Unit 5 Practice Sheet: Linearity, Superposition, and Source Transformation
EGR 2201
Reeder
1. Linearity. Problem 4.3 from the textbook:
a. Using mesh analysis or nodal analysis or any other techniques from previous weeks,
find vo and io when vs = 1 V in the circuit shown below.
b. Use linearity to find vo and io when vs = 10 V.
EGR 2201 Unit 5 Practice sheet - 2
2. Superposition. Practice Problem 4.3 from the textbook:
Suppose we wish to find vo in this circuit.
a. In the space below, redraw the circuit with the current source turned off.
b. Find vo in your redrawn circuit. (Hint: Since you’re dealing with a series circuit, use
the voltage-divider rule.)
c. In the space below, redraw the circuit with the voltage source turned off.
d. Find vo in your redrawn circuit. (Hint: Use the current-divider rule to find out how
much current goes to the left branch, and then use Ohm’s law to find vo.)
e. Find vo in the original circuit by combining your answers from steps b and d.
f. To check your answer, find vo again by applying mesh analysis to the original circuit.
EGR 2201 Unit 5 Practice sheet - 3
3. Combining Sources in Series or Parallel.
a. Redraw the following circuit, replacing the two voltage sources with a single equivalent
voltage source.
b. Repeat the previous question for the following circuit.
c. Redraw the following circuit, replacing the two current sources with a single
equivalent current source.
d. Repeat the previous question for the following circuit.
EGR 2201 Unit 5 Practice sheet - 4
4. Source Transformation. Suppose we wish to find vo in this
circuit.
a. Find vo using techniques that you already know, such as 1) mesh analysis or 2) nodal
analysis or 3) the current-divider rule followed by Ohm’s law.
b. Perform a source transformation by replacing the current source and its parallel
resistor with a voltage source and a series resistor. Draw the transformed circuit
below, and label the voltage source and resistor with their correct values.
c. Find vo in the redrawn circuit, using the voltage-divider rule.