72. (30.2) Interaction between two parallel current carrying wires. Two parallel wires carrying currents exert forces on each other. Each current produces a magnetic field in which the other current is placed. B1 F21 I1 I2 l a 1 2 The magnitude of the magnetic force exerted on segment l of a wire by the other wire (infinite) is µ l F21 = 0 ⋅ I1I2 2πa Parallel "currents" attract and antiparallel repel. Proof. Wire 1 produces a magnetic field which has the following value at the other wire: r r µ 0 B1 = ⋅ I × a$ 2 πa Therefore the magnetic force exerted on the second wire is: r r r µ l r r F21 = I2l × B1 = 0 ⋅ I2 × (I1 × aˆ ) = 2πa r r r µ l r µl r r = 0 ⋅ ((I2 ⋅ aˆ )I1 − (I1 ⋅ I 2 )⋅ aˆ ) = − 0 (I1 ⋅ I 2 )⋅ aˆ 2πa 2 πa 101 73. (30.4, 30.5) The magnetic field of a solenoid - a long tightly wound helical coil. I N S L I From the symmetry of the currents we can approximate the outside field to be zero. Bout = 0 and the magnetic field inside is uniform (approximately). Its direction is parallel to the axis, and the magnitude of the fields is: Bin = µ 0nI where n is the number of turns per unit length of the solenoid, and I is the current in the solenoid. 102 Proof. Imagine an amperian loop along a line of the magnetic field. The contour integral of the magnetic field along this loop is: ∫ B ⋅ds = ∫ B in ds + ∫ B out ds =Bin L in out The current through the surface enclosed by this loop is IA = N⋅I where N is the number of turns in the solenoid. From Amper-Maxwell's equation we obtain: Bin L = µ 0NI therefore Bin = µ 0 N I = µ 0nI L 103 74. (30.9) Magnetic properties of matter. When a substance is placed in a (external) magnetic r field (B 0 ), its molecules acquire a magnetic moment related to the rexternal field. This creates an additional magnetic field (B m ) (internal). The magnetic staterof a substance is described by the magnetization vector, M, defined by the (internal) magnetic field of the substance. r r Bm = µ0M The net magnetic field is different when the substance is present than when it is not. Except for ferromagnetic, the magnetic susceptibility χ of the substance relates the two fields. r r r r B = B 0 + B m = (1 + χ )B 0 Depending on the reaction of a material to an external magnetic field, the substance can be a a) ferromagnetic - a substance that produces a strong magnetic field aligned with the external field (magnetic susceptibility χ>>0), which is sustained even after the external field is removed - ferromagnetic substances exhibit hysteresis of magnetization. b) paramagnetic - a substance that produces a magnetic field aligned with the external field (χ>0) c) diamagnetic - a substance that produces a magnetic field opposed to the external field (χ<0). 104 75. (31.intro, 31.1, 31.2) Magnetic Induction a) An induced electromotive force appears in a conducting loop when the magnetic flux through the surface enclosed by the loop is changing. This effect is called electromagnetic induction. ε N ΦB b) The electromotive force induced in a coil with N loops has value dΦ ε = −N B dt where ΦB is the magnetic flux through the cross-sectional surface of the coil. 76. (31.3) Lenz rule The polarity of an induced electromotive force is such that it tends to produce an induced current creating a magnetic field that opposes the change in flux causing the emf. 105 77. (32.4, 33.9) Mutual induction dΦ Φ dI1 + ε2 I2 If two coils are arranged in such a way that the magnetic fluxes though cross-sectional areas of each coil are related, a changing current in one coil induces an emf in the second coil. The effect is called mutual induction. The emf induced in the second coil is proportional to the rate of change in the current in the first coil. The proportionality coefficient M is called the mutual inductance. dI ε2 = −M 1 dt (The SI unit of mutual inductance is H=Vs/A) 106 78. (32.1) Self-induction A change in current dI in a coil induces an electromotive force εL the same coil. The emf is proportional to the rate of change in current. dΦ m d d N µ 0 N 2 A dI εL = − N ⋅ = − N ⋅ (A ⋅ B) = − NA ⋅ µ0 ⋅ I = − ⋅ dt dt dt l l dt A coil is an inductor with an inductance µ 0N 2A I ∆I L= l + εL + − − Voltage across an inductor is due to the induced emf only. ε 79. Application of electric induction (common examples) a) b) c) d) e) f) g) h) a microphone the playback head of a tape deck or VCR an electric guitar pickup an AC generator an inductor a transformer the back emf of an electric motor ground fault interupter 107 80. (32.3) Magnetic energy a) The energy stored in an inductor depends on the inductance of the inductor and the current through the inductor: 1 U m = LI2 2 Proof. The rate at which energy is delivered to the solenoid depends on the voltage across the solenoid and the current through the solenoid: dI Pel = Iε = I ⋅ L dt Therefore the energy at time t stored in the magnetic field of the solenoid is I (t ) t t dI 1 U m (t ) = ∫ Pel dt ' = ∫ LI(t ') dt ' = ∫ LIdI = LI 2 dt ' 2 0 0 0 b) Magnetic energy density is defined as the energy stored in a magnetic field per unit volume of the field dU m um = dV c) If, at a certain location, the magnitude of the magnetic field vector is B, the magnetic energy density at this location is: 1 um = ⋅ B2 2µ 0 108 Proof. For a solenoid B = µ0 N I L Therefore 2 um 2 U m 12 LI 1 1 µ0 N 2A B ⋅ l 1 = = = = ⋅ ⋅ ⋅ ⋅ B2 A ⋅l A ⋅l 2 A ⋅l l 2µ 0 µ0 N 81. (30.9) Magnetic moment of an electron. In classical physics, the magnetic moment of a particle is always associated with the angular momentum (in a circular motion) of the particle. There is evidence that an electron has a magnetic moment which is not associated with an orbital motion (Stern-Gerlach experiment). The corresponding "angular momentum", called the spin, has a magnitude (very small) of S= 3 h = 9.2 × 10−35 J ⋅ s 2 The electron magnetic moment vector associated with the spin vector has the value: r er µB = − s m Spin is an intrinsic property of an electron (like mass and charge) and should not be confused with a spinning of the electron! 109 82. Radiation (20.7) a) The process of emitting energy in the form of waves or particles; b) Energy radiated in the form of waves or particles; 83. (34.1) Electromagnetic radiation Electromagnetic radiation is associated with electromagnetic waves (oscillations of the electric and magnetic field) or beams of particles called photons. All electromagnetic waves travel in a vacuum with a speed of c = 1 ≈ 3 ⋅ 108 m / s µ0ε0 in all inertial frames. In other media, the speed of light is less and depends on the index of refraction n. The index of refraction of a medium is defined as the ratio of the speed of light in a vacuum c to the speed of light in the medium v. c n≡ v Any electromagnetic radiation can be considered as a superposition of sinusoidal (harmonic) electromagnetic waves. 110 84. (34.2) Electromagnetic wave z k y x a) Electromagnetic waves always move in a direction perpendicular to their electric and magnetic fields (transverse oscillations). For a monochromatic, plane wave, vector k, called the propagation vector, indicates the direction of the wave propagation. Ei (r , t ) = Em, i cos(k ⋅ r − ωt) Bi (r , t) = Bm , i cos(k ⋅ r − ωt ) In an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the propagation vector. b) If the oscillations of the fields are harmonic, the wave is monochromatic (definition). Monochromatic light produces the sensation of a defined color; but a certain color can be caused by non-monochromatic light as well. c) If the oscillations of the fields follow a certain simple pattern we say that the electromagnetic wave is polarized. When the fields oscillate along certain straight lines, the wave is linearly polarized. When the fields rotate without changing their magnitude the wave has circular polarization (an attribute of the wave). 111 85. (34.2) Wave equation. a) Each of the fields satisfies the wave equation. In an empty space ∂2E = µ ε ∂2E 0 0 ∂x2 ∂t 2 ∂2B = µ ε ∂2B 0 0 ∂x2 ∂t 2 and proof. y Applying Faraday's law ∂Φ ∫ E ⋅ ds = − ∂tB to the amperian loop marked in the figure, we obtain an equation relating the magnetic and electric fields. E dy dx x z B ∂E ∂E ∫ E ⋅ ds = E(x + dx)dy + 0 − E( x)dy + 0 = E(x) + ∂x dx − E(x)dy = ∂x dxdy − ∂Φ B = − ∂ (Bdxdy) = − ∂B dxdy ∂t ∂t ∂t Therefore ∂E = − ∂B ∂x ∂t Similarly, from the Ampère-Maxwell law we can show ∂B ∂E = − µ0 ε 0 ∂x ∂t 112 Combining the last two equations leads to the wave equations ∂2E = − ∂ ∂B = − ∂ ∂B = − ∂ −µ ε ∂E = µ ε ∂2E 0 0 2 ∂x ∂t ∂t ∂x ∂t 0 0 ∂t ∂x2 ∂t ∂2B = ∂ −µ ε ∂E = −µ ε ∂ ∂E = −µ ε ∂ − ∂B = µ ε ∂2B 0 0 ∂t ∂x 0 0 ∂t ∂t 0 0 2 ∂x2 ∂x 0 0 ∂t ∂t b) The simplest solution to the wave equation is a plane wave: E(x, t) = Em cos (kx − ωt) B(x, t) = Bm cos (kx − ωt) with E Em ω 1 = = = =c B Bm k µ0ε 0 proof Recall that the wavelength and frequency of the above electromagnetic wave are λ = 2π and f = ω , respectively. k 2π The wave travels with a phase speed of c = λf = 2π ⋅ ω = 1 . k 2π µ0ε0 113 Direct substitution in the wave equations ∂2E ∂2E k E(x , t ) = − 2 = −µ0 ε0 2 = µ 0ε0 ⋅ ω2 E(x , t ) ∂x ∂t 2 leads to ω = k 1 µ0ε0 Through a direct substitution is a differential equation relating magnetic and electric field − kB m sin (kx − ωt ) = ∂B ∂E = −µ 0ε0 = −µ 0ε 0ωE m sin (kx − ωt ) ∂x ∂t we obtain E Em 1 k 1 = = ⋅ = B Bm µ 0 ε0 ω µ 0 ε0 114 86. (34.3) The energy carried by electromagnetic waves a) The (total) energy density u of an electromagnetic wave is defined as the energy dU of both the electric and magnetic fields per unit volume of the wave. dU u≡ dV 3 (SI unit: J/m ) The average energy density comprised by a sinusoidal wave depends on the amplitudes of the magnetic and electric fields 1 u av = ε0 E 2m = ε0 E 2rms 2 1 2 1 u av = Bm = B 2rms 2µ 0 µ0 where Erms and Brms are the root-mean-square values of the electric and magnetic fields respectively. proof. The (instantaneous) total energy density at a certain location is equal to the sum of the energy density associated with each field separately ε 0 E 2 B2 ε0 E2 E2 2 u( t ) = + = + = ε E 0 2 2µ 0 2 2µ 0 c 2 115 From the definition of average value of a function we find t ∫ u(t')dt' uav = lim 0 t ∫ ε0E2m cos 2(kx − ωt)dt' t ∫ 2 + 2 cos 2(kx − ωt')dt' = lim 0 = ε 0E2m lim 0 t−0 t →∞ t − 0t t →∞ t'+ 1 sin 2(kx − ωt') 2ω 0 ε 0E 2m ε E2 = 0 m lim = 2 t →∞ t−0 2 t →∞ 1 1 t−0 = b) The rate of energy flow across a unit area in electromagnetic wave is described by the Poynting vector defined by the following expression 1 S≡ E×B µ0 proof. Consider, a plane electromagnetic wave. If we imagine a surface (with area dA) perpendicular to the path of the wave, the amount of energy passing this surface in a differential time dt is dU = u ⋅ (dA ⋅ cdt ) where u(x,t) is the instantaneous energy density at the surface. The rate at which the energy is transferred across the surface is therefore dU = c ⋅ u( x , t ) ⋅ dA dt 116 Considering the magnitude of the Poynting vector at the location of the surface we find µ 0ε 0 E2 EB E2 ε 0 E2 1 dU S( x, t ) = S = = = = = c ⋅ u( x , t ) = ⋅ µ 0 cµ 0 µ0 µ 0ε 0 dA dt Note that the direction of the Poynting vector coincides with the direction of the wave propagation while its magnitude is equal to the rate of energy transfer per unit area. c) Wave intensity I is the ratio of the average rate at which an electromagnetic wave carries energy through an imaginary surface, which is perpendicular to the propagation direction, to the area of the surface. (SI unit W/m2) I ≡ Sav d) Intensity I and energy density u of a wave are proportional with the speed of light being the proportionality constant. I = Sav = ( c ⋅ u ( t )) av = cu av For a certain electromagnetic radiation (a superposition of sinusoidal waves), the function relating the intensity of each sinusoidal wave with the wavelength is called the spectrum of that radiation. 117 87. (34.7) Electromagnetic radiation that stimulates the human eye is called visible light. This includes waves with wavelengths between 400nm and 700nm. The maximum sensitivity of the human eye is to light with a wavelength of about 555nm, which corresponds to the maximum intensity of the sun's spectrum. Electromagnetic radiation also includes radio waves, infrared and ultraviolet (black) light, X-rays and γ-rays. 118 LIGHT AND OPTICS 88. (35.3, 35.4, 35.5) Reflection and refraction At the boundary of two media, light undergoes both reflection and refraction. angle of incidence incident ray angle of reflection θ1 θ’1 θ2 reflected ray refracted ray angle of refraction a) The law of reflection The reflected ray lies in the plane of incidence and the angle of reflection θ1' is equal to the angle of incidence θ1 θ'1 = θ1 b) The law of refraction (Snell's law) The refracted ray lies in the plane of incidence and the angle of refraction θ2 is related to the angle of incidence by n1 sin θ1 = n2 sin θ2 In general, index of refraction of a medium is a function of the radiation wavelength. 119 89. (35.7) Total internal reflection Total internal reflection occurs when light travels from a medium of high index of refraction to one of lower index of refraction. The smallest angle θc at which total internal reflection occurs is called the critical angle. θc = sin− 1 n2 n1 ( n1 > n2 ) because n1 sin θc = n2 sin 90° 90. In order to be seen, an object must send light from each of its points in many directions. The eye collects some of the light emitted from a point allowing the brain to interpret the location of the point. In some situations diverging rays are interpreted as originating from a single point creating an image of a point. 120