Lecture 11 Chapter 31 Physics II Resistors Course website: http://faculty.uml.edu/Andriy_Danylov/Teaching/PhysicsII 95.144 Lecture Capture: http://echo360.uml.edu/danylov201415/physics2spring.html 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Circuit Elements 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Slide 31-22 Resistors in series/parallel 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Resistors in Parallel Real circuit I2 I3 We have replaced 3 resistors with a “equivalent” resistor. ΔV I Resistors in parallel have the same potential difference, ΔV Equivalent circuit I1 Consider three resistors connected in parallel. ΔV Req is inserted without changing the operation of the circuit, so I and ΔV are same as in the real circuit = Conservation of current I Ohm’s law + + ; ; 95.144 Danylov Lecture 11 Department of Physics and Applied Physics + + + + Equivalent resistance of resistors in parallel. Resistors in Series ΔV2 ΔV1 ΔV3 ΔV Equivalent circuit Real circuit Consider three resistors connected in series. ΔV Req is inserted without changing the operation of the circuit, so I and ΔV are same as in the real circuit + + Ohm’s law ∆ ∆ ∆ 95.144 Danylov Lecture 11 Department of Physics and Applied Physics + + + + Equivalent resistance of resistors in series. ConcepTest 1 Headlights Are headlight wired: A) in parallel? B) in series? ConcepTest 2 Resistors I The battery current I is A) 3 A B) 2 A C) 1 A D) 2/3 A E) ½ A + =2/3 A ConcepTest 3 Resistors II The battery current I is A) 3 A B) 2 A C) 1 A D) 2/3 A E) ½ A + =4 =3 A Example: Analyzing a complex circuit a)Find the equivalent resistance. b)Find the current through and the potential difference across each of the resistors in the circuit. 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Real batteries 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Real Batteries. Internal resistance To drive a current in a circuit we need a “charge pump”, a device that by doing work on the charge carriers maintains a potential difference. Let’s look at a gravitational analog of a battery: Give me a break! I do it as fast as I can! ∆ Terminal voltage A person does work to maintain a steady flow of balls through “the circuit”. However, this guy cannot move balls instantaneously. It takes time. So there is a natural hindrance to a completely free flow. To describe this hindrance we can introduce the internal resistance, r. It is inside a battery and it cannot be separated from the battery. ε (EMF, ) Pot. difference of a battery without an internal resistance is called an electromotive force. 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Why is electric energy useful? It can be easily transformed into other forms of energy. Mechanical energy Thermal energy Electric energy E/M waves How to find the power transformed by these electrical devices 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Light Electric Power Consider any electrical device: Δt (for Q to go through the device) Some charge Q ΔV As some charge Q moves through the potential difference ΔV, the potential energy of the charge changes by: ∆ ∆ Let Δt be the time required the charge to move through the potential difference ΔV. Then, the power P (the rate energy is transformed, Physics I) is: ∆ ∆ ∙∆ ∆ ∆ ∙∆ ∙∆ The power transformed by a resistor can be written like this: 95.144 Danylov Lecture 11 Department of Physics and Applied Physics ∙∆ ∆ power transformed by an electrical device ∙ ∆ / ConcepTest 5 Electric Power Most loudspeakers are designed to have a resistance of 4 Ω. If it is connected to an amplifier with a rating of 100 W, what is the current to the loudspeaker? A) 2 A B) 3 A C) 4 A D) 5 A E) 25 A ∙∆ ∆ ∙ What you should read Chapter 31 (Knight) Sections 31.1 31.3 31.4 31.5 31.6 31.7 (Example 31.29) 95.144 Danylov Lecture 11 Department of Physics and Applied Physics Thank you See you 95.144 Danylov Lecture 11 Department of Physics and Applied Physics ConcepTest 4 Series Resistors I Assume that the voltage of the battery is 9 V and that the three resistors are identical. What is the potential difference across each resistor? A) 12 V B) zero C) 3 V D) 4 V E) you need to know the actual value of R Since the resistors are all equal, R R R the voltage will drop evenly across the 3 resistors, with 1/3 of 9 V across each one. So we get a 3 V drop across each. 9V