Preparing for the Physics GRE Day 4 Circuits and Optics Daniel T. Citron dtc65@cornell.edu Cornell University 3/15/16 Circuits • Kirchoff’s rules • Basic circuit elements – R, L, C – Units and 9me scales – Addi9on Rules • Differen9al equa9on framework • Common Circuit Types • AC Circuits – Inductance – RLC circuit equa9on and solu9ons • Other topics – Logic Gates Kirchoff’s Laws • Conserva9on of Charge ó No net current flux at any point • Conserva9on of Energy ó No net voltage over any loop • Ohm’s law – Most general: – More useful for circuits: V = IR V = IZ Basic Circuit Elements • Remember how they affect voltages Basic Circuit Elements • Voltage drops ó units – [R] = [V/I] = JS/C2 – [C] = C/[V] = C2/J – [L] = [V/(I/S)] = JS2/C2 • Time scales – [RC] = S – [L/R] = S – [LC] = S2 • (Will be useful for circuits with 9me constants) Addi9on Rules • R: Add in series • C: Add in parallel • L: Add in series output voltage. If the angular frequency input voltage is varied, which of the follow gives the ratio Vo Vi G as a function of V (B) 40 m s (C) 1 1012 (D) 4 1012 (E) 2 1013 V m s V m s V m s Example (A) 68. The circuit shown (B)in the figure above consists of eight resistors, each with resistance R, and a battery with terminal voltage V and negligible internal resistance. What is the current flowing through the battery? (A) (B) (C) (D) 68. The circuit shown in the figure above consists (E) of eight resistors, each with resistance R, and a battery with terminal voltage V and negligible internal resistance. What is the current flowing through the battery? 1V 3R 1V 2R V R 3V 2R V 3 R (C) (D) (E) (B) 40 V m s (C) 1 1012 (D) 4 1012 (E) 2 1013 V m s V m s V m s input voltage is varied, which of the fo gives the ratio Vo Vi G as a functio Example • What i(B) s the voltage drop across each of the resistors in parallel? • What d(C)oes this tell us about the voltage drop across the two center resistors (D) • (Related problem: symmetric resistor cube) 68. The circuit shown in the figure above consists of eight resistors, each with resistance R, and a battery with terminal voltage V and negligible internal resistance. What is the current flowing through the battery? 1V (A) (E) Differen9al Equa9on Framework • For a single loop in a circuit, we can use Kirchoff’s loop rule to write an ODE rela9ng voltage drops across each element • Example: LC Series Circuit h]ps://upload.wikimedia.org/wikipedia/commons/b/b2/LC_parallel_simple.svg Differen9al Equa9on Framework • Voltage drop across capacitor vs 9me: • Voltage drop across inductor vs 9me: • Combine using loop rule: al s ws y the then be (A) (B) (C) (D) (E) deflected in the deflected in the deflected in the deflected in the undeflected +x-direction x-direction +y-direction y-direction LC Circuit ODE Example 59. For an inductor and capacitor connected in series, the equation describing the motion of charge is d 2Q 1 L 2 + Q = 0, C dt where L is the inductance, C is the capacitance, and Q is the charge. An analogous equation can be written for a simple harmonic oscillator with position x, mass m, and spring constant k. Which of the following correctly lists the mechanical analogs of L, C, and Q ? (A) (B) (C) (D) (E) L m m k 1/k x C k 1/k x 1/m 1/k Q x x m x 1/m LR Circuit Example • (Ignore numerical values for R, L for now) • What is the voltage drop across R? • What is the voltage drop across L? 40. In the circuit shown above, the switch S is closed at t = 0. Which of the following best represents the voltage across the inductor, as seen on an oscilloscope? (A) (B) (C) (D) Time scale of solu9on? (E) 40. In the circuit shown above, the switch S is closed at RLC Circuits • Most general solu9on gives us damped oscilla9ons • Important to pay a]en9on to boundary condi9ons • Can remove terms based on other circuits Impedance • Like resistance, but with a phase factor • Affects signal amplitude Another Example • What kind of behavior do circuit elements allow? Another Example • What is the star9ng charge on the capacitor? Geometric Op9cs • Reflec9on • Refrac9on -­‐ Snell’s Law • Mirrors and Lenses – Thin Lens Equa9on – Magnifica9on – Lensmaker’s Formula • Other topics – Telescopes – Apertures Reflec9on • Angle of incidence equals angle of reflec9on θin = θout Snell’s Law • Relates angle of incidence to angle of refrac9on – n represents refrac&on index of material – Can change depending on light wavelength Snell’s Law 97. A beam of light has a small wavelength spread d l about a central wavelength l . The beam travels in vacuum until it enters a glass plate at an Suppose a system in quantum stat 99 angle q98. relative to the that normal to the plate, as has energy E . In thermal equilibrium shown in the figure above. The i index of refraction of the glass isexpression given by n ( l ) . The angular spread dq of the refracted beam is given by (A) dq (B) dq (C) dq (D) dq 97. A beam of light has a small wavelength spread d l about a central wavelength l . The beam travels in vacuum until it enters a glass plate at an angle q relative to the normal to the plate, as (E) dq Ei e 1 dl n Ei / kT i dn ( l ) dl dl e Ei / kT i represents which of the following? 1 dl dl l dnThe average energy of the system (A) (B) The partition function sin q d l (C) l sin q Unity (D) The probability to find the system E dn ( l ) tan q energy dl i (E)n Thedlentropy of the system 99. A photon strikes an electron of mass m Thin Lens Equa9on • This is the only equa9on you need, provided you can interpret it correctly • O = object distance from lens • I = image distance from lens • F = focal point distance from lens Thin Lens – Geeng Signs Right • Sign conventions (why this is nontrivial) – A is where light comes from, B is where light passes to – Note side B is different for mirrors and lenses Thin Lens – Geeng Signs Right • Recommend picking on case to memorize – O > 0 – F > 0 – I = ? 74. The figure above shows an object O placed at a distance R Thin Lens Example 74. The figure above shows an object O placed at a distance R to the left of a convex spherical mirror that has a radius of curvature R. Point C is the center of curvature of the mirror. The image formed by the mirror is at (A) infinity (B) a distance R to the left of the mirror and inverted (C) a distance R to the right of the mirror and upright R (D) a distance to the left of the mirror and inverted 3 R (E) a distance to the right of the mirror and upright 3 Thin Lens Example – Ray Diagram • Draw rays to get qualita9ve sense of image – Rays from object to focus reflect parallel – Parallel rays from object reflect from focus – Rays from object to center reflect at equal angle • Same deal for lenses, but with passing through Example Ray Diagrams -­‐ Lenses h]p://hyperphysics.phy-­‐astr.gsu.edu/%E2%80%8Chbase/geoopt/raydiag.html Magnifica9on • Magnifica9on is image size rela9ve to object – Image is “imaginary” if not in real space (I < 0) – Image is “real” if projected into real space One more example: Mul9ple Lenses • Treat the image from the first lens as a virtual object 8. – 1. Find the image from the first lens A positive charge Q is located at a distance L 2. Use geometry to find O above an– infinite grounded conducting plane, as shown in the figure above. What is the total foronthe second lens charge induced the plane? (A) 2Q – 3. Apply lens equation a (B) Q second time (C) 0 (D) Q (E) 2Q 9. Five positive charges of magnitude q are arranged symmetrically around the circumference of a circle of radius r. What is the magnitude of the electric field at the center of the circle? ( k = 1 4 p!0 ) 11. An object is located 40 centimeters from the first of two thin converging lenses of focal lengths 20 centimeters and 10 centimeters, respectively, as shown in the figure above. The lenses are separated by 30 centimeters. The final image formed by the two-lens system is located (A) (B) (C) (D) (E) 5.0 cm to the right of the second lens 13.3 cm to the right of the second lens infinitely far to the right of the second lens 13.3 cm to the left of the second lens 100 cm to the left of the second lens Mul9ple lenses Q is located at a distance L ounded conducting plane, re above. What is the total he plane? 11. An object is located 40 centimeters from the first of two thin converging lenses of focal lengths 20 centimeters and 10 centimeters, respectively, as shown in the figure above. The lenses are separated by 30 centimeters. The final image formed by the two-lens system is located (A) (B) (C) (D) (E) 5.0 cm to the right of the second lens 13.3 cm to the right of the second lens infinitely far to the right of the second lens 13.3 cm to the left of the second lens 100 cm to the left of the second lens • First lens: O = 40 cm, F = 20 cm, I = ? • Second lens: F = 10 cm, O = ?, I = ? s of magnitude q are ally around the circumference r. What is the magnitude of he center of the circle? Lensmaker’s formula 14. Two experimental techniques determine the mass of an object to be 11 1 kg and 10 2 kg. These two measurements can be combined to give a weighted average. The uncertainty of the weighted average is equal to which of the following? • Find the focal point, given the radii of the two faces of the lens (A) (B) (C) 1 kg 2 2 kg 5 2 kg 3 (D) 2 kg (E) 5 kg 15. If the five lenses shown below are made of the same material, which lens has the shortest positive focal length? (A) (B) (C) (D) (E) h]p://hyperphysics.phy-­‐astr.gsu.edu/hbase/hframe.html Telescopes • Telescope angular magnification – fE: Focal length of eyepiece – fO: Focal length of objective – Note: The two lenses share a focal point