vu > 0 with which for a fixed t e [ 0 , T ] . ) min(0,AiJj) for all u'eHj(fl) < A u ' + Aip < 0 . S i n c e , j u s t as f o r (E1), t h e c o n s t r a i n t s on u (and u') above delimit A a c l o s e d c o n v e x s u b s e t o f H g ( f t ) , (32) Now t h i s u solution a priori are of the form belongs to f^ < Au < f 2 can show t h a t t h e s o l u t i o n o f (31) we a r e d o n e . (D1), has a u n i q u e s o l u t i o n H ' (ft) since the with u of (32) 2 conditions p f ,j ^ € L (ft). p ueHg(ft) Therefore u on i f we i s t h e same as t h e s o l u t i o n A n d t o s h o w t h i s we n e e d o n l y show t h a t . of satisfies i.e. 'u > 0 - Au + tup < 0 /u«(Au + A^) = 0 since these conditions characterize t h e s o l u t i o n o f (31) (Theorem 5 ( i ) ) . -49- U£HQ(Q.) Thus l e t u satisfies (33) - (35) above. / u « ( A u ' + AI/J) for all be t h e s o l u t i o n o f ( 3 2 ) a n d we s h a l l < / prove that F i r s t we g e t f r o m ( 3 2 ) t h a t U»(AU+AIJJ) u' G H Q ( ^ ) min(0,AI(J) < A u ' + AI(J < 0 , with min(0,AIP) < p < 0 . p = 0 in (37). This with or / u«p < / u«(Au + AIP) for all peH~ (ft) 1 First choose gives / u«(Au + AIP) > 0 . Then P choose min(0,A\P) on N Au + o n ft ^ N = AIP where N = {zeft : u ( z ) < 0} (Observe that since u£H ' (ft), 2 u p i s a continuous f u n c t i o n , so t h a t i s a w e l l - d e f i n e d o p e n s e t i n ft . ) / u *min(0,AIJ;) N < / u*(Au + A I P ) , We g e t or N / U»(AU + A^ - min(0,A^)) > 0 S i n c e A U + M> - m i n ( 0 , A I P ) > 0 N A U + AIP - m i n ( 0 , A I P ) AU < 0 on N. =0 on and N. U < 0 This shows on N that (42) forces N -50- B u t now u =0 on 3N U 3ft i s c o n t i n u o u s and b e l o n g s t o u > 0 that on N I (by the d e f i n i t i o n of Hg(ft)). Therefore Au < 0 N . Comparing w i t h the d e f i n i t i o n o f i s t h e empty s e t . N, and s i n c e N on we m u s t u N implies conclude Thus u > 0 . Thus of (33) is proven. ( 3 2 ) ) , and c o m b i n i n g ( 3 4 ) we know f r o m t h e b e g i n n i n g (33) and ( 3 4 ) w i t h ( 3 8 ) y i e l d s (it is (35). 2 T h i s ends t h e p r o o f t h a t t h e s o l u t i o n o f and c o m p l e t e s t h e A l t e r n a t i v e This also finishes Remark: Observe t h a t , equivalent (31) belongs to H ' ( f t ) , p 2 program. although i t is t r i v i a l that (D1) and (D2) that statement ( E 1 ) and ( E 2 ) it (ii) o f Theorem 6 i s not completely Minimize ||v-^ || when Minimize ||v|| when t (=v Av < 0 t = u ^ + I ^ ) : •i (veH (ft)) Q 1 v > ty. ( v € H ( f t ) ) n . the obvious. variational says f o r example t h a t the f o l l o w i n g p r o b l e m s h a v e t h e same s o l u t i o n it ( E 1 ) and (E2) a r e e q u i v a l e n t under I n t e r m s o f t h e minimum norm p r o b l e m s a s s o c i a t e d w i t h t h e equalities are v ^ = u^ + I J ^ ( a s s t a t e d i n T h e o r e m 4 ) , is not a complete t r i v i a l i t y i.e. D t h e p r o o f o f Theorem 6. via the r e l a t i o n same r e l a t i o n , part two -51- f - ( D ) => ( C ) . By t h e T h e o r e m s 4 , 5 a n d 6 we know t h a t solutions u^ ferentiate and v t (t£[0,T]), (D1) and (D2) have that these are continuously f u n c t i o n s and a r e r e l a t e d by v^ = u + ^ t . result dif- Our goal is to prove that these solutions give r i s e to a solution of preparation for this unique (C). now As a ( T h e o r e m 9 ) we n e e d t w o l e m m a s , Lemma 7 a n d Lemma 8 . Lemma 7: (i) i L e t u £ H g ( f t ) be t h e s o l u t i o n o f ( D 1 ) . Then u < u 1 ueHg(ft) which s a t i s f y Au + A i p < 0 a n d u > 0 . t t for all t (ii) Let v eH t i vtHg(ft) Remark: first (i) Q 1 (ft) be t h e s o l u t i o n o f ( D 2 ) . which s a t i s f y says that conditions, v > ^ and (ii) < v that satisfy is a consequence of however, (ii). be some f u n c t i o n include a proof here. i n H '^(ft) 1 ^eHg(ft). P r o o f o f Lemma 7: the functions u obviously satisfying the conditions in ( i i ) , in In t h i s proof the S i n c e we know t h a t t h e f u n c t i o n s the r e l a t i o n v = u + ^ (i i ) . (11.49). or at ( f o r some p < <=°), a l t h o u g h Lemma 7 i s r e s p e c t i v e l y a r e r e l a t e d by We p r o v e function, Due t o t h e i m p o r t a n c e o f Lemma 7 be a s s u m e d t o be t h a t f u n c t i o n d e f i n e d b y ( 1 1 . 4 3 ) , satisfying two ( m o r e o r l e s s ) a s p e c i a l c a s e o f Lemma 1.1 \p. w i l l tween the (ii). we w i l l , (ii) all the t h i r d c o n d i t i o n , f o r us for arbitrary for (11.47) and ( I I . 4 8 ) , i n (D1) t h e r e i s a s m a l l e s t o f Lemma 7 i s [ 1 3 ] , and ( i ) t Av < 0. in the class of functions namely t h a t f u n c t i o n which a l s o s a t i s f i e s -Similarly for Then v v ^ = u^ + y u^ a n d v t function least true in ( i ) ( T h e o r e m 4 ) , and since s e t s up a o n e - t o - o n e c o r r e s p o n d e n c e the conditions it suffices i n ( i ) and t h o s e and be- functions t o p r o v e one o f ( i ) and (ii). -52- With v t a n d we s h a l l I(v ) and This as i n t h e s t a t e m e n t o f t h e l e m m a , p u t p r o v e t h a t w > 0. = {zeft t v : v (z) . t is a w e l l - d e f i n e d closed set in and so ( T h e o r e m 6) and ft s i n c e , by a s s u m p t i o n , ^ v^ a r e c o n t i n u o u s Denote by suppAv^ t h e s u p p o r t o f Av SUppAV^ c= I ( v ) (44) shows ft Everywhere t Since - ( v 3ft t in - (v ^ I(v ) t ft on v > - t I(v ), 3(ft x (by t t it t that . (v t - ip ) t . n ( i n some Kv )) c: 3ft u I ( v ) t e t now be t h a t m i i n m u m . (45) t o g e t h e r with (47) imply w > 0 in p r i n c i p l e f o r superharmonic f u n c t i o n s ) t h e minimum p r i n c i p l e n o t n e e d be a n i c e f u n c t i o n b u t i s j u s t an e l e m e n t o f H ( f t ) . Q follows. and this i n a l l ft . H o w e v e r , some c a r e i s n e e d e d i n a p p l y i n g p r o c e e d f o r e x a m p l e as a n d on sense) then gives the desired conclusion, w > 0 w i n ft v - ip^.) i s a c o n t i n u o u s f u n c t i o n w h i c h v a n i s h e s on I ( v ^ ) The argument w i l l ft ^ * ( t ) >0 T h e n , v^ - ip we h a v e - ^ ) t (46) shows t h a t w > 0 P that in w = ( v - 4> ) H -' (ft) . t Aw = A v < 0 G a s a d i s t r i b u t i o n on ft ( s o , t being a non-negative continuous f u n c t i o n which is f r o m ( 1 1 . 5 1 ) and ( 1 1 . 5 2 ) t functions. b y d e f i n i t i o n , s u p p A v ^ i s a r e l a t i v e l y c l o s e d s e t i n ft ) . follows v^, Let = ^ (z)} t w = v - since We c a n -53- C h o o s e an a r b i t r a r y I(v ) u 8ft t e - (v IP ) > T ft such 0 in Then t h e r e E 0 > in < 0 in ft \ I(v ) (by ( 4 6 ) ) we h a v e By (45) , t i n a n e i g h b o u r h o o d o f t h e c o m p a c t s e t ft V N ( C ft \ ( 4 9 ) a n d ( 5 9 ) now show E 0 > d i n a r y minimum p r i n c i p l e f o r C family of regularizations of f o r e x a m p l e by a p p l y i n g t h e superharmonic functions w + E where Since h (z) E > 0 = in P (51) was a r b i t r a r y , a n d Lemma 7 i s proven. Corollary Let IP, IJ/eHj(ft) u,u' 7.1: and v , v ' choices be t h e s o l u t i o n s = IP, Y 1 w h e r e h £ C™( F ) Z n H ' (ft) 2 of p and , h > 0 a n d / h = 1) . some p < O O ) , a n d . If AIP < AIP' then u < u' (ii) If IP > I P ' AIP < A I P ' ) (iii) (= ( i ) (or and ( i i ) if . then v > v' . combined) I f AIP < AIP' then u' - (IP - IP') < u < u 1 and letting (D1) and (D2) c o r r e s p o n d i n g t o (i) v 1 + suitable we c o n c l u d e t h a t w > 0 i n (for (IP - IP') or- P O h ( / P ) , t o some ( s a y t o (w + E ) * h , O N O , I(v that i n ( a n e i g h b o u r h o o d o f ft ^ N) U N = ft , 2 P of N and i n p a r t i c u l a r w + N N . ( i n the sense of d i s t r i b u t i o n s ) . A ( w + e) is a neighbourhood that w + E > e - ( v ^ - IP^.) e v e r y w h e r e Since w + - t in E > 0. > v > v' . let the ft, -54- Proof: (i) (ii) We h a v e A u ' + Aip < A u 1 lemma g i v e s = ip, ( w i t h ip We h a v e v > ip > ip ( w i t h i|> = ip', v t t + Aip and 1 and u^ = u ) A v < 0. = v ) v 1 t < 0 1 u < u' Thus < v . 1 u ' > 0. Thus ( i ) of the . (ii) o f t h e lemma gives (Aip < Aip' i m p l i e s ip > y' as 1 ip, ip' e H g ( f i ) 28.10 (iii) (i) for b y a weak maximum p r i n c i p l e . v < v ' + (ip - i p ) , w h i c h (ii) i s the second p a i r of i n e q u a l i t i e s pair i s t h e n o b t a i n e d by s u b t r a c t i n g Let r, R, T , ft, D Q and ip in ( i i i ) . t be a s on p . 30, t £ Hg(ft) be t h e s o l u t i o n o f (D1) [0,T] 3 t - » t £ Hj(n) the s o l u t i o n of ,J A8 = - (D2). Further let , Xin r Then, for u v t Proof: A ^t = < u T + 2ir(t-T)'9 > V t r T < t, - 27r(t-T)*6 < u > t v and t t From X D, 0 1 + 2irt--n D 7 r D x 1 - r = 2TTt'A0 0 we g e t for x < t and ip T - ip t = 2ir(t-x)9 Now C o r o l l a r y 7.2 . follows from ( i i i ) first let and 1 f u n c t i o n d e f i n e d by The ip . [ 0 , T ] 3 t -* u v together 1 with 7.2: Corollary example.) g i v e s u + ip < u ' + ip, i . e . Corollary See [ 2 0 ] , of Corollary 7.1 . e e H j ( f t ) be t h e -55- Corollary D c c D r 7 . 3 : L e t r, 0 c c c D R , T , ft be a s on p . 3 0 , l e t a n d l e t i|» , 4>' r e s p e c t t o Dg a n d Dg' r e s p e c t i v e l y . corresponding u < uj. t solutions and v of t€ [0,T] Proof: S i n c e Aip^ < Ai|^ W i t h r, 3 t -* v be t h e s o l u t i o n I(v ) t D and ( i i ) v ^ , vj. be the Then ft, te[0,T] of Corollary Dg a n d ^ the c o r o l l a r y follows 7.1 . a s on p . 3 0 , let HJ(A) of ( D 2 ) and = {z eft : v ( z ) t = Dg U (ft x t for all R, T , e t ( D 1 ) and ( D 2 ) . u|. a n d . immediately from ( i ) [0,T] u^, Let with > vj. t for all Lemma 8 : DQ s a t i s f y Q be d e f i n e d b y ( I I . 4 3 ) t R D , put = ip (z)} , t l(v )) . t Then suppAv^ c (ft ^ D g ) n I ( v ^ ) D^ c ft ^ s u p p A v ^ where in both and , inclusions the d i f f e r e n c e - s e t s have measure zero. Moreover, A v t = Proof: all " X(ft-D )nl(v ) 0 Recall p<°° . = t ( p . 45-46 Thus i p , v defined closed set t in x D " t 1 • and Theorem 6) t h a t ^ , t are continuous t ft and D t functions, i s an o p e n set. v £H ' (ft) 2 t I(v ) t p for is a well- -56- Observe next that the d e f i n i t i o n (D2) f o r since the solution of and so I(v ) ip^, v = Ai|>. (58) t G H ' ^P ( f t ) v^=ty^ We c l a i m t h a t Av. t= of 0 is consistent for t = is a.e. i m p l i e s tthhaatt Aip. on I ( v ^ ) and w h i c h w i l l on and Av t are n o t be p r o v e n Suppose u G H ' P ( f t ) left. Then a l l 2 partial (1<p<°°) derivates in p a r t i c u l a r lemma, w h i c h i s Au=0 and t h a t u = 0 of order <2 a.e. I. i n H ^ ' P e v e r y such d e r i v a t i v e o f order on <2 f o r m o f an L - f u n c t i o n , a n d t o s a y t h a t non-trivial on a c l o s e d vanish almost derivative. set every- For a function have a r e p r e s e n t a t i v e i t vanishes p a.e. t o s a y t h a t a n y o n e , and t h e n a l l , o f i t s r e p r e s e n t a t i v e s in on a s e t means vanishes a.e. set.) F o r a p r o o f o f t h e a b o v e lemma we may r e f e r t o [ 1 2 ] , p . 53 . Two a p p l i c a t i o n s Applications o f t h e lemma t o u = v f o l l o w by combining suppAv t <= l ( v ) (58) t - ^ Av. < 0 iiD~r D x > 0 on D, r 0 - 1 ft v settles (58). w i t h the f o l l o w i n g , 27Tt • - r Lemma A . 4 , o f t h a t lemma y i e l d o u r l e m m a . Lemma 8 w i l l t p here. ( B y " d e r i v a t i v e " we a l w a y s mean d i s t r i b u t i o n on t h a t L -functions. I (v.) Lemma: I, Aipg<0), implies is a consequence of the f o l l o w i n g w h e r e on (in view of V Q = ^ Q 0 = ft . n Now (54) D, 0 Now facts: -57- ( 5 9 ) was p r o v e n on p . 52 , D (together with Aip = A v t t hence by (63) Aip ( 1 1 . 5 1 ) and ( 6 1 ) is (11.43) imply that almost everywhere on I ( v t ) w e n a v e < 0 , (61) = - x^^ t is cz D g ) . r (58) and (60) (62) (60) D ( a . e . on I(v )) ( a . e . on I(v )) t hence ^ \ A = - ^ D Q In view of ( 6 5 ) (66) A v t " ft-D = X * I(v ) x Q Since (ft^Dg) suppAv t (59), fl I ( v ) cz ( f t ^ D ) Q if E = " (ft-D ) X n I(v ) t ]R closed in ft , (65) shows (56) i n (66) has measure z e r o . then suppx n E <= E a n d E ^ s u p p x i s o b t a i n e d f r o m (55) by t a k i n g t and (57) is D.. r, R, T , (67) [0,T] 3 t -* u t e H^ft) (68) [0,T] 3 t - t e v Hj(ft) ft, and (GeneE has Dg a n d ip t complements (65) above t o g e t h e r T h i s p r o v e s Lemma 8 . Theorem 9: With that zero.) (and using the d e f i n i t i o n o f D ) , the d e f i n i t i o n of * t that the d i f f e r e n c e - s e t is proven. ft . Lebesgue measure (55) n I(v ) Q is a closed set in n-dimensional Thus (64) shows t h a t i n a l l is r e l a t i v e l y t It also follows rally, t t as on p . 3 0 , let with -58- be t h e s o l u t i o n s o f (D1) and (D2) r e s p e c t i v e l y ( s o t h a t v^ = u^ + i ^ ) . Define D t = D U (n^I(v )) Q = D t for t £ ( 0 , T ] . suffices Then, if that R [ 0 , T ] 3 t -» D U { Z £ ft : u ( z ) Q t R i s l a r g e enough o r > 2T + p , i f t a R ) > 0} D Q c B p T r (C). in (C) is identical u^. ( = v ^ - i f ^ ) a b o v e Proof: ——— F i r s t we m u s t p r o v e t h a t B cc D c c f B <=c= D^ with B t the Further, D. £ I L ^ t K , r (t £ [0,T]) R follows from r (it ) , t h e map i s w e l l - d e f i n e d and s a t i s f i e s that small enough the function "u^." a p p e a r i n g . for all t £ [0,T], i.e. . D c c DQ and r Dg C D^ . To prove Dj.c=c:B we s h a l l a p p l y C o r o l l a r y 7 . 3 . Choose p such D c=B <=<=B and l e t DA = B . T h e n D c c D c D A c c B , and ( J p R U p r U U R R that n D ip'^, u | , v£ with u^ < u | I'(vj.) c where IB , or = {z£ = B > 0 p ft: vj.(z) for t £ (0,T] t I = 2irt + I E I = ij^(z)} that is defined , 7.3 v^. - ip^ < v.j. - if^ . t Now we c l a i m (v!) t d e f i n e d as i n C o r o l l a r y (t£[0,TJ) I(v ) , where I ' ( v j J ft^T n by i.e. , . D we h a v e b y C o r o l l a r y T h i s shows that 7.3 -59- Once ( 7 2 ) is proven PY = 2 T + P D = D t t (72) : u!(z) z = B X (for T E ( 0 , T ] (71) and (72) t h e n U (nM'(vj.)) Q is equivalent P B ^ Q P = B ~ X D A ~ 2 U T * ~ I L T T X D r and ( 7 6 ) f o l l o w s from (77). ((77) is a solution P to (A) is and s u g g e s t e d by t h e f a c t and hence t o ( B ) , IP' Thus t€[0,T] It GHJ(Q) (72) if 1 that u|EHG(ft) B = B P T = 2T + Av t which in view of (11.49) d e f i n e d by A ^ = t X D - " 1 + T d e f i n e d by (77) 2IRT ' i s p r o v e n , a n d s o we h a v e p r o v e n t h a t remains AIP P < 2 R , 2 to prove = X D t " (11.43) combined w i t h This completes DG<= B P = P DQ of and B E & R r solves D Q is (11.13). (77) . = B P .) for (C).*/ Lemma 8 ( 5 7 ) shows 1 (11.14) above. t h e p r o o f o f T h e o r e m 9. u^ g i v e n b y ( 6 7 ) X . . (11.13) - (11.15) */ With with 0 (D1) w i t h is ( C ) , t h a t t h e map t u | = / 9 R dx 0 P domain and t h a t t h e r e f o r e by Theorem 3 is a l s o easy to check d i r e c t l y + . R that x as i n i t i a l t «=<=B ' r Au <=D T u It that give = D U to proving and assuming > 0} = B P^ t - » B follow c a n be p r o v e d s i m p l y b y c o m p u t i n g t h e f u n c t i o n u { e x p l i c i t l y . 1 i t i s f o u n d t h a t u£ is the f u n c t i o n in HG(ft) f o r which In f a c t u c D t and t h i s A since U (J)NL(v )) Q will t < R ) To prove {z£ft D <=c:]DP is ( 1 1 . 4 7 ) , and (11.15) that -60- Corollary 9.1: _ _ _ _ _ _ enough (R Let r, R, T , ft and D be a s on n p. 3 0 w i t h R large u > 2T + p suffices, if DgC]D ) p . Then t h e r e e x i s t s a solu- tion [0,T] of 3 t -> D (C). t This e ^ R j r solution a distribution i s u n i q u e up t o n u l l - s e t s , f o r each t £ [ o , T ] . Moreover, u^ € H g ( f t ) be t h e f u n c t i o n a p p e a r i n g a s an e l e m e n t o f H ^ f t ) , D t = D for U { Z e ft : u ( z ) Q t€[0,T]. (In as let (C). Then (78) above (79) u^ r e f e r s u^ i s unique c a n be c h o s e n t o be to the continuous representative t The e x i s t e n c e of the s o l u t i o n Theorem 9 (combined w i t h the f a c t Theorem 9 a l s o For t = 0 (79) s a y t -» D (for (D1) is unique u t = 0 in t h a t case a solution of of (79) f o r (this u q solutions from (D1)). te(0,T]. follows from s u p p o s e we h a v e t w o s o l u t i o n s o f (11.13). t h e same \|> ) b y T h e o r e m 3 . 5 and 6 ) . Then Thus t distributions, of the since (Theorems immediately c a n be c h o s e n a s i n t -*• D | ( w h e r e D Q = D ) , a n d l e t the corresponding (D1) (78) f o l l o w s that there exists As t o t h e u n i c i t y , and T shows t h a t is true for example). u t u =u| t T h u s , a l s o by or almost everywhere. This and t and (11.13) (78), u^. £ H ( f t ) be Q uj. both solve since the s o l u t i o n (11.13), shows t h e u n i c i t y Xp = Xpi of as part corollary. Corollary 9.2: 3 t - satisfy (i.e. unique 1 S u .) Proof: [0,T] Xn. > 0} t all of and i n in i.e. (C). D ^D. T D t Let e X R j r Then, for x < t, has measure z e r o , o r D T <= D Xn T except for a 5 Xn x i t n null-set the d i s t r i b u t i o n sense), -61- Proof: Let u^ and by t h e s o l u t i o n v^ be t h e s o l u t i o n s (80) of (C) D t = D = D U e 9. : u ( z ) {Z T < t is 7.2 u < u T < t, for t showing t h a t 9.3: „ K i eft be t w o s o l u t i o n s (except Proof: and 9 [ 0 , T ] 3 t -* Dj. R > r of ( C ) , and suppose t h a t for null-sets) The p r o o f for all is similar t £ D Q <= D Q . Corollary 9.4: 3 t -> (a,b) (Unicity D , T to that of Corollary 9 . 2 , but with Proof: . of Then (A) or D t (A)) t (C). close to Dj. The u n i c i t y £ft t > t t^ = 0. we o b t a i n f o r chosen a r b i t r a r i l y 3 t -> D , solutions): implies the Suppose Q (t £ (a,b) (a,b)). s u i t a b l e c h o i c e s o f r, b) some t p £ By a p p l y i n g T h e o r e m 2 ( a n d T h e o r e m 1 two R, T > 0 ( T c a n be solutions R > r part of Corollary 9.1 c o m b i n e d w i t h t h e a s s u m p t i o n s on D^. a n d Dj. t h e n g i v e s t h a t This 7.2. ( B ) , and suppose t h a t f o r = Dj. f o r a l l We may a s s u m e t h a t in case of of of classical Corollary Dj. € S a r e two s o l u t i o n s = Dj. T h e n D^ c Dj. [0,T]. 7.3 used i n t h e l a s t a r g u m e n t i n s t e a d o f C o r o l l a r y [0,T] for Let [ 0 , T ] 3 t -» D , L t D^ c= D^ as w a s t o be p r o v e d . Corollary D zero > 0 } . t Now, b y C o r o l l a r y uniqueness = t Q Then the produced b y c h a n g i n g D^. w i t h a s e t o f m e a s u r e we c a n a s s u m e t h a t U (n^I(v )) Q (D1) and (D2) (as in Theorem 3 ) . p a r t o f T h e o r e m 9 shows t h a t , i f necessary, of corollary. = Dj. regularity for t £ [0,T] . -62- ( C ) «* 9- (H T h e o r e m 10: A map [ 0 , T ] 3 t -> D satisfies (C) ER t R > R i f and o n l y if it satisfies (F). Proof: =* : S u p p o s e ( 8 1 ) s a t i s f i e s (C). Since D. c c ft = D 1 it i s enough t o p r o v e subharmonic Let and u u in = 0 t continuous ? t£[0,T] ? cp £ H g ( f i ) fl H ( F ) which are D^. £ WQ{Q) t (11.61) f o r a l l for all D a.e. be t h e f u n c t i o n d e f i n e d b y ( 1 1 . 1 3 ) . an ft ^ D (since (by t (11.14) and ( 1 1 . 1 5 ) ) . Au^ £ L°°(ft)), i n p a r t i c u l a r 2 1 Now, l e t Then u Moreover, > 0, t u t is b o u n d e d ( a s u^ = 0 on 3ft), 2 cp £ H ' ( f t ) n H ( F ) be s u b h a r m o n i c i n D . . t h e n Acp > 0 o 2 ~ in D in the sense of d i s t r i b u t i o n s . M o r e o v e r , s i n c e Atp £ L ( f t ) , t h e 2 above p r o p e r t i e s o f u^ s h o w t h a t u « A c p £ L ( f t ) , u^« Acp = 0 a . e . on ft v. D. and hence / u . • Acp = 0 . U s i n g t h e s e f a c t s a n d a l s o ( 1 1 . 1 3 ) ftvD t t Z z t and t h e submeanvalue p r o p e r t y o f D /cp - /cp = ( x - X » D t 0 t Q = < u A t + 2irt n n D D <P> .-j^jx,,^. cp i n D = «P> = 1 = ( U j . , Acp) + 27Tt - -jjj—p (x = / u . • Acp + 2lTt • - — - y ft 'V Z »V> D / D = cp = r 1 = / D . • Acp + 2fTt • U t > 2rt Thus | J Z .-JPLJ -i-r-P V / D CP r / cp > 2irt • cp(0) (81) s a t i s f i e s (F) . > . r we g e t -63- *= : Suppose (81) satisfies (F). Thus /tp > 2-nt ' t p ( O ) /tp t D D 0 2 for every see t h i s /tp D - tp e H ( F implies /tp D t 2 ) which is subharmonic I D As we s h a l l presently Q /tp r' D r 1 2 f o r a l l tp G H ( f t ) n H ( f t ) L e t us a s s u m e Then . that 2 Tit '-r^-j > in ( 8 3 ) c a n be which are subharmonic ( 8 3 ) f o r a moment a n d d e f i n e in D t . U j . G H g ( f t ) by (11.13). written ( A u , tp) > 0 t 1 2 tp G H ( f t ) n H ( f t ) w i t h for all Atp > 0 7 ~ n 1 9 Hg(ft) n H (ft) (bijectively) in onto L (ft), (84) D.. Since A maps i s t h e same a s ( w i t h p = Atp) (u ,p) > 0 t for all p G L (ft) Since a l l u > 0 t (in The choice K * ( x t ft) 1 ) = t •(x D t in D t p G L (ft) . are allowed in (85) . p = XQ D " p > 0 non-negative ( and s o , s i n c e t h e Ju with 2 u - t'X 1 D is also allowed in t - > 1 integrand -D = 0• (85). This " ° ' in (87) is non-positive, gives we h a v e -64- This proves that the function u £Hg(ft) d e f i n e d by ( 1 1 . 1 3 ) t fies ( 1 1 . 1 4 ) and ( 1 1 . 1 5 ) ( = (86) and ( 8 8 ) ) . T h u s t h e map ( 8 1 ) fies ( C ) , a n d t h e p r o o f i s c o m p l e t e as s o o n as we h a v e d e d u c e d from (82). satissatis- (83) 2 2 F o r t h a t p u r p o s e o b s e r v e f i r s t t h a t t h e t e s t c l a s s H (]R ) f o r ( 8 2 ) 2 2 2 2 c a n be r e p l a c e d b y H ( f t ) s i n c e t h e r e s t r i c t i o n m a p p i n g H (TR ) -* H ( f t ) i s o n t o ( [ 2 0 ] , T h e o r e m 2 6 . 7 ) . Now l e t Atp > 0 i n D. a n d we s h a l l tp £ H ( f t ) ) outside in ID D^ but u n f o r t u n a t e l y Since in tp i s c o n t i n u o u s tp i n ft (as w h i c h c o i n c i d e s w i t h tp |D . T h i s f u n c t i o n is also p subharmonic i t d o e s n o t b e l o n g t o H ( f t ) s i n c e Atp w i l l be a meas 2 p a r t on 3|D^ , h e n c e A t p € L ( f t ) ) . Suppose 2 (82) were a p p l i c a b l e t o property (83). and w h i c h i s harmonic r with 2 there is a continuous function ure having a singular that prove cp £ H ^ ( f t ) n H ( f t ) be g i v e n tp. nevertheless T h e n we w o u l d o b t a i n , u s i n g t h e f o r h a r m o n i c f u n c t i o n s a n d t h e f a c t t h a t tp > tp i n |D mean-value (and r every- where), /tp D - D t Thus = /$ - /IP D Q / t p > 2 7 T t - t p ( 0 ) = 27Tt D t " Q ' V l ) prove (83) it applicable. there will equality It For with be v a l i d Thus 1 in place of 1 D r D l r , £ HJ(J2) Acp,. = p 2 (e\> 0) to which (82) cp i n ( 8 9 ) t h e f i r s t cp) t h e r e w i l l cp . Consider Acp . where by zero I t c a n be d e c o m p o s e d Acp , s u p p o r t e d What we h a v e t o do i s t o s m o o t h o u t be d e f i n e d inequality be e r r o r s w h i c h t e n d t o where y is the s i n g u l a r p a r t of , is follow. be a f a m i l y o f p o s i t i v e m o l l i f i e r s , = e" h(z/e) £ ( 8 2 ) ) and i n t h e r e m a i n i n g e q u a l i t i e s and i n - (83) w i l l p = Acp - y . £ $ (by £ remains to c o n s t r u c t as Acp = p + y {h } ^ cp (which are v a l i d for as e -» 0 . £ 1 i s e n o u g h t o p r o v e t h a t t h e f u n c t i o n cp a b o v e c a n be a p p r o x i m a t e d u n i f o r m l y b y f u n c t i o n s cp h (z) " r /tp . J - , - ( 8 3 ) w o u l d be p r o v e n . To a c t u a l l y and /tp > 277t - - '-J-j- h£C~(]R ) 2 h>0 say of the a n d /h = 1 , y . kind let Thus by let 3D , r -65- ( h e n c e tp^ G H ( f t ) , a s tp 2 = cp - $ pel. ( f t ) ) , and let . 1 2 E x t e n d b o t h $^ a n d cp t o a l l ]R b y p u t t i n g t h e m z e r o o u t s i d e ft . 2 $1 w i l l be c o n t i n u o u s (on ] R ) , hence a l s o $ 2 2 will Then be s o . Now d e f i n e cp = cp, + cp * h 1 ^2 e 0 S i n c e cp cp -* cp £ cp * h 0 c. since £ is continuous 2 uniformly. co 2 £ C (R ) . p > 0 Thus cp in £/ 2 F u r t h e r cp £ -»• cp u n i f o r m l y as e -» 0 , £ H (ft) s i n c e cp. € H ( f t ) 2 2 F i n a l l y we h a v e and Acp £ = p + y * h and £ >0 in they approximate - D. L \i > 0 . £ > 0, have the r e q u i r e d p r o p e r t i e s : (83) is and so 2 e D^. u n i f o r m l y as £ -»• 0 Thus cp * h and (82) a p p l i e s to them. p r o v e d a n d t h e p r o o f o f T h e o r e m 10 i s complete. -66- SUMMARIZING R E S U L T S AND A P P L I C A T I O N S a . Main theorems We now w a n t t o s u m m a r i z e t h e e s s e n t i a l result of Section a w a y w h i c h i s f r e e f r o m some o f t h e t e c h n i c a l i t i e s occurrence of the parameters T h e o r e m 12 i s a p r e l i m i n a r y Lemma 1 1 : e \ t 1 be t w o s o l u t i o n s spectively), for t e [0, ( t > t Proof: only > r of (e.g. O u r m a i n t h e o r e m i s T h e o r e m 13. We b e g i n w i t h a l e m m a . , (C) (with parameter values r,R,T and r ' , R ' , T ' and suppose t h a t D = D Q . T h e n , modulo n u l l - s e t s , . Moreover, u t = uj. i n \ M R ^ ^ \ a x { re- D = Dj. f o r Q t e [0, min(T.T')] u of Section I I I and r [ O . T ] £ t -* Dj. e \ , u theorem. in Let 3 t -* D [0,T] r,R,T). III t r ^ ) min(TJ')]. are the functions d e f i n e d by (11.13) We may s u p p o s e t h a t t h e t r i p l e t s i n one c o m p o n e n t , in (r,R,T) (C).) and ( r ' , R ' , T ' ) differ s i n c e t h e g e n e r a l c a s e t h e n i s o b t a i n e d as a combination of these pure cases. */ C a s e 1: ft = B R Then i t r*r' and l e t , R = R',T =T ' . w£Hg(ft) be t h e s o l u t i o n i s n o t h a r d t o see t h a t T o mean " n o t n e c e s s a r i l y We may a s s u m e t h a t r < r ' . r=r' w>0 ". in Put of ft and w = 0 o u t s i d e E) , . -67- DEFINE UV = U! FOR T E + T • W WE WANT TO SHOW THAT THE PARAMETER THE UNICITY SET) THE [0,T] PART AND UJ LEMMA TRIPLE OF = U^ IN T -» DJ (R,R,T). IN WITH WHENEVER COROLLARY WHICH, CASE (TOGETHER 9.1 VIEW THAT THIS DJ OF THE UJ) SATISFIES IS = D T DONE ' IT OF FOR FOLLOWS FROM (EXCEPT PROPERTIES (C) FOR A NULL- W, PROVES 1. i USING UV THE > U| > 0 (SINCE W PROPERTIES OF W WE GET (FOR TE[0,T]) = 0 OUTSIDE (7) AND AS WE WANTED CASE 2: DEFINE, (8) TO R = R', FOR T E DJ 3 ID OBSERVE IN THAT T -* DJ, UJ SATISFIES • Xj, • (C) R R FOR R,R,T PROVE. R * R', [0,T] T =T , U */ -JJY-j , ) AND SHOW THAT U" = T 0 £ HQ(R^) , A U j + 2lTt (6), UJ B N ^I) D« = N D, '0 L 1 . WE MAY SUPPOSE THAT R' < R . , -68- Then U J £ H Q ( B ) (since U J . £ H Q ( B t h a t t ~» D J , uj satisfies Corollary shows t h a t r 9.1 required conclusion Case 3 : r = r', i (C) f o r DJ = D in this R = R', r and i t )) r,R,T. (a.e.) t is immediately The u n i c i t y and u j = u^ verified statement which is of the case. T*T'. The r e q u i r e d c o n c l u s i o n follows trivially f r o m C o r o l l a r y 9.1 in this case. T h e p r o o f o f Lemma 11 i s complete. p T h e o r e m 1 2 : G i v e n an o p e n b o u n d e d s e t a DQ £ % (p.33)) [0,oo) 3 t -» D t € there with 0 € D DQCIR 31 T > 0, f o r each r > 0 w i t h R > 0 large (R > p [0,T] satisfies (C) sufficiently of T h e map ( 9 ) each D t (i) (9) to It (ii) ( 9 ) has t h e f o l l o w i n g satisfies if and f o r DQcB ) p the each re- the parameter values f o r each that properties: (F). of (Strictly (9) to [ 0 , T ] speaking, satisfies T>0.) D c= D. t [0,OO) 3 t -» Dj. 6 31 another r,R,T. zero. is formulated, the r e s t r i c t i o n Modulo n u l l - s e t s If for t h e moment i n e q u a l i t y , i (iii) r i s u n i q u e w i t h t h e s e p r o p e r t i e s , w h e r e " u n i q u e " means as ( F ) (F) B <=<= DQ suffices, i s u n i q u e up t o a s e t o f m e a s u r e Moreover, given i s a map such t h a t f o r each striction (i.e. Q initial modulo n u l l - s e t s for T < t . has t h e p r o p e r t i e s d o m a i n DQ £ 51, for all and t £ [0,«>) D . Q of <= DQ (9) with respect then D^ c Dj. to -69- Proof: Corollary 9.1 and c o r r e s p o n d i n g gives a l o t of solutions of the asserted p r o p e r t y . The u n i c i t y of into a global 9 . 1 , and t h e t h r e e a d d i t i o n a l proves the solution properties (i), (ii) 9.3 D Q and (9) with (9) f o l l o w s also immediately f o l l o w f r o m T h e o r e m 10, C o r o l l a r y 9 . 2 a n d C o r o l l a r y This ( f o r the given t o t h e v a r i o u s a l l o w a b l e c h o i c e s o f r , R and T ) Lemma 11 s h o w s t h a t t h e s e m e l t t o g e t h e r Corollary (C) and from (iii) respectively. theorem. L e t us f i n a l l y g i v e a f o r m u l a t i o n o f T h e o r e m 12 w h i c h i s self- i contained (i.e. does n o t r e f e r to (C) e t c . ) , in which the function i s r e p l a c e d by what i t a p p r o x i m a t e s , t h e D i r a c measure 6 at the o r i g i n , and w h i c h i s f o r m u l a t e d i n such a way t h a t t h e domains really become T h e o r e m 13: a Dp £ E ) G i v e n an o p e n b o u n d e d s e t D Q <= R w i t h 0 6 Dq ( i . e . t e & property: F o r e a c h t e [0,«>) t h e r e i s a d i s t r i b u t i o n (11) X in " X n U (12) u t > 0 (13) D t = D where ]R 2 such with that and Q U {z £ F : u (z) 2 t shows t h a t > 0} T h e map (10) , u^ h a s a r e p r e s e n t a t i o n c o n t i n u o u s o u t s i d e 0 , a n d (13) refers in form of a f u n c t i o n , to any such has t h e f o l l o w i n g a d d i t i o n a l representative. properties: /cp - /cp > 2lTt'Cp(0) D compact I Q (11) (i) u. = A u . + 2Trt.fi , n L>t given t h e r e e x i s t s a u n i q u e map with the f o l l o w i n g support r unique. [ 0 , ~ ) 3 t -* D (10) r-jpjX t for every D 0 " 2 cp £ H ( R 2 ) which is subharmonic in D. . -70- (ii) D <= D. T t for (iii) If [0,oo) 3 t -» Dj. £ of (10) for another D ^ e H T < t DQ C= DQ then D for all Proof: c Dj. t Essentially, . K i s a n o t h e r map w i t h t h e te and [0,») properties if . t h e main p a r t o f t h e theorem f o l l o w s by combining C o r o l l a r y 9 . 1 w i t h Lemma 11 j u s t a s i n t h e p r o o f o f T h e o r e m 1 2 . need o n l y modify the f u n c t i o n s in the s i t u a t i o n of C o r o l l a r y w (z)= -t-(loglz| t t T h i s means Aw 1 - -pBs—I / r D 1 t > 0 everywhere w t = 0 outside fit 9 . 1 , add t o l o g Iz - is e a s i l y together D r (in p ) ]R ) by and . seen t h a t the s o l u t i o n s into a solution (10) (cf. of satisfying Theorem 1 2 ) . ( C ) p r o v i d e d by C o r o l l a r y 9 . 1 ( 1 1 ) - ( 1 3 ) properties of f o r t h e new u^ . ( 1 0 ) also follow 1 3 . 1 : L e t M Q J M ^ . M ^ , . . . a n d c be g i v e n c o m p l e x n u m b e r s MQ a n d c r e a l n defined o easily = M with and p o s i t i v e and suppose t h a t t h e r e i s a bounded domain containing / z d x dy D w^ , and t h e t h r e e a d d i t i o n a l D e l u^. t h e f u n c t i o n Thus, c The u n i c i t y Corollary 9.1 a l i t t l e . da ) . p E r w Then i t in C o r o l l a r y that = - 2Trt.(6 - t 1 u^ We N n the o r i g i n such for all n > 0. that -71- T h e n t h e r e e x i s t s a d o m a i n D' ( b o u n d e d a n d c o n t a i n i n g / dx dy D' / z D' = M +c and n Proof: for all n > 1 . Apply the theorem with D Q = D. T h e n D' = D h a s t h e r e q u i r e d p r o p e r t y as i s s e e n b y c h o o s i n g ± Im z in D n (and d e f i n i n g 1 cp e H (1R ) ) (i) g i v e a few f u r t h e r for t = cp = ± Re z i n such a way and n that . o f t h e map ( 1 0 ) now be t h a t in Theorem i n T h e o r e m 13: i s a g i v e n domain and 3 t -* D [0,-) 1 properties Thus the background s i t u a t i o n w i l l Dg e & D t properties We s h a l l (14) cp o u t s i d e i n t h e moment i n e q u a l i t y b. A d d i t i o n a l 13. that U dx dy = M n D) s u c h e ft t i s t h e map u n i q u e l y d e t e r m i n e d b y t h e f o l l o w i n g property: there exist */ distributions (15) „ X T " X (16) u t > 0 (17) D t = D D Q u^ ( t £ [ 0 , « > ) ) = Au q {z U e t + I (18) u (z) (19) u (z) (20) u (0) t : u (z) t is t t = u^ (also called u.) = 0 for in the IE ' s u c h that Zirt.fi The d i s t r i b u t i o n function w i t h compact s u p p o r t t = 0 > 0} will . a l w a y s be r e p r e s e n t e d b y t h e completely determined pointwise by and continuous outside z = 0 + oo */ We a r e g o i n g t o u s e some c o m p l e x v a r i a b l e t h e o r y s o we now r e p l a c e |R b y (C . 2 in t h i s section, -72- for t > 0 . possible u^(z) (18) since AUj.£ ^-t'loglzl L°° o u t s i d e outside 0 0 for In p a r t i c u l a r and i s a s u p e r h a r m o n i c f u n c t i o n (i) It satisfies t h e moment i n e q u a l i t y (ii) D t i s an i n c r e a s i n g (iii) D t is function of Suppose in o f t h e map ( 1 4 ) : , t , t . follows: ( t o have i n f i n i t e c o n n e c t i v i t y e . g . ) . (a) DQC=CZ (b) Dj. h a s f i n i t e c o n n e c t i v i t y (c) Dj. i s s i m p l y c o n n e c t e d f o r a l l (d) Asymptotically t a circular (e) DQ . t . i s c o n n e c t e d b u t o t h e r w i s e a l l o w e d t o be v e r y D for all as t > 0 t -» «> t h e n one e x p e c t s of analytic way: irregular that . for all t > 0 . sufficiently t h e shape o f large curves for all t . Dj. a p p r o a c h e s t h a t disc . 3D. c o n s i s t s to function c o u l d be made p r e c i s e f o r e x a m p l e i n t h e f o l l o w i n g DQ since ( 1 4 ) w h i c h w o u l d be n i c e t o p r o v e c a n be Dj. b e c o m e s n i c e r w i t h i n c r e a s i n g (iv) (17) r e f e r s i n c r e a s i n g a s a f u n c t i o n o f DQ f o r f i x e d v a g u e l y s t a t e d as is natural Uj. i s a s u b h a r m o n i c pointwise definition One e x p e c t e d p r o p e r t y o f is Uj. . Now T h e o r e m 13 g i v e s us t h r e e p r o p e r t i e s (iv) t = 0 , (19) by ( 1 5 ) , and (20) near the o r i g i n . this representative of With t h i s Uj. = 0 is possible since t > 0 . of -73- We h a v e n o t b e e n a b l e t o p r o v e a n y c o m p l e t e f o r m o f we s h a l l holds prove ( T h e o r e m 15 b e l o w ) things t ' . shows t o what e x t e n t Lemma 14: U is o n l y t h a t assuming (iv). ( a ) and I b l a r e t r u e , What then We b e g i n w i t h a lemma w h i c h among the term DQ in (17) r e a l l y is e) other necessary. Let = { z € (E : u ( z ) > 0} t Then, for t > 0 , (i) is (ii) If connected. N ( i i i ) D^ i s a component o f DQ then e i t h e r is the union of meet (iv) If Proof: DQ (i) and t h o s e components o f is connected then It V 3V. be a c o m p o n e n t o f Since u t > 0 in in V. V as we w a n t e d t o I n D Q , and i n p a r t i c u l a r N N i t m u s t be c o n s t a n t l y in N or U Since connected). •k u^ = 0 . t Then D^ i s connected. in contains 9V <= 3u" <= (E ^ U^., s o u^ 0. u^ t shows t h a t 0 c a n n o t be a s u b 0. show. in N, u equal to N , proving is a superharmonic t u t 0 > 0, i f in N. u t function. attains Thus e i t h e r the value 0 u^ > 0 (ii). i s an i m m e d i a t e c o n s e q u e n c e o f = DQ (iv) and i s c o n n e c t e d and in T D Q w h i c h do n o t is a subharmonic f u n c t i o n outside (ii) since U But 0 £ V Therefore, D^ = this Thus D = 0 . i s enough t o p r o v e t h a t each component o f harmonic f u n c t i o n (iii) or N n t U^.. Thus l e t on N <= U (ii) and t h e d e f i n t i o n o f D , T U . t 0 e D Q n U t This gives (i) and ( i i ) immediately show t h a t D Q <= U t (DQ being (iv). I 1 Sakai h a r p r o v e d t h a t a ) I s t r u e , u n d e r t h e h y p o t h e s i s t h a t DQ i s a "domain w i t h q u a s i - s m o o t h b o u n d a r y " , meaning e s s e n t i a l l y t h a t 3Dg i s o f c l a s s C1 b u t w i t h c e r t a i n t y p e s o f c o r n e r s a l l o w e d ( f i n i t e l y m a n y ) . See [ 1 9 ] , T h e o r e m 3 . 7 . S a k a i a l s o h a s r e s u l t s on b ) t o e ) f o r s o l u t i o n s ( i n h i s s e n s e ) o f t h e H e l e Shaw f l o w p r o b l e m . C f . p . 15 in the introduction (of the present paper). -74- T h e o r e m 1 5 : S u p p o s e t h a t , f o r some f i x e d t > 0, D. i s f i n i t e l y connected */ and . DQCCZDJ. and i s o l a t e d Proof: that Then L e t U" = { z € C t 3DQ <= U = U . T This : u (z) > 0} . t Then DQCC D T = D u Q shows U" T i m p l i e s t h a t e a c h c o m p o n e n t o f DQ i n t e r s e c t s U^., o f Lemma 1 4 , DQ C= . Thus D^ i s c o n n e c t e d . Now l e t y be a component o f 9D is an a n a l y t i c curve o r a point. sphere. Since u" i s c o n n e c t e d t h e r e t which contains V Since curves . T In p a r t i c u l a r Let d i s j o i n t union o f a n a l y t i c points. and s o , b y ( i i ) D, 3Dj. i s a f i n i t e U T = 3U a n d we s h a l l t L e t I = (C u {«>} show t h a t y denote the Riemann i s e x a c t l y one component o f (namely t h a t component which c o n t a i n s denote t h a t component. y t 0). Then i t i s easy t o see t h a t i s c o n n e c t e d t h i s a l s o shows t h a t V i s simply (t^y 3V = y . connected. Put (21) W = D and (22) t v DQ = U = z - 4 for z £ W Uy. t - D 0 CZ V define S(z) D T ^ Due t o t h e a s s u m p t i o n t h a t D i s a neighbourhood o f y cluster at y ) . tion) Since in t is finitely V ( t h e o t h e r components o f DQ i s a c o m p a c t s u b s e t o f i t follows that also W i s a f u l l connected 9D t cannot D ( a l s o b y assumpt neighbourhood o f y in V. By " a n a l y t i c c u r v e " we mean t h e f o l l o w i n g : a s u b s e t o f (C i s a n a n a l y t i c c u r v e i f i t i s t h e i m a g e o f ( s a y ) 3 D u n d e r some n o n - c o n s t a n t f u n c t i o n holomorphic i n a neighbourhood o f 3 D . Thus an a n a l y t i c c u r v e i s allowed t o i n t e r s e c t i t s e l f and t o have c u s p s and o t h e r s i n g u l a r i t i e s . We s a y t h a t t h e a n a l y t i c c u r v e i s n o n - s i n g u l a r i f t h e f u n c t i o n above can be chosen t o be u n i v a l e n t i n a n e i g h b o u r h o o d o f 3 D . -75- As is continuously d i f f e r e n t i a t e f u n c t i o n on W U y. a continuous nimum ( u . = 0 ) . 3u On outside the o r i g i n y c t v u^ a t t a i n s its is mi- Therefore t =0 S(z) In on y = z" o n W S(z) > so y • is holomorphic — = 1 - Au. 3z = 1 - x z u + X n t u s i n c e , by + n 2 7 T t < s 0 = (15), in 0 W . Now i t i s known t h a t t h e e x i s t e n c e o f a f u n c t i o n w i t h t h e o f S ( z ) above g i v e s the d e s i r e d conclusion f o r j u s t c o n s i s t s o f o n e p o i n t we a r e d o n e . c o n n e c t e d and f S(z) : D ->- V 3V = y) - TJxJ -» 0 as I t c a n be s e e n t h a t 3D by (25) y simply Let f (W) o f 3lD f(c) extends analytically defining z, i n a n e i g h b o u r h o o d o f Moreover i t in the neighbourhood implies that for i s seen 3D in I \ D . that • T h i s shows t h a t y theorem is D . is € D ) = S(f(1/?)) =y V c- - > 3 E f(?) f(3D) (since if that U across Otherwise V c a n be mapped c o n f o r m a l l y o n t o is holomorphic and ( 2 3 ) shows S(f(?)) . T o be p r e c i s e , be t h e i n v e r s e map . Then S ( f ( ^ ) ) D y properties proven. i s an a n a l y t i c c u r v e ( a s d e f i n e d on p . 7 4 ) and t h e in -76- Remarks: (T) I t m i g h t seem t h a t T h e o r e m 15 i s n o t o f much v a l u e s i n c e i t supposes knowledge a p r i o r i conclusions about i t . h y p o t h e s e s o n l y on a b o u t t h e unknown domain DQ a n d w i t h t h e c o n c l u s i o n t h a t 3Dj. i s s h o u l d be e n o u g h t o a s s u m e a b o u t that D = U on D cal t f o r t > 0; t Lemma very is automatically Firstly, fulfilled DQ <= DQ, w h e r e DQ 1 for all (If t h e n Dj. = B ^ p that whenever t , and c l e a r l y p hypothesis with p 2 for = p o f DQ, h o l o m o r p h i c Then, and (22) o f on 3D in 2 DQCC t t DQCC i s l a r g e enough is to t l a r g e enough and the f o l l o w i n g : DQ ^ K S(z) (29) W = Dj. ^ ( K U { 0 } ) c V (30) S(z) 3u. = z - 4 g-i + the + 2t.) DJ.) that DQ i s c o n n e c t e d and curves. Q implies there is a function S (z) Q where K i s a compact de- subset and w i t h . n to and _ X D Q ( Z ) DJ. DQ<=<= D J . • i n t h e p r o o f o f T h e o r e m 15 we c h a n g e t h e d e f i n i t i o n s W DJ. DQCZC Dj. = Uj. a n d t h e s e c o n d o n e f i n e d a n d c o n t i n u o u s on (DQ ^ K) U 3 D = 7 that 3D union of non-singular a n a l y t i c impUes that ( a n d c a n be r e p l a c e d b y ) S (z) pathologi- i s some d i s c c e n t e r e d a t t h e o r i g i n , we 3DQ i s a f i n i t e d i s j o i n t The f i r s t (so hypotheses (except perhaps in very in which the hypothesis S e c o n d l y , suppose ( i n place of n However, since the s i n c e b y a p p l y i n g T h e o r e m 13 ( i i i ) h a v e Dj. <= Dj. D^ = D analytic. probable. c a n be d i s p e n s e d w i t h . situation drawing is connected s i t u a t i o n s ) , T h e o r e m 15 a t l e a s t makes t h e a s s e r t i o n L e t us m e n t i o n t w o s i t u a t i o n s (28) DQ t h a t i t 14(iv)). i n T h e o r e m 15 seem v e r y p l a u s i b l e analytic before I t w o u l d be d e s i r a b l e t o h a v e a t h e o r e m w i t h Then i t t Dj. pre- •( S ( z ) - z 0 ) ( z e W U y ) . (21) -77- In (30) it s a y by S (z) on i s assumed t h a t S ( z ) is extended to Q Q W U Y = z" for z e(W U Y ) ^Dg » holomorphic in W (since • Then (15) W U Y i n some w a y , S(z) shows t h a t — W ^ 9DQ a n d 9DQ i s a n i c e c u r v e ) and is S(z) = z on — continuous = 0 in 9Z y . T h e r e s t o f t h e p r o o f o f T h e o r e m 15 w o r k s as b e f o r e , a n d s o c o n c l u s i o n o f the theorem holds w i t h the changed (T) If Y "is a n y n o n - s i n g u l a r a n a l y t i c arc hypotheses. there t h e Schwarz f u n c t i o n f o r Y , d e f i n e d and h o l o m o r p h i c of =1 on that the anticonformal map Y is such t h a t S ( z ) It singular. * = is the r e f l e c t i o n Y . in z near to 9 n t u t 9D^ w h e r e i t near the is non- boundary. , the r e f l e c t i o n of z in is 9u. Z z in a neighbourhood S(z) 9D^ a t t h e p i e c e s o f z € D^, S(z), i n t h e p r o o f o f T h e o r e m 15 i s T h i s g i v e s an i n t e r p r e t a t i o n o f Namely, by ( 2 2 ) , i f is a function The i n t e r p r e t a t i o n o f z -> z * = S ( z ) is c l e a r that the f u n c t i o n S ( z ) the Schwarz f u n c t i o n f o r 3D. Y . See [ 4 ] , the z - 4-—Mz) . 9z Thus, - g r a d u. ( z ) t t = - 2 - ^ - (z) 3 u 9 z reflected point (D 1 1 = - ^ ( z * - z ) =•*• . _ - z to its z*). T h e o r e m 15 i s s i m i l a r dence s e t f o r (the vector from variational t o t h e o r e m s on t h e r e g u l a r i t y inequalities of the kind ( E 2 ) . of the coinci- There are t h e o r e m s h a v i n g as c o n c l u s i o n t h a t t h e b o u n d a r y o f t h e c o i n c i d e n c e i s an a n a l y t i c curve, e.g. Theorem 4.3 in [13] These theorems cannot, however, be i m m e d i a t e l y a p p l i e d t o o u r since they always r e q u i r e the obstacle f u n c t i o n analytic, ( s e e a l s o §4 i n ( o u r ty^) t o be satisfied). set [11]). problem real a h y p o t h e s i s w h i c h i s n o t s a t i s f i e d f o r us ( a l o n g w i t h h y p o t h e s e s on t h e o b s t a c l e f u n c t i o n w h i c h a r e n o t such other -78- T h e l a s t l i n e s a b o v e s h e d some l i g h t on t h e h y p o t h e s i s D g c c D^ i n T h e o r e m 15. it Namely, although is so o u t s i d e ip is not real t and t h e h y p o t h e s i s DQ to guarantee a p r i o r i that 3D t DQ<=<= D^ analytic Q, in a l l c a n be v i e w e d a s a w a y avoids the set where ip is not t real analytic. c. Applications to quadrature domains The n e x t theorem c o n c e r n s a c l a s s o f domains c a l l e d q u a d r a t u r e mains. We s a y t h a t D<=([ z . , . . . ,z i n in r . > 1, s u c h D fda D i s a q u a d r a t u r e domain i f and complex numbers a . . , J , K J f v , u ; J f which is a n a l y t i c Q u a d r a t u r e domains and q u a d r a t u r e c i t e some r e s u l t s . = z ([1], (iii) identities Let D If in for D and c o n t i n u o u s l y e x t e n d i b l e (D. shall Then is a function to of D such S(z) that z £ 3D i s simply connected then if some ( a n d t h e n e v e r y ) onto D is a rational curve identities Lemma 2 . 3 ) . D D D . f r o m w h i c h we be a b o u n d e d d o m a i n i n only If in (i.e. D i s a q u a d r a t u r e domain i f and o n l y i f t h e r e meromorphic (ii) and i n t e g r a b l e (31) a b o v e ) a r e t r e a t e d i n [ 1 ] and [ 9 ] , S(z) 0 < k < r . - 1, - - j ( z . ) K for every function (i) where 1 < j < n , - - points that r.-1 = I I a. j = l k=0 the kind there exist do- D i s a q u a d r a t u r e domain i f c o n f o r m a l map o f t h e u n i t d i s c function ( [ 1 ] , Theorem 1). i s a q u a d r a t u r e d o m a i n t h e n 3D i s a c o m p l e t e (i.e. there exists a real polynomial P(x,y) algebraic such that and ID -79- 3D = { z = x + i y : P(x,y) except for a f i n i t e set = 0} (the set i n t h e r i g h t member o f contain i s o l a t e d p o i n t s not in 3D)) Theorem 3.4). It follows subclass This [9], of all bounded s i m p l y connected i s a l s o t r u e f o r domains o f h i g h e r c o n n e c t i v i t y ( [ 9 ] , Theorem (to some 3.3). Now r e t u r n t o t h e s i t u a t i o n on p . 71 is a quadrature domain, say s a t i s f i e s inequality ( [ 1 ] , Theorem 3 and t h a t t h e q u a d r a t u r e d o m a i n s make up a d e n s e ( i n any reasonable t o p o l o g y ) domains. extent) from ( i i ) ( 3 3 ) may ( T h e o r e m 13) shows and suppose t h a t DQ (31). Then, for t > 0 , there t h e moment that / f d a = J f d a + 2-rrt • f ( 0 ) D t D = 0 "J" (k) I X a. . f ( z . ) +2irt • f ( 0 ) j = 1 k=0 ' n 1 [K} J 2 for all K 2 f £ H (K J */ ' ) ' which are a n a l y t i c i n D . ( A p p l y t h e moment T in- e q u a l i t y t o ± Re f and ± I m f . ) T h i s n e a r l y s h o w s t h a t D^ i s a q u a d r a t u r e domain. We m u s t o n l y e x t e n d t h e v a l i d i t y o f ( 3 4 ) t o a l l f G L ( D ^ ) which are a n a l y t i c i n D^. I n s t e a d o f d o i n g s o , h o w e v e r , we s h a l l o u r p r o o f t h a t D ^ i s a q u a d r a t u r e d o m a i n on t h e c h a r a c t e r i z a t i o n base (i) (p.78). T h e o r e m 16: D T Suppose DQ is a quadrature domain. *'We I is a quadrature domain. In p a r t i c u l a r 3D t t e m p o r a r i l y admit complex-valued f u n c t i o n s T h e n , f o r each i s an a l g e b r a i c 2 2 in H ( F ) t>0, curve. -80- L e t S Q ( Z ) be t h e f u n c t i o n g i v e n by ( i ) Proof: on p . 7 8 f o r D = DQ . T h e t h e o r e m i s p r o v e n as s o o n as we h a v e e s t a b l i s h e d t h e of a s i m i l a r f u n c t i o n Sj.(z) f o r Define, for z e D 3u S t ( z ) = " Z 1 ^ 4 _ n ( > - ( Z =z for all Then Sj.(z) On 3D S (z) t 0 ( z ) - z ' ) z £ (C \ D on S D T \ Since Sj.(z) c u r v e ) and meromorphic (15)). Thus, Sj.(z) T in a l l => D U D Q U 3DQ ( D ^ D Q ) Dj. . Thus t S j . ( z ) has a l l I j=1 I k=0 then that of follows. f [K) a. . ' J K (z.) J is r.-1 J f da D = where b^ = 2-RRT t I j=1 algebraic actually is the required properties identities I a, k=0 ' f [K> v J and K (z.) +b f(zl) 1 J z| = 0 . 1 1 , for SQ(Z), in ( D ^ D Q )U D Q . it follows that S (z) t DQ is r.-1 = is meromorphic and proven. T h e o r e m 16 a r e r e l a t e d as If that of so i n a n e i g h b o u r h o o d o f 3 D Q ( w h i c h i s an is clear that the quadrature f da SQ(Z) . t is continuous the theorem is DQ by and i n D Q , e x c e p t a t t h e o r i g i n and a t t h e p o l e s o f DQ 3S. — — = 0 (by using 3z It (C i s c o n t i n u o u s , e x c e p t a t t h e o r i g i n and a t t h e p o l e s o f = z D to all . Q the l a s t t h r e e terms in (35) v a n i s h , t In J S S Q ( Z ) (continuously) w h e r e we h a v e e x t e n d e d Sg(z) . t , t t X D + D=D existence DQ and in -81- L e t u s now c o m b i n e T h e o r e m 16 w i t h t h e e x i s t e n c e p a r t o f T h e o r e m 13. This yields that DQ if i s a bounded q u a d r a t u r e domain c o n t a i n i n g o r i g i n with the quadrature identity exists a q u a d r a t u r e domain where z. = 0. x D^ 0 € DQ and theses ZQ £ D Q . zJj £ D Q if ZQ = 0 this it c a n be r e p l a c e d b y t h e s i n g l e h y p o t h e s i s c a n be r e l a x e d t o z j we may a p p l y t h e p r e v i o u s i s t h e n a q u a d r a t u r e domain w i t h z| e = j ~ 1 a. , f r j=1 £ D nB(zj;e) 0 k=0 ' J ( k ) (z.)+Tre K 2 .f(zi) J z'.,...,z^ for all s t e p some z ' with z j £ 3DQ those lies zj rature / f da D £ 3DQ since DQ r e p l a c e d = 0 and T r e < b DQ U D(z|;e) 2 by 1 ; and . many t i m e s f o r finitely i f we j u s t t a k e c a r e t o make t h e f o r which z j £ DQ (to avoid that at on t h e b o u n d a r y o f t h e c u r r e n t d o m a i n a t t h a t T h u s we h a v e p r o v e d t h e f o l l o w i n g Corollary hypothesis DQ i n d i c a t e d i n t h e l a s t l i n e s above a t once and s i m u l - modification of taneously hypo- 1 T h e a b o v e r e a s o n i n g may be r e p e a t e d f i n i t e l y many p o i n t s point 1 1 DQUB(ZJ; ) (38), identity n f da that with DQU_D(Z^;E) / so s m a l l reasoning for e > 0 quadrature identity there i s c l e a r t h a t the two DQ U D ( z J j ; e ) the b^ > 0 i s n o t i n any way a d i s t i n g u i s h e d identities 1 Actually 1 with the quadrature Since the o r i g i n in the context of quadrature ( 3 7 ) , then g i v e n any the 16.1: Let D corollary some step). o f Theorem 16.*/ be b o u n d e d d o m a i n i n (L admitting the quad- identity n = 1 j=1 r j " I a. . f k=0 ' 1 Then given f i n i t e l y positive n u m b e r s b^ J ( k ) K (z.) 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