Name Answer Key Date Dimensional Analysis Problems 1 kilometer

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Name
Answer Key
Date
Dimensional Analysis Problems
1 kilometer (km) = 1000
Meters (m)
1 m = 10
decimeters (dm)
1 m = 100
centimeters (cm)
1 m = 1000
millimeters (mm)
1 kilogram (kg) = 1000
grams (g)
1 g = 1000
(mg)
1 g = 100
centigrams (cg)
1 g = 10
(dg)
1 kiloliter (kl) = 1000
Liters (l)
1l = 100
cL
1l = 1000
mL
1l = 1000
cm3
(1 mL = 1cm3)
SHOW YOUR WORK for each of the following conversions. Write your final answer in
the blank provided.
SHOW WORK HERE
1.
Convert 25 km to m.
25 km
1000m
_____25000 m___
1
1 km
2.
Convert 6.38 dm to km.
__6.38 X 10-4_km__
3.
6.38 dm
1
1m
10 dm
1 km
1000 m
Convert 68,000 seconds to weeks.
____0.11 wk_______
68000 s
1
1 min
60 s
1 hr
60 min
1day
24 hr
1wk
7days
Name
4.
5.
Answer Key
2
Convert 430 dg to pounds (lbs.)
Hint: 1 kg = 2.2 pounds
__0.946 lbs________
1g
10 dg
430 dg
1
Convert 120 km/hr to m/s.
__33.3 m / s________
120 km
1 hr
1 kg
1000 g
2.2 lbs
1 kg
Here’s a start for you.
1000 m
1 km
1hr
60 min
1 min
60 s
Density Problems – Solve using Dimensional Analysis – Show Your Work and place your
final answer in the blank provided!
6.
The density of dry air at 25°C is 0.00119 g/cm3. What is the volume of 20.0g of air?
__16,806.7_ cm3____ (Fact: 0.00119 g)
1 cm3
7.
1.4 L
1
1.78 g
1L
Convert 8.96 grams of mercury to cm3. (the density of mercury is 13.5 g/cm3)
__0.66 cm3________ (Fact: 13.5 g )
1 cm3
BONUS:
9.
1 cm3
0.00119 g
Convert 1.4 L of argon to g. (the density of argon is 1.78 g/L)
__2.49 g__________ (Fact: 1.78 g )
1L
8.
20.0 g
1
8.96 g
1
1 cm3
13.5 g
Make a conversion factor and solve this next problem.
Again, Show Your Work!
An atom of gold weighs 3.271 x 10-22 g. How many atoms of gold are in 1.00 g of gold?
__3.06 X 1021_atoms
Fact:
1g
1
1 atom = 3.271 X 10-22 g
1 atom
3.271 X 10-22 g
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