BASICS OF ELECTRICAL CIRCUITS EHB 211 E RLC Circuits Asst. Prof. Onur Ferhanoğlu 1 Natural Response of RLC circuits Assume, the solution is in the exponential form Rational assumption, since higher derivatives yield to a similar form with the function itself Natural response: KCL Take derivative Don’t use A = 0 as a solution -> voltage is 0 Characteristic equation 2nd order Differential Equation Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 2 Natural Response of RLC circuits Satisfies the equation, regardless of the A value Their sum is also a solution! Characteristic equation Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS Natural response Initial conditions determine A1, A2 3 Natural Response of RLC circuits Characteristic equation Real roots -> overdamped response Complex roots -> underdamped response Critically damped response Damping: the way voltage response reaches its final value Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 4 Overdamped voltage response Finding v(0+) and dv(0+)/dt: KCL dv(0+)/dt: Finding overdamped response: 1. Find roots (s1,s2) using RLC values 2. Find v(0+) and dv(0+)/dt: 3. Find A1, A2 by solving: (2 eq. 2 unknowns) Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 5 Example 1 For the circuit, v(0+) = 12 V, iL(0+) = 30mA a) Find initial current at each branch b) Find initial value of dv/dt c) Find v(t) d) Sketch v(t) a) b) v(0+) = 12 V (capacitor voltage) iR= 12/200 = 60mA KCL: iC = -90 mA (iL + iR + iC = 0) Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS Before time 0, dv/dt = 0 (stationary voltage) 6 Example 1 continued.. For the circuit, v(0+) = 12 V, iL(0+) = 30mA a) Find initial current at each branch b) Find initial value of dv/dt c) Find v(t) d) Sketch v(t) c) (Units of s1,s2 are inverse of time) exponential terms are unitless Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 7 Example 1 continued.. For the circuit, v(0+) = 12 V, iL(0+) = 30mA a) Find initial current at each branch b) Find initial value of dv/dt c) Find v(t) d) Sketch v(t) d) Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 8 Example 2 For the previous example, derive the branch currents: Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 9 Underdamped voltage response Roots are complex B1 = A 1 + A 2 B2 = j(A1 - A2) Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 10 Underdamped voltage response B1 = A 1 + A 2 B2 = j(A1 - A2) Asst. Prof. Onur Ferhanoğlu The response is oscillatory (sin & cos) wd : oscillation frequency α: damping coefficient (How fast the oscillations die) RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 11 Example 3 In the circuit V0 = 0, I0 = -12.25 mA a) Calculate the roots of the characteristic equation b) Calculate v, dv/dt at t= 0+ c) Calculate v(t) for t > 0 d) Plot v(t) a) Underdamped Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 12 Example 3 continued… In the circuit V0 = 0, I0 = -12.25 mA a) Calculate the roots of the characteristic equation b) Calculate v, dv/dt at t= 0+ c) Calculate v(t) for t > 0 d) Plot v(t) c) Across capacitor: b) Across capacitor: The current in resistive branch is 0 (V=I.R) iC = -iL Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 13 Example 3 continued… In the circuit V0 = 0, I0 = -12.25 mA a) Calculate the roots of the characteristic equation b) Calculate v, dv/dt at t= 0+ c) Calculate v(t) for t > 0 d) Plot v(t) d) Underdamped response: Damped & oscillatory Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 14 Critically damped voltage response or When roots are equal, the solution takes the following form: Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS When two roots are equal, this equation can not satisfy 1 constant (A0) with two independent initial conditions (V0, I0) 15 Example 4 a) Find the value of R that results in critically damped voltage response b) Calculate v(t) c) Plot v(t) b) Same as previous example (given by the problem) a) (same as previous example) Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 16 Example 4 continued… a) Find the value of R that results in critically damped voltage response b) Calculate v(t) c) Plot v(t) c) Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 17 Step response of a parallel RLC circuit Indirect approach Express in terms of v KCL differentiate 3 possible solutions Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 18 Step response of a parallel RLC circuit II Direct approach The solution for a 2nd order D.E with a constant forcing function equals: KCL Final values of the response function Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 19 Example 5 - overdamped step response of parallel RLC The initial stored energy is 0. I = 24 mA. R = 400 Ω. Find a) Initial value of iL b) Initial value of diL/dt c) Roots of the characteristic equation d) iL(t) c) a) No energy stored for t< 0 iL(0-) = iL(0+) = 0 b) vC(0-) = vC(0+) = 0 = vC d) Overdamped response is of the form: Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 20 Example 5 - continued.. The initial stored energy is 0. I = 24 mA. R = 400 Ω. Find a) Initial value of iL b) Initial value of diL/dt c) Roots of the characteristic equation d) iL(t) d) Asst. Prof. Onur Ferhanoğlu Inductor will become a short circuit, and final value of its current If = I = 24 mA RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 21 Example 6 - underdamped step response of parallel RLC The initial stored energy is 0. I = 24 mA. R = 625 Ω. Find = Same as before, does not change with R iL(0+) = 0 from prev. question from prev. question Complex roots, underdamped Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 22 Example 7 - critically damped step response of parallel RLC The initial stored energy is 0. I = 24 mA. R = 500 Ω. Find Same as before, does not change with R Critically damped We know that both equals 0 from prev. question Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 23 COMPARISON For all cases: iL(0) = 0, if = 24 mA • Underdamped overshoots the final value • Overdamped & Critically damped always stay below if Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 24 Natural response of series RLC KVL differentiate rearrange Parallel RLC equation Assume similar solution Similarly with the parallel RLC circuit Different from parallel RLC Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 25 Step response of series RLC KVL Similar to parallel RLC Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 26 Example 8 – underdamped natural response of series RLC Initial voltage on capacitor is 100V. a) Find i(t) b) Find vC(t) underdamped Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 27 Example 8 – continued… Initial voltage on capacitor is 100V. a) Find i(t) b) Find vC(t) This one is easier to handle Asst. Prof. Onur Ferhanoğlu RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 28 Example 9 – underdamped step response of series RLC No energy stored in the inductor or the capacitor. Find vC(t) underdamped Asst. Prof. Onur Ferhanoğlu Initially no energy stored Initial current is 0 (proportional to voltage derivative) RLC Circuits/ BASICS OF ELECTRICAL CIRCUITS 29