• L = rotation matrix (or matrix of direction cosines) • lij = cos of angle

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• L = rotation matrix (or matrix of direction cosines)
• lij = cos of angle between ith axis of S ′ and jth axis of S
This is the fundamental result for the rotation of a vector. Note that by this we
mean that the vector is not rotated – it stays fixed in space – but that the basis is
rotated. (More on this point later.)
For example, consider the rotation through angle α about the z-axis. (NB anticlocky
y′
x′
α
x
z, z ′
wise when looking at tip of arrow.) Then we have


cos α sin α 0
Lz (α) =  − sin α cos α 0  ,
0
0 1
(~e′x · ~ex = cos α, ~e′x · ~ey = cos(π/2 − α) = sin α, ~e′y · ~ex = cos(π/2 + α) = − sin α, and
~e′y · ~ey = cos α etc..)
Similarly (by direct evaluation or cyclic rotations of axes of previous result)




1
0
0
cos γ 0 − sin γ
cos β sin β  ,
0 1
0 .
Lx (β) =  0
Ly (γ) = 
0 − sin β cos β
sin γ 0
cos γ
Note that as Lz (−α)Lz (α) = I and LTz (α) = Lz (−α) (by inspection) then we have
LTz (α)Lz (α) = I ie Lz is an orthogonal matrix.
The general result follows because the length of the vector is invariant,
′2
ak = (lki ai )(lkj aj )
2
~a =
,
a2i = δij ai aj
and as this is true for all ai then LT L = I, so L is an orthogonal matrix and hence
has determinant ±1 and hence an inverse always exists. Thus we have
LT L = I
or LT = L−1
17
or LLT = I ,
Alternatively we may consider the basis when we have a′i~e′i = ai~ei , which means that
lij aj ~e′i = aj ~ej which is true for all aj so lij e~i ′ = ~ej or lkj lij ~e′i = lkj ~ej or
~e′i = lij ~ej .
A matrix representing a rotation is orthogonal and has determinant +1. These are
called proper transformations.
[det L is +1 rather than −1 as for infinitesimal transformations we must have that
L → I continuously.]
But if (~ex , ~ey , ~ez ) is right handed (RH) and (~e′x , ~e′y , ~e′z ) is left handed (LH) then
det L = −1.
For example a reflection in the origin
y
z′
x′
x
z
y′
where


−1
0
0
0 ,
L =  0 −1
0
0 −1
gives det L = −1. These are called improper transformations.
2.1.1
Composition of two rotations
Let ~e′i = l1ij ~ej and ~e′′i = l2ij ~e′j , then we have
~e′′i = (L2 L1 )ij ~ej ,
(note the reversed order).
For example if


0 1 0
L1 =  −1 0 0  ,
0 0 1


0 0 −1
0 ,
L2 =  0 1
1 0
0
18
so L1 represents a rotation about Oz through π/2, while L2 represents a rotation
about Oy ′ again of π/2.
For L2 L1 :
y
S
x′
S′
z ′′
S ′′
x′′
x
y′
y ′′
z′
z


0 0 −1
0 
L2 L1 =  −1 0
0 1
0
~ex′′ = −~ez
~ey′′ = −~ex .
~ez ′′ = ~ey
or
Alternatively L2 followed by L1 gives:
S
y
S′
y′
S ′′
x′′
x′
x
z′
z
z ′′
y ′′


0 1 0
L1 L2 =  0 0 1 
1 0 0
or
~ex′′ = ~ey
~ey′′ = ~ez .
~ez ′′ = ~ex
So L2 L1 6= L1 L2 , ie rotations are non-commutative.
Three rotations first about z-axis (α), then y ′ -axis (β) then z ′′ -axis (γ) give a general
rotation – Euler angles:
L(α, β, γ) = Lz ′′ (γ)Ly′ (β)Lz (α) .
(Note that conventions can vary.) Expanding gives:



cos γ sin γ 0
cos β 0 − sin β
cos α sin α
0 1
0   − sin α cos α
L =  − sin γ cos γ 0  
0
0 1
sin β 0
cos β
0
0

cos β cos α cos γ − sin α sin γ
cos β sin α cos γ + cos α sin γ
=  − cos β cos α sin γ − sin α cos γ − cos β sin α sin γ + cos α cos γ
sin β cos α
sin β sin α

0
0 
1

− sin β cos γ
sin β sin γ  .
cos β
(Nice picture given in Mathews and Walker p405.) A rather complicated result.
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2.2
Rotation of Vectors
The previous transformations are called passive transformations (ie rotate basis,
keeping the vector fixed).
Alternatively we can keep the basis fixed and rotate the vector – active transformations. We now consider this.
2.2.1
General Rotation
Q
θ
S
P
~n × ~x
Q
θ
~y
S
T
P
~x
~n
O
O is a fixed point in the body, which rotates about an axis through O in the direction
of the unit vector ~n.
OS is the component of ~x in the ~n-direction, ie (~x · ~n)~n. Also ~n × ~x is parallel to
T~Q.
~ + ST
~ + T~Q
~y = OS
(~x − (~x · ~n)~n)
~n × ~x
= (~x · ~n)~n + SQ cos θ
+ SQ sin θ
| {z } |
|
{z
}
SP
|~n × ~x|
{z
}
| {z }
~ |
|ST
|T~Q|
c
~
SP
= (~x · ~n)~n + cos θ (~x − (~x · ~n)~n) + sin θ~n × ~x ,
(as SP = SQ and |~n × ~x| = SP = SQ).
This gives finally the important result
~y = ~x cos θ + (1 − cos θ)(~n · ~x)~n + (~n × ~x) sin θ .
20
d
T~Q
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