11/5/2013 In this chapter, we will: Microelectronics Analyze and understand the characteristics of various bipolar circuits used to provide a constant output current. Analyze and understand the characteristics of various MOSFET circuits used to provide a constant output current. Analyze the dc characteristics of amplifier circuits using transistors as load devices (active loads). Analyze the small-signal characteristics of amplifier circuits with active loads. Design an NMOS current source circuit to provide a specified bias current and output resistance. Circuit Analysis and Design Donald A. Neamen Chapter 10 Integrated Circuit Biasing and Active Loads Neamen Microelectronics, 4e McGraw-Hill Chapter 10-1 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-3 Chapter 10-2 DC Equivalent Circuit: 2-Transistor Current Source 2-Transistor Current Source Neamen Microelectronics, 4e McGraw-Hill Neamen Microelectronics, 4e McGraw-Hill Chapter 10-4 1 11/5/2013 2-Transistor Current Source Neamen Microelectronics, 4e McGraw-Hill Chapter 10-5 2-Transistor Current Source Neamen Microelectronics, 4e McGraw-Hill Chapter 10-6 3-Transistor Current Source 3-Transistor Current Sources produce stable Io as β changes. = = Neamen Microelectronics, 4e McGraw-Hill Chapter 10-7 Neamen Microelectronics, 4e McGraw-Hill 2 1+ (1 + ) − − − _ Chapter 10-8 2 11/5/2013 Problem-Solving Technique: BJT Current Source Circuits Other 3 T Current Sources Widlar Wilson (Io not same as Iref) (higher output resistance) 1. Sum currents at various nodes to find relation between reference and bias currents 2. To find output resistance place test voltage at output node and analyze small-signal equivalent circuit. Since the reference current is a constant some base voltages may be constant or at ac ground. Neamen Microelectronics, 4e McGraw-Hill Chapter 10-9 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-10 Widlar Current Source Analysis $1% 2 = 23 Widlar Current Source = 10 / = 5 = =3 = 6 % Which is too large for most IC designs Microelectronics, 4e McGraw-Hill Chapter 10-11 < sothat = E ln 6 3 = E ln ()% 6 − 3 = E ln H%%I'I#'( − 3 = 3 ≅ Finally ) = E ln( "#$%&#'%()( 5 − 0.7 − (−5) = = 0.9/Ω 10,10 - Neamen 789: 7; >89? <> ; ()% ≅ 5 = 6 % Neamen Microelectronics, 4e McGraw-Hill Chapter 10-12 3 11/5/2013 Multi-transistor current Mirror Multi-output Current Mirror 1. 2 'HI%I(%H'%. Q = + 3 + 2. %H(J$'H)%H 3. 'HLL$'%(M#(L#( 2N HH Multitransistor = 3 = ⋯ = P = Neamen (1 + M) 1+ Microelectronics, 4e McGraw-Hill Chapter 10-13 Neamen Chapter 10-14 MOSFET Current Source Generalized Current Mirror = Microelectronics, 4e McGraw-Hill − − − Q = = Q Q3 = 2 QR = 3 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-15 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-16 4 11/5/2013 MOSFET Current Source MOSFET Current Source Alternatively Neamen Microelectronics, 4e McGraw-Hill Chapter 10-17 MOSFET Current Source Neamen Microelectronics, 4e McGraw-Hill Chapter 10-19 Chapter 10-18 MOSFET Wilson Current Source These provide higher output impedance. Uses M3 instead of a resistor Neamen Microelectronics, 4e McGraw-Hill Neamen Microelectronics, 4e McGraw-Hill Chapter 10-20 5 11/5/2013 BJT Amplifier with Active Load Neamen Microelectronics, 4e McGraw-Hill Chapter 10-21 BJT Amplifier with Active Load BJT Amplifier with Active Load Neamen Microelectronics, 4e McGraw-Hill Chapter 10-22 BJT Amplifier with Active Load In the forward active region the Output voltage is in the range =U(6VW) < Q < ( − =3 6VW ) The output voltage from Eqn. 10.82 is 7: < SP ST 6Q % 7; SP = 1− + ( − 3 ) SP + ST SP + ST Neamen Microelectronics, 4e McGraw-Hill Chapter 10-23 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-24 6 11/5/2013 Voltage Gain of BJT Amplifier with Active Load Characteristics of Bipolar Circuit with Active Load The derivative of Eqn. 10.82 is 7[ < SP ST 6Q % 7; 1 Y = = −( ) ( ) Z SP + ST E ≅ 6Q % 7[ <7 ; SP ST Y = =− Z SP + ST Neamen 1 = E 1 − E 1 1 SP + ST Microelectronics, 4e McGraw-Hill Chapter 10-25 MOSFET Amplifier with Active Load = Neamen Neamen Microelectronics, 4e McGraw-Hill Chapter 10-26 MOSFET Amplifier with Active Load 3 [1 + λ^ − _` ] cb (Z − EP ) − λ^ + λb (λ^ + λb ) Microelectronics, 4e McGraw-Hill Chapter 10-27 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-28 7 11/5/2013 Small-Signal Equivalent Circuit: BJT Active Load MOSFET Amplifier with Active Load Y = −2cb (Z − EP ) = Z (λb + λ^ ) H'I%1d = 2cb (Z − EP ) and = Z e9f g Y = Neamen −1d = −1d (b ||^ ) 1 1 + b ^ Microelectronics, 4e McGraw-Hill The resistance looking into the collector of Q2 is just = 3 Chapter 10-29 Fig. 10.37 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-30 Fig. 10.37 Y = Q = −1d i ( 3 j ) Y = = −1d ( 3 j ) k = −1d ( 3 j ) k Note: 1d = Zl<7; & = 7no<Zl &3 = 7np<Zl Hqj = ∞; 1 −( ) E Y = 1 1 + SP ST As before!! Neamen Microelectronics, 4e McGraw-Hill Chapter 10-31 Neamen Microelectronics, 4e McGraw-Hill Chapter 10-32 8 11/5/2013 Fig. 10.40 Small-Signal Equivalent Circuit: MOSFET Active Load Y = Neamen Microelectronics, 4e McGraw-Hill Chapter 10-33 Neamen = −1d ( 3 j ) k Microelectronics, 4e McGraw-Hill Chapter 10-34 9