ESI The Erwin Schrodinger International Institute for Mathematical Physics Boltzmanngasse 9 A-1090 Wien, Austria On the Berezin-Toeplitz Calculus L.A. Coburn Vienna, Preprint ESI 834 (2000) Supported by Federal Ministry of Science and Transport, Austria Available via http://www.esi.ac.at January 26, 2000 On the Berezin-Toeplitz Calculus* L.A. Coburn Abstract I consider the problem of composing Berezin-Toeplitz operators on the Hilbert space of Gaussian square-integrable entire functions on complex nspace, Cn . For several interesting algebras of functions on Cn , we have T'T = T' for all '; in the algebra, where T' is the Berezin-Toeplitz operator associated with ' and ' is a \twisted" associative product on the algebra of functions. On the other hand, there is a C 1 function ' for which T' is bounded but T'T' 6= T for any . *Research supported by a grant of the NSF and a visiting membership in the Erwin Schrodinger Institute. 1991 Mathematics Subject Classi cation: Primary 47B35, Secondary 47D25. 1 1. Introduction. For z = (z ; :::; zn) in complex n-space, Cn ; with zj in C; z w = z w + ::: + znwn ; consider the space L (Cn ; d) of Gaussian squareintegrable complex-valued functions on Cn , with d(z) = expf? jzj =2gdv(z)(2)?n with dv(z) Lebesgue measure. The entire functions in L (Cn ; d) form a closed subspace H (Cn ; d) which arises naturally as a representation space of the Heisenberg group [B, F, BC1; C]. On this (Segal-Bargmann) space, there are natural operators, formally introduced by Berezin [Be], de ned densely for '() with '(w)ewa in L (Cn ; d) for all a in Cn ; by 1 1 2 1 2 2 2 2 Z (T'f )(z) = ezw= '(w)f (w)d(w): 2 C n The (possibly unbounded) operator T' is called the Berezin-Toeplitz operator associated to ': Note that H (Cn ; d) is a Bergman space with reproducing kernel function eza= for the functional of \evaluation at a" [B]. Note also that T' = 0 if and only if ' = 0 [F, p. 140]. The operators T' are closely related to pseudodi erential operators on L (Rn ; dv ). For ' bounded, and somewhat more generally, the relation is given by 2 2 2 B ? T'B = W ' 1 where B is the Bargmann isometry [Gu], W is the Weyl operator on L (Rn; dv) given by 2 (W g)(x) = (2)?n Z Z + '(; x) = ?n Z ( n '(w)e?jw? x?i j dv (w): ( C ) 2 RR n and (; x y )ei x?y g(y)dyd; ) 2 n The operators T' might, therefore be expected to share many of the properties of pseudodi erential operators. It is not easy to demonstrate a 2 complete equivalence, partly because ' is a \very smoothed" version of ': The analytic structure of H (Cn ; d) also enters the picture so that, for example, T'Tz = T'z : Moreover, the available function-theoretic machinery on H (Cn ; d) is relatively rudimentary, limited primarily to the Bergman space structure and the structure inherited as a representation space of the Heisenberg group. In this note, I deal with the composition problem: is there a function ' so that T'T = T' ? (*) As a consequence of representation-theoretic results in [C], we do have (*) for a reasonably large class of bounded '; and there is an explicit formula for ' . The same \Moyal-type" formula also holds for a large class of unbounded '; (with unbounded T'; T ; T' ) { precisely, '; can be arbitrary polynomials in fzj ; zj : 1 j ng: On the other hand, I will exhibit a '; (unbounded, but C 1) for which T' is a bounded operator but T'T' can not be approximated in norm by bounded Berezin-Toeplitz operators. Thus, there is a genuine limitation on our ability to compose Berezin-Toeplitz operators. I thank Don Schack for useful comments. 2 j j 2 3 2. Composition of Berezin-Toeplitz operators. For C 1 functions '; we consider the (formal) twisted product ' = X k (?2)jkj (@ k ')(@k ) k! (**) where k = (k ; :::; kn) with kj non-negative integers, and 1 = @z@ ; @j = @z@ k k k @ k = @ k1 :::@nk ; @ = @ 1 :::@n jkj = k + k + ::: + kn k ! = k !k !:::kn!: @j j j n n 1 1 1 1 2 2 In the cases we will consider, the sum in (**) will converge. The rst case we consider arises from representation-theoretic considerations of the Heisenberg group [C]. We consider '; in the \smooth Bochner algebra" Ba(Cn ) which consists of all Fourier-Stieltjes transforms of compactly supported, regular, bounded complex-valued Borel measures on Cn : More precisely, let a(z ) = expfi Im(z a)g: Then Ba(Cn ) consists of all functions ^ (z ) = Z C a (z ) d (a) n where is a compactly supported, regular, bounded complex-valued Borel measure. It is well known that such functions are bounded, uniformly continuous, with bounded derivatives of all orders. As our rst positive result, we have Theorem 1. For '; in Ba(Cn ), ' is also in Ba(Cn ) and T'T = T' : The series in (**) converges uniformly and absolutely. 4 Proof. In [C], I showed that for ' = ^ ; = ^ in Ba(Cn ); = T b . T'T ( ) Here, we de ned for all in C (Cn ) by 0 Z C (c) d( )(c) = ( )b(z) = CC Z Z n a b (z )eba= d (a) d (b) (***) 2 CC n Ba (Cn ): (a + b)eba= d (a) d (b) 2 n n so that Z Z + n is in Expanding eba= in McLaurin series in (***) gives 2 ( )b(z) = 1 X s 1 X =0 = s 1 X =0 = s 1 1 1 Z X ! 2s ji n aj1 :::aj a(z ) d (a) s X ! 2s s bj1 :::bj b (z )d (b) s ji n 2s (@j1 :::@j ')(?2)s (@j1 :::@j ) s s 1 ? s ( Z 1 X (@j1 :::@js')(@j1 :::@js ji n X (?2)jkj k ( @ k ')(@ ) k! k s =0 = 1 2) s ! ) 1 and it is clear that the series converges uniformly and absolutely. Comparison with (**) shows that T'T = T' and completes the proof. Our second case consists of '; arbitrary polynomials in fzj ; zj : 1 j ng: Here, the operators T'; T are unbounded and we need to be a little more careful. Nevertheless, we have for ' given by (**), Theorem 2. For '; polynomials in (z ; :::; zn; z ; :::; zn); we have T'T de ned on a dense domain consisting of linear combinations of functions of 1 5 1 the form fp(z)eza : a 2 Cn and p(z) polynomial in (z ; :::; zn)g: On this domain T'T = T' and ' is polynomial in the zj ; zj : 1 Proof. Clearly, Tz = 2@j and it is now easy to check that T' p(z)eza = q (z )eza j where p; q are polynomial in z ; :::; zn: The proof of the composition formula is inductive, in several steps. We note rst that, for ' polynomial in fzj ; zj : 1 j ng; T'Tz = T'z implies T'jz j2 = T'Tjz j2 : This is because 1 j j j j = (T'Tz )Tz = T 'z z = T'jz j2 : T'Tjz j2 j j ( j j) j j Next, we check inductively that T'Tz = T'z for all ' polynomial in fzj ; zj : 1 j ng: It is enough to consider ' monomial. Assume the result for ' of xed degree (' constant is trivial). The inductive step is: j j T'z Tz k j = T'Tz Tz = T 'z z = T'z z k 6= j; j j) k ( j k T'z Tz j j = = = = = T'(Tz Tz ) T'(Tjz j2 ? 2I ) T'Tjz j2 ? T ' T'jz j2 ? ' T'z z ; j k j 2 j j j j j k 2 k( j j k j 2 j k j j j = Tz (T'Tz ) = Tz = T'z z ? z @ ' = Tz 'z : for all '. Tz ' Tz Thus, T'Tz = T'z k 6 ) 'zj k( ) Next, for arbitrary ' we consider T'T and do induction on the degree of . We can assume is monomial. Assume the result for all ' and for of xed degree ( constant is trivial). The inductive step is, rst, T'T z j = (T'T )Tz = T ' ( j z ) j = T' z : j We must also consider T'Tz = (T'Tz )T : j j By the rst part of the proof, T'Tz j = T'z j and by the inductive hypothesis T'z T j = T 'z ( : j) Thus, we need only check that ' zj = (' zj ) : This is a direct calculation. We note that ' zj = 'zj ? 2(@j ') so (' zj ) = 'zj ? 2(@j ') X (?2)jkj k = zj (@ k ')(@ ) k! k jkj X ?2 (?k2)! (@ k @j ')(@k ): k Using k @ (z j ) = zj (@ k ) + kj (@ k? ) j 7 where k ? j = (k ; k ; :::; kj ? 1; kj ; :::; kn); 1 2 +1 we see that (?2)jkj (@ k ')(@k z ) j k! k X (?2)jkj k z j (@ k ')(@ ) = k! k jkj X + (?k2)! (@ k ')kj (@ k? ): k ' zj = X j Thus, we need only check that X k (?2)jkj (@ k ')k (@ k? ) = ?2 X (?2)jkj (@ k @ ')(@k ): j j k! k! k j Reindexing the sum on the left by ` = k ? j completes the proof. Remark. Since zj = zj ; the identity ' zj = (' zj ) follows from the reasonably well-known associativity of [G]. Our computational proof has the advantage of giving associativity of as an immediate corollary of Theorem 2 since T' ( ) = T'(T T ) = (T'T )T = T ' ( 8 : ) 3. T' with T'T' 6= T for any : In this section, I produce the promised obstruction to composition of Berezin-Toeplitz operators. I use some calculations from [BC2]. I begin with a needed improvement of [BC2: Theorem 17]. In this section, we work on H (C; d) (n = 1): Here, the Bergman reproducing kernel function for evaluation at z is just 2 K (w; z ) = ewz= 2 and it follows that q 2 kz (w) = K (w; z )= K (z; z ) = ewz= ?jzj = 2 4 is a unit vector in H (C; d): We consider the unitary operator 2 (Raf )(z) = f (az) on H (C; d) for jaj = 1: Theorem 3. For jaj = 1 and Re a < 0, we have 2 kRa ? T k 1 for all such that K (; z) is in L (C; d) for every z in C: Proof. We consider 2 kT ? Rak jhT jhT kz ; Ra kz i ? hRa kz ; Rakz ij kz ; Ra kz i ? 1j : Now, hT 2 kz ; Ra kz i = h z ; K (; (1 + a)z )i e?jzj = 2 so we have jhT kz ; Rakz ij q e?jzj = k k K ((1 + a)z; (1 + a)z) k k e?jzj = ej aj jzj = k k ejzj a= : 2 2 2 2 2 Re 9 1+ 2 2 2 4 Since Re a < 0, we see that jhT kz ; Rakz ij ! 0 as jzj ! 1. Thus, kT ? Rak 1: The function ' will be chosen to have the form '(z) = ejzj2 where Re < so that T' makes sense. 1 4 Lemma. For = + i and '(z) = ejzj ; we have T' unitary with 1 2 5 5 2 T'T' = aRa for a = (1 ? 2) = ? + i . Proof. Re < and calculations outlined in [BC2; p. 582] show that T' is diagonal in the basis ek = (2k k !)? = z k ; k = 0; 1; ::: for H (C; d); with T'ek = (1 ? 2)? k ek : Now = +i and so 2 7 24 25 25 1 4 1 2 2 ( +1) T'T'ek 1 2 5 5 = (1 ? 2) = ak ek : k 2( +1) ek +1 But aRaek = ak ek +1 and we are done. We now have the promised Theorem 4. For = +i and a = (1 ? 2) = ? + i, with '(z) = ejzj2 , kT'T' ? T k 1 for all such that K (; z) is in L (C;d) for every z in C. Proof. Direct combination of Theorem 3 and the Lemma. 1 2 5 5 2 2 10 7 24 25 25 4. Remarks. There is a considerable space between Theorems 1 and 2 and Theorem 4. It does not seem easy to lift the known much stronger positive results directly over from the setting of pseudodi erential operators. It does seem likely that (**) provides a composition formula for BerezinToeplitz operators in a setting substantially larger than those of Theorems 1 and 2. For non-C 1 '; or even for general C 1 '; ; the problem of determining whether there is a ' with T'T = T' ; as well as the form of ' remains open. Theorems 1 and 2 can be extended to the natural family of Gaussian measures on Cn which provide representation spaces for the Heisenberg group [C]. For dr (z) = ( r )ne?rjzj2 dv(z) with r > 0 and H (Cn ; dr ) as before, we have Bergman kernels 2 Kr (w; z ) = erwz and Berezin-Toeplitz operators on H (Cn ; dr ) 2 Z (T' r f )(z) = erzw '(w) f (w) dr (w): ( ) C n Then minor modi cations yield Theorem 10: For '; in Ba(Cn); ' r is also in Ba(Cn ) for X k ' r = ( ?r )jkj k (@ k ') (@ ) (y) 1 1 ! k and T' r T r = T'r : The series in (y) converges uniformly and absolutely. Moreover, for r > 1 X ( ? )jkj (@ k ')(@k )k 1 C ('; ; K ) k' ? ( ) ( ) ( ) r r 1 k jkjK r 1 1 k ! rK +1 for C ('; ; K ) a constant independent of r: Theorem 20. For '; polynomials in (z ; :::; zn; z ; :::; zn); we have T' r T 1 ( ) 1 r ( ) de ned on a dense domain consisting of linear combinations of functions of the form fp(z)eza : a 2 Cn and p(z) polynomial in (z ; :::; zn)g: On this domain 1 11 T' r T r ( ) ( ) = T'r ( ) r for ' r given by (y) and ' r is polynomial in the zj ; zj : While Theorems 1 and 2 provide some basis for optimism about the development of a reasonably extensive Berezin-Toeplitz calculus on Cn , the situation is considerably less promising on the classical Bergman space of the disc, H (D; dA ) where D = fz 2 C : jzj < 1g and dA is normalized Lebesgue area measure. In this case, the Bergman kernel function is just K (z; w) = (1 ? zw )? and the Berezin-Toeplitz operator T' on H (D; dA ) is given by Z (T'f )(z) = K (z; w) '(w) f (w) dAw : 2 2 2 ( ) D Direct calculation shows, rst, that Tz Tz Moreover, R where P f = f (z) dA z 0 D ( ) =T jzj2 : 1+log =T jzj2 + P and P 6= T' for any ': Tz2 Tz 2 1+2 log 0 0 References [B] V. Bargmann, On a Hilbert space of analytic functions and an associated integral transform, Comm. Pure and Appl. Math. 14 (1961), 187-214. [Be] F. A. Berezin, Covariant and contravariant symbols of operators, Math. USSR Izv. 6 (1972), 117-1151. [BC1] C. A. Berger and L. A. Coburn, Toeplitz operators on the SegalBargmann space, Trans. AMS 301 (1987), 813-829. , Heat ow and Berezin-Toeplitz estimates, Amer. [BC2] J. Math. 116 (1994), 563-590. 12 [C] L. A. Coburn, The measure algebra of the Heisenberg group, J. Funct. Analysis 161 (1999), 509-525. [F] G. B. Folland, Harmonic analysis in phase space, Annals of Math. Studies, Princeton Univ. Press, Princeton, N.J., 1989. [G] M. Gerstenhaber, On the deformation of rings and algebras, III, Annals of Math. (2) 88 (1968), 1-34. [Gu] V. Guillemin, Toeplitz operators in n-dimensions, Integral Equations and Operator Theory 7 (1984), 145-205. State University of New York at Bu alo Bu alo, NY 14214, USA email: lcoburn@acsu.bu alo.edu 13