Space Vector Modulation (SVM) Reference: Bin Wu, High Power Converters and AC Drives, IEEE Press, 2006. Three Phase Switching States (1) Three Phase Switching States (2) Three Phase Switching States (3) • Eight switching states Space Vector Review • Three-phase voltages v An (t ) vBn (t ) vCn (t ) 0 (1) • Two-phase voltages 2 4 v (t ) An cos0 cos cos v (t ) 2 3 3 vBn (t ) v (t ) 3 sin 0 sin 2 sin 4 v (t ) 3 3 Cn (2) • Space vector representation V (t ) v (t ) j v (t ) (3) (2) (3) 2 V (t ) v An (t ) e j 0 vBn (t ) e j 2 /3 vCn (t ) e j 4 /3 3 (4) Space Vector Diagram • Active vectors: V1 to V6 (stationary, not rotating) • Zero vector: V0 • Six sectors: I to VI Space Vector Example Switching state [100] S1, S4 and S6 ON v AN (t ) Vd , vBN (t ) 0, vCN (t ) 0 v AB (t ) Vd , vBC (t ) 0, vCA (t ) Vd 2 1 v An (t ) Vd , vBn (t ) Vd 3 3 (5) (4) 2 V1 Vd e j 0 3 (6) Similarly, 2 j ( k 1) 3 Vk Vd e 3 k 1, 2, ..., 6. (7) and 1 vCn (t ) Vd 3 (5) Active and Zero Vectors • Active Vector: 6 • Zero Vector: 1 • Redundant switching states for zero vector: [111] and [000] Reference Vector • Definition Vref Vref e j • Rotating in space at ω 2 f (8) • Angular displacement (t ) t 0 dt (9) Relationship Between Vref and VAB • Vref is approximated by two active and a zero vectors • Vref rotates one revolution, VAB completes one cycle • Length of Vref corresponds to magnitude of VAB V2 Vref Tb V2 Ts SECTOR I Q Ta V1 Ts V1 A Simple Method to Decide the Sector Number A. Calculate the following expression: N sign( v An ) 2sign( vBn ) 4sign( vCn ) where sign(+)=1,sign(-)=0. B. Use the following look-up table to determine the sector number: N 1 2 3 4 5 6 Sector 6 2 1 4 5 3 Dwell Time Calculation (1) • Volt-Second Balancing Vref Ts V1 Ta V2 Tb V0 T0 Ts Ta Tb T0 V2 (10) • Ta, Tb and T0 – dwell times for V1 , V2 and V0 • Ts – sampling period Vref Tb V2 Ts Q Ta V1 Ts • Space vectors 2 2 j j 3 , and Vref Vref e , V1 Vd V2 Vd e V0 0 3 3 (11) (11) (10) 2 1 Re : V (cos ) T V T Vd Tb ref s d a 3 3 Im : Vref (sin ) Ts 1 Vd Tb 3 SECTOR I (12) V1 Dwell Time Calculation (2) Solve (12) Ta Tb T0 Ts 3 Ts Vref Vd 3 Ts Vref Vd sin ( sin Ta Tb 3 ) 0 /3 (13) Vref Location versus Dwell Times V2 Vref Tb V2 Ts SECTOR I Q V1 Ta V1 Ts V ref Location Dwell Times 0 Ta 0 Tb 0 0 6 Ta Tb 6 6 T a Tb Ta Tb 3 3 Ta 0 Tb 0 Modulation Index T T m sin ( ) s a a 3 T T m sin s a b T0 Ts Ta Tb ma Vref Vd / 3 (15) (16) Replacing by ’, he above equation (15) can be extended to the kth sector: ' ( k 1) 3 where k 1, 2, ..., 6. Modulation Range • Vref,max 2 3 Vd Vref , max Vd 3 2 3 (17) (17) (16) • ma,max = 1 • Modulation range: 0 ma 1 (18) Switching Sequence Design • Basic Requirement: Minimize the number of switchings per sampling period Ts • Implementation: Transition from one switching state to the next involves only two switches in the same inverter leg. Undesirable Switching Sequence • Total number of switchings: 10 7-Segment Switching Sequence (1) • Selected vectors: V0, V1 and V2 • Dwell times: Ts = T0 + Ta + Tb • Total number of switchings: 6 7-Segment Switching Sequence (2) Note: The switching sequences for the odd and ever sectors are different. 7-Segment Switching Sequence (3) Simulated Waveforms f1 = 60Hz, fsw = 900Hz, ma = 0.696, Ts = 1.1ms Waveforms and FFT Waveforms and Spectrum (1) Waveforms and Spectrum (2) ( f1 60Hz and Ts 1 / 720 sec ) Even-Order Harmonic Elimination (1) Sector 4 Type-A sequence (starts and ends with [000]) Type-B sequence (starts and ends with [111]) Even-Order Harmonic Elimination (2) V3 b SECTOR III V4 a a 30 30 a a b a b a V5 SECTOR I b b SECTOR IV V2 SECTOR II SECTOR VI b SECTOR V V1 V6 Space vector Diagram Type-A sequence Type-B sequence Even-Order Harmonic Elimination (3) Even-Order Harmonic Elimination (4) ( f1 60Hz and Ts 1 / 720 sec ) 7-Segment Type B sequence (1) 7-Segment Type B Sequence (2) 5-Segment SVM 5-Segment Switching Sequence (1) 5-Segment Switching Sequence (2) 5-Segment Simulated Waveforms v g1 2 / 3 vg 3 2 vg 5 vAB 0 4 Vd 2 4 iA 0 2 4 • f1 = 60Hz, fsw = 600Hz, ma = 0.696, Ts = 1.1ms • No switching for a 120° period per cycle. • Low switching frequency but high harmonic distortion Comparison of SPWM and SVM Space Vector PWM generates less harmonic distortion in the output voltage or currents in comparison with sine PWM Space Vector PWM provides more efficient use of supply voltage in comparison with sine PWM Sine PWM: Locus of the reference vector is the inside of a circle with radius of 1/2 Vdc Space Vector PWM: Locus of the reference vector is the inside of a circle with radius of 1/ 𝟑 Vdc Voltage Utilization: Space Vector PWM = 2/ 𝟑 =1.155 times of Sine PWM