MIT OpenCourseWare http://ocw.mit.edu 6.013/ESD.013J Electromagnetics and Applications, Fall 2005 Please use the following citation format: Markus Zahn, Erich Ippen, and David Staelin, 6.013/ESD.013J Electromagnetics and Applications, Fall 2005. (Massachusetts Institute of Technology: MIT OpenCourseWare). http://ocw.mit.edu (accessed MM DD, YYYY). License: Creative Commons AttributionNoncommercial-Share Alike. Note: Please use the actual date you accessed this material in your citation. For more information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.013 Electromagnetics and Applications Problem Set #11 Fall Term 2005 Issued: 11/29/2005 Due: 12/9/05 Suggested Reading Assignment: Staelin, Sections 6.1-6.4, 10.1, 10.2, 10.4 Final Exam: Wednesday, Dec. 21, 2005, 1:30-4:30pm. Problem 11.1 A popular 1-MHz AM radio station in the middle of Kansas has a single transmitting antenna on a flat prairie that radiates 100kW isotropically (equally in all directions) over the upper 2 steradians (i.e., this station has no underground audience.) The matched input impedance (the radiation resistance Rr ) of this antenna is ~70 ohms, and it is driven by V0 sin t volts at maximum power. a) What is V0 [Volts] ? b) What is the radiated intensity I [W / m 2 ] 50 kilometers from this antenna? c) What is the maximum power Pr that can be received from this station by an antenna 50 km away with an effective area A = 10 m2 ? Problem 11.2 A short dipole antenna, 10 cm in length and aligned along the zˆaxis, is driven uniformly along its length with a sinusoidal current of peak value 1 amp. a) What is the electric field E ( r , , t ) in the far field? b) At what frequency would this antenna radiate 1 watt of power? c) If a receiver with effective area A = 0.1 m2 needed 10-20 watts for successful reception, how far away could it be and still receive signals from the 1 watt dipole? In what direction? Problem 11.3 An antenna consists of two short dipoles, oriented along the z-axis and separated along the y-axis by a distance a. They are driven in phase, each with a current I 0 and an effective length deff , ( deff ), at an angular frequency of . (Assume that each antenna radiates as it would in the absence of the other.) a a) What is the intensity of the radiation in the far field as a function of angle in the x-y plane? b) For a 2, at what angles max and min is the intensity a relative maximum or zero? Page 1 of 7 Problem 11.4 A "turnstile" antenna consists of two short Hertzian dipoles driven at an angular frequency and oriented at right angles to each other as shown in the figure below. One dipole, oriented along the x-axis is driven ˆ ˆ ˆˆ ˆ with a current I1 Iˆ 0 x and the other, oriented along the y-axis is driven with I2 jI0 y . Both have the same effective length d eff . a) Find the complex amplitude of the total electric field on the +z axis in the far field. (Express your answer in Cartesian coordinates with unit vectors xˆˆ , y, and zˆ.) b) Why is the result of part (a) called left-handed circular polarization (LHCP) for +z directed waves along the +z axis? c) What is the complex amplitude of the magnetic field on the +z axis in the far field? d) What is the intensity of the radiation on the z axis in the far field? 1 ˆ ˆ Hint: S Re E H 2 Problem 11.5 Sketch the far field radiation patterns in the x-y plane for each of the following short dipole antenna arrays. The identical dipoles are directed in either the +z or -z directions, as indicated, and the so that its complex 2 amplitude is j. In each case find the angles corresponding to nulls ( n ) and peaks ( p ). If the peaks currents have equal amplitudes of 1 . In part (b) one current has a phase of are unequal, also evaluate their relative values. Page 2 of 7 Problem 11.6 Using the format of Problem 11.5 design two-dipole arrays that could produce the far field antenna gain patterns illustrated below. The two dipoles have the same current amplitude but may differ in phase. Find the spacing a between the two dipoles and their relative phase that results in the radiation patterns shown in parts (a) - (c). Page 3 of 7 6.013 Final Exam Formula Sheet December 21, 2005 Cartesian Coordinates (x,y,z): xˆ yˆ zˆ x y z A y Az A A x x y z A Ay Az Ax A A A xˆ y yˆ z zˆ x z z x x y y 2 2 2 2 x2 y2 z2 Cylindrical coordinates (r,,z): z ˆ1 rˆ ˆ r r z rA r 1 A Az 1 A r r r z ˆ zˆ rˆ r rA 1 Az A A A A 1 1 ˆ r z zˆ A rˆ r det r z r z z r r r r A r rA A z 2 2 1 1 2 r 2 2 2 r r r r z Spherical coordinates (r,,): ˆ1 ˆ 1 rˆ r r r sin A 12 r r 2A r sin A 1 A 1 r r sin r sin sin A 1 rA 1 A ˆ A r 1 Ar ˆ rA A rˆ 1 r sin r sin r r r r ˆ r sin ˆ rˆ r 1 2 det r r sin A rA r sin A r 2 2 1 2 1 1 r sin 2 2 2 2 r r sin 2 r r r sin Gauss’ Divergence Theorem: G dv Gnˆda V A Stokes’ Theorem: G nˆda G d A C Vector Algebra: xˆ x yˆ y zˆ z A B Ax Bx Ay By Az Bz A 0 A A 2 A Page 4 of 7 Basic Equations for Electromagnetics and Applications Fundamentals f q E v o H N (Force on point charge) E1// E 2 // 0 E B t H1// H 2 // Js nˆ d E ds B da c dt A H J D t B1 B2 0 nˆ D1 D2 s d Electromagnetic Quasistatics E r , r r / 4 r r dv V f 2 C = Q/V = A/d [F] L = /I i(t) = C dv(t)/dt v(t) = L di(t)/dt = d/dt 2 2 we = Cv (t)/2; wm = Li (t)/2 2 Lsolenoid = N A/W = RC, = L/R B da (per turn) A J t -1 E = electric field (Vm ) -1 H = magnetic field (Am ) -2 D = electric displacement (Cm ) B = magnetic flux density (T) -2 Tesla (T) = Weber m = 10,000 gauss = charge density (Cm -3) J = current density (Am -2) -1 = conductivity (Siemens m ) KCL : i Ii (t) 0 at node -1 J s = surface current density (Am ) KVL : i Vi (t) 0 around loop -2 s = surface charge density (Cm ) o = 8.85 10 -7 Q 0 wT / Pdiss 0 / -1 Fm 0.5 0 LC -1 o = 410 Hm c = ( o o) -0.5 8 3 10 ms V 2 t / R kT -1 e = -1.60 10-19 C o 377 ohms = ( o/o)0.5 Electromagnetic Waves t E 0 [Wave Eqn.] 2 2 2 2 t 2 E 0 [Wave Eqn.] 2 Ey(z,t) = E+ (z-ct) + E-(z+ct) = Re{Ey (z)ejt} Hx(z,t) = o- 1[E+ (z-ct)-E-(z+ct)] [or(t-kz) or (t-z/c)] E 2 H 2dv E H da d dt A V E J dv (Poynting Theorem) V 2 2 2 k 2 Eˆ0, EˆEˆo e jk r k = ( )0.5 = /c = 2/ 2 2 2 2 2 kx + ky + kz = ko = vp = /k, vg = (k/)-1 r i sint / sini ki / kt ni / nt Media and Boundaries D E P o c sin1 nt / ni D f , B tan 1 t / i for TM ˆ ˆ xjkz z E E Te 0.5 f p oE c P p , J E t i k k jk T 1 B H o H M 1 p , p Ne m (plasma) TTE 2 / 1 i cost / t cosi eff 1j/ TTM 2 / 1 t cost / i cosi 2 2 2 1 2 0 = if = H ds J da D da c A dt A D D da dv A V B 0 B da 0 A -12 nˆ 0.5 Skin depth = 2 / m 0.5 Page 5 of 7 Radiating Waves Wireless Communications and Radar 1 A 2 A 2 2 J f c t 2 1 2 f 2 2 c t 2 G(,) = P r/(P R/4r2 ) PR P , , r r2 sin d d 4 r J f t rQP / c dV A V 4rQP Prec = Pr (,)Ae(,) f t rQP / c dV V 4 rQP Ae ( , ) G( , )2 4 A E , B A t r ˆ(r ) ˆ(r )e jkr / 4 r 'r dV V ˆ A(r) r e jk r ' r 4r 'r dV ' Jˆ V' ˆ H ˆ ˆ 4r E jkId ejkr sin ff ff 2 ˆ 2 ˆ x, y, z ˆ ˆ, x, y, z, t Re e jt ˆ 2 ˆ 2 j t ˆ ˆ A A J , A x, y, z, t Re A x, y, z e G ( , ) 1.5sin2 (Hertzian Dipole) i2 (t) R r PR jkx x jky y jkr Eff 0 je r Et (x, y)e dxdy A ˆ a Eejkri (element factor)(array f) E z i i Ebit ~4 10 -20 [J] Z12 Z21 if reciprocity At o , we wm Forces, Motors, and Generators J E v B 2 2 ˆ 4 H dv V w e Eˆ 4 dv V wm F I B Nm-1 (force per unit length) Q n n w Tn Pn n 2 n E v B inside perfectly conducting wire f mnp c 2 m a n b p d 2 2 -2 Max f/A = B /2, D /2[Nm ] dw vi T f dz dt dt f = ma = d(mv)/dt 2 sn = j n - n Acoustics P = fv = T(Watts) P Po p, U Uo u T = I d/dt p u t o I i mi ri u 1 Po p t 2 FE E Nm 1 Force per unit length on line charge 2 k 22 t 2 p 0 1 2 1 q2 WM , x ; WE q, x 2 L x 2 C x 2 k 2 2 cs Po o W fM , x M x W fE ( q, x) E x 2 0.5 2 q x 1 d 1 dL 2 x I 2 1/ L 2 dx 2 dx x 1 d 1 dC q2 1/ C x v2 2 dx 2 dx 2 cs vp vg Po o or K o 0.5 0.5 s = p/u = oc s = (o P o) s = (oK) Optical Communications 0.5 gases solids, liquids p, u continuous at boundaries E = hf, photons or phonons p = p+e hf/c = momentum [kg ms -1] uz = s (p+e dn 2 dt An 2 B n 2 n 1 0.5 -jkz -1 +jkz + p- e -jkz – p-e +jkz ) up da d dt o u A V 2 2 p 2 2 Po dV Page 6 of 7 Transmission Lines Time Domain v(z,t)/z = -Li(z,t)/t i(z,t)/z = -Cv(z,t)/t 2 2 2 2 v/z = LC v/t v(z,t) = V+ (t – z/c) + V-(t + z/c) i(z,t) = Yo [V+ (t – z/c) – V-(t + z/c)] c = (LC) -0.5 -0.5 = ( ) Zo = Y o-1 = (L/C)0.5 L = V-/V+ = (R L – Zo)/(RL + Zo) Frequency Domain ˆ =0 (d 2 /dz 2 +2 LC)V(z) ˆ = Vˆe -jkz + V ˆe +jkz , v( z, t ) Re V(z) Vˆ ( z )e j t + ˆ ˆe-jkz - Vˆe +jkz ], i( z, t) Re ˆz) e j t I(z) = Y0[V I( + k = 2/= /c = ()0.5 ˆ ˆ Z(z) V(z) I(z) Zo Zn (z) Zn (z) 1(z) 1 (z)R n jX n (z) V V e 2 jkz Z n (z) 1 Z n (z) 1 Z(z) Zo ZL jZo tan kz Zo jZL tan kz VSWR Vmax Vmin Page 7 of 7