CE- Amplifier Experiment -415 S CE AMPLIFIER Jeethendra Kumar P K KamalJeeth Instrumentation & Service Unit, No-610, Tata Nagar, Bengaluru-560092,INDIA Email: labexperiments@kamaljeeth.net Abstract Using a BC107 silicon transistor, frequency response of a common emitter (CE) amplifier is studied in the frequency range 100Hz-3MHz and gain-bandwidth product, mid-band gain, input and output impedances are determined and compared with the corresponding theoretical values. Introduction Design and construction of CE amplifier is one of the classic experiments in physics. Single transistor voltage amplification from milli-volt to volt level was employed in the early transistor radio circuits, which are now replaced by integrated circuits. Hence these circuits are the fundamental building blocks of integrated circuits. CE amplifier provides a fundamental circuit design exercise in physics. CE amplifier design +12V R1, 75K RC, 3K VC Co,1µF Cin, 1µF VB VE Vo Vin R2, 33K RE, 3K CE, 10µF Figure-1: CE amplifier circuit To start with the design of a transistor amplifier circuit involves selection of an appropriate transistor and noting down its h-parameters from the data manual. The manufacturer typically provides the minimum and maximum values of the hparameters for a certain value of the collector current. The h-parameters of the BC107 1 KAMALJEETH INSTRUMENTS CE- Amplifier transistor are tabulated in Table-1, taken from the previous experiment in this issue of LE. Generally the transistors are graded by the manufacturer depending on their DC gain, βdc (hFE). We have used a BC107B transistor for which the parameters are listed in Table-1. Figure-1 shows a CE amplifier circuit with voltage divider bias. The CE amplifier design starts with fixing a Q-point (setting VCE, IC) at the middle of the dc load line. Once we choose the Q-point the voltage gain is determined. A small ac signal is coupled to the input using a coupling capacitor. The ac input signal produce fluctuations in the quiescent current and the Q-point move up-down on the dc load line as shown in Figure-2 producing fluctuations or amplifications in the collector current. Hence a small change in the base current (∆IB = ib) is capable of producing large change in the collector current (∆IC = iC), hence producing amplification. The Q-point will move to position A during positive half cycle of the input sine wave and move to position C during the negative half of input sine wave, thus producing sinusoidal fluctuations in the collector current. Table-1: h-parameters and DC current gain of a BC107B transistor Parameters BC107B β dc (hFE) 110* hfe 125 hie (KΩ) 7.5 *These are the minimum values measured at 2mA, VCE=5V I C sat A IB=30uA I C Q IB=20uA C V CE IB=10uA V CC Figure-2: DC load line and Q-point Coupling capacitor Ac signals are generally coupled through a coupling capacitor in discrete form of amplifier circuits. However, in the integrated form, capacitor above 100pF is difficult to 2 KAMALJEETH INSTRUMENTS CE- Amplifier fabricate hence direct coupling is preferred. The size of the coupling capacitor will depend on the lowest frequency of amplifier operation. A firm coupling is the one whose reactance at the lowest frequency of operation is 1/10 of total series resistance. This 1:10 ratio is followed in coupling ac signal to the CE amplifier. A coupling capacitor is always associated with a resistance. The input impedance (Zin) of the CE amplifier in Figure-1 is in series with the input coupling capacitor CC. The input impedance is combination of resistances RB= R1//R2 and h ie of the transistor used in the circuit. The value RB large (at least 10 times) in compared to h ie, hence hie is the resistance in series with input coupling capacitor. Hence input coupling capacitor is selected such that its impedance XCC ≤ 0.1hie For the BC107B transistor used in this experiment XCC ≤ 0.1x7.5K =750Ω ଵ 750 = ଶ̟େ ౙ At lowest frequency of operation, say 100Hz CC is CC = 2.12µF A 1µF capacitor is used as input coupling capacitor. Similarly the output coupling capacitor is decided by the series resistance R C =3K XCC ≤ 0.1x3K =300Ω This gives 0.5µF at 100Hz. We have selected 1µF. By-pass capacitor Capacitor CE connected in parallel to RE is used to filter or by-pass the ac signal from the emitter there by keeping emitter at ac ground. This capacitance is in series with hie of the transistor as shown in the input circuit in Figure-3. The three larger resistances (RB, h ie and RE) can be neglected in comparison with Rs, the resistance of ac source or the function generator. Hence the smallest time constant in the input circuit is CERs, which will decide the lower cut-off frequency of the CE-amplifier. 3 KAMALJEETH INSTRUMENTS CE- Amplifier Rs 50 7.5K hie 3K RE RB 22.9K 10uF CE Figure-3: Input equivalent circuit of the CE amplifier The value CE can be selected using same 1:10 thumb rule as XCE = ଵ ଶ̟ୖు ≤ 0.1RE =300Ω This gives CE = 5.3µF we have used 10µF. With selection the lower cut-off frequency becomes fL = ଵ ଶ̟୶ହ୶ଵ୶ଵషల = 318Hz Firm voltage divider bias A CE amplifier circuit shown in Figure-1 is biased (energized) with firm voltage divider bias circuit [1]. Figure-4 shows the equivalent circuit for the voltage divider bias. R R TH I VT H C Vcc V BE B I R E E Figure-4: Equivalent circuit of firm voltage divider Applying Kirchhoff’s voltage law to the input loop we can write VTH = IBRTH+VBE+IER E Substituting for IB =IE/βdc , the emitter current IE = ୖ ౄ ିాు ుାୖౄ /β ౚౙ 4 KAMALJEETH INSTRUMENTS CE- Amplifier A firm voltage divider is the one that satisfy the condition RTH ≤ 0.1βdc RE This 10:1 ratio must be satisfied for the minimum value of βdc. The manufacture will provide the minimum and maximum value in data sheet. For the transistor BC107B βdcmin is 110. The value of R2 is always smaller than R1 hence the smaller value should be selected such that R2 ≤ 0.1βdcmin RE = 0.1x3Kx110= 33KΩ We have taken R2 as 33K and hence R1 is calculated using voltage divider formula V = R1= Rଶ V R ଶ + Rଵ େେ ୖమ ሺిిష ా ሻ ా = ଷଷሺଵଶିଷ.ሻ ଷ. =77K We have selected R 1=75KΩ Setting the Q-point The Q-point is set at the center of dc load line by selecting VCE = 0.5VCC. This selection ensures a rock-solid Q-point. Taking VCC =12V, VCE = 6V, which appears across the collector emitter terminal of the transistor. The remaining 6 volts is dropped equally across the collector resistance RC and Emitter resistance RE. Since CE amplifier is voltage amplifier we shall take IC =1mA as small Quiescent current. Hence IE =1mA, Voltage across RE =3V ు ୍ు = R = 3KΩ Since equal voltage dropped across RE, and IC≈ IE ి ୍ి = R େ = 3KΩ The voltage gain is fixed when choose the collector current and collector resistor R C AV = ୖి ୰′ 5 KAMALJEETH INSTRUMENTS CE- Amplifier Where RC is the collector resistor and ݎ′ is ac emitter resistance. The value of which depend on the quiescent current rୣ′ = ଶହ ୍ి Ohms Where IC is quiescent current in milli-amphere Once we decide the Q-point the gain is fixed In our design IC =1mA hence rୣ′ = AV = ଶହ ଵ = 25 Ohms ଷ ଶହ = 120 Band width of CE Amplifier As frequency is varied, the reactive impedance of various capacitors rolls of the voltage gain. The coupling capacitors (Cin, Co) are effective in the low frequency region and the shunt capacitor (CE and inter junction capacitance of the transistor) are active in the high frequency region. The three capacitance in the CE amplifier circuit, that provide three cut off frequencies namely fin, fout and fE. The cut off frequency fin, is the result of input impedance of the function generator (RS) along with CE rolls of the gain at lower frequencies. Out of the two time constants in the CE amplifier circuit namely, RSCE, hie CE, whichever is smaller will be considered as the lower cut-off frequency. The upper cut-off frequency (f2) will depend entirely on the inter-junction capacitance of the transistor. Hence band width BW = f2-f1 Where f1 is lower cut off frequency and f2 is upper cut of frequency Gain bandwidth product GBW is given by GBW = Av (f2-f1) 6 KAMALJEETH INSTRUMENTS CE- Amplifier This product is constant for given transistor amplifier. Apparatus used Transistor amplifier Expt set-up model TRA-201, KamalJeeth make consisting of 12 Volt power supply, wide band ac volt meter (0-2V, 200 KHz), Function generator 3MHz, Digital storage oscilloscope (DSO). The complete experimental set-up is shown in Figure-5. Figure-5: Hybrid parameter experimental set-up Experimental procedure Experiment consists of three parts Part-1: Construction of CE amplifier and Verification Q-point Part-2: Frequency response Part-3: Determination of input and output resistances Part-1: Construction of CE amplifier and Verification Q-point 1. The CE amplifier circuit is rigged using BC107B transistor as shown in Figure-1 and supply voltage (12V) is connected circuit. Using a multi meter (20V range) the voltages at the three terminals of the transistor is measured. VB = 3.02V, VC = 9.01V, VE = 3.59V ଵ These voltages are as per our design and VCE = 5.99V= ( Vୡୡ) ensures that the Qଶ point is at the center of dc load line. The quiescent current ICQ The emitter current IE is calculated 7 KAMALJEETH INSTRUMENTS CE- Amplifier ICQ = IE = ಶ ோಶ ଷ.ଶ = ଷ =1mA Hence Q-point (VCE, IC) = (5.99V, 1mA) Ac emitter resistance rୣ′ =25/IC =25/1 =25 Ω Ac voltage gain of the amplifier is AV = RC/rୣ′ = 3000/25 =120 The input resistance of the function generator measured using a multi-meter with function generator switched off RS =50 Ω The input resistance (h ie) of the CE amplifier is much greater than 50Ω. Hence the lower cut-off frequency is given by ଵ fL = f1 = ଶ̟େ ు ୖ ଵ = ଶగ௫ହ௫ଵషల = 318Hz Part-2: Frequency response 2. The function generator is connected to input of CE amplifier and sine input is selected and its frequency is set to 100Hz and amplitude is set to 50mV (this is the minimum input from the function generator) and output is noted and gain is calculated and presented in Table-2. At 100Hz, Vin = 50mV, VO = 1.1V Voltage gain = ೀ = ଵଵ ହ = 22 3. Trial is repeated by varying frequency in suitable steps up to maximum of 3MHz. At each frequency, the input and output is noted from the CRO and gain is calculated and presented in Table-2. 4. A graph is drawn taking frequency on log on X-axis and gain on Y-axis as shown in Figure-6. From the frequency response curve, mid band gain AM (100) and lower and upper cut-off frequencies at gain (0.707x AM) are noted. Table-2: Gain at different frequencies Frequency Output (V) Gain 8 KAMALJEETH INSTRUMENTS CE- Amplifier (KHz) CRO WBM CRO WBM 0.1 1.1 0.33 22 18 0.2 2.0 0.65 40 37 0.4 3.4 1.09 68 61 0.6 4.0 1.37 80 78 0.8 4.4 1.54 88 87 1 4.8 1.63 96 92 2 5.0 1.80 100 102 3 5.0 1.84 100 104 4 5.0 1.86 100 105 10 5.0 1.86 100 105 20 5.0 1.86 100 105 30 5.0 1.86 100 105 40 5.0 1.86 100 105 50 5.0 1.86 100 105 60 5.0 1.86 100 105 70 4.9 1.86 98 105 100 4.8 1.81 96 102 200 4.3 1.50 86 85 300 3.7 1.13 74 64 400 2.8 56 500 2.4 48 600 2.1 42 9 KAMALJEETH INSTRUMENTS CE- Amplifier 800 1.6 32 1000 1.3 26 1500 1.0 20 2000 0.8 16 2500 0.6 12 3000 0.5 10 50mV PP input with CRO, 17.6mV with WBM f1 = fL = 400 Hz = 0.4 KHz f2 = 300 KHz BW = 300 KHz-0.4 KHz ≈ 300 KHz GBW =100x300K =30MHz Voltage gain CRO 0.1 Wide band meter 120 110 100 90 80 70 60 50 40 30 20 10 0 1 10 100 1000 10000 Frequrncy (KHz) Figure-6: Frequency variation 5. The experiment is repeated using the wideband meters provided in the set-up. The readings obtained are tabulated in Table-2. And Figure-6 shows the frequency response. Both CRO and the wide band meters almost same readings. However after 300 KHz the wide band meter does not show reading. Part-3: Determination of input and output resistances 10 KAMALJEETH INSTRUMENTS CE- Amplifier 6. To measure the input impedance of the CE amplifier a decade resistor box is connected in series with the function generator as shown in Figure-7. Cc Cc DRB CE-amplifier Output to wide band meter Figure-7: Circuit connection to determine input resistance 7. The resistance in the DRB is set 0Ω, and frequency is set to 10 KHz (Mid band). The output is noted Vo =1.88V The resistance in the DRB is slowly increased until the output is reduced to half (0.94V). The resistance in box is noted. This is input impedance of the CE amplifier Zin = 7.5KΩ This value tally with the h ie (7.5KΩ) of the BC107B transistor used. 8. To determine output impedance, the resistance box is first adjusted to maximum value, before shunting to the CE amplifier circuit as shown in Figure-8.The output is monitored on CRO 9. With f=10KHz, input 50mV output is noted V0 =1.88V The resistance in the box is decreased until the output becomes half (0.94V). The resistance in the box is noted. This is the output impedance of the CE amplifier Zout =3KΩ =RC This exactly equal to RC, which the theatrical value of output impedance. 11 KAMALJEETH INSTRUMENTS CE- Amplifier Cc DRB Cc CE-amplifier Output to wide band meter Figure-8: Circuit connections to determine output resistance Results The results obtained are summarized in Table-3. Table-3: Experimental results Parameters Experimental 105 Voltage gain Theoretical 120 Lower cut-off frequency 318Hz 400Hz Upper cutoff frequency - 300KHz GBW 30MHz References [1] A P Malvino, Electronic Principles, 3rd Edition, 1984, Page-172. 12 KAMALJEETH INSTRUMENTS