LECTURE 8

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Physics 132 Quiz # 14
1.1. Which
Whichis(are)
is(are)true?
true?Kirchhoff’s
Kirchhoff’ssecond
secondrule
rulerelates
relates
a.)
a.) the
thesum
sumof
ofthe
theemfs
emfsaround
aroundaaclosed
closedloop
loopininaa
circuit
circuittotothe
thepotential
potentialchanges
changesacross
acrossall
allresistors
resistors
and
andcircuit
circuitelements.
elements.
b.)
b.) implies
impliesconservation
conservationof
ofenergy
energyininelectric
electric
circuits.
circuits.
c.)
c.) relates
relatesthe
thecurrents
currentsentering
enteringand
andleaving
leavingany
any
branch
branchpoint
pointininaacircuit.
circuit.
d.)
d.) all
allof
ofthe
theabove
above
e.)
e.) two
twoof
ofthe
theabove
above
f.)
f.) none
noneof
ofthe
theabove
above
2.2. AAresistor
resistorand
andan
aninitially
initiallyuncharged
unchargedcapacitor
capacitor
arranged
arrangedininseries
seriesare
arecharged
chargedby
byaabattery,
battery,which
which
isisconnected
connectedatattt==0.The
0.Thecurrent
currentininthe
thecircuit
circuit
a.)
a.) isisconstant
constantbecause
becausethe
theemf
emfsupplied
suppliedby
bythe
the
battery
batteryisisconstant.
constant.
b.)
b.)decreases
decreasesexponentially
exponentiallyinintime.
time.
c.)
c.)increases
increasesexponentially
exponentiallyinintime.
time.
d.)
d.)There
Thereisisno
nocurrent
currentbecause
becausethe
theelectrons
electrons
cannot
cannotflow
flowthrough
throughthe
thegap
gapininthe
thecapacitor.
capacitor.
LECTURE 15
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must show
show work
work on
on the
the
problem,
problem, and
and must
must have
have
specific
specific question
question
Wednesday
Wednesday lecture:
lecture: more
more
practice
practice of
of DC
DC circuits
circuits
New
New assignment
assignment handed
handed out
out
on
on Wednesday
Wednesday
Kirchhoff’s rules for electric circuits
Typical
Typicalproblem
problem
Given:
Given:
••resistors,
resistors,
••batteries,
batteries,
••connections
connections
Find:
Find:
•current
•currentthrough,
through,
•voltage
•voltageacross
across
any
anycircuit
circuitelement
element
Gustav Robert Kirchhoff
I.I. Rule
Rulefor
for“nodes”
“nodes”
“current
“currentin=current
in=currentout”
out”
Example:
I1
J1
I2
I3
J2
I1 + I 2 + I 3 = J 1 + J 2
I=
∆Q
∆t
⇓
∆Q1 ∆Q2 ∆Q3 ∆q1 ∆q2
=0
−
−
+
+
∆t ∆t ∆t
∆t
∆t
c
∆Q1 + ∆Q2 + ∆Q3 − ∆q1 − ∆q2 = 0
Charge on the node
is conserved
II.
II.Rule
Rulefor
for“loops”
“loops”
“Algebraic
“Algebraicsum
sumof
ofpotential
potentialchanges
changes==zero”
zero”
E1
E2
Energy
Energyisis
conserved
conserved
II.
II.Rule
Rulefor
for“loops”(cont’d)
“loops”(cont’d)
“Algebraic
“Algebraicsum
sumof
ofpotential
potentialchanges
changes==zero”
zero”
− IR1 − IR2 − E2 − Ir2 − IR3 + E1 − Ir1 = 0
E1 − E2
I=
R1 + R2 + R3 + r1 + r2
Alternate form:
E1 − E2 = IR1 + IR2 + Ir2 +IR3 + Ir1
“Loop rule”: Sum of E’s = sum of IR’s
Basic strategy: WATCH FOR +/- SIGNS!!
1. Label each battery with + (long side) and
– (short side)
2. Label the current in each branch with a
symbol and an arrow (arbitrary
direction).
3. Apply Kirchhoff’s node rule to one node
4. Apply Kirchhoff’s loop rule to a loop:
a. Choose a direction (clockwise or
counter-clockwise) to “go” around a
loop
b. Battery E is positive, if your direction
of circulation takes you from the “-”
pole to the “+” pole of the battery
c. Product IR is positive if direction of
circulation coincides with current
direction on the resistor
d. Write “Sum of E’s = Sum of IR’s”
5. Repeat 3-4 until # eqs. = # unknowns
6. Solve for unknowns (currents, for e.g.)
Problem 1: Calculate the current in the circuit
R2= 15 kΩ
R1= 5 kΩ
I
+
-
E=12 V
CONCEPT TEST:
TEST:
CONCEPT
Twoidentical
identicallight
lightbulbs
bulbs AAand
andBBare
are wired
wiredin
in
Two
seriesand
andconnected
connectedto
toaapower
powersupply,
supply,as
asshown
shown
series
inthe
thefigure.
figure.When
Whenthe
theswitch
switchisisclosed,
closed,the
the
in
brightnessof
ofbulb
bulbAA
brightness
1.increases
increases
1.
remainsthe
thesame
same
2.2.remains
3.decreases
decreases
3.
A
B
Problem 2: Calculate the current in each branch of
the circuit below:
R1= 5 kΩ
I1
I2
I
R2= 5 kΩ
+ E=12 V
R3= 15 kΩ
CONCEPT TEST:
TEST:
CONCEPT
Thelight
lightbulbs
bulbs in
inthe
thecircuit
circuitare
areidentical.
identical.When
When
The
theswitch
switchisisclosed
closed
the
bothgo
goout
out
1.1.both
2.AAbecomes
becomesbrighter
brighter
2.
3.BBbecomes
becomesbrighter
brighter
3.
4.AAbecomes
becomesdimmer
dimmer
4.
becomesdimmer
dimmer
5.5.BBbecomes
combinationof
of1-5
1-5
6.6.combination
nothingchanges
changes
7.7.nothing
12 V
12 V
12 V
Example: Wheatstone bridge: measures resistance
a.) Draw the equivalent circuit when the
bridge is balanced, and write Kirchoff’s laws
b.) calculate Rx if the bridge is balanced at 18 cm
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