Advanced Physics, Chapter 8 (8-1 only), “Describing Rotational Motion”, pp. 197-152 and Chapter 6 (6-2) Circular Motion, pp. 153-156: Syllabus Remember that you can access the online physics textbook in pdf format at the following web address: http://www.glencoe.com/ose/ click link and type " A7AFD238AE " under student access code There will be two online homework assignments: • Homework 021 (rotational kinematics) • Homework 022 (centripetal forces) One test at the end of the unit Helpful websites: http://dev.physicslab.org/Document.aspx?doctype=3&filename=RotaryMotion_Rotatio nalKinematics.xml http://hypertextbook.com/physics/mechanics/rotational-kinematics/ http://media.pearsoncmg.com/bc/aw_young_physics_11/pt1a/Media/RotMotionStatics/ RotationalKinematics/Main.html http://www.knowsoft.com/HS_physics/pdf/Rotational_Kinematics.pdf http://hyperphysics.phy-astr.gsu.edu/Hbase/circ.html#rotcon http://www.physicsclassroom.com/Class/circles/U6L1c.cfm Rotational Motion and Centripetal Acceleration Chapter 8 (Section 8-1) Chapter 6 (Section 6-2) Two general types of circular motion: a) Rotation b) Revolution Two different ways to discuss motion for a rotating object: a) angular displacement rotating objects ‘sweeps’ out an angle measure angle (θ) usually in radians θ in radians = arc length (s) / radius (r) Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 1 11/1/2009 θ: radians ↔ degrees ↔ rotations or revolutions The time it takes to complete one orbit or one complete circle? Called the Period of rotation (units of sec). example: the reciprocal of Period? Called frequency Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 2 11/1/2009 angular velocity (ω): This is a measure of how much angle is being swept out by a rotating object in a given time ω= ∆θ radians ∆t sec Other units to specify ω If we have an object rotating at a constant angular velocity: ∆θ = ω ( ∆t ) Notice its similarity to: Δx = v (t) But often we don’t have objects rotating constantly. We can object speed up or slow down their rotational velocities. In linear systems, we call a change of velocity an acceleration, but in rotating systems, we call this acceleration an angular acceleration and it is given the symbol, α α= ∆ω ∆t radians sec sec You know what? You can do the exact same derivations we did with translational kinematics to find rotational kinematics equations if we are considering a case with constant angular acceleration. Basically, what comes out is essentially the same equations but with different variables: Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 3 11/1/2009 Rotational Kinematics equations Comparing linear motion with angular motion: Constant velocity linear motion: 5 4 3 2 1 0 x (displacement, meters) x f = xi 0 1 2 3 4 5 + v(t) t (time seconds) Constant angular velocity 5 4 3 2 1 0 (θ, angular displacement, radians) 0 1 2 3 4 5 t (time seconds) Equation: Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 4 11/1/2009 Constant linear acceleration: vf = vi + at vf 2 = vi2 + 2a(∆x) xf = xi + vit + ½at2 Constant angular acceleration (ω, angular velocity, rads/sec) (θ, angular displacement, rads) t (time, seconds) (ω, angular velocity, rads/sec) t (time, seconds) (θ, angular displacement, rads) t (time, seconds) t (time, seconds) Equations Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 5 11/1/2009 Sample Problems: 1. Some of the motors we used in our fan cars were rated at 10,200 rpm. If this velocity stays constant, calculate the angular velocity in rad/s. How if takes the fan car 5 seconds to complete the race, how many radians would have been swept out in this time? How many rotations would the propeller have undergone in these 5 seconds? (answers = 1068.14 rads/sec; 5340.7 rads; 850 rotations) 2. The blades of a fan running at low speed turn at 250 rpm. When the fan is switched to high speed, the rotation rate increases uniformly to 350 rpm in 5.75 seconds. What is the angular acceleration of the blades during this time? How many revolutions do the blades go through while the fun is accelerating? (answers: 1.82 rads/s^2; 28.7 or 28.8 revolutions) 3. A CD player reaches its operational rotational rate of 3.5 rps after making 2 rotations. What is its angular acceleration in rads/s2? (answer = 19.2 rads/s/s) Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 6 11/1/2009 Connecting linear and angular quantities… I had mentioned on page 1 that there is another way to describe motion of a rotating object. This is called tangential velocity (vt) Why called tangential? For one complete rotation, Is there a relationship between angular velocity (ω) and tangential velocity (vt)? Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 7 11/1/2009 Other ancillary notes of Chapter 6: What gives objects accelerations? What give objects angular acceleration? The measure of a force's tendency to produce a rotation about an axis is called torque. That is, if a force is used to begin to spin something, or to attempt to spin something, a torque is generated. A torque would also be generated if a force was used to stop something from spinning. Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 8 11/1/2009 Situations dealing with torque… Balanced torques: See-Saw problems… Equilibrium… Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 9 11/1/2009 Angular Momentum and its conservation We know from our unit on momentum that momentum is conserved if we neglect any external forces such as friction. (collision problems) We see something similar with objects rotating… Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 10 11/1/2009 Chapter 6 (Section 6-2) Uniform Circular Motion Special type of acceleration for objects moving along a circular path: - let’s go back to the definition of acceleration - Could acceleration exist even if an object is moving at constant velocity? liquid accelerometer demo Acceleration is directed inward…we call it a centripetal acceleration (ac) - This acceleration is not caused by the change of the magnitude of the velocity vector but because the direction of the velocity vector is changing. Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 11 11/1/2009 The centripetal acceleration expression is obtained from analysis of constant speed circular motion by the use of similar triangles. From the ratio of the sides of the triangles: Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 12 11/1/2009 Two important relationships to guide our thinking: (a) Newton’s 2nd Law: Fnet = ma Forces causing objects to move in a circle are called centripetal forces… (b) Fnet = Fc = mv 2 r What forces act centripetally? What forces tend to keep objects moving in circular paths?? a) tension b) gravity c) friction d) normal forces Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 13 11/1/2009 Sample Problems 1. A 900-kg car makes a 180-degree turn with a speed of 10.0 m/s. The radius of the circle through which the car is turning is 25.0 m. Determine the force of friction and the coefficient of friction acting upon the car. (answer: the force of friction is 3600 N; the coefficient of friction of 0.41.) 2. The coefficient of friction acting upon a 900-kg car is 0.850. The car is making a 180degree turn around a curve with a radius of 35.0 m. Determine the maximum speed with which the car can make the turn. (answer = maximum speed of 17.1 m/s.) 3. A 1.5-kg bucket of water is tied by a rope and whirled in a circle with a radius of 1.0 m. The bucket of water travels at a constant speed of 4 m/s. Determine the acceleration, the values of the tension at the top and the bottom of the circular path. (answers: Tension at the top = 9.3 N; Tension at the bottom = 38.7 N) Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 14 11/1/2009 4. Two identical objects are placed on a flat turntable that can rotate at different velocities. One of the objects is placed 25 cm away from the center while the other is placed twice this distance. The coefficient of static friction (μ) for each object is 0.5. The turntable’s rotational speed (vt) is gradually increased. At what tangential velocity will each object just begin to slide off (maximum tangential velocity)? (answers = 1.11 m/s for the inner object and 1.56 m/s for the outer object) 5. In 1901, circus performer, Allo “Dare Devil” Diavolo introduced the student of riding a bicycle in a loop-the-loop. If the radius of the loop was 3 m, what is the least tangential velocity Diavolo could have at the top of the loop to remain in contact with the surface? (answer = 5.4 m/s is the least tangential velocity) 6. How many rpm would a 7.5 m radius Ferris wheel need to make for the passengers to feel “weightless” at the topmost point? What would the period of revolution for the passengers? (answers: rpm = 10.9 rpm; Period (T) = 5.5 seconds/revolution) Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 15 11/1/2009 How do objects continue moving in circles if the centripetal force is directed inward? If not enough vt… If not enough Fc… Via the 1st law, object moves off tangentially… Reference frames and circular motion a can… From a reference point outside the can… From a reference point inside the can… ‘Centrifugal’ Simulated gravity Centrifugal force can feel like gravity Space stations Artificial gravity Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 16 11/1/2009 Different visions of space stations Adv. Physics, Rotational Kinematics/Centripetal Forces Notes, p. 17 11/1/2009