ESE 372 / Spring 2013 / Lecture 7 pn ‐ Junction. When these two materials are brought into contact the electrons will go from n to p and holes from p to n regions by diffusion. They will be leaving behind immobile charges of ionized donors and acceptors. acceptors The corresponding electric field will eventually stop diffusion currents. 1 ESE 372 / Spring 2013 / Lecture 7 pn – Junction band diagram. Donor concentration Acceptor concentration Surface charge densities on both sides of pn-junction Built-in potential 2 ESE 372 / Spring 2013 / Lecture 7 pn – Junction under reverse bias. External field is trying to move electrons from p to n and holes from n to p. Almost no current can flow since there is small number of electrons in p and holes in n regions Junction capacitance decreases 3 ESE 372 / Spring 2013 / Lecture 7 pn – Junction under forward bias. External field is trying to move electrons from n to p and holes from p to n. Current should be expected. 4 ESE 372 / Spring 2013 / Lecture 7 Current of pn–junction under forward bias. Reverse saturation current Observe accumulation of mobile charges on both sides on pn-junction under forward bias 5 ESE 372 / Spring 2013 / Lecture 7 IV of pn‐junction diode. Nonideality factor 6 ESE 372 / Spring 2013 / Lecture 7 Diode models. Ideal diode: Constant voltage drop model. Battery + resistance model. 7 ESE 372 / Spring 2013 / Lecture 7 Reverse breakdown. Diodes demonstrate unilateral conductance only as long as: Breakdown voltage Mechanisms of reverse breakdown Breakdown current should be limited not to should be limited not to burn the device Tunnel Avalanche 8 ESE 372 / Spring 2013 / Lecture 7 Zener diodes (designed to operate in breakdown regime) (designed to operate in breakdown regime) Example of Zener‐based voltage regulator Unregulated: Regulated: 9 ESE 372 / Spring 2013 / Lecture 7 Effect of Temperature on diode IV Forward bias: Reverse bias: 10 ESE 372 / Spring 2013 / Lecture 7 Rectifiers Power outlet gives sine wave Electronics uses DC power supplies How can we convert 60Hz 120 Vrms into 5 V DC ? For sine wave Rectifier Filter and regulator 11 ESE 372 / Spring 2013 / Lecture 7 Ideal diode in series with AC generator and load. No DC component Id l diode Ideal di d IV There is DC component 12 ESE 372 / Spring 2013 / Lecture 7 Let’s use more realistic diode model Ideal since We got nonzero DC component at the output BUT it is not DC voltage yet. Also, we utilized only half of the input energy. 13 ESE 372 / Spring 2013 / Lecture 7 Diode in series with capacitor Ideal diode conducts only when Capacitor directly connected to AC source Charge stored on capacitor plates Voltage across capacitor is DC voltage for t > T/4 14 ESE 372 / Spring 2013 / Lecture 7 Half wave rectifier with filtering capacitor Capacitor is charged to What happens when 15 ESE 372 / Spring 2013 / Lecture 7 Half wave rectifier with filtering capacitor Capacitor is charged to Wh When initially Hence diode become reverse biased and capacitor starts discharging through load. Rapid charge through small diode series resistance Slow discharge through 16 ESE 372 / Spring 2013 / Lecture 7 Voltage ripple of half wave rectifier Diode closes Diode opens Discharge time Charging time << discharge time 17 ESE 372 / Spring 2013 / Lecture 7 Charging time Taylor’s series expansion: Charging time: Ideally the current flows through diode only during charging time 18 ESE 372 / Spring 2013 / Lecture 7 Example 19 ESE 372 / Spring 2013 / Lecture 7 Example – cont. Charge lost by capacitor during discharge time ~ T. This charge will be replenished during charge time << T. 20 ESE 372 / Spring 2013 / Lecture 7 Half wave rectifier circuit VD Square wave input q p ID Vin ID For diode with no parasitic capacitance and no charge accumulation effect we would obtain: T Simplified diode model RS 0, I S 0 Vin VB , VTO 0.7V VD *Spectrum of square wave signal contains many frequencies besides f0=1/T. y –V0 to +V0 square q wave: Fr 50% duty Vin t 4 Vin sin 6 f 0 sin 2 f 0 ... 3 21 ESE 372 / Spring 2013 / Lecture 7 Diode recovery time VD ID Real diodes have depletion and diffusion capacitances so the transient response will be complicated. Vin ID Simplified diode model RS 0, I S 0 Vin VB , VTO 0.7V VD Diode “keeps” forward bias after input is switched Diode recovery time. Determined by how fast the caps can be discharged. *Spectrum of square wave signal contains many frequencies besides f0=1/T. 22 ESE 372 / Spring 2013 / Lecture 7 Pn‐junction diode recovery time Under forward bias the excess minority carriers are injected. Hence, the excess carrier concentrations are present on both sides id off pn-junctions. j ti W We callll it – “charge “ h accumulation” l ti ” and d characterize h t i it b by so called ll d diff diffusion i capacitance. it Recovery time REC S TR Discharge of junction depletion capacitance Accumulated charges cannot disappear immediately after bias is changed, hence diode would appear to keep his forward bias VT0 for some time after bias is changed. Transition time I TRAN 0.7V R Storage time S TR QStored I TRAN 23 ESE 372 / Spring 2013 / Lecture 7 Pn‐junction diode recovery time Consider the case when voltage changes from positive to negative Large negative current spike but recovery time is decreased as compared to positive-to-zero transition case since now the same stored charge is being removed by larger current. 24