Introduction to Circuits © UC3M/TSC 2008 3.1 Elements in Circuits i (t ) Elements in circuits + • Two terminals v(t ) Device (R, L,C) (Source) Both voltage and current are signed variables − i (t ) • Instantaneous power + p (t ) = v(t )i (t ) 3A p (t ) = 15 W 5V − − p (t ) = −15 W -5 V p (t ) = −15 W + − Consumes v (t ) Device (R, L,C) (Source) −3 A + − © UC3M/TSC 2008 If p(t)<0, the device generates 3A + 5V If p(t)>0, the device consumes Generates Systems and Circuits Generates 2 3.1 Elements in Circuits Active • Ideal Sources: maintain their nominal value independently of what is connected to their terminals (do not exist as practical devices) − Voltage v(t ) + VS − + constant − − Current i (t ) 5V 5A + − 2A Remember: Both voltage and current are signed variables © UC3M/TSC 2008 Permitted Systems and Circuits 2A Not permitted 3 3.1 Elements in Circuits Active • Dependent sources or controlled sources: − Establishes a voltage or current whose value depends on the value of a voltage or current elsewhere in the circuit. • Voltage source dependent on: Current Voltage α vx (t ) + ρ i y (t ) − + − • Current source dependent on: Current β is (t ) © UC3M/TSC 2008 Voltage µ vr (t ) Systems and Circuits 4 3.1 Elements in Circuits Passive • Relationship between the voltage and current in − Resistor (Ohm’s law) + v(t ) Both the voltage and the current are signed variables + 10RΩ 5V 10RΩ − − R − v(t ) = Ri (t ) + 0.5 A −5 V − © UC3M/TSC 2008 −0.5 A 0.5 A 5V i (t ) + Systems and Circuits 10RΩ − 5V 0.5 A 10 RΩ + 5 3.1 Elements in Circuits Passive • Voltage-current relationship in resistors (Ohm’s law) + v(t ) = Ri (t ) i (t ) v(t ) R 400 − v(t ) = 220 2 sin(2π 50t ) V 300 200 100 R = 10Ω i (t ) = 22 2 sin(2π 50t ) A 0 -100 -200 -300 -400 © UC3M/TSC 2008 0 0.01 0.02 0.03 Systems and Circuits 0.04 0.05 0.06 0.07 0.08 0.09 0.1 6 3.1 Elements in Circuits Passive 400 • Voltage-current relationship in resistors (Ohm’s law) 200 100 + i (t ) i (t ) v(t ) = Ri (t ) v(t ) 0 -100 R -200 -300 − -400 v(t ) = 220 2 sin(2π 50t ) V 0 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 10000 p (t ) R = 10Ω 8000 i (t ) = 22 2 sin(2π 50t ) A p (t ) = v(t )i (t ) = v(t ) 300 6000 2 v (t ) 2 = i (t ) R [W] R Consumes 4000 2000 p(t)>0, resistors always consume power 0 -2000 © UC3M/TSC 2008 0 0.01 0.02 Systems and Circuits 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.1 7 3.1 Elements in Circuits Circuits • Nodes, branches, closed paths and loops Branch Mesh L1 L2 R2 v(t ) + C2 C3 R1 − Loop L3 C4 C1 Node Essential node: point where two or more circuit elements meet Essential branch: connects two essential nodes © UC3M/TSC 2008 Systems and Circuits 8 3.2 Resolution by means of Kirchhoff Laws Circuit resolution • Obtain current values in each branch and/or voltage in each node Kirchhoff’s current law • “The algebraic sum of all currents at any node in a circuit equals 0 A”. ia ib ic ia − ib − ic − id = 0 −ia + ib + ic + id = 0 id Incoming currents (+) Outgoing currents (-) Incoming currents (-) Outgoing currents (+) ia = ib + ic + id © UC3M/TSC 2008 Sum of incoming currents = Sum of outgoing currents Systems and Circuits 9 3.2 Resolution by means of Kirchhoff’s Laws Circuit resolution • Obtain current values in each branch and/or voltage in each node Kirchhoff’s current law • “The algebraic sum of all currents at any node in a circuit equals 0 A”. −3A 12A −16A 1A −3 − 12 + 16 − 1 = 0 3 + 12 − 16 + 1 = 0 Incoming currents (+) Outgoing currents (-) Incoming currents (-) Outgoing currents (+) −3 = 1 + 12 − 16 Sum of incoming currents = Sum of outgoing currents © UC3M/TSC 2008 Systems and Circuits 10 3.2 Resolution by means of Kirchhoff Laws Circuit resolution • Obtain current values in each branch and/or voltage in each node Kirchhoff’s voltage law • “The algebraic sum of all voltages around any closed path in a circuit equals 0 V” − The tracing direction of the closed path is arbitrary vL 3 (t ) + vC 2 (t ) + vL 2 (t ) − vC1 (t ) = 0 L1 − + R2 vC 2 (t ) C2 − vL 3 (t ) − © UC3M/TSC 2008 L3 + vC1 (t ) − Voltage rise (+) −vL 3 (t ) − vC 2 (t ) − vL 2 (t ) + vC1 (t ) = 0 Voltage drop (-) vL 2 (t ) + + C4 L2 Voltage rise (+) Voltage drop (-) C1 vC1 (t ) = vL 3 (t ) + vC 2 (t ) + vL 2 (t ) Sum of voltage drops = Sum of voltage rises Systems and Circuits 11 Examples Simple resistive circuits © UC3M/TSC 2008 Systems and Circuits 12 3.3 Resistive Circuits Equivalent resistor • Series-connected elements: Kirchhoff’s voltage law −+ + R1 − −+ R2 − + R3 RN I ( R1 + R2 + L + RN ) = IReq I Req I © UC3M/TSC 2008 N Req = R1 + R2 + L + RN = ∑ Rk k =1 Systems and Circuits 13 3.3 Resistive Circuits Equivalent resistor: • Parallel-connected elements: Kirchhoff’s current law + V − R1 R2 R3 + V − RN Req = 1 1 1 1 + +L + R1 R2 RN ⎛ 1 1 1 + + L + V Req ⎜ RN ⎝ R1 R2 = ⎞ V ⎟= ⎠ Req 1 N ∑ 1 Rk 1 = k =1 − Two resistors in parallel: R1 © UC3M/TSC 2008 R2 Req Req = 1 1 + R1 R2 Systems and Circuits R1 R2 R1 + R2 14 3.3 Resistive Circuits The voltage-divider circuit: R1 + + R2 V − V2 − ⎛ R2 ⎞ V V2 = R2 = ⎜ ⎟V R1 + R2 ⎝ R1 + R2 ⎠ ⎛ R2 ⎞ ⎜ ⎟ ≤1 ⎝ R1 + R2 ⎠ © UC3M/TSC 2008 Systems and Circuits 15 3.3 Resistive Circuits The current-divider circuit: I I1 I1 + I 2 = I R1 I2 R2 I1 R1 = I 2 R2 R1 I1 + I1 =I R2 ⎛ R2 ⎞ I1 = ⎜ ⎟I ⎝ R1 + R2 ⎠ ⎛ R2 ⎞ ⎜ ⎟ ≤1 ⎝ R1 + R2 ⎠ © UC3M/TSC 2008 ⎛ R1 ⎞ I2 = ⎜ ⎟I ⎝ R1 + R2 ⎠ ⎛ R1 ⎞ ⎜ ⎟ ≤1 ⎝ R1 + R2 ⎠ Systems and Circuits 16 Voltage sign Why can a voltage be negative? © UC3M/TSC 2008 Systems and Circuits 17 Elements in Circuits Inductors… © UC3M/TSC 2008 Systems and Circuits 18 Elements in Circuits Resistors © UC3M/TSC 2008 Systems and Circuits 19 Elements in circuits Capacitors © UC3M/TSC 2008 Systems and Circuits 20 3.4 Source transformations • Technique that allows a voltage source in series with a resistor to be replaced by a current source in parallel with the same resistor or vice versa. • The two configurations are equivalent with respect to nodes a and b. RS VS i + i a vab VS = I S RP IS RP vab RS = RP b b slope -RS vab VS Short circuit (vab=0) Open circuit (i=0) © UC3M/TSC 2008 vab v-I characteristic VS RS i slope -RP a v-I characteristic I S RP Short circuit (vab=0) i IS Systems and Circuits 21 3.5 Thévenin Equivalent A linear circuit made of sources (both independent and dependent) and resistors can be replaced by an independent voltage source VTh in series with a resistor RTh. • VTh is the Thévenin voltage • RTh is the Thévenin resistance Circuit A a RTH VTH RL b © UC3M/TSC 2008 ia + − RL b Systems and Circuits 22 3.5 Thévenin Equivalent A linear circuit made of sources (both independent and dependent) and resistors can be replaced by an independent voltage source VTh in series with a resistor RTh. Circuit A RTH a VTH RL + − RL b b ia Finding the Thévenin equivalent • Calculate the open-circuit voltage: VOC = VTH • Calculate the short-circuit current: IAB = ISC VOC R = • The Thévenin resistance is simply given by: TH I SC © UC3M/TSC 2008 Systems and Circuits 23 3.6 Norton Equivalent A linear circuit made of sources (both independent and dependent) and resistors can be replaced by an independent current source IN in parallel with a resistor RN. • IN is the Norton current • RN is the Norton resistance Circuit A a i a RL RN RL b b © UC3M/TSC 2008 IN Systems and Circuits 24 3.6 Norton Equivalent A linear circuit made of sources (both independent and dependent) and resistors can be replaced by an independent current source IN in parallel with a resistor RN. Circuit A a i a IN RL RL b b RN Finding the Norton Equivalent • • Calculate the short-circuit current: ISC = IN Calculate the open-circuit voltage: VAB = IN RN • The Norton resistance is given by: RN = © UC3M/TSC 2008 VOC IN Systems and Circuits 25 Thévenin Equivalent Maximum power transfer: • What’s the value of RL such that the dissipated power is maximum? R a TH VTH i + − RL b PRL 2 ⎛ VTH ⎞ PRL = ⎜ ⎟ RL ⎝ RTH + RL ⎠ PRL MAX 0 © UC3M/TSC 2008 RL , MAX RL Systems and Circuits 26 Thévenin Equivalent Maximum power transfer: • What’s the value of RL such that the dissipated power is maximum? RTH ia VTH 2 ⎛ VTH ⎞ RL PRL = ⎜ ⎟ RL ⎝ RTH + RL ⎠ + − PRL b dPRL dRL 0 © UC3M/TSC 2008 RTH ⎛ ( RTH + RL )2 − RL 2 ( RTH + RL ) ⎞ =V ⎜ ⎟ 4 ⎜ ⎟ dRL ( RTH + RL ) ⎝ ⎠ dPRL 2 = 0 → ( RTH + RL ) − RL 2 ( RTH + RL ) = 0 dRL dPRL =0 RL dPRL dR L Systems and Circuits 2 TH = 0 → RTH = R L 27