PIERS Proceedings, Suzhou, China, September 12–16, 2011 368 Generalized Representation of Sideband Radiation Power Calculation in Arbitrarily Distributed Time-modulated Planar and Linear Arrays E. Aksoy and E. Afacan Department of Electrical & Electronics Engineering, Gazi University, Maltepe, Ankara, Turkey Abstract— In this study, grid independent general representation of formulation of sideband radiation (SR) power calculation in time-modulated planar and linear arrays is aimed. It is shown that both distinct formulations can be written in one form which provides an expectation about conformal case. 1. INTRODUCTION Recently a useful formulation which gives the total radiated power associated with the harmonic frequencies of a TMLA is published by Brégains et al. [1]. After this work, Poli et al. applied this same idea to rectangular grid planar arrays [2]. Both of these formulations provide calculation simplicity when the harmonic radiation is concerned but they are still in distinct forms. In this study, generalization of the formulation originally given in [2] which is constructed on the idea given in [1] to a grid independent form for linear cases is aimed while trying to keep the original notation as much as possible. 2. FORMULATION Consider a planar array consisting of total N elements whose elements are on the x-y plane but not on a canonical grid. The array factor of this array may be written as X In gn (t) ejkxn sin θ cos φ ejkyn sin θ sin φ , (1) AF (θ, φ, t) = ejω0 t hni where xn and yn represent apsis and ordinate values in standard Cartesian coordinate system of corresponding element, respectively. k is the wave number and In represents the element excitations. gn (t) is a periodic function. Since gn (t) is periodic it can be expanded to Fourier Series which is: ∞ X gn (t) = Gnh ejhωp t , (2) h=−∞ where Gnh 1 = Tp Z Tp /2 −Tp /2 gn (t) e−jhωp t dt. (3) As in [2] it is also assumed that: ( gn (t) = 1, 0 < |t| ≤ t̃2n . 0, otherwise According to [1] and [2] the total power radiated on harmonics is given by: Z Z ∞ 1 2π π X PSR = |µh (θ, φ)|2 sin θdθdφ 2 0 0 (4) (5) h=−∞ h6=0 where µh (θ, φ) for planar arrays can be written as: X µh (θ, φ) = In ejkxn sin θ cos φ ejkyn sin θ sin φ hni From relation |µh (θ, φ)|2 = µh (θ, φ) µ∗h (θ, φ), |µh (θ, φ)|2 becomes: (6) Progress In Electromagnetics Research Symposium Proceedings, Suzhou, China, Sept. 12–16, 2011 |µh (θ, φ)|2 = ∗ X In ejkxn sin θ cos φ ejkyn sin θ sin φ In ejkxn sin θ cos φ ejkyn sin θ sin φ X hni 2 |µh (θ, φ)| = 369 hni X 2 (|In | Gnh ) + N −1 X (7) < {Im In∗ } Gnh Gmh ejk(xm −xn ) sin θ cos φ ejk(ym −yn ) sin θ sin φ m,n=0 m6=n hni where < {·} represents the real part of a complex number, so that PSR becomes: PSR = where F1 (θ, φ) = 1 [F1 (θ, φ) + F2 (θ, φ)] 2 ∞ X X Z 2 (|In | Gnh ) h=−∞ hni h6=0 2π Z (8) π sin θdθdφ 0 (9) 0 and F2 (θ, φ) = ∞ X N −1 X < {Im In∗ } Gnh Gmh h=−∞ m,n=0 h6=0 m6=n Z 2πZ 0 π ejk(xm −xn ) sin θ cos φ ejk(ym −yn ) sin θ sin φ sin θdθdφ. 0 (10) Since Eq. (4) produces real results for Gnh ,Gmh and from [1], the infinite summation of Gnh Gmh becomes: ∞ X Gnh Gmh = τmnM inV al − τm τn , (11) h=−∞ h6=0 so that F1 (θ, φ) reduces to: F1 (θ, φ) = 4π X |In |2 [τn (1 − τn )] . (12) hni For F2 (θ, φ) the integral inside summation must be solved. To do this (like in [2]) by using: µ µ ¶¶ p b −1 2 2 a cos (x) + b sin (x) = a + b cos x − tan , (13) a complex exponentials in integrals becomes: “ “ ”” √ n jk sin θ (xm −xn )2 +(ym −yn )2 cos φ−tan−1 xym −y −xn m Fθ = e . (14) So integrals in Eq. (10) may be written as: Zπ Z2π “ “ ”” √ 2 2 −1 ym −yn ejk sin θ (xm −xn ) +(ym −yn ) cos φ−tan xm −xn dφ sin θdθ Fθ = 0 Zπ = ¶ µ q 2 2 2πJ0 k sin θ (xm − xn ) + (ym − yn ) sin θdθ. (15) 0 q Letting 0 (xm − xn )2 + (ym − yn )2 = C Eq. (15) may be written as: Zπ/2 2π −π/2 Z0 J0 (kC cos θ) cos θdθ = 2π −π/2 Zπ/2 J0 (kC cos θ) cos θdθ + 2π J0 (kC cos θ) cos θdθ 0 (16) PIERS Proceedings, Suzhou, China, September 12–16, 2011 370 By letting θ = −θ and since J0 (x) is even Eq. (16) reduces to: Zπ/2 2π Zπ/2 J0 (kC cos θ) cos θdθ = 4π J0 (kC cos θ) cos θdθ. (17) 0 −π/2 Again by letting u = π/2 − θ Eq. (17) becomes Zπ/2 Zπ 2π J0 (kC sin θ) sin θdθ = 2π 0 Zπ/2 J0 (kC cos θ) cos θdθ = 4π J0 (kC sin θ) sin θdθ. (18) 0 −π/2 Using the relation [3] z v+1 Jµ+v+1 (z) = v 2 Γ (v + 1) Zπ/2 Jµ (z sin θ) sinµ+1 θ cos2v+1 θdθ, (19) 0 and by letting µ = 0 and v = −1/2 Eq. (17) reduces to: ¡ ¢ Zπ/2 J1/2 (kC) Γ 21 sin (kC) √ 4π J0 (kC sin θ) sin θdθ = 4π = 4πj0 (kC) = 4π . kC 2kC (20) 0 Substituting Eq. (20) and Eq. (11) into Eq. (10) F2 (θ, φ) becomes: µ q ¶ 2 2 sin k (xm − xn ) + (ym − yn ) N −1 X ∗ q F2 (θ, φ) = 4π < {Im In } [τmnM inV al − τm τn ] . m,n=0 k (xm − xn )2 + (ym − yn )2 (21) m6=n Combining Eq. (12) and Eq. (21) PSR becomes: X |In |2 [τn (1 − τn )] PSR = 2π hni µ q ¶ 2 2 sin k (xm −xn ) +(ym −yn ) N −1 X q +2π |Im || In | cos (βm − βn )[τmnM inV al −τm τn ] .(22) m,n=0 k (xm −xn )2 +(ym −yn )2 m6=n Integrating Eq. (30) in [1] gives the same result for linear arrays (note that the domain of second summation is not the same with the case given here). PSR = 2π X |In |2 [τn (1−τn )]+2π hni N −1 X |Im In | cos (βm −βn ) [τmnM inV al −τm τn ] m,n=0 m6=n sin (k (zm −zn )) (23) k (zm −zn ) It can be easily seen from Eq. (22) and Eq. q (23) that both equations are in the same form q and can 2 2 be represented as one equation. Both (xm − xn ) + (ym − yn ) and (zm − zn ) = (zm − zn )2 gives the Euclidian distance and βm − βn gives the phase difference between distinct elements in standard Cartesian coordinate system and can be represented as dmn and ∆βmn , respectively. So that both formulations may be written in one form which is: PSR = 2π X hni |In |2 [τn (1 − τn )] + 2π N −1 X m,n=0 m6=n ³ ´ sin (kdmn ) . (24) |Im || In | cos ∆βmn [τmnM inV al − τm τn ] kdmn Progress In Electromagnetics Research Symposium Proceedings, Suzhou, China, Sept. 12–16, 2011 371 It must be noted that these formulations are valid if there exist only one pulse per period which are symmetric around t = 0. If there exist more than one pulse in each period Eq. (24) must be extended to a new general form and if relative positions of pulses are not symmetric around t = 0 total loss seems to be not equal to the symmetric cases. 3. CONCLUSION In this paper a general representation of total power loss calculation for planar and linear arrays and some comments about power loss calculations are presented. It is shown that both distinct formulations given in published works can be combined and written in one form. This form also provides an expectation about the conformal case. 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