November 4th Chapter 33 RLC Circuits Review ! RL and RC circuits ! ! Charge, current, and potential grow and decay exponentially LC circuit ! Charge, current, and potential change sinusoidally ! Total electromagnetic energy is Li 2 q 2 U = UB + UE = + 2 2C Review ! Ideal LC circuit ! ! dU =0 dt Total energy conserved Solved differential equation to find q = Q cos(ωt ) ω= i = − I sin(ωt ) ! U 1 LC Substituting q and i into energy equations E Q2 = cos 2C 2 (ω t ) U B Q2 = sin 2C U = U B + U E = Q 2 / 2C 2 (ω t ) Review ! RLC circuit ! ! ! Energy is no longer conserved, becomes thermal energy in resistor Oscillations are damped Solved differential equation to find q = Qe − Rt / 2 L cos(ω ′t ) 2 2 ′ ω = ω − ( R / 2 L) ! dU = −i 2 R dt If R is very small ω′ = ω Energy goes as Q 2 − Rt / L UE = e cos 2 (ω ′t ) 2C Q 2 − Rt / L Utot = e 2C Resistive Load ε −v =0 ! Apply loop rule ! Using ! We have ! Amplitude across resistor is same as across emf ! vR = ε ε =ε m R sin ω d t vR = ε m sin ω d t Rewrite vR as vR = VR sin ω d t ε m = VR Forced Oscillations Resistive load vR = VR sin ω d t VR = ε m Capacitive load vC = VC sinω d t VC = ε m Inductive load vL = VLsinω d t VL = ε m Resistive load ! Use definition of resistance to find iR v R = V R sin ω d t vR VR = sin ω d t iR = R R ! ! Voltage and current are functions of sin(ωdt) with φ = 0 so are in phase No damping of vR and iR , since the generator supplies energy Resistive load ! Compare current to general form vR VR iR = = sin ω d t R R VR = I R R iR = I Rsin(ωd t − φ ) ! ! ! Minus sign for phase is tradition For purely resistive load the phase constant φ = 0 Voltage amplitude is related to current amplitude VR IR = R VR = I R R Capacitive load ! Use definition of capacitance qC = Cv C = CV C sin ω d t ! Use definition of current and differentiate dq C iC = = ω d CV C cos ω d t dt ! Replace cosine term with a phase-shifted sine term cosωd t = sin(ωd t + 90°) Capacitive load ! Voltage and current relations vC = VC sin ω d t iC = ωd CVC sin(ωd t + 90°) = IC sin(ωd t + 90°) VC IC = XC ! 1 XC = ωd C XC is called the capacitive reactance and has units of ohms Capacitive load ! Compare vC and iC of capacitor vC = VC sin ω d t iC = ωd CVC sin(ωd t + 90°) iR = I Rsin(ωd t − φ ) ! Voltage and current are out of phase by -90° ! Current leads voltage by T/4 Inductive load (skipped in lecture) ! ! ! Derivation of current: Self-induced emf across an inductor is di L = vL = L Relate dt ε di v L = VL sin ω d t = L dt ! di VL = sin ω d t dt L Want current so integrate VL VL cos(ωd t ) iL = ∫ sin(ωd t ) dt = − L ωd L ! Then use − cos( ω d t ) = sin( ω d t − 90° ) Inductive load ! Voltage and current relations v L = V L sin ω d t VL iL = sin(ωd t − 90°) = I L sin(ωd t − 90°) ωd L VL IL = XL ! X L = ωd L XL is called the inductive reactance has units of ohms Inductive load ! Compare vL and iL of inductor vL = VL sin ω d t iL = I L sin (ω d t − 90°) ! iL ! and vL are +90° out of phase Current lags voltage by T/4 Summary of Forced Oscillations Element Resistor Reactance/ Resistance R Phase of Phase Amplitude Current angle φ Relation In phase 0° VR=IRR Capacitor XC= 1/ωdC Leads vC (ICE) Inductor XL=ωdL Lags vL (ELI) ! -90° VC=ICXC +90° VL=ILXL ELI (positively) is the ICE man ! ! ! Voltage or emf (E) before current (I) in an inductor (L) Phase constant φ is positive for an inductor Current (I) before voltage or emf (E) in capacitor (C) EM Oscillations ! If the driving frequency, ωd , in a circuit is increased does the amplitude voltage and amplitude current increase, decrease or remain the same? ! For purely resistive circuit ! From loop rule VR = εm So amplitude voltage, VL stays the same IR also stays the same VR IR = IR only depends on R ! ! R EM Oscillations ! If the driving frequency, ωd , in a circuit is increased does the amplitude voltage and amplitude current increase, decrease or remain the same? ! For purely capacitive circuit ! From loop rule Vc = εm So amplitude voltage, VC stays the same IC depends on XC which depends on ωd by So IC increases VC ! ! ! IC = XC = ω d CVC EM Oscillations ! If the driving frequency, ωd , in a circuit is increased does the amplitude voltage and amplitude current increase, decrease or remain the same? ! For purely inductive circuit ! From loop rule VL = εm So amplitude voltage, VL stays the same IL depends on XL which depends on ωd by So IL decreases VL VL ! ! ! IL = XL = ωd L RLC Circuits ! LC and RLC circuits with no external emf ! Free oscillations with natural angular frequency, ω 1 ω= ω ′ = ω − ( R / 2 L) LC ! Add external oscillating emf (e.g. ac generator) to RLC circuit 2 ! ! ! 2 Oscillations said to be driven or forced Oscillations occur at driving angular frequency, ωd When ωd = ω, called resonance, the current amplitude, I, is maximum RLC circuits ! ! ! ! RLC circuit – resistor, capacitor and inductor in series Apply alternating emf ε =ε m sin ω d t Elements are in series so same current is driven through each From the loop rule, at any time t, the sum of the voltages across the elements must equal the applied emf i = I sin(ωd t − φ ) ε =v R + vC + vL RLC circuits ε = iR + iX ! C Taking into account the phase find current amplitude to be I= ! ! + iX L ε R + ( X L − XC ) Write amplitude voltage as Where Z is the impedance ! m 2 ε m 2 = IZ Like resistance and has units of Ohms X L = ωd L Z = R + (X L − XC ) 2 2 XC = 1 ωd C EM Oscillations XL − XC tan φ = R ! If XL > XC the circuit is more inductive than capacitive ! ! ! φ is positive Emf is before current (ELI) If XL < XC the circuit is more capacitive than inductive ! ! φ is negative Current is before emf (ICE) RLC Circuits X L − XC tan φ = R ! ! If XL = XC the circuit is in resonance – emf and current are in phase Current amplitude I is max when impedance, Z is min ε I= m Z = ε m R + (X L − XC ) 2 X L − XC = 0 2 ε = m R EM Oscillations ! When XL = XC the driving frequency is 1 ωd L = ωd C ! This is the same as the natural frequency, ω ωd = ω = ! ωd = 1 LC 1 LC For RLC circuit, resonance and the max current I occurs when ωd = ω RLC circuits I= Em 1 R + ( ωd L − ωd C 2 ! I is largest when X L = XC ! When ωd=ω circuit said to be in resonance ! When homework says resonance frequency it means ωd=ω ω = ω d = 2π f d )2