Lab-Report Analogue Electronics The Common-Emitter Amplifier Name: Course: Group: Student No.: Date: Dirk Becker BEng 2 A 9801351 30/10/1998 1. Contents 1. 2. 3. a) b) c) d) 4. a) b) c) d) e) 5. a) b) c) 6. 7. a) b) c) 8. a) b) c) d) 9. a) b) c) CONTENTS ............................................................................................................................................ 2 INTRODUCTION .................................................................................................................................. 3 DC BIAS OF COMMON-EMITTER AMPLIFIER ........................................................................... 3 Measurment of the “true” resistor values.................................................................................................. 3 DC-bias precalculation with given resistors ............................................................................................. 4 Measurement of DC-Voltages (DC-bias) ................................................................................................. 5 Calculation of IB, IC and β with measured values ..................................................................................... 5 i. IB with IE and IC (RE and RC)..................................................................................................................... 5 ii. IB with I1 and I2 (R1 and R2) ................................................................................................................. 5 AC AND SMALL SIGNAL CHARACTERISTICS............................................................................ 6 BJT small signal behavioural model......................................................................................................... 6 Definitions of the small signal parameters................................................................................................ 6 Measured small signal values ................................................................................................................... 7 Calculation and derivation of the small signal parameters ....................................................................... 7 i. Amplifier input resistance Ri ..................................................................................................................... 7 ii. Amplifier output resistance Ro ............................................................................................................. 8 iii. Voltage amplification without load Avo ................................................................................................ 9 iv. Voltage amplification with load Av ...................................................................................................... 9 v. Current amplification Ai .................................................................................................................... 10 vi. Amplifier power gain Ap ..................................................................................................................... 10 Comparison between measured and calculated values ........................................................................... 11 i. DC-Bias .................................................................................................................................................. 11 ii. Small signal parameters..................................................................................................................... 11 FREQUENCY RESPONSE OF THE CE-AMPLIFIER................................................................... 12 Measured frequency response of Av ....................................................................................................... 12 Determination of the theoretical cut-off frequency................................................................................. 13 Frequency response of Ai........................................................................................................................ 16 DISCONNECTION OF BYPASS CAPACITOR C3 ......................................................................... 18 DC-BIAS WITH DISCONNECTED C3 ............................................................................................. 18 Calculation of DC-Bias........................................................................................................................... 18 Measurement of DC-Voltages (DC-bias) ............................................................................................... 18 Calculation of IB, IC and β with measured values( C3 disconnected) ...................................................... 19 i. IB with IE and IC (RE and RC)................................................................................................................... 19 ii. IB with I1 and I2 (R1 and R2) ............................................................................................................... 19 AC AND SMALL SIGNAL CHARACTERISTICS (WITHOUT C3) ............................................. 20 BJT small signal behavioural model....................................................................................................... 20 Measured small signal values without C3 ............................................................................................... 20 Calculation and derivation of the small signal parameters (mid freq., without C3) ................................ 21 i. Amplifier input resistance Ri ................................................................................................................... 21 ii. Amplifier output resistance Ro ........................................................................................................... 22 iii. Voltage amplification at mid frequencies without load...................................................................... 22 iv. Voltage amplification at mid frequencies with load........................................................................... 23 v. Current amplification Ai .................................................................................................................... 23 vi. Amplifier power gain Ap ..................................................................................................................... 24 Comparison between measured and calculated values ........................................................................... 24 FREQUENCY RESPONSE OF THE CE-AMPLIFIER WITHOUT C3 ......................................... 25 Frequency response of Av ....................................................................................................................... 25 Theoretical calculation of the lower cut-off frequency........................................................................... 27 Frequency response of Ai without C3...................................................................................................... 29 2 2. Introduction The common-emitter amplifier is one of the most common discrete amplifier used in conventional electronics. Its special characteristics were to be discovered in this lab session. 3. DC bias of common-emitter amplifier figure 1 a) Measurment of the “true” resistor values For calculating the correct bias values at first the real values of the used resistors and capacitors have to be measured, because they all have got deviations from the printed values. Also a measurement of the very small currents is not possible. So the voltage drop across the different devices has to be determined and then the flowing current can be calculated via KCL and Ohm’s law. The following values were measured: RS=3.26kΩ R1=9.99kΩ R2=55.7kΩ RE=986Ω RC=3.82kΩ RL=6.72kΩ C1=80.54µF C2=8.949µF C3=9.177µF 3 b) DC-bias precalculation with given resistors β=200, VBE=0.7V ! - " ! " . RI = R 1R 2 10kΩ ⋅ 56kΩ = = 8.485kΩ R 1 + R 2 10kΩ + 56kΩ Vo = R1 10kΩ VCC = 10V = 1.515V R1 + R 2 10kΩ + 56kΩ & ' ( ) * + ( #$ % - 3 2 , with VBE = 0.7 V - , - - 0 #$ 1 4 / 0 , ! 5 , 1 6 , KCL : 0V = I E R E − VO + R I I B - 7 - + 7 9 " : 8 0V = (I C + I B ) − VO + R I I B 0V = I B (βR E + R E + R 1 ) − VO R1 10kΩ VCC 10V VO R1 + R 2 10 k 56 k Ω + Ω IB = = = = 7.232µA R 1R 2 βR E + R E + R I 200 ⋅ 1000Ω + 1000Ω + 8.485kΩ βR E + R E + R1 + R 2 I C = βI B = 200 ⋅ 7.232µA = 1.446mA I E = (β + 1)Ι Β I E = 201 ⋅ 7.232µΑ = 1.4536mA VRC = R C I C VRC = 3.9kΩ ⋅ 1.446mA VR 2 = VCC − VBE − VRE VRC = 5.639V VR 2 = 10V − 0.7 V − 1.454V VR 2 = 7.846V VRE = R E I E = R C [I B (β + 1) VRE = 1000Ω(7.232µA ⋅ 201) IR2 = VRE = 1.454V VR 2 7.846V = R2 56kΩ I R 2 = 0.140mA VCE = VCC − VRE − VRE VCE = 10V − 5.639V − 1.454V VC = VRE + VCE = 1.454V + 2.907V VCE = 2.907 V VC = 4.361V I R1 = VR1 = VCC − VR 2 VR1 2.54V = = 0.215mA R 1 10kΩ VR1 = 10V − 7.846V = 2.154V 4 c) Measurement of DC-Voltages (DC-bias) Next step was to measure the voltages in order to check the real bias and to calculate based on this values the DC current amplification and the other occurring currents and voltages. VR1=1.477V VR2=8.51V VRE=0.863V VRC=3.33V VC=6.66 VBE=0.618 VCE=5.80 d) Calculation of IB, IC and β with measured values i. IB with IE and IC (RE and RC) IE = VRE 0.863V = = 0.875mA RE 986Ω IC = VRC 3.33V = = 0.8713mA R C 3.82kΩ IB = IE − IC I B = 0.875mA − 0.8713mA I B = 3.7µA β = h fe = I C 0.8713mA = = 235 IB 3.7µA ii. IB with I1 and I2 (R1 and R2) I R1 = VR1 1.477V = = 0.14785mA R 1 9.99kΩ IR2 = VR 2 8.51V = = 0.15278mA R2 55.7kΩ I B = I R 2 − I R1 = 0.15278mA − 0.14785mA = 4.93µΑ β= I C 0.8713mA = = 177 IB 4.93µA 5 4. AC and small signal characteristics Next part of the lab was to determine the small signal characteristics of the common-emitter amplifier. Small signal characteristics are the essential values for the amplification function of the circuit. For calculation of these characteristics a special model is used, the small signal model of the BJT. These models are derived from the characteristic curves of the real devices and, when properly devised, can be used to predict accurately the behaviour of semiconductor devices in practical applications such as voltage and current amplification. By computer simulation more complex models can be used. a) BJT small signal behavioural model @ C @ @ A ? @ ; B < = H I J J L H L Q R S T U V Y S L H Z L U ; K W S X R > ; H H ? O D K ; < G M N N E F G G P figure 2 In the small signal model for mid frequencies the capacitors are short circuited because their impedance is negligble to the rest of the circuit. b) Definitions of the small signal parameters voc: vo: vs: vi: vrs: Ri: Ro: Avo: Av: Ai: Ap: open circuit output voltage output voltage with load signal voltage ampifier input voltage voltage drop across sensor resistor amplifier input resistance amplifier output resistance amplifier voltage gain without load amplifier voltage gain with load amplifier current gain amplifier power gain 6 [ c) Measured small signal values (A generator with f=1kHz works as voltage source V1) vs=20mV voc=1.242V vo=0.799V vi=10.8mV vrs=9.1mV d) Calculation and derivation of the small signal parameters ALL THEORETICAL VALUES WITH INDEX ‘ (i.e. R’) i. Amplifier input resistance Ri ` b ` a ] \ ^ g h i i k k p q r s t u r k \ _ j g l m n g c \ ] f d e f f o figure 3 Measured value of R i : Theoretical Values for R i : R 'i = R 'i = R 1 || R 2 || h fe re R 'i = R 1 || R 2 || h fe with re = 26mV IE vi v 10.8mV = i = = 3.87kΩ v rs 9.1mV ii 3.26kΩ rs 26mV IE R 'i = 10kΩ || 56kΩ || 200 R 'i = Ri = vi = R 1 || R 2 || h ie ii 26mV 1.453mA 1 1 1 1 + + 10kΩ 56kΩ 3.578kΩ = 2.52kΩ The theoretical value of Ri fits good with the determination due the measured values. The measurement of vi and ii was relative uncertain because of the small values and not using the whole range of the measuring instrument (~20mV to 200mV Range). 7 ii. Amplifier output resistance Ro y x | z v w x v { | ~ w } figure 4 Theoretical value of R o : Measured value of R o : R 'o = R C Ro = with h OE = 0S R ' o = 3.9kΩ Ro = v oc − v o vo RL 1.242V − 0.799V = 3.72kΩ 0.799V 6.72kΩ From these in the lab measured values hOE can be easily determined: 1 1 1 = + R O h OE R C 1 h OE = h OE = 1 1 − RO RC 1 1 1 − RO RC = 1 1 1 − 3.72kΩ 3.82kΩ h OE = 142.1kΩ It can be seen, that hOE can be let out at calculation of BJTs, because of its large value to the rest of the circuit. 8 iii. Voltage amplification without load Avo Theoretical values of A vo : A' vo = v oc vi A' vo = − icR C h i R = − fe B C h ie i B h ie i B A' vo = − A' vo = A vo = R L →∞ h fe R C =− h ie Measured value of A vo : h fe R C 26mV h fe IE v oc vi 1.242V 10.8mV A vo = 115 A vo = 3.9kΩ = 218 26mV 1.4536mA iv. Voltage amplification with load Av Measured value of A v : Theoretical value of A v : A' v = A' v = vo vi Av = − i c (R C R L ) A' v = − h fe (R c R L ) h ie 0.799V 10.8mV A v = 74 Av = h ie i B = h fe (R c R L ) 26mV h fe IE RC ⋅RL RC RL R + RL A' v = = C 26mV 26mV IE IE A' v = vo vi 2.479kΩ = 138 26mV 1.4536mA 9 v. Current amplification Ai Theoretical value of A i : A'i = iC iI A'i = h fe i B iI with i B = Measured value of A i : R1 R 2 h ie + R 1 R 2 v oc iC Rc Ai = = v rs iI Rs iI R1 R 2 R1 R 2 A'i = h fe = h fe h ie + R 1 R 2 h fe 26mV + R 1 R 2 IE 8.485kΩ A'i = 200 3.58kΩ + 8.485kΩ A'i = 140 Ai = 1.242V 9.1mV A i = 117 3.82kΩ 3.26kΩ vi. Amplifier power gain Ap Theeoretic values of A p : Measured value of A p : A' p = A i ⋅ A v A 'p = A i ⋅ A v A' p = h fe A' p = h fe h fe (R C R L ) RI h ie + R I h ie A'p = 74 ⋅117 A'p = 8658 RC RL RI h ie + R I 26mV IE 8.458kΩ 2.479kΩ ⋅ 3.58kΩ + 8.458kΩ 26mV 1.1436mA A' p = 19494 A' p = 200 10 e) Comparison between measured and calculated values i. DC-Bias Measurand measured VRC 3.33V VRE 0.863V VCE 5.80V VC 6.66V VR1 2.154V VR2 7.846V calculated 5.639V 1.454V 2.907V 4.361V 2.154V 7.846V hfe 237/ 177 200 ii. Small signal parameters Measurand measured calculated Rin 3.87 kΩ 2.52 kΩ Rout 3.72kΩ 3.9kΩ Avo 115 218 Av 74 138 Ai 117 140 Ap 8685 19494 The measured and the calculated values are partly very different. Major problem of the determination of the Bias and the small signal parameters were the uncertain measurements. Especially the small values like IB and the input current of the small signal equivalent circuit were very difficult to determine exactly. 11 5. Frequency response of the CE-amplifier a) Measured frequency response of Av The voltage amplification over a range from 10Hz to 1kHz was to measure to determine the cut-off frequency of the CE-Amplifier. f/Hz vi/mV vo/mV vo/vi 10 13.1 183.4 14 20 12.8 0.324 25.31 50 11.4 555 48.7 70 11.1 618 55.7 100 10.7 667 62.3 120 11.4 730 64 200 10.2 714 70 500 10 734 73.4 700 10 736 73.6 1000 10 738 73.8 Voltage Amplification vs frequency Av 100 − 3dB = 1 A v max 2 10 10 100 1000 f fc=58Hz figure 5 The cut-off frequency is defined as the frequency, when the amplification is dropped down to 70.7% (-3dB or ½√2). Below this frequency there is still amplification, but the frequency range of amplifiers is commonly defined by the 3dB cut-off freuency. 12 b) Determination of the theoretical cut-off frequency ¡ £ ¤ ¥ ¢ ¥ figure 6 Figure 6 shows the equivalent circuit for low and mid frequencies. To determine the cut-off frequency the input and output circuit has to be separated. ¦ ¦ ¦ ¯ § ¯ ± ¦ ± ¼ ¬ « © ¨ ² ° ª ³ ± ² ³ ½ ® ¯ µ ¶ · ¸ ¹ º · ¯ ¼ ± ¼ ¼ Â » ° ¼ ´ ± ¨ « ± ¿ À Á » © ¾ « ¿ » ± ² Ä » À Å » « Ã ® Æ Ç È É Æ Ç Ê Ë Ì « ¬ ­ figure 7 Input Current source ic=constant Output Í The cut-off frequency of the CE-Amplifier is above all depending on the emitter bypass capacitor CE=C3. The impedance of the two coupling capacitors is about 1500Ω at 10Hz each and can be neglected because of these small values in comparison to the rest of the circuit. For the input circuit: IB = vi h ie + R In + Z EIn where Z EIn = (β + 1)Z E = β +1 1 + jω C E RE = 1 C 1 + jω E β +1 (β + 1)R E 13 The current through (β+1)RE can be neglected because of it’s large resistance v in iB = β +1 ωC E h ie + R In − j The current IB will drop to 70.7% of it’s maximum value when the voltage drop at (hie+RIn) and ZE are of the same magnitude. 1 = R In + h ie ωC E β +1 β +1 ωcutoff = where R in = R 1 R 2 R S = 2.38kΩ C E (R in + h ie ) ωc = fc = 201 1 = 337 100µF(2.38kΩ + 3.577 kΩ) s ωc = 54Hz 2πf The calculated cut-off frequency is with 54Hz very close at the measured value of 58 Hz. The exact calculation of the cut-off frequency is very complex and is done in most cases with a computer and a simulation software like (P) or (H)spice. On the following pages (P)spice printouts of the simulated CE-Amplifier can be found. Ô Î â Ó Î Ô â ã Ð Î Ï à ä å å Ñ × Ò Ô Õ Ö Ö ß à Ó × Ñ ã Ô â à Ó à Î Ü Ø Î Î Ó Þ Ñ Î Î Ô Î ã à Ï Ð Ï Þ Ô à Õ Î æ Ð Ý å Þ Î Ï Ø Ð Ó Ù Ó Ó Ó Ó Þ Ô Î Î Î Ò × × Û Ò Ô Ò Ö × Î Î × Ï á Ú à Ö Î Ö Þ Ñ Ò Û Ü Î Ô Î Î Ò ä å Î Ý Ï Ï Ð Þ figure 8 figure 8 shows the BIAS calculated by a (P)spice simulation. 14 Ô â Ö Spice printout of frequency response AV 15 c) Frequency response of Ai f/Hz vrs/mV vo/mV v rs µA Rs 10 4.5 197 1.38 20 6.2 351 1.90 50 8.0 600 2.45 70 8.3 668 2.54 100 8.7 720 2.67 120 8.9 738 2.73 200 9.1 771 2.79 500 9.2 792 2.82 700 9.2 795 2.82 1000 9.3 797 2.85 vo µA RL Ai 29.31 52.23 89.29 99.4 107 110 115 118 118 119 21 27.5 36 40 40,5 41 42 42 42 39 Current Amplification vs frequency Ai 100 − 3dB = 1 A i max 2 10 10 100 fc=23Hz figure 9 The cut-off frequency of the current amplification is read out from the diagram 23Hz. This frequency is above all determined by the capacitor CE. 16 1000 f Spice printout of the frequency response of the current amplification Ai vs frequency 17 6. Disconnection of bypass capacitor C3 Next step of the Lab was to disconnect the Emitter bypass capacitor to proof the importance of the bypass capacitor especially on the voltage and current amplification, the main ó ó è í ð õ ö ñ ÷ ò ò è í ì é ê é è ë ï é é í é ó ô ð ò ë î í í í í ó ð ñ ó é ó ì é ë ù ø ö ñ ú ò ò é ì ë ç ï ò ô ê ç figure 10 Figure 10 shows the schematics of the CE-Amplifier with disconnected C3. 7. DC-Bias with disconnected C3 a) Calculation of DC-Bias The calculated DC-Bias with disconnected capacitor C3 can’t change, because C3 has no influence to any DC-values. C3 is not used for calculation of the DC-Bias and so it’s not able to change it. û see DC-Bias values at DC-bias precalculation with given resistors b) Measurement of DC-Voltages (DC-bias) The same DC-bias measurements were to make with disconnected C3 like in the first part of the Lab. VR1=1.479V VR2=8.47V VRE=0.849V VRC=3.27V VC=6.65 VBE=0.625 VCE=5.81 18 c) Calculation of IB, IC and β with measured values( C3 disconnected) i. IB with IE and IC (RE and RC) IE = VRE 0.849V = = 0.861mA RE 986Ω IC = VRC 3.27 V = = 0.856mA R C 3.82kΩ IB = IE − IC I B = 0.861mA − 0.856mA I B = 5µA β = h fe = I C 0.856mA = = 171.2 IB 5µA ii. IB with I1 and I2 (R1 and R2) I R1 = VR1 1.479V = = 0.14805mA R 1 9.99kΩ IR2 = VR 2 8.47V = = 0.15206mA R2 55.7kΩ I B = I R 2 − I R1 = 0.15206mA − 0.14805mA = 4.01µΑ β= I C 0.856mA = = 213 IB 4.01µA The different values of β=hfe can be led back to the uncertainty of measurement, because the measured values were very small and at the lower range of the measuring instrument. 19 8. AC and small signal characteristics (without C3) Next part of the lab was to determine the small signal characteristics of the common-emitter amplifier. By computer simulation more complex models can be used. a) BJT small signal behavioural model With the disconnected Capacitor C3 another model of the circuit has to be used now, because the Emitter Resistor is now not short circuited at mid-frequencies and generates an important current feedback of the AC-signals through IE, which reduces the amplification of the CEAmplifier considerably. ü ü ü ÿ þ ý ü ÿ ü figure 11 All the definitions can be taken from Definitions of the small signal parameters b) Measured small signal values without C3 The input voltages are increased by a factor 10 to obtain better measurands at the low amplifications without bypass capacitor. (A generator with f=1kHz works as voltage source V1) vs=200mV voc=533mV vo=340mV vi=143mV vrs=57.3mV 20 c) Calculation and derivation of the small signal parameters (mid freq., without C3) ALL THEORETICAL VALUES WITH INDEX ‘ (i.e. R’) i. Amplifier input resistance Ri # " ! ) ) + * $ + 8 % & , - + , - 9 ( 0 1 2 3 4 5 6 ) 3 . ) 8 + 8 + ; < = 7 # : % > + . / 8 7 / * 8 ; 7 + , @ 7 < A 7 % ? ( 8 B % 6 & ' 8 B D - E C figure 12 The Figure 12 shows, that the Emitter resistor is divided into two parts for separating input and output circuit. The connection between both is given through the voltage drop at the emitter resistor RE. Measured Value of R in : Theoretical value of R in : R 'in = R 2 R 1 (h ie + R EIn ) where R EIn = R 'in = R 2 R 1 [h ie + (h fe + 1)R E ] v RE (h fe + 1)R E i B = iB iB vi vi = i i v rs Rs 143mV 57.3mV 3.26kΩ R in = 8.14kΩ R in = R 'in ≈ R 2 R 1 (h ie + h fe R E ) R 'in ≈ R in = 1 1 1 1 + + 56kΩ 10kΩ 3.577kΩ + 200 × 1kΩ R 'in ≈ 8.15kΩ The calculated value of Rin is very close to the measured value. The approximation of REin can be done because there’s a negligible difference between hfe and (hfe+1). 21 ii. Amplifier output resistance Ro I H L R J F G H F K L N G M O P Q figure 13 It’s the same small signal model than in the first part. The series connection of the current source and the emitter resistor can be reduced to the current source only. Theoretical value of R o : Measured value of R o : R 'o = R C Ro = with h OE = 0S R ' o = 3.9kΩ Ro = v oc − v o vo RL 533mV − 340mV = 3.81kΩ 340mV 6.72kΩ The calculated and the measured value are again very close together. iii. Voltage amplification at mid frequencies without load Theoretica l value of A vo : Measured value of A vo : A ' vo = − h fe i B R C v oc = vi i B ( h ie + R Ein ) A vo = A vo = − h fe R C ( h ie + R Ein ) A vo = A vo = − A vo = h ie a vo h fe R C h fe R C ≈ + ( h fe + 1) R E h ie + h fe R E v oc vi 533mV 143mV = 3.3 200 ⋅ 3 . 9 k Ω = 3 . 83 3 . 577 k Ω + 200 ⋅ 1k Ω The Voltage amplification is very low, because the emitter resistor without bypass capacitor causes a current feedback which results in a low Amplification at all frequencies (see frequency response). 22 iv. Voltage amplification at mid frequencies with load Theoretical value of A vo : A' v = A' v = Measured value of A vo : v o − h fe i B (R C R L ) = vi i B (h ie + R Ein ) A vo = − h fe (R C R L ) A' v = − h ie + (h fe + 1)R E 340mV 143mV = 2.38 A vo = (h ie + R Ein ) h fe (R C R L ) v oc vi ≈ A vo h fe (R C R L ) h ie + h fe R E 3.9kΩ ⋅ 6.8kΩ 3.9kΩ + 6.8kΩ = 2.45 A' v = 3.577 kΩ + 200 ⋅ 1kΩ 200 ⋅ The amplification without bypass capacitor is again very low, but the theoretical value and the measured value are very close together. v. Current amplification Ai Theoretical value of A i : A'i = iC iI A'i = h fe i B iI A'i = h fe with i B = R1 R 2 h ie + (h fe + 1)R E + R 1 R 2 R1 R 2 h ie + R E (h fe + 1) + R 1 R 2 A'i = 200 = h fe R1 R 2 h fe 26mV 8.485kΩ 3.58kΩ + 1kΩ(201) + 8.485kΩ A'i ≈ 8 Measured value of A i : v oc iC Rc Ai = = v rs iI Rs 533mV 3.82kΩ 57.3mV 3.26kΩ A i = 7.93 Ai = iI 23 IE + R E (h fe + 1) + R 1 R 2 vi. Amplifier power gain Ap Theeoretic values of A p : A' p = A i ⋅ A v A' p = h fe R1 R 2 h ie + R E (β + 1) + R 1 R 2 A' p = 200 × RC RL h ie h fe + RE 8.48kΩ 2.479kΩ × 3.577 kΩ + 1kΩ ⋅ 201 + 8.48kΩ 3.577 kΩ + 1kΩ 200 A' p = 19 Measured value of A p : A' p = A i ⋅ A v A' p = 7.93 ⋅ 2.38 A' p = 19 d) Comparison between measured and calculated values Measurand measured calculated hfe 171/ 213 200 Rin 8.14kΩ Rout 3.81kΩ Avo 3.3 Av 2.38 Ai Ap 8 19 8.15kΩ 3.9kΩ 3.83 2.45 8 24 19 9. Frequency response of the CE-amplifier without C3 a) Frequency response of Av f/Hz vi/mV vo/mV vo/vi 10 134 305 2.3 20 131.8 309 2.3 50 131.4 311 2.4 70 131.2 310 2.3 100 131.3 311 2.3 200 130.9 310 2.3 500 130.9 310 2.3 700 730.9 310 2.3 1000 130.9 310 2.3 Voltage Amplification vs frequency Av 10 1 10 100 1000 f figure 14 fc is not readable and so the cut-off frequency is much lower than 10Hz. The current amplification is linear over the low and mid frequency band. 25 (P)spice printout of the Voltage Amplification without bypass capacitor 26 b) Theoretical calculation of the lower cut-off frequency At this circuit only the coupling capacitors have an influence to the lower cut -off frequency because the bypass capacitor is removed. S S S \ T \ ^ k Y ] ^ S X V U _ W ` a ^ _ ` l [ \ d e f g h i f \ a k ^ k k q p j j b ] k c ^ ^ n o V m n j ^ s _ j o X t j U X b X r [ k u X ^ Y Z j figure 15 figure 15 shows the small signal equivalent circuit for the CE-Ampflifier with disconnected bypass capacitor. S S S \ T \ ^ S ^ k X Y V U _ ] W ` ^ a _ ` l [ \ d e f g h i f a \ k ^ k k q p j j c b ] k ^ U X ^ n o V m j ^ _ s j o t j X r b X n [ v w x y v w z { | X Y Z figure 16 In figure 16 the emitter resistor is separated into its input and output circuit part. For the input circuit: ii = iB = iB = vi R in + 1 jω C R1 R 2 R 1 R 2 + h ie + R Ein ii = RB R B + h ie + R Ein vi R in + 1 jω C 1 1 v i where R in = R B (h ie + R Ein ) 1 (h ie + R Ein )1 + jωR in C1 27 For the output circuit: io = RC 1 RC + RL + jω C 2 v o = −R L i o = − vo = ic = RC 1 RC + RL + jω C 2 R L R C h fe RL + RC + 1 jω C 2 h fe i B i b where R C R L = R CR L RC + RL (R C R L )h fe iB 1 1+ jω(R L + R C )C 2 Combining the I/P and O/P circuit Av = vo =− vi (R C R L )h fe h fe (R C R L ) 1 where A vmid = − 1 1 h ie + (1 + h fe )R E 1+ 1+ (h ie + R Ein ) jω(R L + R C )C 2 jωR In C1 τ1 = R In C1 = [R B (h ie + (1 + h fe )R E )]C1 τ 2 = ( R C + R L )C 2 A V (s) = vo τ1 τ 2 s 2 = A vmid vi (1 + τ1s)(1 + τ 2 s) Using the calculated values: τ1 = (8.48kΩ 8.14kΩ)10µF τ1 = 0.081s ω1 = ω 1 = 12.28 ⇒ f c1 = 1 = 1.95Hz 2π τ1 τ 2 = (3,9kΩ + 6.8kΩ)10µF τ 2 = 0.107s ω2 = ω 1 = 9.34Hz ⇒ f c1 = 2 = 1.48Hz τ2 2π ω1 ≈ ω 2 ⇒ A(s) s2 ω2 = = A mid (s + ω c ) 2 ω 2 + ωc2 ω L = 1.55ωC ωc ≈ 2Hz This low frequency was not measurable in the lab, because the generator and the measuring instruments were not able to determine such a low frequency correctly. The amplification of the CE-Amplifier without bypass capacitor reaches nearly into the DCregion. 28 c) Frequency response of Ai without C3 f/Hz vrs/mV vo/mV v rs µA Rs 10 56 333 17.17 20 57 337 17.5 50 57 339 17.5 70 57 339 17.5 100 57 340 17.5 200 57 339 17.5 500 57 339 17.5 700 57 339 17.5 1000 57 339 17.5 vo µA RL Ai 49.55 50 50.5 50.5 50.5 50.5 50.5 50.5 50.5 2.88 2.87 2.88 2.88 2.88 2.88 2.88 2.88 2.88 Current Amplification vs frequency Ai 10 1 10 100 1000 f figure 17 fc is not readable and so the cut-off frequency is much lower than 10Hz. The current and voltage amplification of the CE-amplifier is very low, but constant during the lower frequencies, therefor the CE-Amplifier without bypass capacitor is not often used. For low frequency amplification usually direct coupled amplifiers with bypass capacitors are used. If the circuit is well designed the lower cut-off frequency is mostly determined by the emitter capacitor and NOT by the coupling capacitors. 29 (P)spice printout of the current amplification vs frequency 30