HowtoDetermineClassMeetingTimes
Step1–Full-termorShort-term?
First,determinewhethertheclassistobescheduledfortheentireFallorSpringsemester,
orwhetherthecourseisgoingtobeshort-term.
Note:Allclassesscheduledinthesummerareshort-termclasses.
Step2a–Full-termClasses
1. Dividethenumberofhoursonthecourseoutlineby17.5togetthenumberofhours
perweek.
2. Dividethenumberofhourstobescheduledperweekbythenumberofmeetings
perweek–thisisthenumberofhourspermeeting.
Example1:HIST1
ThecourseoutlineforHIST1saysthatitmeetsfor52.5totalhoursoflecture.
52.5hourspersemester÷17.5weekspersemester=3hoursperweek
IftheclassisscheduledMWF,thenthat’s3meetingsperweek.
3hoursperweek÷3meetingsperweek=1hourpermeeting
Example2:ART130A
ThecourseoutlineforART130Asaysthatitmeetsfor35totalhoursoflectureand70total
hoursoflab,or105hourstotal
105hourspersemester÷17.5weekspersemester=6hoursperweek
IfthisclassisscheduledTR,thenthat’s2meetingsperweek
6hoursperweek÷2meetingsperweek=3hourspermeeting
Example3:MATH110A
ThecourseoutlineforMATH110Asaysthatitmeetsfor87.5hoursoflecture
87.5hourspersemester÷17.5weekspersemester=5hoursperweek
IfthisclassisscheduledMW,thenthat’s2meetingsperweek
5hoursperweek÷2meetingsperweek=2.5hourspermeeting
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Step2b–Short-termClasses
1. Usetheacademiccalendartodeterminetheactualnumberofmeetings
2. Dividethenumberofhoursonthecourseoutlinebytheactualnumberofmeetings
todeterminethenumberofhourspermeeting.
Example1:PSYC1
ThecourseoutlineforPSYC1saysthatitmeetsfor52.5totalhoursoflecture.
Iftheclassisscheduledfor24meetingsinthesummer,hourspermeetingare:
52.5hourstotal÷24meetings=2.1875hourspermeeting
Example2:IDST80C
ThecourseoutlineforIDST80Csaysthatitmeetsfor9totalhoursoflecture.
Iftheclassisscheduledfor2meetings,hourspermeetingare:
9hourstotal÷2meetings=4.5hourspermeeting
Example3:ENGN45
ThecourseoutlineforENGN45saysthatitmeetsfor35hoursoflectureand52.5hoursof
lab,or87.5hourstotal
Ifthisclassisscheduledasahalf-termclassintheFallorSpring,itmightmeetatotalof23
meetings.Hourspermeetingare:
87.5hours÷23meetings=3.804hourspermeeting
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Step3–RoundHoursperMeetingtotheClosestValueinthe“ContactHours”
columnoftheContactHourCalculationChart
TakethevaluefromStep2aor2baboveandroundittotheclosestvalueinthe“Contact
HourCalculationChart”.
Examples
Here’showthiswouldworkforthecalculationexamplesshownabove:
Course
CalculatedHours RoundedHours
perMeeting
perMeeting
HIST1
1
1
ART130A
3
3
MATH110A
2.5
2.5
PSYC1
2.1875
2.3
IDST80C
4.5
4.5
ENGN45
3.804
3.8
Note:You’llnoticethattherearejumpsintheContactHourscolumnofthischart.For
example,the2.1875valueforPSYC1wasn’troundedto2.2,sincethereisno2.2hourson
thischart–there’sonly2.0and2.3.
Step4–UsetheClockTimeforthatrowtoscheduletheclass
Examples
Here’showthiswouldworkforthecalculationexamplesshownabove:
Course
RoundedHours
ClockTime
Example
perMeeting
HIST1
1
0hours50mins
8:10–9:00
ART130A
3
2hours50mins
1:00–3:50
MATH110A
2.5
2hours15mins
9:10–10:25
PSYC1
2.3
2hours5mins
12:10–2:15
IDST80C
4.5
4hours15mins
10:00–2:15
ENGN45
3.8
3hours30mins
6:00–9:30
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AdditionalConsiderations
Therearesomeschedulingcombinationsthatworkbetterthanothers.
Forexample,afull-termclassthatshouldmeet5hoursaweekcaneasilybescheduledthe
followingways:
• Fivedaysaweek(e.g.,M-F)–1houraday
• Twodaysaweek(e.g.,MW)–2.5hoursaday
• Onedayaweek–5hours
It’smoredifficulttoschedulethisclass3or4daysaweek:
• Threedaysaweekcomesoutas1.67hours,whichroundsto1.7hourspermeeting
• Fourdaysaweekcomesoutas1.2hours,whichroundsto1.3hourspermeeting
Bothoftheseschedulingpatternsresultinclocktimesthatcanbedifficulttoschedule.
Additionally,whenschedulingshort-termclasses,youmayfindthatchangingthenumber
ofmeetingsmakestheschedulemorestraightforward.
Forexample,inthePSYC1exampleabove,wewoundupwithaclassscheduledtomeetfor
2hoursand5minutes.Ifwehadscheduleditfor26meetingsinsteadof24,themath
worksbetter:
52.5hourstotal÷26meetings=2.02hourspermeeting
Wewouldroundthatto2hourspermeeting,oraclocktimeof1hourand50minutes,
whichisamuchmorereasonableschedulingpattern.
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