Convolution Table - Department of Electrical and Electronic

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Convolution Integral
 
Lecture 5
Convolution Integral:
∞
y (t ) = x(t )* h(t ) = ∫ x(τ )h(t − τ )dτ
−∞
Time-domain analysis:
Convolution
 
(Lathi 2.4)
System output (i.e. zero-state response) is found by convolving input x(t)
with System’s impulse response h(t).
LTI System
Impulse Response
h(t)
Peter Cheung
Department of Electrical & Electronic Engineering
Imperial College London
y (t ) = x(t )* h(t )
URL: www.ee.imperial.ac.uk/pcheung/teaching/ee2_signals
E-mail: p.cheung@imperial.ac.uk
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E2.5 Signals & Linear Systems
Lecture 5 Slide 1
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Convolution Table (1)
 
E2.5 Signals & Linear Systems
Lecture 5 Slide 2
Convolution Table (2)
Use table to find convolution results easily:
L2.4 p177
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E2.5 Signals & Linear Systems
Lecture 5 Slide 3
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E2.5 Signals & Linear Systems
Lecture 5 Slide 4
Convolution Table (3)
Example (1)
Find the loop current y(t) of the RLC circuits for input
the initial conditions are zero.
 
We have seen in slide 4.5 that the system equation is:
 
The impulse response h(t) was obtained in 4.6:
 
The input is:
 
Therefore the response is:
L2.4 p177
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E2.5 Signals & Linear Systems
Lecture 5 Slide 5
L2.4 p178
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Using distributive property of convolution:
 
 
 
E2.5 Signals & Linear Systems
Lecture 5 Slide 6
When input is complex Example (2)
 
when all
What happens if input x(t) is not real, but is complex?
If x(t) = xr(t) + jxi(t), where xr(t) and xi(t) are the real and imaginary part of x(t),
then
Use convolution table pair #4:
 
That is, we can consider the convolution on the real and imaginary components
separately.
L2.4 p178
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E2.5 Signals & Linear Systems
Lecture 5 Slide 7
L2.4 p179
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E2.5 Signals & Linear Systems
Lecture 5 Slide 8
Intuitive explanation of convolution
 
 
 
 
Convolution using graphical method (1)
Determine graphically y(t) = x(t)*h(t) for x(t) = e-tu(t) and h(t) = e-2tu(t).
Assume the impulse response decays
linearly from t=0 to zero at t=1.
Divide input x(τ) into pulses.
The system response at t is then
determined by x(τ) weighted by h(t- τ)
(i.e. x(τ) h(t- τ)) for the shaded pulse,
PLUS the contribution from all the
previous pulses of x(τ).
The summation of all these weighted
inputs is the convolution integral.
Remember: variable of
integration is τ, not t
y (t ) = x(t )* h(t )
L2.4-2 p191
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Lecture 5 Slide 9
E2.5 Signals & Linear Systems
L2.4-1 p183
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Convolution using graphical method (2)
Lecture 5 Slide 10
E2.5 Signals & Linear Systems
Interconnected Systems
 
Parallel connected system
x (t )
 
 
Cascade systems &
Commutative property
y(t ) = h1 (t )* x(t ) + h2 (t )* x(t )
y(t ) = [h1 (t )* h2 (t )]* x(t )
x (t )
L2.4-3 p192
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E2.5 Signals & Linear Systems
Lecture 5 Slide 11
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E2.5 Signals & Linear Systems
Lecture 5 Slide 12
Interconnected Systems
 
Integration:
 
Also true for differentiation:
 
Let
 
Then g(t), the step response is:
Total Response
( x(t) is an impulse, and h(t) is the impulse response of
the system)
 
Let us put everything together, using our RLC circuit as an example.
 
Let us assume
 
In earlier slides, we have shown that
x(t) = 10e−3t u(t), y(0) = 0, y (0) = −5.
L2.4-3 p193
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E2.5 Signals & Linear Systems
Lecture 5 Slide 13
L2.4-5 p197
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Natural vs Forced Responses
 
 
 
E2.5 Signals & Linear Systems
Lecture 5 Slide 14
Additional Example
*
Note that characteristic modes also appears in
zero-state response (because it has an impact
on h(t)).
We can collect the e-t and e-2t terms together, and
call these the NATURAL response.
The remaining e-3t which is NOT a characteristic
mode is the FORCED response.
L2.4-5 p197
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E2.5 Signals & Linear Systems
Lecture 5 Slide 15
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E2.5 Signals & Linear Systems
Lecture 5 Slide 16
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