Electronics II Lab EELE 3120 Experiments #4 Frequency Response of BJT 1) Objectives: To study the frequency response and bandwidth of the common emitter CE-BJT, the common collector CC-BJT, and the common base CB-BJT amplifiers. 2) Introduction: Most amplifiers have relatively constant gain across a range or band of frequencies, this band of frequencies is referred to as the bandwidth (BW) of the circuit. Bandwidth means the difference between the upper and lower frequencies of the frequency response as shown in the figure 4.1 Figure 4.1: the frequency response of BJT When operated within its bandwidth, the values of π΄π£ & π΄π for an amplifier are calculated as shown earlier, these values are referred to as mid-band gain values, and are designated as π΄π£πππ & π΄ππππ . The frequency response is a graphical representation of the relationship between amplifier gain and operating frequency for input signal, as an example sinusoidal signal. Page 1 of 8 Electronics II Lab EELE 3120 So why we need this type of analysis for an amplifier, because we need to determine the: - To determine the stability region for amplifier systems. To design an amplifier systems that met the required specifications. 3) AC & DC Analysis: a) DC Analysis: As we know the frequency in DC is equal zero because there is no oscillation in DC signal so, the reactance of capacitor is equal infinity that mean the capacitors work as open circuit. b) AC Analysis: In this analysis we will study the effect of capacitors in different level of frequencies as: ο· ο· ο· Low frequency Middle frequency High frequency Before we start our analysis we need first know the names of capacitors and its locations, there are two type of capacitor: ο· ο· Practical capacitors: Cin, Cout, CE these capacitors are connected as shown in figure 4.1 and it’s effective in low frequency. Virtual capacitors: Cwi, Cwo, CBE, CBC, CCE these capacitors are appears and effectives on the high frequency because its value in Nano-farad. Page 2 of 8 Electronics II Lab EELE 3120 Cases of capacitor: ο· ο· ο· At very low frequency the capacitor work as open circuit. At very high frequency the capacitor work as short circuit. At normal frequency the capacitor have a magnitude and effect on the frequency response. ππ = 1 2πππ Now, we will show the relationship between the voltage gain and varying frequency and defined the regions on this curve as shown in figure 4.2 Figure 4.2: The frequency response of BJT amplifier Figure 4.3: The sample circuit diagram of BJT amplifier Page 3 of 8 Electronics II Lab ο· EELE 3120 Low frequency response of BJT amplifier: (π → ππππ ) At this region all capacitors will be open circuit because its reactance will be equal infinity at π = 0 and π΄π£ = 0. Now, if the frequency increase slightly the voltage gain will be increase also until the frequency reach to low cut frequency, after this critical point the capacitors will be short circuit and voltage gain raise to the maximum value (π΄π£(πππ) ). 1- πΆππ ππ‘ πΆππ’π‘ & πΆπΈ short circuit: πππΆππ = 1 2π(π π + ππ)πΆππ Where: πππ = π 1//π 2//π΅ππ 2- πΆππ’π‘ ππ‘ πΆππ & πΆπΈ short circuit: πππΆππ’π‘ = 1 2π(π π + π π)πΆππ’π‘ 3- πΆπΈ ππ‘ πΆππ & πΆππ’π‘ short circuit: πππΆπΈ = 1 π `π + π΅ππ 2π (π πΈ + ) πΆπΈ π΅ Where: π `π = π π //π 1//π 2 ο· High frequency response of BJT amplifier: (πππππ → ∞) In this region will be appear the effect of virtual capacitors which called parasitic effect (πΆπ€π, πΆπ€π, πΆπ΅πΈ, πΆπΆπΈ, πΆπΆπ΅), and its value in Nano-farad. These capacitors at very high frequency will be short circuit and it reactance equal zero, and the voltage gain goes to zero. In this region all practical capacitors are short circuit also. Page 4 of 8 Electronics II Lab EELE 3120 1- At πΆππ, πΆππ’π‘, πΆπΈ are short circuit: πΆπ = πΆπ€π//πΆπ΅πΈ//πΆππ πΆππ = πΆπ΅πΈ[1 − π΄π£] πΆπ = πΆπ€π + πΆπ΅πΈ + πΆππ πΆπ = πΆπ€π//πΆπΆπΈ//πΆππ πΆππ = πΆπ΅πΆ[1 − 1 ] π΄π£ πΆπ = πΆπ€π + πΆπΆπΈ + πΆππ 2- High frequency law: πβπ = 1 2ππ π‘βπ ∗ πΆπ πβπ = 1 2ππ π‘βπ ∗ πΆπ π π‘βπ = π΅ππ//π 1//π 2//π π π π‘βπ = π πΏ//π π//ππ Page 5 of 8 Electronics II Lab EELE 3120 Before we are going to lab work we need to know some important definitions which we need them in design. Logarithm: π₯ = log π π , π = π π₯ Why we need log scale? To represent a large scale of frequency start from π»π§ and goes to ππ»π§. There are two modes of log scale: - Semi Log: that mean the x-axis is logarithm increment and y-axis is linear increment. Double Log: that mean the x-axis and y-axis are logarithm increment. Decibels: (dB) 1 ππ΅ = 10 log10 π2 π1 1 ππ΅ = 20 log10 π΄π£ Notes: - To find the Low cut off frequency ππΏ = ππ΄π(ππΏπππ , ππΏπππ’π‘ , ππΏππ ). To find the upper cut off frequency ππ» = ππΌπ(ππ»π , ππ»π ) Page 6 of 8 Electronics II Lab EELE 3120 4) Lab work: Figure 4.4: Common Emitter Amplifier 1- Connect the circuit in figure 4.4. 2- Adjust the DC power supply at 20Vdc. 3- Adjust the function generator to sinusoidal of ππ = 1πππ at a frequency 1πΎπ»π§. 4- Measure the output voltage Vo RMS value (AC mode in Multi-meter device). 5- Calculate π΄π£πππ & 0.707π΄π£πππ which be equal 0.707ππ because the input voltage equal 1πππ. 6- Now decrease the frequency of input signal to get π`π = 0.707ππ on Multi-meter screen to find ππΏ . 7- Then increase the frequency of input signal to get π`π = 0.707ππ on Multi-meter screen to find ππ» . 8- Now calculate the Bandwidth π΅π = ππ» − ππΏ . 9- Now varying the frequency of function generator according to table 1 shown below and measure the variable on each level. 10- Plot the voltage gain π΄π£ relative to frequency. Page 7 of 8 Electronics II Lab EELE 3120 Frequency (Hz) Vin (RMS) Vo (RMS) π¨π = π½π⁄π½ππ 1 10 100 1k 10k 50k 100k 1M 2M 5M Table 1: Common Emitter Amplifier result 5) Exercise: 1- Repeat all steps for common emitter amplifier using Orcad. 2- Repeat all steps for emitter follower amplifier which shown below using Orcad. Page 8 of 8