Chapter 14 Introduction to Frequency Selective Circuits 14.1 14.2 14.3 14.4 14.5 Some preliminaries Low-pass filters High-pass filters Bandpass filters Bandreject filters 1 Overview We have seen that the response of a circuit depends on the types of elements, the way the elements are connected, and the impedance of the elements that varies with frequency. In this chapter, we analyze the effect of varying source frequency on circuit voltages and currents. In particular, the circuits made of passive elements (R, L, C) that pass only a finite range of input frequencies. 2 Section 14.1 Some Preliminaries 1. 2. Frequency response Four types of filters 3 Frequency response plot The steady-state response due to a sinusoidal input Acost is determined by sampling the transfer function H(s) along the imaginary axis, i.e. H(j). Since H(j)C, a frequency response plot consists of two parts: (1) magnitude plot |H(j)|, (2) phase angle plot (j). 4 Four types of ideal filters HPF LPF Cutoff freq. BPF BRF 5 Section 14.3 High-pass Filters (HPFs) 1. 2. Frequency response of HPF Effects of load 6 Series RC circuit Zc = 1/( jC). Zc as 0, vo 0 (no current flows through R). Zc 0 as , vo vi (short circuit). The input voltage can pass through the circuit if the source frequency is high enough. ( 0) ( 0) ( ) ( vi) 7 Frequency response plot of a series RC circuit By the equivalent circuit in the s-domain: 1 Vo ( s ) R s , where c . H ( s) 1 Vi ( s ) R ( sC ) s c RC j H ( j ) , j c H ( j ) 2 c2 1 c . ( j ) 90 tan H ( jc ) 1 0.71 2 ( jc ) 45 8 Example: Superposition of sinusoids 1 2 Let x (t ) x1 (t ) x2 (t ) cos(0.1c t ) sin(3ct ). H ( j1 ) 0.1084 j c H ( j ) , j c 1 H ( j2 ) 0.9518 Y1 10 0.1084 , y1 (t ) 0.1 cos(0.1c t 84 ); Y2 1 90 0.9518 , y2 (t ) 0.95 cos(3c t 72 ); (Tc = 2/c) 9 Example: Filtering in the spatial-frequency domain An image is a function of (x,y), which can be decomposed into many “spatial-frequency” components ( fx, fy). HPF enhances the contrast. (wikipedia.org) 10 Example 14.4: RL circuit with load (1) An RL circuit can be an HPF if vo vL. (E.g. 14.3) When a load resistor RL is in parallel with the output inductor L: 1 Ks R H ( s) , where c , K 1. 1 ( R RL ) s Kc L 11 Example 14.4: RL circuit with load (2) The effects of RL are: (1) reducing the passband magnitude by a factor of K, (2) lowering the cutoff frequency by the same factor of K. (RL = R) Problem: the response varies with the load. Solution: use active filters (Ch15). 12 Section 14.4 Bandpass Filters (BPFs) 1. 2. Frequency response of BPF Relation with the poles, zeros 13 Series RLC circuit Zc = 1/( jC), ZL = j L. Zc as 0, vo 0. ZL as , vo 0. At some frequency 0(0,), Zc + ZL = 0, vo = vi. The input voltage can pass through the circuit if the source frequency is near 0. ( 0) ( 0) ( ) ( 0) 14 Frequency response plot of a series RLC circuit By the equivalent circuit in the s-domain: s R R , where , 0 H ( s) 2 1 2 sL ( sC ) R s s 0 L 1 . LC H ( j ) 2 2 2 2 ( ) 0 1 ( j ) 90 tan 2 2 . 0 ( j 0 ) 0 15 Calculations of parameters Center (resonance) frequency is derived by: 1 jL 0, 0 jC 1 . LC Cutoff frequencies are derived by: 1 2 H ( j ) , c1,c 2 0 . 2 2 2 c1 c 2 R ; . Bandwidth c 2 c1 0 c1 c 2 2 L 2 Quality factor (~ inversed relative bandwidth) is: LC 0 . Q R 16 Example: White-noise rejection If a signal of specific frequency f1 is buried in strong “white” noise, a BPF centered at f1 can be used to extract the signal. (www.chem.vt.edu) 17 Frequency response visualized by poles, zeros The poles and zeros of HPF and BPF are: s , p c , z 0. H HPF ( s ) s c 2 2 4 s 0 H BPF ( s ) 2 , p , z 0. 2 s s 0 2 Im -c Im Re -/2 Re 18 Practical Perspective Pushbutton Telephone Circuits 19 Application of BPFs Q: How to tell which button was pushed? How to tell the difference between the button tones and the normal vocal sounds (both are within 3003000 Hz) or ringing bell tones (20 Hz)? (wikipedia.org) (jouielovesyou.wordpress.com) 20 Dual-tone-multiple-frequency (DTMF) Each bottom is encoded with a unique pair of sinusoidal tones (fL, fH), where the relative timing and amplitudes must be close enough. (sohilp.blogspot.com) BPFs: (1) identify whether both freq. groups are present, (2) select among possible tones. 21 BPF design for the low-frequency group The transmission spectrum of a series RLC is: H ( j ) 2 2 2 0 R where , 0 L ( ) 2 , 1 . LC For the low-freq. group, c1 = 2(697) = 4379 rad/s, c2 = 2(941) = 5912 rad/s, c2–c1 = 1533 rad/s. R L , L R (600 ) 1533 0.39 H. 0 c1c 2 1 LC , C 1 ( Lc1c 2 ) 100 nF. 22 BPF performance (1) The transmission of the 4 frequencies in the lowfrequency group are imperfect (<1): H 697Hz H 941Hz 1 0.707, 2 H 770Hz H 852Hz 2 2 2 0 ( ) 2 0.948. 23 BPF performance (2) The transmission of the high-frequency group tones and the 20 Hz ringing tone are imperfect (>0): 24 BPF design for the high-frequency group The transmission spectrum of a series RLC is: H ( j ) R , , 0 2 L 2 02 ( )2 1 . LC For the high-freq. group, c1 = 2(1209) = 7596 rad/s, c2 = 2(1633) = 10260 rad/s, c2–c1 = 2664 rad/s. Both L and C values are smaller: R L , L R (600 ) 2664 0.26 H. 0 c1c 2 1 LC , C 1 ( Lc1c 2 ) 57 nF. 25 BPF performance The transmission of the low-frequency group tones and the 20 Hz ringing tone are imperfect (>0): 26