Load--Line Analysis Load Electronic Circuits The load line plots all possible combinations of diode current (ID) and voltage (VD) for a given circuit. The maximum ID equals E/R, and the maximum VD equals E. Prof. Nizamettin AYDIN naydin@yildiz.edu.tr http://www.yildiz.edu.tr/~naydin The point where the load line and the characteristic curve intersect is the Q-point, which identifies ID and VD for a particular diode in a given circuit. 1 2 Series Diode Configurations Series Diode Configurations Forward Bias Constants • Silicon Diode: VD = 0.7 V • Germanium Diode: VD = 0.3 V Reverse Bias Diodes ideally behave as open circuits Analysis • VD = E • VR = 0 V • ID = 0 A Analysis (for silicon) • VD = 0.7 V (or VD = E if E < 0.7 V) • VR = E – VD • ID = IR = IT = VR / R 3 Parallel Configurations Half--Wave Rectification Half V = 0.7 V D The diode only conducts when it is forward biased, therefore only half of the AC cycle passes through the diode to the output. V =V = V = 0.7 V D1 D2 O V = 9.3 V R I I R = D1 E−V D = 10 V − .7 V = 28 mA R .33kΩ =I D2 = 28 mA 2 4 = 14 mA The DC output voltage is 0.318Vm, where Vm = the peak AC voltage. 5 6 1 PIV (PRV) Full Full--Wave Rectification Because the diode is only forward biased for one-half of the AC cycle, it is also reverse biased for one-half cycle. The rectification process can be improved by using a full-wave rectifier circuit. It is important that the reverse breakdown voltage rating of the diode be high enough to withstand the peak, reverse-biasing AC voltage. Full-wave rectification produces a greater DC output: PIV (or PRV) > Vm • • • PIV = Peak inverse voltage PRV = Peak reverse voltage Vm = Peak AC voltage • • Half-wave: Vdc = 0.318V 0.318Vm Full-wave: Vdc = 0.636 0.636V Vm 7 Full Full--Wave Rectification 8 Full Full--Wave Rectification CenterCenter-Tapped Transformer Rectifier Bridge Rectifier • • Requires • Two diodes • Center-tapped transformer Four diodes are connected in a bridge configuration VDC = 0.636Vm VDC = 0.636Vm 9 Diode Clippers Summary of Rectifier Circuits Rectifier Ideal VDC Realistic VDC Half Wave Rectifier VDC = 0.318Vm VDC = 0.318Vm – 0.7 Bridge Rectifier VDC = 0.636Vm VDC = 0.636Vm – 2(0.7 V) Center-Tapped Transformer Rectifier VDC = 0.636Vm VDC = 0.636Vm – 0.7 V 10 The diode in a series clipper “clips” any voltage that does not forward bias it: • •A reverse-biasing polarity •A forward-biasing polarity less than 0.7 V (for a silicon diode) Vm = peak of the AC voltage. In the center tapped transformer rectifier circuit, the peak AC voltage is the transformer secondary voltage to the tap. 11 12 2 Biased Clippers Parallel Clippers Adding a DC source in series with the clipping diode changes the effective forward bias of the diode. The diode in a parallel clipper circuit “clips” any voltage that forward bias it. DC biasing can be added in series with the diode to change the clipping level. 13 Summary of Clipper Circuits 14 Summary of Clipper Circuits more… 15 Clampers 16 Biased Clamper Circuits The input signal can be any type of waveform such as sine, square, and triangle waves. A diode and capacitor can be combined to “clamp” an AC signal to a specific DC level. The DC source lets you adjust the DC clamping level. 17 18 3 Zener Diodes Summary of Clamper Circuits The Zener is a diode operated in reverse bias at the Zener Voltage (Vz). • When Vi ≥ VZ – The Zener is on – Voltage across the Zener is VZ – Zener current: IZ = IR – IRL – The Zener Power: PZ = VZIZ • When Vi < VZ – The Zener is off – The Zener acts as an open circuit 19 20 Zener Resistor Values Voltage--Multiplier Circuits Voltage If R is too large, the Zener diode cannot conduct because the available amount of current is less than the minimum current rating, IZK. The minimum current is given by: I Lmin = IR − I ZK Voltage multiplier circuits use a combination of diodes and capacitors to step up the output voltage of rectifier circuits. • • • The maximum value of resistance is: R Lmax = VZ I Lmin Voltage Doubler Voltage Tripler Voltage Quadrupler If R is too small, the Zener current exceeds the maximum current rating, IZM . The maximum current for the circuit is given by: VL V = Z RL RL min The minimum value of resistance is: I L max = RL min = RVZ Vi − VZ 21 22 Voltage Doubler Voltage Doubler This half-wave voltage doubler’s output can be calculated by: • Positive Half-Cycle o D1 conducts o D2 is switched off o Capacitor C1 charges to Vm • Negative Half-Cycle o D1 is switched off o D2 conducts o Capacitor C2 charges to Vm Vout = VC2 = 2Vm Vout = VC2 = 2Vm where Vm = peak secondary voltage of the transformer 23 24 4 Practical Applications Voltage Tripler and Quadrupler 25 • Rectifier Circuits – Conversions of AC to DC for DC operated circuits – Battery Charging Circuits • Simple Diode Circuits – Protective Circuits against – Overcurrent – Polarity Reversal – Currents caused by an inductive kick in a relay circuit • Zener Circuits – Overvoltage Protection – Setting Reference Voltages 26 5