© 2011 Technological Studies Standard Grade Credit Finalised Marking Instructions Scottish Qualifications Authority 2011 The information in this publication may be reproduced to support SQA qualifications only on a non-commercial basis. If it is to be used for any other purposes written permission must be obtained from SQA’s NQ Delivery: Exam Operations Team. Where the publication includes materials from sources other than SQA (secondary copyright), this material should only be reproduced for the purposes of examination or assessment. If it needs to be reproduced for any other purpose it is the centre’s responsibility to obtain the necessary copyright clearance. SQA’s NQ Delivery: Exam Operations Team may be able to direct you to the secondary sources. These Marking Instructions have been prepared by Examination Teams for use by SQA Appointed Markers when marking External Course Assessments. This publication must not be reproduced for commercial or trade purposes. Mark Allocation 1. Marks KU RNA (a) RNA Light Sensor/ LDR Set light level - Control Unit + TD/ Transducer driver/ Output driver (transistor) Lamp Desired light level 2 1 0 RNA (b) Control diagram (c) Compares the set level to the feedback level KU 2. 2 1 0 KU KU 1 0 (a) Light Dependent Resistor (b) As the light level increases the LDR’s resistance decreases. As the light level increases Vout increases. The variable resistor acts as a sensitivity control etc KU 1 0 3 2 1 0 RNA for each correct descriptive statement up to 3. (c) (i) (ii) 400 Vout 1 0 (-420 ) = R1 VCC R2 = 1500 5 1900 = 3·95 V FTE RNA for substitution RNA for answer from given working Page 2 2 1 0 Marks KU RNA 2. (continued) (d) Complete the circuit diagram to show how a diode could be used to protect the transistor from back-voltage (e.m.f.). 1 0 KU for diode symbol RNA for wiring RNA for orientation of diode (e) The transistor is fully switched on when VBE is 0·7 V. (i) Saturated/saturation KU 1 0 (ii) collector 1 Base 2 Emitter KU for each correct 2 1 0 ( KU if names reversed) (f) (i) It allows a low powered circuit to control a high powered circuit. There is no physical link between the circuits. Control circuits can’t work with very high currents 2 1 0 KU for each correct answer up to 2 (ii) (iii) SPST/ Single Pole Single Throw SPDT/ Single Pole Double Throw KU KU DPDT/Double Pole Double Throw Page 3 2 1 0 KU 1 0 2 1 0 Marks KU RNA 3. (a) 1 0 RNA (2 lines) RNA Valve RNA Component A RNA all 3 shuttle pipes KU for at least 1 correct pilot line (b) (i) (ii) Component A Valve 1 Reservoir KU 3/2/Pilot/Spring Return Page 4 1 0 3 2 1 0 0 4 3 2 1 0 Marks KU RNA 3. (continued) (c) A1 = r2 = × 152 = 706mm2 = r = ×5 RNA for correct area calculation A2 2 2 = 78mm 2 ATOTAL = A1 – A2 = 628mm2 F 628 × 0·5 = 314N = 1 4 3 2 1 0 RNA for subs RNA for ans from working (if only using A1 max 2 marks) (d) RNA for combined area Reduce area of cylinder KU Larger piston rod diameter 2 Reduce main air pressure KU Page 5 2 1 0 Marks KU RNA 4. init: symbol counter = b0 for counter = 1 to 3 ‘set for ... next loop to 3 OR clean: low 7 high 6 RNA let pins = %0100000 ‘cleaning head down RNA RNA RNA for both pause 5000 OR low 6 high 7 let pins = %10000000 pause 5000 alternative position for low 7 OR high 5 low 7 label: OR let pins = 0 next counter RNA let pins = %00100000 RNA if pin0 = 0 then label RNA let pins = %00000000 or low 5 RNA return RNA If candidates do not switch off pin then max – 2 marks Page 6 9 8 7 6 5 4 3 2 1 0 Marks KU RNA 5. (a) RNA time in seconds calculation Ee (b) (i) = = ItV 7 × (20 × 60) × 120 = 1008000 J = 1 MJ 3 2 1 0 RNA for substitution RNA for answer from given working = useful power out total power in = 17×8 = 23 RNA for substitution RNA for answer from 0·774 (77·4%) 2 1 given working 0 (ii) RNA (c) 2 1 0 Energy is lost/due to friction etc or sound/heat RNA Reduces energy consumption KU Reduces cost of running system etc (d) (i) 1 KU Coal/gas/oil 2 (ii) each up to 2 1 0 2 1 0 Energy source can be replenished/won’t run out Reduces pollution/greenhouse gas etc Uses less resources KU each up to 2 Page 7 2 1 0 Marks KU RNA 6. (a) Z= (A•B) + (B•C) 2 1 0 RNA for ANDing inputs RNA for OR conditions Alt (A•B•C) + (A•B•C) + (A•B•C) A 0 0 0 0 1 1 1 1 (b) B 0 0 1 1 0 0 1 1 C 0 1 0 1 0 1 0 1 Z 0 0 0 1 0 0 1 1 3 2 1 0 RNA each correct entry (c) (d) Protects the LED (from large current) KU Characteristic TTL 1 0 CMOS Large fan out Higher power consumption Easily damaged by static electricity Faster switching speed Can use supply voltages from 3-18 V KU for each correct single entry Page 8 4 3 2 1 0 7. (a) Marks KU RNA 1 0 Electrically Erasable Programmable Read Only Memory (b) Name Function ROM Stores PBASIC language for microcontroller operations. Data remains after power is switched off. RAM Stores data required Data will not remain when running the when power is program. removed. Stores the program. Data remains after EEPROM Characteristic power is switched off. Data can be re-written. 4 3 2 1 0 KU for each correct entry (c) (i) V mark space t KU for pulsed/on-off signal KU for identifying/describing mark and space KU for identifying/describing that speed is determined by 3 2 1 0 mark/space ratio (ii) Maintains a high torque/smooth turning Only required 1 output pin from microcontroller Page 9 1 0 Marks KU RNA 8. (a) CWM = ACWM (1600 × 0·8) + (1200 × 2) + (1000 × 3) = F × 4 F= 6680 4 RNA for transposition = 1670 N (b) 1 RNA for substitution RNA for answer from given working Lubrication/ball bearing/using alternative materials 2 (c) (i) 3 2 1 0 KU each up to 2 Speed of Drum 2000 × 1 = 50 × X X= 2000 50 cir = d = 3·14 × 0·1 m = 0·314 m RNA for circumference = 40 rev/min Speed of Load 2 1 0 RNA for drum speed Drum speed × Circumference = 40 × 314 = 12560 mm/min OR = 0·2 m/s 3 2 1 0 RNA for answer from working (ii) Part A Wheel KU Part B Worm KU 2 1 0 KU total if answers reversed (d) (i) Rack & Pinion (ii) Crank & Slider KU KU [END OF MARKING INSTRUCTIONS] Page 10 1 0 1 0