MasteringPhysics: Assignment Print View Student View Summary View Diagnostics View Page 1 of 4 Print View with Answers Edit Assignment Settings per Student PY1P10 - Physics of Motion - Assignment #1 Due: 11:00pm on Tuesday, October 26, 2010 Note: To understand how points are awarded, read your instructor's Grading Policy. Welcome to your first Physics tutorial assignment based on your lecture material. Please remember that you should record all your attempts and rough work for each question in a hardback notebook. This will allow you to effectively review and revise the material covered in this assignment at a later date. Running and Walking Description: One person walks half of a distance and runs the other half. Another person covers the same distance by running and walking for the same amount of time. Determine total time taken by each, and their average velocities. Tim and Rick both can run at speed and walk at speed , with . They set off together on a journey of distance . Rick walks half of the distance and runs the other half. Tim walks half of the time and runs the other half. Part A How long does it take Rick to cover the distance Hint A.1 ? Compute midpoint for Rick Find the time that it takes Rick to walk the first half of the distance, that is, to travel a distance at speed . ANSWER: = Hint A.2 Compute running time for Rick Now find the time Rick spends running. ANSWER: = Hint A.3 What equation to use Now just add the two times up and you're done. Express the time taken by Rick in terms of , , and . ANSWER: = Part B Find Rick's average speed for covering the distance Hint B.1 Calculate velocity using . and time You were given the total distance and have calculated the total time. Recall that average velocity is equal to total distance traveled divided by the amount of time it took to travel this distance. Express Rick's average speed in terms of and . ANSWER: = Part C How long does it take Tim to cover the distance? http://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=1436... 27/10/2010 MasteringPhysics: Assignment Print View Hint C.1 Page 2 of 4 Calculate average speed Tim walks at speed Hint C.1.1 half the time and runs at speed for the other half. Solve a related problem Consider a related problem. Tim walks for a time Find the total distance he travels in time at speed and runs for a time in terms of given quantities and at speed . . ANSWER: = Now use this expression for to find Tim's average speed. Find Tim's average speed in terms of given quantities. ANSWER: = From this result, you can see that when a journey consists of equal amounts of time walking and running, the average speed will be equal to the simple average of the walking and running speeds. This is not the case when the journey is broken into walking and running segments in some other manner. Express the time taken by Tim in terms of , , and . ANSWER: = Part D Who covers the distance Hint D.1 more quickly? Consider the relative positions at the midpoint Imagine that both Rick and Tim do all of their walking before they start to run. Rick will start running when he has covered half of the total distance. When Tim reaches half of the total distance, will he already have started running? Think logically, but without using the detailed answers in the previous parts. ANSWER: Rick Tim Neither. They cover the distance in the same amount of time. Part E In terms of given quantities, by what amount of time, , does Tim beat Rick? It will help you check your answer if you simplify it algebraically and check the special case Express the difference in time, in terms of , , and . . ANSWER: = Part F In the special case that Hint F.1 If , what would be Tim's margin of victory ? Think it through , is the any difference between what Tim and Rick do? ANSWER: http://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=1436... 27/10/2010 MasteringPhysics: Assignment Print View Page 3 of 4 Speed of a Bullet Description: This problem reviews speed from the angle between bullet holes in two disks following a standard experiment. A bullet is shot through two cardboard disks attached a distance apart to a shaft turning with a rotational period , as shown. Part A Derive a formula for the bullet speed the hole in the second. If required, use in terms of , , and a measured angle between the position of the hole in the first disk and that of , not its numeric equivalent. Both of the holes lie at the same radial distance from the shaft. means that the holes are in a line and measures the angular displacement between the two holes; for instance, means that when one hole is up, the other is down. Assume that the bullet must travel through the set of disks within a single revolution. Hint A.1 Consider hole positions The relative position of the holes can be used to find the bullet's speed. Remember, the shaft will have rotated while the bullet travels between the disks. Hint A.2 How long does it take for the disks to rotate by an angle ? The disks rotate by 2 Hint A.2.1 in time . How long will it take them to rotate by ? Checking your formula If your formula is correct, when you plug 2 Give your answer in terms of in for , your answer will be , , and constants such as . . ANSWER: = You know that the bullet went a distance in the time it took for the disks to rotate by . ANSWER: = Exercise 2.34 Description: A subway train starts from rest at a station and accelerates at a rate of 1.60 m/s^2 for 14.0 s . It runs at constant speed for 70.0 s and slows down at a rate of 3.50 m/s^2 until it stops at the next station. (a) Find the total distance covered. A subway train starts from rest at a station and accelerates at a rate of for 14.0 . It runs at constant speed for 70.0 and slows until it stops at the next station. down at a rate of Part A Find the total distance covered. ANSWER: = Exercise 2.50 Description: The acceleration of a bus is given by a_x(t)= alpha t, where alpha is a constant. (a) If the bus's velocity at time t_1 is v_1, what is its velocity at time t_2? (b) If the bus's position at time t_1 is x_1, what is its position at time t_2? http://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=1436... 27/10/2010 MasteringPhysics: Assignment Print View The acceleration of a bus is given by , where Page 4 of 4 = 1.28 is a constant. Part A If the bus's velocity at time = 1.00 is 4.90 = 1.00 is 6.00 , what is its velocity at time = 2.11 ? ANSWER: = Part B If the bus's position at time , what is its position at time = 2.11 ? ANSWER: = Problem 2.97 Description: A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of t later. You may ignore air resistance. (a) If the height of the building is h, what must the initial speed be of the first ball if ... A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.20 air resistance. later. You may ignore Part A If the height of the building is 19.8 , what must the initial speed be of the first ball if both are to hit the ground at the same time? ANSWER: = Part B Consider the same situation, but now let the initial speed of the first ball be given and treat the height What must the height of the building be for both balls to reach the ground at the same time for = 8.70 of the building as an unknown. . ANSWER: = Part C If is greater than some value , a value of does not exist that allows both balls to hit the ground at the same time. Solve for . ANSWER: = Part D If is less than some value , a value of does not exist that allows both balls to hit the ground at the same time. Solve for . ANSWER: = Score Summary: Your score on this assignment is 0%. You received 0 out of a possible total of 100 points. http://session.masteringphysics.com/myct/assignmentPrintView?assignmentID=1436... 27/10/2010