ESE 271 / Spring 2013 / Lecture 12 Last time: Phasors. Harmonic Signal in time domain Corresponding Phasor Amplitude of sine wave or Signal Magnitude Initial phase of sine wave or Signal Phase Phasor contains information about both Signal Magnitude and Signal Phase Frequency of the signal remains unchanged in linear circuits. 1 ESE 271 / Spring 2013 / Lecture 12 Complex Impedance – generalized resistance. Ohm’s law for Phasors: Complex impedance: Series Parallel 2 ESE 271 / Spring 2013 / Lecture 12 Complex Impedance of R, C and L. Resistor: Capacitor: Inductor: 3 ESE 271 / Spring 2013 / Lecture 12 Phasor circuits. 4 ESE 271 / Spring 2013 / Lecture 12 Phasor diagrams. Magnitude and phase of complex impedance are functions of frequency: Hence, the phasor diagram changes with frequency! 5 ESE 271 / Spring 2013 / Lecture 12 Phasor diagram of series RLC circuit. Voltage and current phasors can be treated as vectors on complex plane. 6 ESE 271 / Spring 2013 / Lecture 12 Series RLC circuit at different frequencies. Resonance ! At resonant frequency and they can be but 7 ESE 271 / Spring 2013 / Lecture 12 Series RLC resonance. resonant frequency 8 ESE 271 / Spring 2013 / Lecture 12 How to use phasor diagrams? 9 ESE 271 / Spring 2013 / Lecture 12 Thevenin and Norton equivalents for phasors. Can be represented by equivalent circuit Active circuit Thevenin form Norton form 10 ESE 271 / Spring 2013 / Lecture 12 Example 1. Find current using phasor analysis and by replacing circuit to the left of AB by its Norton equivalent Phasor circuit 11 ESE 271 / Spring 2013 / Lecture 12 Example 1 ‐ cont. Phasor circuit Norton equivalent Phasor circuit 12 ESE 271 / Spring 2013 / Lecture 12 Example 1 ‐ cont. Phasor circuit Norton equivalent Phasor circuit 13 ESE 271 / Spring 2013 / Lecture 12 Example 1 ‐ cont. Norton equivalent Phasor circuit 14 ESE 271 / Spring 2013 / Lecture 12 Example 2. Find Norton and Thevenin equivalents Norton Thevenin 15 ESE 271 / Spring 2013 / Lecture 12 Example 2 – cont. Equivalent impedance is inductive 16 ESE 271 / Spring 2013 / Lecture 12 Nodal analysis of Phasor circuits. 17 ESE 271 / Spring 2013 / Lecture 12 Example 1. Phasor circuit Let’s simplify the circuit a bit 18 ESE 271 / Spring 2013 / Lecture 12 Example 1 ‐ cont. Simplified Phasor circuit contains 4 nodes. Node 2: Node 3: 19 ESE 271 / Spring 2013 / Lecture 12 Example 1 ‐ cont. 20 ESE 271 / Spring 2013 / Lecture 12 Example 1 ‐ cont. 21 ESE 271 / Spring 2013 / Lecture 12 Example 2. Phasor circuit Phasor circuit contains 4 nodes: 22 ESE 271 / Spring 2013 / Lecture 12 Example 2 ‐ cont. 23 ESE 271 / Spring 2013 / Lecture 12 Example 2 ‐ cont. 24 ESE 271 / Spring 2013 / Lecture 12 Example 2 ‐ cont. 25