EE C245 - ME C218 Introduction to MEMS Design Fall 2003 Roger Howe and Thara Srinivasan Lecture 13 Alternative Transduction Principles EE C245 – ME C218 Fall 2003 Lecture 13 Today’s Lecture • • • • Piezoelectric materials for MEMS: courtesy of Justin Black (jblack@eecs) and Prof. R. M. White Piezoresistive strain sensing in silicon: mechanism and device application Thermal actuation: microtweezers Reading: Senturia, S. D., Microsystem Design, Kluwer Academic Publishers, 2001, Chapter 18, pp. 470477, Chapter 21, 570-578. EE C245 – ME C218 Fall 2003 Lecture 13 2 1 Origin of the Piezoelectric Effect Several views of an α -quartz crystal Z X2 X3 Si Y O X1 EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 3 Origin of the Piezoelectric Effect For r >> a, the electric field at the point P is: E p = E + + E − ≈ 3q 4 πε r 2 − 3q 4 πε r 2 = 0 The potential and electric field appear as if the charges are coincident at their center of gravity (point O) Ep ≅ 0 a/ 4 P a/ 2 O r >> a Si atom O atom Introduction to Quartz Crystal Unit Design , Virgil Bottom, 1982. EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 4 2 Origin of the Piezoelectric Effect ♦ ♦ ♦ Assume the applied force F causes the line OD to rotate counter clockwise by a small angle dθ This strain shifts the center of gravity of the three positive and negative charges to the left and right, respectively 60° dθ O A dipole moment, p = qr, is created which has an arm (r) of: p = qr @ qa33/2 dθ ♦ F D Assuming the crystal contains N such molecules per unit volume, each subject to the same strain dθ, the polarization (or dipole moment per unit volume) is: P = Nqa33/2 dθ polarization strain EE C245 – ME C218 Fall 2003 Lecture 13 P = Nqr F Si atom O atom J. Black and R. M. White 5 Origins of the Piezoelectric Effect ♦ For sufficiently small deformations, the polarization (P) is linearly related to the strain (S) by: P = gS where g is the piezoelectric voltage coefficient. ♦ The polarization P equals the surface charge per unit area, or piezoelectric displacement. Converse Piezoelectric Effect ♦ When a piezoelectric crystal is placed in an electric field, pos itive and negative ions are pushed in opposite directions and a dipole tends to rotate to align itself with the electric field. ♦ The resulting motion gives rise to a strain S that is proportional to the electric field E S = dE where d is the piezoelectric charge coefficient. EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 6 3 Anisotropic Crystal Properties: Generalized Stress-Strain Perspective and cross sectional views of α -quartz ♦ In anisotropic materials a tensile stress can produce both axial and shear strain. ♦ For example, a thin, X-cut rod of quartz subject to a tensile force will not only become longer and thinner, but it will also rotate about its longitudinal axis. ♦ Since we have 6 components of stress (T) and 6 components of strain (S), 36 constants must be used to describe behavior in the general case. ♦ Crystal symmetry (e.g. trigonal, hexagonal) greatly reduces the number of independent constants. Si EE C245 – ME C218 Fall 2003 Lecture 13 O 7 J. Black and R. M. White Anisotropic Crystal Properties: Generalized Stress-Strain For small deformations, stress (T) and strain (S) are related through the compliance matrix (s) Sxx S yy Szz = Syz S zx Sxy s11 s 21 s31 s41 s51 s61 s12 s22 s13 s14 s15 s23 s 24 s25 s32 s42 s52 s33 s34 s35 s43 s 44 s45 s53 s54 s55 s62 s63 s 64 s65 s16 Txx s26 Tyy s36 Tzz s46 Tyz s56 Tzx s66 Txy Quartz has threefold symmetry, physical properties repeat every 120°. Quartz is also symmetric about the X-axis Z Conservation of energy requires sij = sji. Performing rotations based upon trigonal symmetry considerations, the compliance matrix reduces to 6 independent coefficients: Sxx s1 1 s1 2 Syy s 2 1 s1 1 Szz s s1 3 = 13 Syz s1 4 − s1 4 0 0 Szx Sxy 0 0 s1 3 s1 4 s1 3 − s1 4 s3 3 0 0 s44 0 0 0 0 0 0 0 0 s4 4 2s1 4 Txx T yy Tzz T yz 2s1 4 Tzx 2(s1 1 − s1 2 ) Txy EE C245 – ME C218 Fall 2003 Lecture 13 0 0 0 0 X2 X3 Y X1 J. Black and R. M. White 8 4 Anisotropic Crystal Properties: Piezoelectric Constants Recall that the strain (S) is related to the electric field (E) by the piezoelectric charge coefficient matrix (d) Sxx S yy Szz = Syz S zx Sxy d11 d21 d 12 d 22 d13 d23 d14 d 24 d15 d25 d16 d 26 d31 d32 E x d33 E y d34 E d35 z d36 Applying the symmetry conditions for quartz, the piezoelectric strain matrix (d) simplifies to: STRAIN (S) S xx S yy Szz = Syz S zx S xy d11 0 − d 0 11 0 0 0 d14 0 − d14 − 2d11 0 0 0 E x 0 E y 0 E 0 z 0 FIELD (E) X EXTENSIONAL Y Z X Y Z SHEAR (about axis) X Y Z EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 9 Anisotropic Crystal Properties Modes in Quartz ♦ Elastic modulus and compliance ♦ Thermal conductivity ♦ Electrical conductivity ♦ Coefficient of thermal expansion ♦ Dielectric constants ♦ Piezoelectric constants ♦ Optical index of refraction ♦ Velocity of propagation of longitudinal waves ♦ Velocity of propagation of shear waves EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 10 5 Constitutive Equations for Piezoelectric Materials compliance piezoelectric strain coefficients S = sE T + d E strain stress electric field piezoelectric strain coefficients (transpose) dielectric permittivity D = dTr T + ε T E electric stress displacement electric field Superscripted material constants (e.g. s E ) are those values obtained when the superscripted quantity is held constant. EE C245 – ME C218 Fall 2003 Lecture 13 11 J. Black and R. M. White Properties of Common Piezoelectrics Stiffness (1010 N / m2) Strain Coefficient (10-1 2 C / N) Relative Permittivity Coupling Coefficient K2 (%) Velocity (m / s) Density (kg / m3) Aluminum Nitride (AlN) 33.0 5.6 (d33) 8.6 6.0 11,300 3.26 Barium Titanate (BaTiO 3) * 11.0 - 27.5 82-145 (d33) 625-1350 39 – 46 4460 5.85 Lithium Niobate (LiNbO 3) 24.5 19.2 (d33) 44 17.2 4379 † 4.64 Lithium Tantalate (LiTaO 3) 23.3 8.0 (d33) 41 4.7 4112 † 7.64 P(VDF –TrFE) 0.3 -12.0 (d31) 13 Quartz (SiO 2) 10.7 2.3 (d11) 4.5 0.11 PZT (PbZrTiO3)* 4.8 – 13.5 240-550 (d3 3) 1100- 3200 Zinc Oxide (ZnO) 21.0 10-12 (d 33) 8.5 SAW Substrates Thickness mode, thin film Ferroelectric ceramic, bulk material Ferroelectric polymer EE C245 – ME C218 Fall 2003 Lecture 13 † † 0.18 k2 = 2400 1.88 3948 † 2.65 66 - 73 4600 7.55 7.5 6,080 5.60 † mechanical energy stored electrical energy applied 12 6 SAW Devices Uz ♦ The stress-free boundary condition imposed by the surface of a crystal gives rise to an acoustic mode known as a surface acoustic wave (Rayleigh wave) ♦ SAW energy is confined to within one wavelength of the surface ♦ The components of surface particle motion, Ux and Uz, are 90º out of phase, and Uz >> Ux ♦ SAWs can be excited by interdigitated transducers (IDTs) patterned on the surface of piezoelectric crystals* ♦ IDT geometry allows construction of delay lines, convolvers, correlators, pulse compressors, filters Ux Used by the billions in communications and electronic systems; invented by Prof. R. M. White, EECS Dept., UC Berkeley, 1965. EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 13 SAW State-of-the-Art ♦ Smallest SAW RF filter is 1.4 x 2.0 x 0.7 mm3 (EPCOS) ♦ Trend towards integration of passive components into ceramic SAW package 2 mm x 2mm x 0.8 mm3 SAW from EPCOS Integrated SAW duplexer: receiver filter, transmit filter, antenna matching network Robert Weigel, et al ., “Microwave Acoustic Materials, Devices,and Applications,” IEEE Transactions on Microwave Theory and Techniques, March 2002. EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 14 7 Thin Film Bulk Acoustic Resonators Piezoelectric thin film (ZnO or AlN) sandwiched between electrodes Quarter wavelength reflectors (e.g. W and SiO2) Piezoelectric thin film (ZnO or AlN) sandwiched between electrodes Substrate Solidly Mounted Resonator (SMR): Quarter wavelength reflectors (also called acoustic Bragg reflectors) confine acoustic energy to top piezoelectric layer FBAR: Remove substrate to confine energy within the membrane. Resonant frequency can range from 500 MHz to 20+ GHz. EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 15 Thin Film Bulk Acoustic Resonators ♦ Commercially available from Agilent (FBAR) and TFR Technologies (SMR) ♦ Agilent’s volume is ~ 2.5 million / month (Rich Ruby, Agilent, Oct. 2003) ♦ Advantages include: ♦ • Up to 20 times area reduction • Lower parasitics • Steeper skirts • Lower insertion loss • Operation above 10 GHz • Power handling www.agilent.com Filter bandwidth limited by K2 of piezoelectric film EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 16 8 Derivation of Equivalent BVD Circuit Assume piezoid is a thin plate of thickness d with infinite extent in x and z (1-d solution) The equation of motion for the particle displacement ψ(y, t) is: ρ ∂ 2ψ ∂ 2ψ ∂ψ −c +r = 0 2 ∂t ∂y 2 ∂t k = β − jα = → ψ ( y , t ) = A ( y )e j ω t V (t ) = V m e jω t ρω 2 ωr − j c c P = strain * g = d piezoid y x c = stiffness ∂ψ *g ∂y ρ = density r = damping ∂ 2V σ 1 ∂P = − = ∂y 2 ε ε ∂y i =ε y = plate position g = piezoelectric coefficient ∂E = i dielectric + i piezoelectric = Y ( jω )Vm e jωt ∂t displacement displacement P = polarization V = voltage E = electric field σ = charge density EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 17 Equivalent BVD Circuit K.M. Lakin, Thin Film Resonators and Filters, IEEE Ultrasonics Symp., Oct. 1999. R= d 3r 8Ag 2 Co = Aε d ρd 3 L = 8 Ag 2 C = Ra Co La Ca 8 Ag 2 8 k 2 C o = π 2 dc π2 k2 = g2 cε ♦ Impedance governed by transducer area ♦ Typical SMR values are Co= 1.91 pF, Ca = 0.80 pF, Ra = 1.14 Ω, and La = 123.6 nH. These values correspond to a Q of approximately 1000† EE C245 – ME C218 Fall 2003 Lecture 13 J. Black and R. M. White 18 9 Piezoresistivity • Strain dependence of electrical resistivity: a strong effect in semiconductors, including silicon and poly-Si • General expression: tensors galore! resistivity piezoresitivity tensor (4th rank) electric field E = (ρ + Π σ) J electric field Stress tensor (2nd rank) • Silicon: resistivity is a diagonal tensor with all elements equal to ρ ; the stress tensor collapses with cubic symmetry to a six-element array (reduced notation) EE C245 – ME C218 Fall 2003 Lecture 13 19 Piezoresistive Coefficients in Silicon • Field-current equation has three independent piezoresistive coefficients; along the <100> direction E1 = ρ{[1 + π 11σ 1 + π 12 (σ 2 + σ 3 )] J1 + π 44 (τ 12 J 2 + τ 13 J 3 )} • The conventional π coefficients are related to the tensor elements by: Π 1111 = ρπ 11 Π 1122 = ρπ 12 Π 2323 = ρπ 44 / 2 EE C245 – ME C218 Fall 2003 Lecture 13 20 10 Typical Embedded Strain-Sensing Resistor • Implantation defines a shallowresistor of opposite type to bulk silicon structure F side view X top view F Orientation of piezoresistor is longitudinal (aligned with bending strain in beam) EE C245 – ME C218 Fall 2003 Lecture 13 21 Longitudinal and Transverse Piezoresistive Coefficients • Relative resistance change can be expressed by the longitudinal πl and transverse πt piezoresistive coefficients ∆R / R = π lσ l + π tσ t • Piezoresistors are often aligned to the wafer flat of (100) wafers, which is in the [110] direction. Senturia, p. 473 provides the result of coordinate transformations: 1 (π11 + π 12 + π 44 ) 2t 1 π t ,110 = (π 11 + π 12 − π 44 ) 2t π l ,110 = EE C245 – ME C218 Fall 2003 Lecture 13 22 11 Silicon Piezoresistive Coefficients • Function of type, doping, and temperature ρ π11 π12 π44 n-type 11.7 -102.2 53.4 -13.6 p-type 7.8 6.6 -1.1 138.1 Units: ρ [Ω-cm], π’s 10-11 Pa-1 Values are at T = 25oC • Longitudinal and transverse coefficients in [110] direction n-type: π l = -31.2 x 10-11 Pa-1 π t = -17.6 x 10-11 Pa-1 p-type: π l = 71.8 x 10-11 Pa-1 π t = - 66.2 x 10-11 Pa-1 EE C245 – ME C218 Fall 2003 Lecture 13 23 Piezoresistor Placement • Bulk micromachined diaphragm pressure sensor R1 R3 R2 R1 R3 R4 EE C245 – ME C218 Fall 2003 Lecture 13 24 12 Piezoresistive Wheatstone Bridge • Resistors experience both longitudinal and transverse stress when diaphragm deflects: effects are almost equal and opposite on two sets of resistors ∆R1 / R1 = π lσ l + π tνσ l = l (π l + νπ t )σ l = 67.6 x10− 11σ l ∆R2 / R2 = π tσ l + π lνσ l = (π t + νπ l )σ l = −61.7 x10− 11σ l VDC R2 R3 v + out - R1 R4 EE C245 – ME C218 Fall 2003 Lecture 13 25 Piezoresistive Strain Sensing Summary • Attractive for single crystal silicon structures, since π’s are specified by crystal orientation • Large literature on resistor sizing and placement for minimizing sensitivity to lithographic errors • Can result in highly sensitive transduction, depending on design of mechanical structure and placement of strain sensors • No need for a Ph.D. in analog IC design from Berkeley in order to amplify the output voltage from a Wheatstone bridge! (Why? Impedance levels are much lower … off-chip amplifier actually works.) EE C245 – ME C218 Fall 2003 Lecture 13 26 13 Limits of Piezoresistive Force Sensing • • Scale AFM cantilever to 70 nm thickness; develop very shallow (20 nm) implanted piezoresistor. Tom Kenny, Stanford ME Dept., Hilton Head Workshop, June 2002. Sensitivity is about 1 femto-Newton in a 1 Hz BW at 1 kHz EE C245 – ME C218 Fall 2003 Lecture 13 27 Piezoresistors as “Internal Transducers” • Instrumented micro force plate: capacitive transduction would lead to exposed electrodes, which could easily become contaminated • Application: measure forces exerted by a cockroach while walking on all six legs … and while running on two legs! Tom Kenny, Hilton Head Workshop, June 2002. EE C245 – ME C218 Fall 2003 Lecture 13 28 14 Measurements from Micro Force Plate Prof. Robert Full, Dept. of Integrative Biology, UC Berkeley Prof. Tom Kenny, ME Dept., Stanford EE C245 – ME C218 Fall 2003 Lecture 13 29 Thermal Actuation • Simple idea: thermal strain à dimensional change à generate desired motion. No tensors! • Challenges: 1. Thermal actuation requires static power dissipation (compare electrostatic actuation) 2. “Heatuator” on EE 245 MUMPS chip: limits to using geometry to control thermal expansion 3. Bandwidth of actuator is limited by thermal time constant … but could have BW > 100 kHz for MEMS EE C245 – ME C218 Fall 2003 Lecture 13 30 15 Hexsil Tweezer tweezer tips thermal expansion bar Linkage to amplify bar’s length change to control tweezer tip separation Chris Keller, Ph.D. MSE Dept., UC Berkeley, 1998 EE C245 – ME C218 Fall 2003 Lecture 13 31 Basic Hexsil Fabrication Process fabricate silicon mold conformal sacrificial layer deposition conformal structural layer deposition Chris Keller, Ph.D. MSE Dept., UC Berkeley, 1998 EE C245 – ME C218 Fall 2003 Lecture 13 32 16 Basic Hexsil Fabrication Process (cont.) Hexsil structure (surface layer holds molded portions together) reuse mold Deposit and pattern surface layers (e.g., for tweezer tips) Release structure by means of a (lengthy) sacrificial layer etch Chris Keller, Ph.D. MSE Dept., UC Berkeley, 1998 EE C245 – ME C218 Fall 2003 Lecture 13 33 PolySi Hexsil Structures Close-up of top of hexsil tweezer leverage mechanism, showing surface poly-Si face sheet EE C245 – ME C218 Fall 2003 Lecture 13 Close-up of bottom of hexsil tweezer leverage mechanism, showing molded poly-Si ribs 34 17 Thermal Actuation of Tweezer Tips 50 mW dissispated in the thermal expansion bar will actuate tweezer tips by about 40 µm; structure will withstand temperatures up to 1100o C for periods of 10 minutes Chris Keller, Ph.D. MSE Dept., UC Berkeley, 1998 EE C245 – ME C218 Fall 2003 Lecture 13 35 18